When the plutonium bomb was tested in New Mexico in 1945, approximately 1 gram of matter was converted into energy. Suppose another bomb is tested, and 1.5 grams of matter are converted into energy. How many joules of energy are released by the explosion?

Answer:

in a plane mirror distance of object from mirror is equal to distance of image

so it will be 24 ÷ 2 = 12 cm

Answer:

Eccentricity = 0.0557

Semi-major axis = 9,095 km

Angular momentum/mass = 60,116 [tex]\frac{km^{2} }{Sec}[/tex]

Kinetic energies/mass = 24,500 KJ

Potential energies/mass = 21,673 KJ

Explanation:

Eccentricity

To find the eccentricity use the following formula

Eccentricity = [ Altitude from the earth x ( [tex]Velocity^{2}[/tex] / Gravitational parameter for the Earth ) ] - 1

Where

Altitude from the earth radius = Radius of the earth + Altitude of the earth from radius = 6,378 km + 2,210 km = 8,588 km

Velocity = 7,000 m/s

Gravitational parameter for the Earth = 3.986004418 × [tex]10^{14}[/tex]

Eccentricity = ?

Placing values in the formula

Eccentricity = [ ( 8,588 km x 1000 ) x ( [tex]7000^{2}[/tex] / 3.986004418 × [tex]10^{14}[/tex]   ) ] - 1

Eccentricity = 0.0557

Semi-major axis

Total Distance = Semi-major axis x ( 1 - Eccentricity )

Where

Total Distance = 8,588 km

Eccentricity = 0.0557

8,588 x 1,000 m = Semi-major axis x ( 1 - 0.0557 )

8,588,000 m = Semi-major axis x 0.9443

Semi-major axis = 8,588,000 m / 0.9443

Semi-major axis = 9,094,567.40 m

Semi-major axis = 9,094.56740 km

Semi-major axis = 9,095 km

Angular momentum/mass

L = MVR

L/M = VR

Where

V = Velocity = [tex]\frac{7,000 m/s}{1000}[/tex] = 7 km/s

R = Total Radius = Radius of Earth + Altitude = 6,378 km + 2,210 km = 8,588 km

Placing values in the formula

L/M = 7 km/s x 8,588 km = 60,116 [tex]\frac{km^{2} }{Sec}[/tex]

Kinetic energies/mass

Ke = I [tex]W^{2}[/tex]

Ke = [tex]\frac{1}{2} mr^{2}[/tex] [tex]W^{2}[/tex] ( Where I = [tex]mr^{2}[/tex] )

[tex]\frac{ke}{m}[/tex] = [tex]\frac{r^2}{2}[/tex] [tex]W^{2}[/tex]

[tex]\frac{ke}{m}[/tex] = [tex]\frac{r^2}{2}[/tex] [tex]\frac{V^2}{r^2}[/tex] ( [tex]W^{2}[/tex] = [tex]\frac{V^2}{r^2}[/tex] )

[tex]\frac{ke}{m}[/tex] = [tex]\frac{V^2}{2}[/tex]

[tex]\frac{ke}{m}[/tex] = [tex]\frac{7000^2}{2}[/tex]

[tex]\frac{ke}{m}[/tex] = 24,500,000 J

[tex]\frac{ke}{m}[/tex] = 24,500 KJ

Potential energies/mass

PE = mgh

[tex]\frac{PE}{m}[/tex] = gh

Where

g = 9.807 [tex]\frac{m}{s^2}[/tex]

h = 2,210 km x 1,000 = 2,210,000 m

Placing values in the formula

[tex]\frac{PE}{m}[/tex] = 9.807 [tex]\frac{m}{s^2}[/tex]  x 2,210,000 m

[tex]\frac{PE}{m}[/tex] = 21,673,470 J

[tex]\frac{PE}{m}[/tex] = 21,673.470 KJ

[tex]\frac{PE}{m}[/tex] = 21,673 KJ

Answer:

127.53 J

Explanation:

Given that

Height of the floor, h = 1.3 m

Acceleration due to gravity, g = 9.81 m/s²

Mass of the box, m = 10 kg

To find the work done on the box by the janitor, we use the formula for potential energy. Remember that potential energy is actually the energy stored in an object as a result of its position.

P.E = mgh, substituting each parameters for its value, we then have

P.E = 10 * 9.81 * 1.3

P.E = 127.53 J

Therefore, we can conclude that the amount of work done on the box by the janitor is 127.53 J

Answer:

d = 52.20 miles

Explanation:

Given that,

Devon drove 50 miles west and then drove 15 miles north.

We need to find Devon's displacement. Let it is d. It can be calculated as follows :

[tex]d=\sqrt{50^2+15^2} \\\\=52.20\ \text{miles}[/tex]

Hence, Devon's displacement is 52.20 miles.

Given :

A microscope using ultraviolet light is used to study bacteria. If the aperture diameter is 1.5 cm.

Angular size is 0.036 arc seconds.

To Find :

The maximum wavelength that can be used.

Solution :

Converting given angle into radians :

[tex]\theta = \dfrac{0.036}{3600}\times \dfrac{\pi}{180}\\\\\theta = 1.745\times 10^{-7}\ radians[/tex]

Now, we know maximum wavelength is given by :

[tex]\lambda = \dfrac{\theta \times D}{1.22}\\\\\lambda = \dfrac{1.745\times 10^{-7} \times 0.015}{1.22}\ m\\\\\lambda =2.145 \times 10^{-7}\ m[/tex]

Hence, this is the required solution.

Answer:

[tex]\Delta H=687.4 J[/tex]

Explanation:

Hello!

In this case, for this melting process, we can identify two sub-processes in order to take the stainless steel from solid to liquid:

1. Heat up from 298.15 K to 1673 K.

2. Undergo the phase transition.

Both process have an associated enthalpy as shown below:

[tex]\Delta H_1=1g*0.5\frac{J}{g*K} (1673K-298.15K)=687.4J[/tex]

[tex]\Delta H_2=0.001kg*\frac{0.260J}{kg} =0.00026J[/tex]

Therefore, the required heat is:

[tex]\Delta H=\Delta H_1+\Delta H_2\\\\\Delta H=687.4J+0.00026J\\\\\Delta H=687.4J[/tex]

Notice the problem is not providing neither the mass or volume, that is why we assumed the mass is 1 g; however, it can be changed to the mass you are given.

Best regards!

Answer:

179.47m/s

Explanation:

Using the law of conservation of momentum

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the final velocity

Substitute

7750(179)+72(230) = (7750+72)v

1,387,250+16560 = 7822v

1,403,810 = 7822v

v = 1,403,810/7822

v= 179.47m/s

Hence the final velocity of the probe is 179.47m/s

Answer:gamma>beta>alpha

Explanation: Just took the test

Answer:

5.096*10^-8

Explanation:

Given that

The average value of the electromagnetic wave is 310 mW/m²

To find the maximum value of the magnetic field the wave is closest to, we say

Emax = √Erms

Emax = √[(2 * 0.310 * 3*10^8 * 4π*10^-7)]

Emax = √233.7648

Emax = 15.289

Now, with our value of maximum electromagnetic wave gotten, we divide it by speed of light to get our final answer

15.289 / (3*10^8) = 5.096*10^-8 T

Suffice to say, The maximum value of the magnetic field in the wave is closest to 5.096*10^-8

Answer: (iii) the same about both ends

Explanation:

The moment of inertia is the sum of the square of the distance from the axis of massage and rotation of each length of the rod. The moment of inertia can be expressed as I = imiri2. The connection of the rod is the product of the moment length and distance (square), so it is the same at both ends.

The moment of inertia depends on the distribution of mass and the square of the distance from the axis.

The moment of inertia of the rod is the same about both ends. Hence, option (iii) is correct.

The degree measure of the resistance of an object towards an angular acceleration about the given axis is known as the moment of inertia of an object.

Given data -

The total mass of rod is, M = 6m.

The moment of inertia is the sum of the square of the distance from the axis of massage and rotation of each length of the rod. The mathematical expression is given as,

[tex]I = M \times r^{2}[/tex]

Since the connection of the rod is the product of the moment length and distance (square), so it is the same at both ends.

Thus, we can conclude that the moment of inertia of the rod is the same about both the ends.

Learn more about the moment of inertia here:

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Answer:

This question is incomplete but the completed question is below

A ray of light parallel to the principal axis of a spherical mirror passes through its _____ after reflection.

(a) focus (b) pole (c) centre of curvature (d) imaginary centre of curvature

The correct option is (a)

Explanation:

After reflection, a ray of light will usually appear to diverge after they hit a spherical mirror, extending behind the mirror to meet at a point (called the focus or focal point) between the pole and the centre of curvature of this mirror.  Hence, option a is the correct option.

Answer:

The cost per week of electricity is Rm 46.8

Explanation:

Electrical Power and Energy

The electrical power consumed by an appliance connected to a voltage V and carrying a current I is given by:

P = V.I

The energy consumed by an electrical appliance of power P during a time t is:

E = P.t

The electrical equipment in an office takes I=13 A when connected to a V=240 V supply.

The power consumed is:

P = 240 V * 13 A

P = 3,120 Watt

Converting to Kilowatt:

P = 3,120/1,000 KW

P = 3,12 KW

If the equipment is used t=30 hours each week, the energy is:

E = 3.12 KW * 30 h

E = 93.6 KWh

Since the cost of each KWh is Rm 0.50, the weekly cost of electricity is:

C = 93.6 * 0.50 = 46.8

The cost per week of electricity is Rm 46.8

Answer:

An electric fan is considered to be a mixture of several simple machines. It includes the Wheel and Axle type, wedges, and the Inclined plane types. The blades of an electric fan are the inclined planes and the wedges.

An atomic nucleus . . .

-- contains all of the atom's positive charge

-- contains almost all of the atom's mass

-- contains none of the atom's negative charge.

Answer:

An atomic nucleus . . .

-- contains all of the atom's positive charge

-- contains almost all of the atom's mass

-- contains none of the atom's negative charge.

Explanation:

yaaaaaa what the person on top said

Answer:

25.68 N

Explanation:

From the question given above, the following data were obtained:

Density of cylindrical rod = 7800 kg/m³

Length = 92.4 cm

Diameter = 2.15 cm

Acceleration due to gravity (g) = 9.8 m/s²

Weight of rod =?

Next, we shall determine the volume of the rod. This can be obtained as follow:

Height (h) = 92.4 cm

Diameter (d) = 2.15 cm

Pi (π) = 3.14

Volume (V) =?

V = π(d/2)²h

V = 3.14 × (2.15/2)² × 92.4

V = 335.29 cm³

Next, we shall convert 335.29 cm³ to m³. This can be obtained as follow:

1 cm³ = 1×10¯⁶ m³

Therefore,

335.29 cm³ = 335.29 cm³ × 1×10¯⁶ m³ / 1 cm³

335.29 cm³ = 0.00033529 m³

Thus, 335.29 cm³ is equivalent to 0.00033529 m³.

Next, we shall determine the mass of the rod. This can be obtained as follow:

Density of rod = 7800 kg/m³

Volume of rod = 0.00033529 m³.

Mass of rod =?

Density = mass /volume

7800 = mass / 0.00033529

Cross multiply

Mass of rod = 7800 × 0.00033529

Mass of rod = 2.62 Kg

Finally, we shall determine the weight of the rod. This can be obtained as follow:

Mass (m) of rod = 2.62 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Weight (W) of rod =?

W = m × g

W = 2.62 × 9.8

W = 25.68 N

Therefore, the weight of the rod is 25.68 N

Answer:

  (b)  Friction increases as the normal force (weight) increases, and also depends on the surface

Explanation:

The coefficient of friction relates the normal force between surfaces to the friction force opposing motion. The coefficient depends on the surface.

The appropriate choice is ...

  Friction increases as the normal force (weight) increases, and also depends on the surface

Answer: Areobic Resporation

Explanation; -Aerobic respiration is the process in living things that evolved as oxygen levels increased in earth's atmosphere.

Answer:

intertidal zone.

the shallowest part of the ocean ecosystem, where the ocean floor os covered and uncovered as the tide goes in and out. Plankton. the organisms that float on the water in aquatic ecosystems and are unable to swim.

Answer:

The law zero of thermodynamics.

Explanation:

The law zero of thermodynamics, which tells us that heat flows from a body at a higher temperature to another body with lower temperature, when the heat transfer is zero, it is said that the two bodies are in thermal equilibrium, their temperatures are equal

Complete question is:

It's is difficult to walk on a wet floor than a smooth floor. Why?

Answer:

Because friction on wet floor is far lesser than on a smooth floor

Explanation:

On wet surfaces, the friction is far lesser than on smooth surfaces and thus the grip between the bottom of your shoes/feet and the ground is very very small and as such walking on the wet surface becomes more difficult. Whereas on Smooth surfaces, there is plenty of friction and as a result, there is enough grip between the bottom of your shoes/feet and the ground thereby making walking far easier.

Answer:

362.6 N

Explanation:

[tex]F_{g}=mg[/tex]

[tex]F_{g}=37\cdot9.8[/tex]

[tex]F_{g}=362.6\ N[/tex]

Therefore, the force that the glass hits the floor with is 362.6 N

Answer:

d₂ = 6.18 mm

Explanation:

We can work on this interesting exercise using the concepts of energy conservation

alpha (1) particle, with have a charge q = 2e

Starting point

            Em₀ = U = q V₁

final point

            [tex]Em_{f}[/tex] = ½ m v²

             Em₀ = Em_{f}

            2eV₁ = ½ m₁ v²

           v² =[tex]\frac{4 \ e \ V_{1}}{m_{1} }[/tex]

proton (2) particle, with have a charge q = e

Starting point

          Em₀ = qV₂

Final point

          Em_{f} = ½ m₂ v²

          Em₀ = Em_{f}

          eV₂ = ½ m₂ v²

          v² = [tex]\frac{2 \ e \ V_{2} }{m_{2} }[/tex]

in the exercise, it should be noted that the two particles have the same velocity when reaching the plate, therefore let us solve the velocity in each equation and equal

        \frac{4 \ e \ V_{1}}{m_{1} }= \frac{2 \ e \ V_{2} }{m_{2} }

         [tex]V_{2} = \frac{2 m_{2} }{m_{1} } \ V_{1}[/tex]

the alpha particle is composed of two protons and two neutrons, therefore in first approximation

          m₁ = 4 m₂

subtitute

         V₂ =[tex]\frac{1}{2}[/tex] V₁

let's calculate

         V₂ = [tex]\frac{1}{2}[/tex] 600

         V₂ = 300 V

To find the distance we use the relationship between the electric field and the potential difference

         V = -d E

The electric field between the plates is constant, so

          E = - V / d = - V₂ / d₂

          d₂ = [tex]\frac{V_{2} }{V} \ d[/tex]

let's calculate

          d₂ = [tex]\frac{300}{680} \ 15[/tex]  

          d₂ = 6.18 mm

Answer:

Earth-crossing asteroid, asteroid whose path around the Sun crosses Earth's orbit. Two groups of such asteroids—Aten and Apollo asteroids—are distinguished by the size of their orbits and how closely they approach the Sun.

Explanation:

Answer: the amount of mass is oscillating is 34.8 kg

Explanation:

Given that;

amplitude A = 20.0 cm

time t = 10 s

amplitude decreases x = 15.0 cm

damping coefficient b = 2.00 N.s/m

amount of mass is oscillating = ?

we know that; amplitude can be expressed as;

x = Ae^-(∝t)

we substitute

15 = 20e^-∝(10)

∝ = 0.02877 s⁻¹

Hence mass m will be;

m = b/2∝

we substitute

m = (2 N.s/m) / ( 2 × 0.02877 s⁻¹)

m = 34.8 kg

Therefore the amount of mass is oscillating is 34.8 kg

Answer:

0.124 miles

Explanation:

Since the radius of the atom R = 10000r where r = radius of nucleus. Now, if r = 2.0 cm = 0.02 m,

R = 10000r

= 10000 × 0.02 m

= 200 m

We know that 1 mile = 1609 m.

So the radius of the atom in miles is R = 200 m × 1 mile/ 1609 m = 0.124 miles

So, the radius of the atom in miles is 0.124 miles  

Answer: the answer is B. 2.0

Explanation:

Answer:

1200J

Explanation:

W.D=mass×accelerarion due to gravity×distance

W.D=40kg×10m/s²×3m

W.D=1200kgm²/s²

W.D=1200J

A 40 kg person is climbing 3 m up a flight of stairs in 6 seconds, then the work done by the person to climb the stairs is 1200 J.

When we apply a force called "F" to a block, the body moves with an acceleration or, additionally, its speed changes depending on the force's direction. The system's kinetic energy changes depending on whether the speed increases or decreases.

Energy must be transformed into another form because, as far as we are aware, it cannot be created or destroyed. In this view, it is referred to as work completed.

[tex]Work\ done = Force*Distance[/tex]

and Force = mg

Substitute all the values in the above formula,

W.D = 40 kg × 10 m/s² × 3 m

W.D = 1200 kg m²/s² or,

W.D = 1200 J

To get more information about Work done :

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#SPJ2

Answer:

The fraction of incident light or radiation reflected by a surface or body, commonly expressed as a percentage.

2.

biology The whitish inner portion of the rind of citrus fruits that is a source of pectin, commonly referred to as the pith.

Explanation: