Answer:
When the tides are especially weak, it is called a NEAP tide.
Explanation:
Hope this helps :)
Answer:
Neap
Explanation:
Answered!
A 2.00 kg rock is dropped from the top of a 30.0 m high building. Calculate the ball’s momentum at the time that it strikes the ground.
Explanation:
We use the Theorem of conservation of mechanical energy for finding the velocity when it strikes the ground:
Ei = Ef
Ki + Ui = Kf + Uf
Ui = Kf
m g h = 1/2 m v^2
v = sqrt(2gh)
So the momentum will be:
p = mv = m * sqrt(2gh)
You hang a light in front of your house using an
elaborate system to keep the 12-kg object in static
equilibrium (Figure 1). What are the magnitudes of the
forces that the ropes must exert on the knot connecting
the three ropes if 02 = 639 and 03 = 45° ?
The magnitudes of the forces that the ropes must exert on the knot connecting are :
F₁ = 118 N F₂ = 89.21 N F₃ = 57.28 NGiven data :
Mass ( M ) = 12 kg
∅₂ = 63°
∅₃ = 45°
Determine the magnitudes of the forces exerted by the ropes on the connecting knota) Force exerted by the first rope = weight of rope
∴ F₁ = mg
= 12 * 9.81 ≈ 118 kg
b) Force exerted by the second rope
applying equilibrium condition of force in the vertical direction
F₂ sin∅₂ + F₃ sin∅₃ - mg = 0 ---- ( 1 )
where: F₃ = ( F₂ cos∅₂ / cos∅₃ ) --- ( 2 ) applying equilibrium condition of force in the horizontal direction
Back to equation ( 1 )
F₂ = [ ( mg / cos∅₂ ) / tan∅₂ + tan∅₃ ]
= [ ( 118 / cos 63° ) / ( tan 63° + tan 45° ) ]
= 89.21 N
C ) Force exerted by the third rope
Applying equation ( 2 )
F₃ = ( F₂ cos∅₂ / cos∅₃ )
= ( 89.21 * cos 63 / cos 45 )
= 57.28 N
Hence we can conclude that The magnitudes of the forces that the ropes must exert on the knot connecting are :
F₁ = 118 N, F₂ = 89.21 N, F₃ = 57.28 N
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A 2N and an 6N force pull on an object to the right and a 4N force pulls on the object to the left. If the object has a mass of 0.25 kg what is its acceleration?
Answer:
[tex]16m/s^{2}[/tex]
Explanation:
Please ask if you have more questions!
Two 5 kg potted cacti, one in a black pot and one in a blue pot, slide down a sagging shelf in the same direction with
the same speed.
Which two equations correctly model the momentum of the two-cactus system?
Answer:
Answers A and D are the correct solution.
Explanation:
Both pots have the same mass and the same velocity vector.
the only difference between A and D is the selection of the reference frame positive direction.
The equation (A) and equation (D) correctly model the momentum of the two-cactus system.
What is momentum?The product of a particle's mass and velocity is called momentum. Being a vector quantity, momentum possesses both magnitude and direction.
According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum.
Given that: mass of each cactus: m = 5 kg.
And they slide down a sagging shelf in the same direction with the same speed.
In equation (A), both velocities of two cacti are in positive direction whereas, in equation (B), both velocities of two cacti is in negative direction. Hence, equation (A) and equation (D) correctly model the momentum of the two-cactus system.
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Convert the decimal number 61078 to binary by using sum-of-weights method
Answer:
1110111010010110
Explanation:
I am not able to upload the working out using the sum of weights method sorry
How long does it take the second hand of a clock to move through 3.57 rad?
Answer in units of s.
Answer:
Its angular velocity is
π
30
radians per second (about 0.105 radians/s.
Explanation:
Explanation:
Think of it like this:
There are
2
π
radians in one complete rotation, and that takes the second hand 60 seconds to complete.
So, the rate of rotation (the angular velocity) is
2
π
/60 = pi/30 radians per second# which is about 0.105 radians per second.
To solve the problem we will first calculate the time taken by the second arm to travel 1 rad.
Time taken by the second arm to travel 1 rad
We know that the arm of the second travels 2π radians in 60 seconds. therefore, the time is taken to travel 1 rad by the second arm,
[tex]1\rm\ rad = \dfrac{60}{2\pi}[/tex]
Time taken by the second arm to travel 3.57 radTime taken by the second arm to travel 3.57 rad
[tex]=3.57\times \dfrac{60}{2\pi}\\\\= 34.09\rm\ sec[/tex]
Hence, the time taken by the second arm to travel 3.57 rad is 34.09 sec.
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When Elements neutral atom contains 5 neutrons 4 electrons and 4 protons
Answer:
What is the atomic number of an atom that has 5 neutrons and 4 electrons? A neutral atom will have the same number of electrons is does protons. Since it has 4 protons, it must have an atomic number of 4. (That makes it beryllium.)
Explanation:
mark me brainliest please and thank you Ma'aM/Sir
Answer:
4 protons, 5 neutrons, and 4 electrons are there in an atom of beryllium.
Make a generalization about Earth's magnetic field and its properties. In not more than 10 sentences.
Answer:
Earth's magnetic field (and the surface magnetic field) is approximately a magnetic dipole, with the magnetic field S pole near the Earth's geographic north pole (see Magnetic North Pole) and the other magnetic field N pole near the Earth's geographic south pole (see Magnetic South Pole). This makes the compass usable for navigation. The cause of the field can be explained by dynamo theory. A magnetic field extends infinitely, though it weakens with distance from its source. The Earth's magnetic field, also called the geomagnetic field, which effectively extends several tens of thousands of kilometres into space, forms the Earth's magnetosphere. A paleomagnetic study of Australian red dacite and pillow basalt has estimated the magnetic field to be at least 3.5 billion years old
a hairdryer is used for 600 seconds to dry hair. it has a 750 watt rating. how much work did the hairdryer do
The amount of work done by the hairdryer is equal to 450 Kilojoules.
Given the following data:
Time = 600 secondsPower = 750 wattTo determine the amount of work done by the hairdryer:
Mathematically, the work done by an object with respect to power and time is given by the formula:
[tex]Work\;done = power \times time[/tex]
Substituting the given parameters into the formula, we have;
[tex]Work\;done = 750 \times 600[/tex]
Work done = 450,000 Joules
Note: 1000 Joules = 1 Kilojoules.
Work done = 450 Kilojoules.
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4. Protons and neutrons are held together to form this _________
Answer:
strong nuclear force.
Explanation:
hope this helps you!!
Hey guys can you help me solve this problem "how long will it take a car travelling 30m/s to come to stop ifs its acceleration is -3 m/s2".
Answer:
10 seconds.
Explanation:
We can use a kinematic equation where we know the final velocity, initial velocity, acceleration, and need to determine the time t:
[tex]\displaystyle v_f = v_i + at[/tex]
The initial velocit is 30 m/s, the final velocity is 0 m/s (as we stopped), and the acceleration is -3 m/s².
Substitute and solve for t:
[tex]\displaystyle \begin{aligned} (0\text{ m/s}) & = (30 \text{ m/s}) + (-3 \text{ m/s$^2$}) t \\ \\ t & = \frac{-30\text{ m/s}}{-3 \text{ m/s$^2$}} \\ \\ & = 10 \text{ s} \end{aligned}[/tex]
Hence, it will take the car 10 seconds to come to a stop.
Blaine and her sister are identical twins riding roller coasters at Kinetic Kars. They each ride the
roller coaster on their own once. Next time, they ride the roller coaster together. On which ride
do you think they have the most kinetic energy? Explain your answer using information from class
activities.
Which statement is true for a series circuit
Answer: they have one path to flow
Explanation: share the same current
Find the magnitude of the potential difference between two points located 1.2 m apart in a uniform 700 N/C electric field, if a line between the points is parallel to the field. Express your answer in volts.
The magnitude of the potential difference between the two points is 840 V
To solve the problem above, we need to use the formula of Potential difference as related to distance and electric field.
Potential difference: This can be defined as the work required to move a unit charge from a point to another in an electric field.
⇒ Formula:
V = E×d.................. Equation 1⇒ Where:
V = Potential differenceE = Electric Fieldd = DistanceFrom the question,
⇒ Given:
E = 700 N/Cd = 1.2 m⇒ Substitute these values into equation 1
V = 700(1.2)V = 840 VHence, The magnitude of the potential difference between the two points is 840 V
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Do you think the rider in the above figure is really in danger? What If people below were removed?
The rider will be in danger when the people below are removed, because they initially helped to maintain equilibrium.
A system subjected to different forces is said to be in equilibrium when all the forces applied to the system are equal.
For a system subject to two opposite forces, the following exists;
If the upward force and the downward forces are equal, the system will remain in equilibrium positionIf the upward or downward force is greater than the other, the system will move in the direction of the greater force.Thus, we can conclude that the rider will be in danger when the people below are removed, because they initially helped to maintain equilibrium. Once these people are removed, the rider tends to move at a greater speed and possibly fall from the initial position.
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if a current of 2.0 A is flowing from point a to point b, the potential difference between Vb- Va (in V) is:
a. 6
b. 8
c. -6
d. -8
e. 22
Answer:
[tex]\huge\color{skyblue}\boxed{\colorbox{black}{Answer ☘}}[/tex]
[tex]total \: resistance \: ( R_{t} ) = (3 + 1)ohm \\ (since \: the \: resistors \: are \: connected \\ in \: series)[/tex]
[tex]current \: flowing \: through \: circuit(I) = 2A \\ \\ now... \: by \: ohms \: law \\ V = IR\\ V = (2)(4) \\ = > 8v[/tex]
therefore , option (b) is correct!!hope helpful~
Two Blocks are connected by a massless rope over a massless,
frictionless pulley, as shown in the figure. The mass of block 2
is m2 = 10.1 kg, and the coefficient of kinetic friction
between block 2 and the incline is Mk = 0.200. The angle 0 of
the incline is 27.5º. If block 2 is moving up the incline at
constant speed, what is the mass mi of block 1?
The mass of block 1 will be 1.99 kg.The tension force is applied along the whole length of the wire, pulling energy equally on both ends.
What is tension force?The tension force is described as the force transferred through a rope, string, or wire as it is pulled by opposing forces.
Given that,
Mass of block 1=? kg
The coefficient of the kinetic friction,μ=0.200
Now consider the weight component in the uphill direction.The weight is found as;
[tex]\rm W=m_1gsin \theta[/tex]
The force is balanced in the vertical direction as;
[tex]\rm T=F_f-W[/tex]
When the force of friction is;
[tex]\rm F_F=\mu_k N[/tex]
[tex]\rm F_f=(m_1 gcos \theta)[/tex]
Substitute the value in the vertical balanced equation;
[tex]\rm T=m_1gsin(27.5)^0-\mu_kmgcos27.5^0[/tex]
[tex]\rm T-m_2g=0\\\\T=m_2g[/tex]
[tex]\rm (10.1) g=m_1g(0.699-0.2 \times(-0.714) ) \\\\ (10.1) g=m_1g (0.699+0.1428) \\\\\ (10.1) g= m_1 \times 0.8418 \\\\ m_1 =11.99 \ kg[/tex]
Hence the mass of block 1 will be 1.99 kg.
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True or False. When Isaac’s father was a 100 God changed his name from Abram to Abraham.
Velocity is an extensive property of a system. TRUE OR FALSE
[tex] \: \: \: [/tex]
[tex] \pink{false}[/tex]
because velocity is neither an intensive nor extensive propertyhope it helpsAnswer:
False
Explanation:
I hope this helped have a great day!!!
3. Particles carrying no charge ____________
Answer:
Neutrons
Explanation:
A stone of mass m = 1.05 kg is released from a height of h = 2.1 m into a pool of water. At a time of t = 1.83 s after hitting the surface of the water, the stone's velocity has decreased by 50%.
What is the magnitude of the average force the stone experiences, in newtons, during the time t?
Answer:
Explanation:
ignoring air resistance, the kinetic energy at water impact will equal the potential energy converted
½mv² = mgh
v = √(2gh)
v = √(2(9.81)2.1) = 6.4188... m/s
after impact, an impulse will result in a change of momentum.
There is a downward impulse due to gravity equal to the weight of the stone and an upward average force due to water resistance and buoyancy force.
FΔt = mΔv
(F - mg)Δt = m(vf - vi)
(F - mg) = m(vf - vi)/Δt
F = m(vf - vi)/Δt + mg
F = m((vf - vi)/Δt + g)
F = 1.05(((½(-6.4188) - -6.4188)/ 1.83) + 9.81)
F = 12.14198...
F = 12.1 N
The magnitude of the average force the stone experiences, will be 12.1 N.
What is force?Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.
The given data in the problem is;
m is the stone mass = 1.05 kg
The height is h, = 2.1 m i
The time is, t = 1.83 s
Velocity decreased by 50%.
From the law of conservation of energy the kinetic energy is equal to the potential energy;
[tex]\rm \frac{1}{2} mv^2 = mgh \\\\ v = \sqrt{2gh}\\\\ v = \sqrt{2 \times 9.81 \times 2.1 } \\\\ v= 64188 \ m/sec.[/tex]
From Newton's second law of motion, the impulsive force is equal to the change in momentum;
[tex]\rm F \triangle T = m \traingle v \\\\ (F - mg) = \frac{v_f-v_i}{\triangle t } \\\\ F = \frac{v_f-v_i}{\triangle t } + mg \\\\ F =m\frac{v_f-v_i}{\triangle t + g} \\\\ F= 12.14 98 \\\\ F=12.1 N[/tex]
Hence the magnitude of the average force the stone experiences, will be 12.1 N.
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A 4.0-mF capacitor initially charged to 50 V and 6.0-mF capacitor charged to 30 V are connected to each other with the positive plate of each connected to the negative plate of the other. what is the final charge of the 6.0-mF capacitor?
a. 20 mC
b. 8.0 mC
c. 10 mC
d. 12 mC
e. 230 mC
[tex]\huge\color{pink}\boxed{\colorbox{black}{Answer ☘}}[/tex]
12 mC
Explanation:We are given that...
[tex]C_{1} = 4mF \\ V_{1} = 50v \\ C_{2} = 6mF \\ V_{2} = 30v \\ \\ we've \: to \: find \: the \: final \: charge \: on \: the \: 6mF \\capacitor \:- \\ \\ we \: know \: that ,\: \\ Q = CV \\ \\ using \: the \: formula \: \\ Q_{1} = 4 \times 50 = 200mC \\ Q_{2} = 6 \times 30 = 180mC \\ \\ total \: charge , \: Q_{1} - Q_{2} = 200 - 180 = 20mC \\ \\ let \: V \: be \: the \: final \: potential \: \\ 4V + 6V = 20mC\\ 10V = 20mC \\ V = \frac{20}{10} = 2V \\ final \: charge \: Q = CV = 6 \times 2 = 12mC[/tex]
therefore,
✯ σptíσn ( d ) íѕ cσrrєct!hope helpful~
~Be Brainly!a car moving at 5 m/s accelerates at a rate of 10 m/s2 for 25 seconds. How far does it move during this time?
Answer:
t is time in s For example, a car accelerates in 5 s from 25 m/s to 3 5m/s. Its velocity changes by 35 - 25 = 10 m/s. Therefore its acceleration is 10 ÷ 5 = 2 m/s2
Explanation:
A sailcraft is stalled on a windless day. A fan is attached to the craft and blows air into the sail which bounces backward upon impact. The boat can what?
Answer:
Impulse = change in momentum w bounce
There are 2 impulses acting. Recoil of the fan going the negative direction and the impulse of the air bouncing off the sail. The greater impulse will bounce so the direction will be to the right moving the craft.
What net force acting on a 6 kg car produces an acceleration of 6 m/s2?
Explanation:
Mass (m) = 6 kgAcceleration (a) = 6 m/s²Force (F) = ?We know that,
• F = ma→ F = (6 × 6) N
→ F = 36 N
Therefore, the net force is 36N.
Where do hyperbolic comets originate?
A. the Oort cloud
B. the asteroid belt
C. the Kuiper belt
D. interstellar space
Answer:A.the Oort cloud
Explanation:
Answer:
try answer A..the Ootor cloud
The fundamental of a closed organ pipe is 259.6 Hz. The second harmonic of an open organ pipe has the same frequency. What is the length of the closed pipe
Answer:
A closed organ pipe is λ/4 (node-antinode) long.
λ = speed / frequency = 331.5 / 259.6 = 1.28 m
λ/4 = .319 m length of closed pipe
An open pipe has a fundamental wavelength of A-N-A or λ/2
The second harmonic would be A-N-A-N-A or λ = 1.28 m for the second harmonic 331.5 / 259.6 = 1.28 (the fundamental would be 331.5 / .628
What can happen when untreated sewage water contaminates water?
Answer:
Health Effects ↯Life-threatening human pathogens carried by sewage include cholera, typhoid and dysentery. Other diseases resulting from sewage contamination of water include schistosomiasis, hepatitis A, intestinal nematode infections, and numerous others.
Explanation:
BRAINLIEST PLEASE • •︴︴
____
Need help asap
A scientist has invented a robot to work on the seabed. According to his calculation, the armour of the robot can withstand a maximum pressure of 10⁵ Pa exerted by the sea water. If the density of the sea water is 1025 kg/m3, what is the maximum depth of the seabed that this robot can work? [Given g = 9.81 m/s2 and rho water = 1000 kg/m3]
Answer:
Explanation:
Well which is it ? ρ = 1000 kg/m³ or ρ = 1025 kg/m³?
Obviously the sea is salt water so we can ignore ρ = 1000 kg/m³
1025 kg/m³(d m)(9.81 N/kg) = 1 x 10⁵ N/m² = Pa
d = 9.9450535...
d = 10 meters
That's if we only account for the pressure due to the water. On top of that pressure would be atmospheric pressure which is about 101000 Pa
so the robot would be a hair above its pressure limit before it even got in the water.
Hey guys can you help me with this problem it's giving me a headache. "If 2500 kg roller coaster car begins its descent from 500m above above the first hill. What is its kinetic energy at the bottom of the hill."
The kinetic energy of the roller coaster at the bottom of the hill is 12250000 J
To answer this question, we must understand that the energy of a system is always conserved as explained by the law of conservation of energy.
The kinetic energy of the roller coaster will be equivalent to the potential energy of the roller coaster.
The kinetic energy of the roller coaster can be obtained as follow:
Mass (m) = 2500 KgHeight (h) = 500 mAcceleration due to gravity (g) = 9.8 m/s²Kinetic energy (KE) =?Kinetic energy = Potential energy
KE = mgh
KE = 2500 × 9.8 × 500
KE = 12250000 J
Therefore, the kinetic energy of the roller coaster is 12250000 J
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