Which compound contains a double bond?
ethene (C2H4)
chlorine (C12)
ammonia (NH3)
methane (CH)

Answer:

Cartilage

Explanation:

Be careful, if you grind down your cartilage it pinches your nerves and can cause serious problems

Which arrow represents the force of gravity acting upon the car?

✔ B

Which arrow represents the normal force on the car?

✔ A

Which arrow represents the applied force on the car when the driver steps on the gas pedal?

✔ C

Answer:

Types Descriptions

Flows occur when soil or rock acts like a liquid

Slumps a slice of material that moves as one piece along a curved surface

Landslides made up of unconsolidated rock; includes rockslides and avalanches

Creeps material that moves slowly down gently sloping areas

Explanation:

Googled it.

Water can affect mass movements by reducing the friction along a sliding surface and can also allow particles to slide past each other easily.

Mass movement refers to the transfer of rocks and solid downslope as a result of gravity. Mass movement is the relocation of surface material such as solid or rock from a point along a slope to a position that's further down the slope.

It should be noted that water triggers mass movement. This is done as water fills the pores that are in the sediments, this then allows the particles to slide past each other easily.

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Answer:

Alkali Metals

Explanation:

Answer:

For all uncharged atoms, the number of electrons equals the number of protons. The mass number 40 is the sum of protons and neutrons. To find the number of neutrons, subtract the number of protons from the mass number.

Answer:

mass number- protons

Explanation:

Answer:

Rule 1. The cation is written first in the name; the anion is written second in the name.

Rule 2. When the formula unit contains two or more of the same polyatomic ion, that ion is written in parentheses with the subscript written outside the parentheses.

examples: ammonium ion and hydrogen carbonate

Explanation:

hope this helps

Answer:65

Explanation:

Answer:

20 mol H₂

General Formulas and Concepts:

Chem

Explanation:

Step 1: Define

RxN: C + H₂ → CH₄

8 moles CH₄

Step 2: Balance RxN

C + 2H₂ → CH₄

Step 3: Stoichiometry

[tex]8 \ mol \ CH_4(\frac{2 \ mol \ H_2}{1 \ mol \ CH_4} )[/tex] = 16 mol H₂

Step 4: Check

We are given 1 sig fig. Follow sig fig rules.

16 mol H₂ ≈ 20 mol H₂

Answer:

isoborneol and camphor both have methyl groups that have different shielding zones with -OH and -C=O groups respectively.

Explanation:

Using the knowledge of chemical shift we can see that out of the three methyl groups in isoborneol, there are two methyl groups that are not influenced by the chemical Influence of the -OH functional group while one of the methyl groups is influenced by the -OH functional group.

For Camphor, two out of the three methyl groups are in shielding zones of the Carbonyl group, -C=O. While the last of the three methyl groups is out of the shielding zones of Carbonyl group, -C=O.

Answer:

C) The positive and negative charges are equal.

Explanation:

Ions can be made by single element or covalently bonded group of elements. The covalently bonded group of elements is called polyatomic ions or polyatomic atoms. The correct option are option C.

Any species that contain charge whether it is positive charge or negative charge is called ions. The example of polyatomic ions are sulfate, phosphate, nitrate etc.

Cation is the species that loose electron and attain positive charge while anion is a species which gain electron and attains negative charge so when anion and cation combine in fixed ration the the overall charge of the molecule is zero that is molecule is neutral, the charge over cation and anion is also called oxidation state.

Before there is a transfer of charges between objects, they are uncharged as the positive and negative charges are equal.

Therefore the correct option are option C.

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Answer:

its a gas

Explanation:

Hydrogen  is the chemical element in the periodic table that has the symbol H and atomic number 1. At standard temperature and pressure it is a colorless, odorless, non-metallic, univalent, highly flammable diatomic gas. Hydrogen is the lightest and most abundant element in the universe.

In the given question, the state of matter of Hydrogen is gas in nature.

A state of matter is one of the four distinct forms in which matter can exist as solid, liquid, gas, and plasma.

Hydrogen is a chemical element that occurs naturally as a gas at standard temperature and pressure (STP). It is the lightest and most abundant element in the universe and is found in stars, gas giants, and other celestial bodies.

It is also used in various industrial processes, such as the production of ammonia and methanol, and as a fuel source in fuel cells.

Therefore, hydrogen is in the gaseous state at room temperature and normal atmospheric pressure.

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Answer:

Magnesium sulfide and potassium bromide.

Explanation:

Hello!

In this case, for the two mentioned solutions, which are composed by both potassium sulfide (K2S) and magnesium bromide (MgBr2), the following chemical reaction would be carried out:

[tex]K_2S+MgBr_2\rightarrow MgS+KBr[/tex]

However, due to the discrepancy in the atoms of bromine and potassium, the balanced chemical equation should be:

[tex]K_2S+MgBr_2\rightarrow MgS+2KBr[/tex]

Whereas the products are magnesium sulfide and potassium bromide which are both soluble in water.

Best regards!

Answer:

Number of hydrogen sulfide molecule = 5.7672 x 10²³ (Approx)

Explanation:

Molar mass of H2S = (1x2) + 32 = 34 g

Total number of molecule = 34 / 35.50

Total number of molecule = 0.9577

Avogadro's number = 6.022 x 10²³

Number of hydrogen sulfide molecule = 0.9577 x 6.022 x 10²³

Number of hydrogen sulfide molecule = 5.7672 x 10²³ (Approx)

Answer:

Democritus

Explanation:

Answer:

Democritus of Abdera

Explanation:

900 mph................

Answer:

a = 0.8 m/s/s

Vav = 45m/s

Explanation:

Vav = [tex]\frac{Vi + Vf}{2\\}[/tex]

Vav = [tex]\frac{10 +80}{2}[/tex]

Vav = 45m/s

a = [tex]\frac{v}{t}[/tex]

a = [tex]\frac{4m/s}{5s}[/tex]

a= 0.8m/s/s

Solution :

Given that the violet line from Balmer series having a recorded wavelength of 410 nm. As the recorded wavelength is 410 nm we know, the wavelength range of violet light is 380 nm -450 nm. So the 410 nm is corresponding to violet light wavelength.

We know, among all the series of lines spectrum of [tex]$H_2$[/tex] atom, only the Balmer series are in visible range. For Balmer series, the equation of wavelength associated with the e-transition of n = 2 orbit to n > 2 is

[tex]$\frac{1}{\lambda}=R\left[\frac{1}{2^2}-\frac{1}{n^2}\right]$[/tex]

where, R = Rydberg constant = 109678 per cm

            λ = wavelength

Here the recorded λ = 410 nm = [tex]$410 \times 14^{-7} \ cm$[/tex]

∴ [tex]$\frac{1}{410 \times 10^{-7}}=109678\left[\frac{1}{2^2}-\frac{1}{n^2}\right]$[/tex]

[tex]$\frac{1}{2^2}-\frac{1}{n^2}=\frac{1}{410 \times 10^{-7}\times 109678}$[/tex]

[tex]$\frac{1}{4}-\frac{1}{n^2}=0.222$[/tex]

[tex]$\frac{1}{n^2}=\frac{1}{4}-0.222$[/tex]

[tex]$n^2=\frac{1}{0.0276}$[/tex]

[tex]$n^2=36.2$[/tex]

[tex]$n^2 $[/tex] ≈ 36

n = ±6

Here, n is the principle quantum number. It cannot be negative, so the value of n = 6 for hydrogen atom if the violet line from Balmer series that has a recorded wavelength of 410 nm.

The value of n for the Hydrogen transition in the Balmer series with the wavelength 410 nm has been 6.

The principal quantum number in the Balmer series transition has been given by n. The minimum transition for the Balmer series has been from the 2 energy level.

The expression for the wavelength transition can be given by:

[tex]\rm \dfrac{1}{\lambda}\;=\;R\;[\dfrac{1}{2^2}\;-\;\dfrac{1}{n^2} ][/tex]

[tex]\lambda[/tex] = Wavelength = 410 nm = 410 [tex]\rm \times\;10^-^7[/tex] cm

R = Rydbreg constant = 109678/cm

[tex]\rm \dfrac{1}{410\;\times\;10^-^7}\;=\;109678\;[\dfrac{1}{2^2}\;-\;\dfrac{1}{n^2} ][/tex]

[tex]\rm \dfrac{1}{410\;\times\;10^-^7\;\times\;109678}\;=\;\;[\dfrac{1}{2^2}\;-\;\dfrac{1}{n^2} ][/tex]

[tex]\rm 0.222\;=\;\;[\dfrac{1}{2^2}\;-\;\dfrac{1}{n^2} ][/tex]

[tex]\rm 0.222\;=\;\;[\dfrac{1}{4}\;-\;\dfrac{1}{n^2} ][/tex]

[tex]\rm 0.222\;-\;\dfrac{1}{4}\;=\;\dfrac{1}{n^2}[/tex]

[tex]\rm n^2\;=\;36.2[/tex]

n = 6

The value of n for the Hydrogen transition in the Balmer series with the wavelength 410 nm has been 6.

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Answer:

B They travel only through solids.

Explanation:

Seismic s-waves are also known as secondary or shear-waves. They are elastic waves that travels within a body.

Answer:

7 AM was the first to be the best Friend and a friend and I have seen the target market share of a million dollars and Diamond.

Answer:Density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.

Explanation:

Answer:

a) electron

Explanation:

Answer:

a

Explanation:

i took the test

Answer:

The question is incomplete. Searching in google I found: A 3.96x10⁻⁴ M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000-cm cuvette. A blank solution containing only solvent had an absorbance of 0.029 at the same wavelength. Find the molar absorptivity of compound A.

The molar absorptivity of compound A is 1502.5 M⁻¹cm⁻¹.

Explanation:

The question is incomplete. Searching in google I found: A 3.96x10⁻⁴ M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000-cm cuvette. A blank solution containing only solvent had an absorbance of 0.029 at the same wavelength. Find the molar absorptivity of compound A.  

The absorbance (A) is given by:

[tex] A = \epsilon cl [/tex]

Where:

c: is the concentration of compound A = 3.96x10⁻⁴ M    

ε: is the molar absorptivity of compound A =?

l: is the pathlength = 1 cm

[tex]A_{s}[/tex]: is the absorbance of the solution= 0.624

[tex]A_{b}[/tex]: is the absorbance of the blank solution= 0.029

First, we need to find the absorbance of compound A:

[tex] A = A_{s} - A_{b} = 0.624 - 0.029 = 0.595 [/tex]

Now, we can calculate the molar absorptivity of compound A:

[tex] \epsilon = \frac{A}{cl} = \frac{0.595}{3.96 \cdot 10^{-4} M*1 cm} = 1502.5 M^{-1}cm^{-1} [/tex]

Therefore, the molar absorptivity of compound A is 1502.5 M⁻¹cm⁻¹.    

I hope it helps you!

The heat (kJ) released to the surroundings : -70.56 kJ

Reaction

CH₄(g) + 3Cl₂(g) → CHCl₃(l) + 3HCl(g) ΔH°=-336 kJ

For 3 mol HCl formed ⇒ ΔH°=-336 kJ

23.0 g of HCl :

[tex]\tt \dfrac{23}{36.5}=0.63[/tex]

Heat released for 0.63 mol HCl :

[tex]\tt \dfrac{0.63}{3}\times -336=-70.56~kJ[/tex]

The heat (kJ) released to the surroundings at the given equation is 70.7KJ.

We know that

[tex]Moles\ or\ HCl\ formed = mass \div molar\ mass\\\\= 23.0\div 36.46[/tex]

= 0.631 mole

Since energy should be related at the time when 3 moles of HCI should be generated = 336 K

Now energy released is  

[tex]= (336\div 3)\times 0.631[/tex]

= 70.65 kJ

Hence we can conclude that heat released to the surrounding is 70.7 kJ.

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Answer:

it is because all energy are bound to use up according to the law of conversion of energy

Answer:

Possibility of a single replacement reaction

Explanation:

The activity series of element can be used to predict the possibility of a single replacement reaction.

Answer:

Possibility of a single replacement reaction

Explanation:

Answer:

6

Explanation:

Answer:

Option B. Heptane

Explanation:

To obtain the parent name of the above compound, all we need to do is to locate the longest continuous carbon chain.

The longest continuous carbon chain of the above compound is 7.

Next, we shall also consider the chain if there is any double or triple bond.

From the diagram given above, no double or triple bond is present.

Finally, the parent name of the compound is heptane since the longest continuous carbon chain is 7 and no double or triple bond is present in the compound.

Answer:

decrease.

Explanation:

WHY? - As you go across a period, electrons are added to the same energy level. ... The concentration of more protons in the nucleus creates a "higher effective nuclear charge." In other words, there is a stronger force of attraction pulling the electrons closer to the nucleus resulting in a smaller atomic radius.