where is the location of the incenter of triangle abc is

Answer:

The range is from 1.62 to 1.98.

Step-by-step explanation:

We have to solve for the percentage of the particular value if the range of the answer should be +/- 10% of the particular value.

The value given is 1.8, we thus want to find 10% of that: 1.8 * 10/100 = 0.18

Then, add this value to the original value of 1.8: 1.8+0.18 = 1.98

Furthermore, subtract .18 from from the original value of 1.8: 1.8-0.18 = 1.62

The range will be between these two numbers, so the range is from 1.62 to 1.98.

Answer:

A

Step-by-step explanation:

edge 2021

Answer:

Logistic model

Step-by-step explanation:

A scatter plot is a mathematical representation or diagram which is used to shoe the relation between two given variables. It uses the Cartesian coordinates which is used to display the values for a typically two variables for the given set of data.

In the context, a scatter plot is made between two variables. The two variables are the total number of hours and the number of weeks.

From the graph shown, we can say that model is a logistic model as the shape of the graph is S shaped.

Therefore, the appropriate model for the data given is logistic model.

Answer:

(I) yessssssssssssssssssssssss

Answer:

yes it is.

Step-by-step explanation:

i did this and it was correct

Answer:

[tex]40\sqrt3\ m[/tex]

Step-by-step explanation:

Given that,

The height of the tower, h = 40 m

The angle of elevation is 30°

We need to find the distance between the tower and the point. Let the distance is x. Using trigonometry,

[tex]\tan(30)=\dfrac{h}{x}\\\\\dfrac{1}{\sqrt3}=\dfrac{40}{x}\\\\x=40\sqrt3\ m[/tex]

So, the distance between the tower and the point is equal to [tex]40\sqrt3\ m[/tex].

Answer:

A. (-2, -5), (0, -7), (1, -4)

Step-by-step explanation:

The following transformation is applied:

[tex](x,y) \rightarrow (y + 2, -x - 4)[/tex]

To find the range:

We apply the transformation to the points in the domain. Thus:

[tex](1,-4) \rightarrow (-4 + 2, -1 - 4) = (-2, -5)[/tex]

[tex](3,-2) \rightarrow (-2 + 2, -3 - 4) = (0, -7)[/tex]

[tex](0,-1) \rightarrow (-1 + 2, 0 - 4) = (1, -4)[/tex]

Thus the correct answer is given by option a.

Hey there!

(4 + 21) - (1 - 71)

4 + 21 = 25

= 25 - (1 - 71)

1 - 71 = -70

= 25 - (-70)

= 25 + 70

= 95

Answer: 95

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

b = 50°

c = 130°

Step-by-step explanation:

Two angles A and B are complementary if:

A + B = 90°

And two angles are supplementary if:

A + B = 180°

Then, we know that:

a = 40°

b is a complement of a (this means that a and b are complementary angles)

c is a supplement of b (this means that b and c are supplementary angles).

From the first statement, we have that:

b + a = 90°

Replacing the value of a we get

b + 40° = 90°

b = 90° - 40° = 50°

b = 50°

And now we can use that b and c are supplementary, then:

b + c = 180°

replacing the value of b we get:

50° + c  = 180°

c = 180° - 50° = 130°

c = 130°

Then the values we wanted are:

b = 50°

c = 130°

Given that exp(2x) is a solution, we assume another solution of the form

y(x) = v(x) exp(2x) = v exp(2x)

with derivatives

y' = v' exp(2x) + 2v exp(2x)

y'' = v'' exp(2x) + 4v' exp(2x) + 4v exp(2x)

Substitute these into the equation:

(2x + 5) (v'' exp(2x) + 4v' exp(2x) + 4v exp(2x)) - 4 (x + 3) (v' exp(2x) + 2v exp(2x)) + 4v exp(2x) = 0

Each term contains a factor of exp(2x) that can be divided out:

(2x + 5) (v'' + 4v' + 4v) - 4 (x + 3) (v' + 2v) + 4v = 0

Expanding and simplifying eliminates the v term:

(2x + 5) v'' + (4x + 8) v' = 0

Substitute w(x) = v'(x) to reduce the order of the equation, and you're left with a linear ODE:

(2x + 5) w' + (4x + 8) w = 0

w' + (4x + 8)/(2x + 5) w = 0

I'll use the integrating factor method. The IF is

µ(x) = exp( ∫ (4x + 8)/(2x + 5) dx ) = exp(2x - log|2x + 5|) = exp(2x)/(2x + 5)

Multiply through the ODE in w by µ :

µw' + µ (4x + 8)/(2x + 5) w = 0

The left side is the derivative of a product:

[µw]' = 0

Integrate both sides:

∫ [µw]' dx = ∫ 0 dx

µw = C

Replace w with v', then integrate to solve for v :

exp(2x)/(2x + 5) v' = C

v' = C (2x + 5) exp(-2x)

∫ v' dx = ∫ C (2x + 5) exp(-2x) dx

v = C₁ (x + 3) exp(-2x) + C₂

Replace v with y exp(-2x) and solve for y :

y exp(-2x) = C₁ (x + 3) exp(-2x) + C₂

y = C₁ (x + 3) + C₂ exp(2x)

It follows that the second fundamental solution is y = x + 3. (The exp(2x) here is already accounted for as the first solution.)

Answer:

1,773.33 Mexican pesos

Step-by-step explanation:

Create a proportion where x was how many Mexican pesos it was worth:

[tex]\frac{1}{0.075}[/tex] = [tex]\frac{x}{133}[/tex]

Cross multiply and solve for x:

133 = 0.075x

1773.33 = x

So, it was worth approximately 1,773.33 Mexican pesos

Answer:

x = 2

Step-by-step explanation:

The minimum point of the curve is (2, 0). Hence, axis of symmetry is x = 2

Answer:

(21.064 ; 23.136)

Step-by-step explanation:

Given :

Sample, n = 80

Mean, xbar = 22.1

Standard deviation, s = 5.6

Standard Error, S. E = 0.63

Confidence interval :

Xbar ± Zcritical * S.E

22.1 ± (1.645 * 0.63)

22.1 ± 1.036

Lower boundary = 22.1 - 1.036 = 21.064

Upper boundary = 22.1 + 1.048 = 23.136

(21.064 ; 23.136)

Answer:

Step-by-step explanation:

your solution is almost true h=V/πr^2 but the final answer is 36/9π= (4π)cm

--->4×3.14=12.56cm

Answer:

a. The friend is incorrect.

2(x) is the same as x(2). PEMDAS does not apply to the same order of operation under normal conditions and both are directly proportional functions.

b. The parentheses are the only thing making the functions different. After you simplify from the parentheses, both values have the same priority.

Step-by-step explanation:

Answer:

87,500

Step-by-step explanation:

Since the last 2 digits arent 5 or greater than 5 it can not be rounded to the next hundred.

Answer:

875

Step-by-step explanation:

th t h t u

8 7 5 2 1

the hundred is 5 so the next digit after that is 2 remember 0 to 4 round down 5 to 9 round up

so 875

Answer:

altitude = 30 cm

lateral surface area = 301 cm² (approximately)

Step-by-step explanation:

let the altitude be x,

240=6*4*x/3

or, x=30 cm

Lateral surface area,

=l×√(w/2)²+h²]+w×√[(l/2)²+h²]

=6×√[(4/2)²+30²]+4×√[(6/2)²+30²]

≈300.99806

≈ 301 cm²

Answered by GAUTHMATH

Answer:

2.43

Step-by-step explanation:

1.80 x 0.35 + 1.80

Answer:

The answer is below

Step-by-step explanation:

a) A cube is a three dimensional solid with 6 square faces.

A cube has 8 vertices

b) A rectangular prism is a three dimensional solid with two parallel rectangular bases.

A rectangular prism has 6 faces.

c) A rectangular prism is a three dimensional solid with two parallel rectangular bases.

A rectangular prism has 12 edges.

d) A square-based pyramid is a pyramid with a square base.

A square-based pyramid has 8 edges

e) A triangular prism is a three dimensional solid with two parallel triangular bases.

A triangular prism has 5 faces.

f) A triangular prism is a three dimensional solid with two parallel triangular bases.

A triangular prism has 6 vertices.

Answer:

SAA

Step-by-step explanation:

HOPE IT HELPS YOU IN YOUR LEARNING PROCESS.

Answer:

a) 11670-0.09%

b)11670-1.8%=11459

Step-by-step explanation:

Answer:

1/2 or 0.5

Step-by-step explanation:

6/8 x 4/6 = 24/48

Answer:

1/2

Step-by-step explanation:

Answer:

Step-by-step explanation:

two points are (-5,-2) and (-1,3)

slope=(3-(-2))/(-1-(-5))=(3+2)/(-1+5)=5/4

Answer:

x = - 5

Step-by-step explanation:

[tex]Let \ (x _ 1 , y _ 1 ) \ and \ (x _ 2 , y _ 2 ) \ be \ the \ points. \\\\The \ distance \ between \ the \ points \ be ,\ d = \sqrt{(x_2 - x_1)^2 + ( y _ 2 - y_1)^2}[/tex]

Given : d = 10 units

         And the points are ( x , - 4) and ( 3 , 2 ).

Find x

[tex]d = \sqrt{( 3 - x)^2 + ( -4 - 2)^2} \\\\10 = \sqrt{( 3 - x)^2 + ( -6)^2} \\\\10^2 = [ \ \sqrt{( 3 - x)^2 + 36} \ ]^2 \ \ \ \ \ \ \ \ \ [ \ squaring \ both \ sides \ ] \\\\100 = ( 3 - x )^2 + 36\\\\100 - 36 = ( 3 - x )^ 2\\\\( 3 - x ) = \sqrt{64}\\\\3 - x = \pm 8\\\\3 - x = 8 \ and \ 3 - x = - 8\\\\-x = 8 - 3 \ and \ -x = - 8 - 3\\\\-x = 5 \ and \ -x = - 11\\\\x = - 5 \ and \ x = 11\\\\[/tex]

Check which value of x satisfies the distance between the points.

x = 11

[tex]d = \sqrt{(3-11)^2 + (-2--4)^2} = \sqrt{(-8)^2 + (-2+4)^2}= \sqrt{64+4} = \sqrt {68} \ units[/tex]

does not satisfy.

x = - 5:

[tex]d = \sqrt{ (3 -- 5)^2 + ( - 4 - 2)^2} = \sqrt{8^2 + 6^2} = \sqrt{100} =10 \ units[/tex]

Therefore , x = - 5

Answer:

(2,3) (4,2) (5,2) (1,4) (0,2)

Step-by-step explanation:

because all these points have something common to each other. Now pay attention in your class and stop cheating!!

Answer:

Step-by-step explanation:

eq. of circle is (x-2)²+(y-3)²=10²

now substitute the values of x and y

which satisfies the above eq.that point lies on the circle.

Answer:

The possible values are a = -2.5 or a = 4.5.

Step-by-step explanation:

Composite function:

The composite function of f(x) and g(x) is given by:

[tex](f \circ g)(x) = f(g(x))[/tex]

In this case:

[tex]f(x) = 4x^2 - 8x - 20[/tex]

[tex]g(x) = 2x + a[/tex]

So

[tex](f \circ g)(x) = f(g(x)) = f(2x + a) = 4(2x + a)^2 - 8(2x + a) - 20 = 4(4x^2 + 4ax + a^2) - 16x - 8a - 20 = 16x^2 + 16ax + 4a^2 - 16x - 8a - 20 = 16x^2 +(16a-16)x + 4a^2 - 8a - 20[/tex]

Value of a so that the y-intercept of the graph of the composite function (fog)(x) is (0, 25).

This means that when [tex]x = 0, f(g(x)) = 25[/tex]. So

[tex]4a^2 - 8a - 20 = 25[/tex]

[tex]4a^2 - 8a - 45 = 0[/tex]

Solving a quadratic equation, by Bhaskara:

[tex]\Delta = (-8)^2 - 4(4)(-45) = 784[/tex]

[tex]x_{1} = \frac{-(-8) + \sqrt{784}}{2*(4)} = \frac{36}{8} = 4.5[/tex]

[tex]x_{2} = \frac{-(-8) - \sqrt{784}}{2*(4)} = -\frac{20}{8} = -2.5[/tex]

The possible values are a = -2.5 or a = 4.5.

Answer:

this is the answer I got! i don't know if it helps, but I hope it does

Answer: [tex]R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}[/tex]

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts [tex]38^{\circ}[/tex] angle to each other

The resultant of the two forces is given by

[tex]\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}[/tex]

Insert the values

[tex]\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb[/tex]

Resultant makes an angle of

[tex]\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}[/tex]

So, the resultant makes an angle of [tex]22.57^{\circ}[/tex] with 9 lb force

Angle made with 13 lb force is [tex]38^{\circ}-22.57^{\circ}=15.43^{\circ}[/tex]

Answer:

Step-by-step explanation:

Answer:

150 m at 10 m/s

350 m at 50 m/s

Step-by-step explanation:

x + y = 500

x/10 + y/50 = 22

~~~~~~~~~~~~~~~~~

x + y = 500

5x  + y  = 1100

~~~~~~~~~~~~~~~~

x + y = 500

-5x  - y  = -1100

-4x = -600

x = 150

y = 350

Answer:

170

Step-by-step explanation:

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Answer:

[tex]g(x) = \frac{-2}{x-1}+5\\\\[/tex]

The graph is shown below.

=========================================================

Explanation:

Notice that if we multiplied the denominator (x-1) by 5, then we get 5(x-1) = 5x-5.

This is close to 5x-7, except we're off by 2 units.

In other words,

5x-7 = (5x-5)-2

since -7 = -5-2

Based on that, we can then say,

[tex]g(x) = \frac{5x-7}{x-1}\\\\g(x) = \frac{5x-5-2}{x-1}\\\\g(x) = \frac{(5x-5)-2}{x-1}\\\\g(x) = \frac{5(x-1)-2}{x-1}\\\\g(x) = \frac{5(x-1)}{x-1}+\frac{-2}{x-1}\\\\g(x) = 5+\frac{-2}{x-1}\\\\g(x) = \frac{-2}{x-1}+5[/tex]

This answer can be reached through alternative methods of polynomial long division or synthetic division (two related yet slightly different methods).

-------------------------

Compare the equation [tex]g(x) = \frac{-2}{x-1}+5\\\\[/tex] to the form [tex]g(x) = \frac{a}{x-h}+k\\\\[/tex]

We can see that

The vertical asymptote is x = 1, which is directly from the h = 1 value. If we tried plugging x = 1 into g(x), then we'll get a division by zero error. So this is why the vertical asymptote is located here.

The horizontal asymptote is y = 5, which is directly tied to the k = 5 value. As x gets infinitely large, then y = g(x) slowly approaches y = 5. We never actually arrive to this exact y value. Try plugging in g(x) = 5 and solving for x. You'll find that no solution for x exists.

The point (h,k) is the intersection of the horizontal and vertical asymptote. It's effectively the "center" of the hyperbola, so to speak.

The graph is shown below. Some points of interest on the hyperbola are

Another thing to notice is that this function is always increasing. This means as we move from left to right, the function curve goes uphill.