Which best illustrates the electromagnetic force in action?
-a football being kicked
-leaves falling from tree
-flashlight
-neutron beta particle and proton

Answer:

We are given:

m = 50g OR  0.05 kg

v = 1000 m/s

Force applied by the gunner in a second = 180 N

Momentum(p) of the bullet:

p = mv

p = 0.05 * 1000

p = 50 kg m/s

Finding the recoil force:

The units kg m/s are also known as 'N' (newtons)

So, we can say that the force exerted on every bullet is 50 N

According to the law of conservation of momentum, every bullet fired applies a force of 50N towards the gunner

Hence, we can say that the recoil force of every bullet is 50N

Finding the number of bullets fired in a minute:

We are given that the gunner applied an average force of 180N on the gun

we know that that can also be written as 180 kg m/s. Notice the 's' in the units of the momentum, it tells us that this force is applied every second

So, to find the amount of force applied in a minute, we can multiply it by 60

Force applied by the gunner in a minute = (60 * 180) = 10800 N

Let n be the number of bullets fired in a minute

We can say that the force applied by the gunner is equal to the force applied by a bullet times the number of bullets fired

F(gunner) = n * F(bullet)

10800 = n * 50

n = 10800/50

n = 216 bullets / minute

The gunner shoots 216 bullets in a minute

Answer:

"When face is placed between the concave mirror and its focus, it produces a magnified image. This enlarged image of face is helpful in makeup as even pores of skin are clearly visible."

Answer:

The value is  [tex]\lambda  = 214.3  \ nm [/tex]

Explanation:

From the question we are told that

   The  slit separation is  [tex]d =  3.00 * 10^{-5} m[/tex]

    The  distance of the screen is  [tex]D =   2.00\ m[/tex]

    The  order of fringe is  n  =  7

    The path difference is  [tex]y =  10.0 \ cm  =  0.1 \  m[/tex]

    Generally the path difference is mathematically represented as

      [tex]y =  \frac{n *  \lambda  *  D}{ d}[/tex]

=>   [tex]0.1 =  \frac{7 *  \lambda  * 2.00 }{ 3.00 * 10^{-5}}[/tex]

=>  [tex]\lambda  =  \frac{0.1 *3.00 * 10^{-5} }{7 * 2.00 }[/tex]

=>   [tex]\lambda  =  \frac{0.1 *3.00 * 10^{-5} }{7 * 2.00 }[/tex]

=>   [tex]\lambda  = 2.143 *10^{-7} \  m [/tex]    

=>    [tex]\lambda  = 214.3  \ nm [/tex]

Answer:

a) The average force that acts on the man is [tex]2.508\times 10^{8}[/tex] newtons.

b) The average force that acts on the man is 1023.673 newtons.

c) The force of the ground on the man is 1612.093 newtons upwards.

Explanation:

a) After a careful reading of the statement we construct the following model by applying Impact Theorem, that is:

[tex]m\cdot \vec v_{A} + \vec F \cdot \Delta t = m\cdot \vec v_{B}[/tex] (Eq. 1)

Where:

[tex]m[/tex] - Mass of the man, measured in kilograms.

[tex]\vec v_{A}[/tex] - Initial velocity of the man, measured in meters per second.

[tex]\vec v_{B}[/tex] - Final velocity of the man, measured in meters per second.

[tex]\Delta t[/tex] - Impact time, measured in seconds.

[tex]\vec F[/tex] - Average net force, measured in newtons.

Now we proceed to clear average net force within expression:

[tex]\vec F \cdot \Delta t = m\cdot (\vec v_{B}-\vec v_{A})[/tex]

[tex]\vec F = \frac{m}{\Delta t}\cdot (\vec v_{B}-\vec v_{A})[/tex] (Eq. 2)

If we know that [tex]m = 60\,kg[/tex], [tex]\vec v_{A} = -4.18\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex], [tex]\vec v_{B} = 0\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex] and [tex]\Delta t = 1\times 10^{-6}\,s[/tex], we obtain the following vector:

[tex]\vec F = \frac{60\,kg}{1\times 10^{-6}\,s} \cdot (4.18\,\hat{j})\,\,\,\left[\frac{m}{s} \right][/tex]

[tex]\vec F = 2.508\times 10^{8}\,\hat{j}\,\,\,[N][/tex]

The average force that acts on the man is [tex]2.508\times 10^{8}[/tex] newtons.

(b) If we know that  [tex]m = 60\,kg[/tex], [tex]\vec v_{A} = -4.18\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex], [tex]\vec v_{B} = 0\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex] and [tex]\Delta t = 0.245\,s[/tex], we obtain the following vector:

[tex]\vec F = \frac{60\,kg}{0.245\,s} \cdot (4.18\,\hat{j})\,\,\,\left[\frac{m}{s} \right][/tex]

[tex]\vec F = 1023.673\,\hat{j}\,\,\,\left[N\right][/tex]

The average force that acts on the man is 1023.673 newtons.

(c) From Second Newton's Law we find the following equation of equilibrium:

[tex]\vec F = \vec N -\vec W[/tex] (Eq. 3)

Where:

[tex]\vec F[/tex] - Average force that acts on the man, measured in newtons.

[tex]\vec N[/tex] - Force of the ground on the man, measured in newtons.

[tex]\vec W[/tex] - Weight of the man, measured in newtons.

By applying the concept of weight, we expand the previous equation:

[tex]\vec F = \vec N -m\cdot \vec g[/tex] (Eq. 3b)

Where [tex]\vec g[/tex] is the gravitational acceleration, measured in meters per square second.

And then we clear the force of the ground on the man:

[tex]\vec N = \vec F +m\cdot \vec g[/tex] (Eq. 4)

If we get that [tex]\vec F = 1023.673\,\hat{j}\,\,\,\left[N\right][/tex],  [tex]m = 60\,kg[/tex] and [tex]\vec g = 9.807\,\hat{j}\,\,\,\left[\frac{m}{s^{2}} \right][/tex], the average force is:

[tex]\vec N = 1023.673\,\hat{j}\,\,\,[N]+(60\,kg)\cdot (9.807\,\hat{j})\,\,\,\left[\frac{m}{s^{2}} \right][/tex]

[tex]\vec N = 1612.093\,\hat{j}\,\,\,\left[N\right][/tex]

The force of the ground on the man is 1612.093 newtons upwards.

Answer:

The idea that population growth is potentially exponential while the growth of the food supply or other resources is linear.

Explanation:

Answer:

a) 209.3 kilojoules must be removed from two liter of beverage, b) A rate of heat removal of 1.163 kilowatts is required to cool down 10 2-liter bottles, c) Cooling 10 2-L bottles during 30 minutes costs 4.9 cents.

Explanation:

a) How much heat energy must be removed from your two liters of beverage?

At first we suppose that the beverage has the mass and specific heat of water and that there are no energy interactions between the bottle and its surroundings.

From the First Law of Thermodynamics and definition of sensible heat, we get that amount of removed heat ([tex]Q[/tex]), measured in kilojoules, is represented by the following formula:

[tex]Q = \rho \cdot V\cdot c\cdot (T_{o}-T_{f})[/tex] (Eq. 1)

Where:

[tex]\rho[/tex] - Density of the beverage, measured in kilograms per cubic meter.

[tex]V[/tex] - Volume of the bottle, measured in cubic meters.

[tex]c[/tex] - Specific heat of water, measured in kilojoules per kilogram-Celsius.

[tex]T_{o}[/tex], [tex]T_{f}[/tex] - Initial and final temperatures, measured in Celsius.

If we know that [tex]\rho = 1000\,\frac{kg}{m^{3}}[/tex], [tex]V = 2\times 10^{-3}\,m^{3}[/tex], [tex]c = 4.186\,\frac{kJ}{kg\cdot ^{\circ}C}[/tex], [tex]T_{o} = 35\,^{\circ}C[/tex] and [tex]T_{f} = 10\,^{\circ}C[/tex], then:

[tex]Q = \left(1000\,\frac{kg}{m^{3}}\right)\cdot (2\times 10^{-3}\,m^{3})\cdot \left(4.186\,\frac{kJ}{kg\cdot ^{\circ}C} \right) \cdot (35\,^{\circ}C-10\,^{\circ}C)[/tex]

[tex]Q = 209.3\,kJ[/tex]

209.3 kilojoules must be removed from two liter of beverage.

b) You are having a party and need to cool 10 of these two-liter bottles in one-half hour. What rate of heat removal, in kW, is required?

The total amount of heat that must be removed from 10 2-L bottles is:

[tex]Q_{T} = 10\cdot (209.3\,kJ)[/tex]

[tex]Q_{T} = 2093\,kJ[/tex]

If we suppose that bottles are cooled at constant rate, then, rate of heat removal is determined by this formula:

[tex]\dot Q = \frac{Q_{T}}{\Delta t}[/tex] (Eq. 2)

Where:

[tex]Q_{T}[/tex] - Total heat, measured in kilojoules.

[tex]\Delta t[/tex] - Time, measured in seconds.

[tex]\dot Q[/tex] - Rate of heat removal, measured in kilowatts.

If we know that [tex]Q_{T} = 2093\,kJ[/tex] and [tex]\Delta t = 1800\,s[/tex], we find that rate of heat removal is:

[tex]\dot Q = \frac{2093\,kJ}{1800\,s}[/tex]

[tex]\dot Q = 1.163\,kW[/tex]

A rate of heat removal of 1.163 kilowatts is required to cool down 10 2-liter bottles.

c) Assuming that your refrigerator can accomplish this and that electricity costs 8.5 cents per kW-hr, how much will it cost to cool these 10 bottles (in $)?

A kilowatt-hour equals 3600 kilojoules. The electricity cost is equal to the  removal heat of 10 bottles ([tex]Q_{T}[/tex]), measured in kilojoules, and unit electricity cost ([tex]c[/tex]), measured in US dollars per kilowatt-hour. That is:

[tex]C = c\cdot Q_{T}[/tex]

If we know that [tex]c = 0.085\,\frac{USD}{kWh}[/tex] and [tex]Q_{T} = 2093\,kJ[/tex], the total cost of cooling 10 bottles is:

[tex]C = \left(0.085\,\frac{USD}{kWh}\right)\cdot \left(2093\,kJ\right)\cdot \left(\frac{1}{3600}\,\frac{kWh}{kJ} \right)[/tex]

[tex]C = 0.049\,USD[/tex]

Cooling 10 2-L bottles during 30 minutes costs 4.9 cents.

Given parameters:

Mass of block = 5kg

Coefficient of friction = 0.5

g = 10m/s²

Unknown

Minimum force F required to hold the block =?

Solution:

Frictional force is a force that opposes motion.

The minimum force required to hold the block to the wall is the frictional force.

   Frictional force  =  uN

  Where u is coefficient of friction

              N is the normal force

      N = mg

where m is the mass of the body

          g is the acceleration due to gravity

 So,

         Frictional force = umg

                                   = 0.5 x 5 x 10

                                    = 25N

The force required here is 25N

Answer:

ome acid rain occurs naturally, but sulfur dioxide and nitrogen oxide emissions from smokestacks combine with rain to make sulfuric and nitric acid in amounts that harm the environment. The region of the United States most harmed by acid rain is the East Coast, including the Appalachian Mountains and the Northeast.

Explanation:

pls give me brainlist

Answer:

the conclusion is that the plant that had been given fertilizer B grew more than the plant with fertilizer A and the plant without fertilizer. so in conclusion fertilizer B is better for growing plants fastly.

the problem is that you noticed your tomatoes were not growing properly.

Hope this helps!❤

Explanation:

1) N₂ + O₂ → 2 NO

Kc = [NO]² / ([N₂] [O₂])

Set up an ICE table:

[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\N_{2}&0.114&-x&0.114-x\\O_{2}&0.114&-x&0.114-x\\NO&0&+2x&2x\end{array}\right][/tex]

Plug into the equilibrium equation and solve for x.

1.00×10⁻⁵ = (2x)² / ((0.114 − x) (0.114 − x))

1.00×10⁻⁵ = (2x)² / (0.114 − x)²

√(1.00×10⁻⁵) = 2x / (0.114 − x)

0.00316 = 2x / (0.114 − x)

0.00361 − 0.00316x = 2x

0.00361 = 2.00316x

x = 0.00018

The volume is 1.00 L, so the concentrations at equilibrium are:

[N₂] = 0.114 − x = 0.11382

[O₂] = 0.114 − x = 0.11382

[NO] = 2x = 0.00036

2(a) Cl₂ → 2 Cl

Kc = [Cl]² / [Cl₂]

[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\Cl_{2}&2.0&-x&2.0-x\\Cl&0&+2x&2x\end{array}\right][/tex]

1.2×10⁻⁷ = (2x)² / (2 − x)

1.2×10⁻⁷ (2 − x) = 4x²

2.4×10⁻⁷ − 1.2×10⁻⁷ x = 4x²

2.4×10⁻⁷ ≈ 4x²

x² ≈ 6×10⁻⁸

x ≈ 0.000245

2x ≈ 0.00049

2(b) F₂ → 2 F

Kc = [F]² / [F₂]

[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\F_{2}&2.0&-x&2.0-x\\F&0&+2x&2x\end{array}\right][/tex]

1.2×10⁻⁴ = (2x)² / (2 − x)

1.2×10⁻⁴ (2 − x) = 4x²

2.4×10⁻⁴ − 1.2×10⁻⁴ x = 4x²

2.4×10⁻⁴ ≈ 4x²

x² ≈ 6×10⁻⁵

x ≈ 0.00775

2x ≈ 0.0155

F₂ dissociates more, so Cl₂ is more stable at 1000 K.

Answer:

it a most depends on the moving objects mass

Answer:

Its amount depends on the moving object’s mass,

It can be transferred from one object or body to another, and  Its amount depends on the moving object’s speed.

Explanation:

Answer:

opinion

Explanation:

Answer:

The additional trials needed is 48 trials

Explanation:

Given;

initial number of trials, n = 16 trials

the standard deviation, σ = 0.24 s

initial standard error, ε = 0.06 s

The standard error is given by;

[tex]\epsilon = \frac{\sigma}{\sqrt{n} }[/tex]

To reduce the standard error to 0.03 s, let the additional number of trials = x

[tex]0.03= \frac{0.24}{\sqrt{n+x} } \\\\0.03= \frac{0.24}{\sqrt{16+x} }\\\\0.03\sqrt{16+x} = 0.24\\\\\sqrt{16+x} = \frac{0.24}{0.03} \\\\\sqrt{16+x} = 8\\\\16+x = 8^2\\\\16+x = 64\\\\x = 64 -16\\\\x = 48 \ trials[/tex]

Therefore, the additional trials needed is 48 trials.

Answer:

, Nervous tissue is composed of two types of cells, neurons and glial cells. Neurons are the primary type of cell that most anyone associates with the nervous system. They are responsible for the computation and communication that the nervous system provides.

Answer:

no but yes at the same time

Explanation:

they are going a different direction but they are the same speed.

Answer:

How would you describe where you are right now? You

might say that you are sitting one meter to the left of your

friend. You might explain that you are at home, which is two

houses north of your school.

Explanation:

Hope this helps!

Answer:

53.85m

Explanation:

If we are assuming that d1 is one side of a triangle, and d2 is the other, and we are looking for the magnitude, which is essentially the hypotenuse, we use Pythagorean Theorem. a^2+b^2=c^2. 20^2 + 50^2 = 2900.

The square root of 2900 is 53.85164. Therefore, that is your hypotenuse.

Answer:

Yes, the water will be reach the fire.

The hose should be at 34.7 m from the building

Explanation:

Given that,

Height of building's =34.5 m

Speed = 29 m/s

Angle = 63°

Distance from the ground = 0.90 m

We need to calculate the actual height

Using formula of height

[tex]H=\dfrac{u^2\sin^2\theta}{2g}[/tex]

Put the value into the formula

[tex]H=\dfrac{29^2\sin^2{63}}{2\times9.8}[/tex]

[tex]H=34.0\ m[/tex]

The height from the ground will be

[tex]H'=34+0.90[/tex]

[tex]H'=34.9\ m[/tex]

We can say that, the water gun attained the maximum height that is 0.4 m more than the 10th floor.

So, yes, the water will be reach the fire.

We need to calculate the range

Using formula of range

[tex]R=\dfrac{u^2\sin2\theta}{g}[/tex]

Put the value into the formula

[tex]R=\dfrac{29^2\times\sin(2\times63)}{9.8}[/tex]

[tex]R=69.4\ m[/tex]

The house should be at half of R.

[tex]\dfrac{R}{2}=\dfrac{69.4}{2}[/tex]

[tex]\dfrac{R}{2}=34.7\ m[/tex]

Hence, Yes, the water will be reach the fire.

The hose should be at 34.7 m from the building

Answer:

v=6.05 m/s

Explanation:

Given that,

Th initial velocity of the lander, u = 1.2 m/s

The lander is at a height of 1.8 m, d = 1.8 m

We need to find the velocity of the lander at impact. It is a concept based on the conservation of mechanical energy. So,

[tex]\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2=W\\\\\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2=F\times d\\\\\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2=mgd\\\\\dfrac{1}{2}m(v^2-u^2)=mgd\\\\v^2-u^2=2gd[/tex]

v is the velocity of the lander at the impact

g is the acceleration due to gravity on the surface of Mars, which is 0.4 times that on the surface of the Earth, g = 0.4 × 9.8 = 3.92 m/s²

So,

[tex]v=\sqrt{u^2+2gd} \\\\v=\sqrt{(1.2)^2+2\times 9.8\times 1.8} \\\\v=6.05\ m/s[/tex]

So, the velocity of the lander at the impact is 6.05 m/s.

Answer:

Explanation:

10.00 5

Explanation:

u=0 m/s

v=9.6 m/s

s= 40.5 m

a=?

V^2=u^2 +2as

9.6^2=0+2×a×40.5

92.16=81a

a=92.16/81

a=1.14m/s^2

Answer:

R∠          is  152,3 ∠ 246,8

Explanation:

We need to add (vectorially)  these two velocities. We can choose the coordinates system just that speed of the airplane is the negative part of the y-axis, and negative region of the x-axis, for wind speed, according to

this, the module of the resultant velocity R is:

R =√ (60)² + (140)²

R = √( 3600) + ( 19600)

R =√ 23200

R = 152,315 mph

The tangent of the angle (α )  between R and the y-axis is:

tan α = 60/140

tan α = 0,4286

From tangent tables, we get arctan 0.4286  

α = 23,2⁰

Then R∠    is  152,3 ∠ 246,8

Answer:

R∠          is  152,3 ∠ 246,8

Answer:

Newtons third law states, "The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object."

Explanation:

an illustration of this would probably be a missile.

Answer: C. “More mass is added to a wheelbarrow remains, and larger forces required to move it”

Answer:

Stated below:

Explanation:

Let's calculate the maximum height

.

H=v^2/2g=320mH=v  

2

/2g=320m

PE=mgh=0.1*10*320=320 J

at halfway up PE will be half of max = 320/2=160 J

KE will be equal to PEmax=320 J.

Hope I helped! ☺

Answer:

like

Explanation:

Have a good day!!

Answer: negitive

Explanation:

Answer:

i had this question as well!

Explanation:

Answer:

1. to the Mystic 2. A Theme or social value 3. Something that can be valued 4. Can’t be observed/ Noticed.

Explanation:

Answer:

b

Explanation:

I took this unit last year and i think b is the right answer

Acceleration of an object is directly related to the net force exerted upon it and inversely related to the mass of the object.

Newton's second law of motion states that the acceleration of an object as produced by a net force, is directly proportional to the magnitude of the net force, and inversely proportional to the mass of the object.

From this law, it means that once the acceleration is doubled, the force exerted on the object is equally doubled.

Also when the mass is increased, the acceleration is reduced.

Therefore, mathematically:

F =ma

where, f = force

m = mass

a= acceleration

Therefore, acceleration of an object is directly related to the net force exerted upon it and inversely related to the mass of the object.

Learn more here:

https://brainly.com/question/12043464

Answer:

50

Explanation: