Which equation represents a circle that contains the point (-5, 3) and has a center at (-2, 1)? Distance formula: vaa -02 (x - 1)2 + ( + 2)2 = 25 (x + 2)2 + (-1)=5 O (* + 2) + (-1) - 25 (x-1) + ( + 2) = 5

Answers

Answer 1

Given:

The center of the circle = (-2,1).

Circle passes through the point (-5,3).

To find:

The equation of the circle.

Solution:

Radius is the distance between the center of the circle and any point on the circle. So, radius of the circle is the distance between the points (-2,1) and (-5,3).

[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]r=\sqrt{(-5-(-2))^2+(3-1)^2}[/tex]

[tex]r=\sqrt{(-5+2)^2+(2)^2}[/tex]

[tex]r=\sqrt{(-3)^2+(2)^2}[/tex]

On further simplification, we get

[tex]r=\sqrt{9+4}[/tex]

[tex]r=\sqrt{13}[/tex]

The standard form of a circle is:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Where, (h,k) is the center of the circle and r is the radius of the circle.

Substitute h=-2, k=1 and [tex]r=\sqrt{13}[/tex].

[tex](x-(-2))^2+(y-1)^2=(\sqrt{13})^2[/tex]

[tex](x+2)^2+(y-1)^2=13[/tex]

Therefore, the equation of the circle is [tex](x+2)^2+(y-1)^2=13[/tex].


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