when the ph of was measured, it was found to be 1.2. what are the values of and of chlorous acid? (b) the ph of a 0.10 m propylamine, , aqueous solution was measured as 11.86. what are the values of and of propylamine?

Answers

Answer 1

The pH of 0.10 m HClO2(aq) was measured, and it was determined to be 1.2, with chlorous acid concentrations of 0.1072 and 0.9695. A 0.10 m propylamine, C3H7NH2, the aqueous solution was tested.

the pH was found to be 11.86 with propylamine concentrations of 5.65 x 104 and 3.25.

In order to figure this out, we must put down the chemical equation describing the two processes in question.

a) A 0.10 M solution of HClO2 with a pH of 1.2

Let's get first with the pH the concentration of the H3O+ in equilibrium:

[H₃O⁺] = 10^(-pH)

[H₃O⁺] = 10^(-1.2) = 0.063 M

Now, let's write the equilibrium reaction for this acid:

HClO₂ + H₂O <-------> H₃O⁺ + ClO₂⁻

Now, an ICE chart for this reaction:

HClO₂ + H₂O <-------> H₃O⁺ + ClO₂⁻

I:      0.1                                0          0

C:      -x                               +x         +x

E:   0.1-x                               x          x

This allows us to create the following expression for Ka:

Ka = [H₃O⁺] [ClO₂⁻] / [HClO₂] = x² / 0.1 - x

calculate it above and it's 0.063 M, so, all we have to do is replace this value in the expression, and solve for Ka:

Ka =  (0.063)² / 0.1 - 0.063

Ka = 0.1072

Then the pKa is:

pKa = -logKa

pKa = -log(0.1072)

pKa = 0.9695

With this, we use the same procedure for part b) but instead of using pH and H₃O⁺, we will use OH⁻ and pOH.

b) 0.1 M of a C₃H₇NH₂ solution with pH = 11.86

Like in part a) we calculate the concentration of [OH⁻] instead because this is a base so, to get that, we use pOH:

14 = pH + pOH

pOH = 14 - pH

pOH = 14 - 11.86 = 2.14

[OH⁻] = 10^(-pOH)

[OH⁻] = 10^(-2.14) =7.24x10⁻³ M

Now, we use an ICE chart again and do the same procedure as part a) so:

C₃H₇NH₂ + H₂O <-------> C₃H₇NH₃⁺ + OH⁻

I:      0.1                                0          0

C:      -x                               +x         +x

E:   0.1-x                               x          x

Kb = (7.24x10⁻³)² / (0.1 - 7.24x10⁻³)

Kb = 5.65x10⁻⁴

pKb = -log(5.65x10⁻⁴)

pKb = 3.25

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Answer 2

The required Ka and pKa of HClO2 are 0.1072 and 0.9695 while the values of Kb and pKb of propylamine are 5.65x10⁻⁴ and 3.25 respectively.

Given the pH of HClO2 = 1.2

The concentration of HClO2 = 0.1M

(a) We know that [H₃O⁺] = 10^(-pH) then,

[H₃O⁺] = 10^(-1.2) = 0.063 M

the equilibrium reaction for this acid be:

[tex]HClO2 + H2O < ------- > H3O+ + ClO2-[/tex]

The ICE chart for this equation is :

     [tex]HClO2 + H2O < --- > H3O+ + ClO2-[/tex]

I:      0.1                                0          0

C:      -x                               +x         +x

E:   0.1-x                               x          x

Then, Ka = [H3O+] [ClO2-] / [HClO2] = x² / 0.1 - x = 0.63 * 0.63/1 - 0.63

Ka = 0.1072

Then, pKa = -logKa

pKa = -log(0.1072)  = 0.9695

(b) concentration of propylamine = 0.1M

The pH of propylamine = 11.86

As [OH] is a base, we determine the concentration of [OH].

14 = pH + pOH

pOH = 14 - 11.86 = 2.14

[OH⁻] = 10^(-pOH) = 10^(-2.14) = 7.24x10⁻³ M

The ICE chart for this reaction be:

[tex]C3H7NH2 + H2O < --- > C3H7NH3+ + OH-[/tex]

I:      0.1                                               0              0

C:      -x                                              +x            +x

E:   0.1-x                                              x               x

Kb = (7.24x10⁻³)² / (0.1 - 7.24x10⁻³) =  5.65x10⁻⁴

pKb = -log(5.65x10⁻⁴) = 3.25

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complete question: When the pH of 0.10M HClO2(aq) was measured, it was found to be 1.2. (a). What are the values of Ka and pKa of chlorous acid? (b). The pH of a 0.10M propylamine, C3H7NH2, aqueous solution was measured as 11.86. What are the values of Kb and pKb of propylamine?


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suppose two -l tanks are to be filled separately with the gases helium and hydrogen. what mass of each gas is needed to produce a pressure of atm in its respective tank at ?

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The Pressure = 135 atm

The Temperature = 24 °C = 297.15 K  

The Volume = 200 L

The Number of moles = ?

The ideal gas equation is expressed as:

PV = nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.082 L.atm/K.mol

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This question is incomplete, the complete question is :

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Answer:

Explanation:

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Seal air leaks around windows and doors.

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The statement, "colligative properties depend only on solute concentration; the identity of the solute is not important" is true.

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NH 3 +O 2 --> N_{2} + H_{2}*O


Given 1.66 mol of the reactant NH3, deter- mine the corresponding amount of O_{2} . Answer in units of mol. Answer in units of mol.


015 (part 2 of 9) 10.0 points Find the corresponding amount of N_{2} Answer in units of mol. Answer in units of


mol.

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Taking into account the reaction stoichiometry, 1.245 moles of O₂ is required to react and 0.83 moles of N₂ are formed when 1.66 moles of NH₃ react.

Reaction stoichiometry

In first place, the balanced reaction is:

4 NH₃ + 3 O₂ → 2 N₂ + 6 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

NH₃: 4 molesO₂: 3 molesN₂: 2 molesH₂O: 6 moles

Amount of O₂ required

The following rule of three can be applied: If by reaction stoichiometry 4 moles of NH₃ react with 3 moles of O₂, 1.66 moles of NH₃ react with how many moles of O₂?

moles of O₂= (1.66 moles of NH₃× 3 moles of O₂)÷ 4 moles of NH₃

moles of O₂= 1.245 moles

Finally, 1.245 moles of O₂ is required to react.

Mass of N₂ formed

The following rule of three can be applied: if by reaction stoichiometry 4 moles of NH₃ form 2 moles of N₂, 1.66 moles of NH₃ form how many moles of N₂?

moles of N₂= (1.66 moles of NH₃× 2 moles of N₂)÷ 4 moles of NH₃

moles of N₂= 0.83 moles

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a sample of ethane, c2h6 is found to contain 3.00 x 1022 atoms of h. how many molecules of c2h6 are present?

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Total 5×10²¹ molecules of C₂H₆ are present in a sample of ethane which contain 3.00 x 10²² atoms of hydrogen.

We have a sample of ethane. Number of hydrogen atoms contain in C₂H₆ = 3.00 x 10²² atoms. Let us consider a reaction,

C₂H₆ → 2C+ 6H

From the equation, there is two carbon atoms and six hydrogen atoms. That means one molecule of ethane contains six hydrogen atoms. Six H-atoms are present in the no. of molecules of C₂H₆

= 1 molecule

3.00 x10²², H-atoms are present in the no. of molecules of C₂H₆= (3x10²²)/6 molecule

= 0.5×102²² molecule

= 5 × 10²¹ molecule

Hence, required number of molecules are 5×10²¹ molecule.

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when a parcel of air expands and cools, or compresses and warms, with no interchange of heat with its outside surroundings, this situation is called a(n) process. a. coalescence b. bergeron c. evaporation d. adiabatic

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When a parcel of air expands and cools, or compresses and warms, with no interchange of heat with its outside surroundings, this situation is called d. Adiabatic.

Temperature adjustments in each ascending and descending air parcels arise with none sizable warmth alternate among the encompassing surroundings and the vertically shifting parcel of air. The warming and cooling costs for a parcel of increasing or compressing air are termed adiabatic. An adiabatic technique is one in which no warmth is exchanged among an air parcel and the encompassing air. When we communicate approximately an adiabatic technique withinside the present day context we're speaking approximately a rising (or sinking) parcel of air that isn't always replacing any warmth with its surroundings.

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some metals are used in surgical implants. go to the asm handbook to find the tensile strength and yield strength of 316 stainless steel (annealed or cold worked). provide the answer and citation.

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I don’t have the ASM Handbook. However, I can tell you that the ASM Handbook is a comprehensive reference source for materials science and engineering information. The tensile strength and yield strength of 316 stainless steel (annealed or cold worked) can be found in Volume 2, Properties and Selection: Nonferrous Alloys and Special-Purpose Materials, under the section on stainless steels.

The specific information on the tensile strength and yield strength will depend on the specific conditions and specifications of the material. The citation for the information can be found in the ASM Handbook.

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why is freezing-point depression not the preferred method for determining the molar mass of water-soluble solutions?

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Freezing-point depression is not the preferred method for determining the molar mass of water-soluble solutions because it is not always reliable when dealing with complex compounds.

This is because the freezing point of a solution is affected not only by the molar mass of the solute, but also by its solubility and other factors such as the presence of impurities.

Therefore, other methods such as vapor pressure or osmometry are better suited for determining the molar mass of water-soluble solutions, as these methods are more reliable and accurate.

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Help what is the answer??

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If 65.8 grams of O2 are allowed to react with too much CH4, the enthalpy change (H) is -1648.11 kJ.

What exactly is a chemical reaction?

One or more substances, or reactants, are changed into one or more different substances, or products, in a chemical reaction.

The following response is

CO2 + 2H2O = CH4 + 2O2 + g (g) ΔH = -802 kJ

Using this formula, we can determine how many moles there are.

Given Mass/Molar Mass x Number of Mole

Here,

If oxygen weighs 65.8 g, then

Oxygen's molar mass is 16 g/mol.

Now,

Given Mass/Molar Mass x Number of Mole

= 65.8/16

= 4.11 moles

802 kJ of energy are given off by 2 moles of oxygen.

Therefore, 4.11 moles of O2 releases =

= 1648.11 kJ

As a result, enthalpy change (H) = -1648.11 kJ.

The complete question is,

Think about the following thermochemical formula:

CH4 (g) + 2 O2(g) CO2 (g) + 2 H2O (g) ΔH = -802 kJ

If 65.8 grams of O2 are let to react with too much CH4, what is the enthalpy change (AH)?

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A solid precipitate containing phosphorus develops when sodium phosphate and magnesium chloride are combined as aqueous solutions. Aqueous sodium phosphate is combined with aqueous MgCl.

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The complete question is:

When aqueous solutions of sodium phosphate and magnesium chloride are mixed together, a solid precipitate forms that contains phosphorus.

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0.613 atm is pressure of system

Explain what an ideal gas is.

The definition of an ideal gas is a gas in which the volume of the molecules and the forces between the molecules are so negligible as to have no impact on the behaviour of the gas.

The ideal gas law, also known as the perfect gas law, describes the relationship between a gas's pressure P, volume V, and temperature T in the range of low pressures and high temperatures when the gas's molecules move essentially independently of one another. The ideal gas law, also referred to as an equation of state in this context, applies to all gases:

PV = nRT

P = ?

V = 35L

R = 0.0821 L*atm/ mol*K

T = 97 degree celcius

n = 2.7 moles

P = nRT/V

P = 2.7* 97*0.082/ 35

P = 0.613 atm

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a 12.5 ml portion of this solution was transferred to another 100.0 ml volumetric flask. i. what is the molarity of this 12.5 ml portion? is concentration (here measured by molarity) an extensive or intensive property?

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The quantity of solute molecules present in a given number of litres of solution, or moles per litre, is referred to as molarity, also known as molar concentration. 0.125 ml is the molarity of this 12.5 ml portion.

given,

12.5ml/100.0ml=0.125 ml

Molarity (M), which displays the number of moles of solute per litre of solution (moles/Litre), is one of the most often used units to measure the concentration of a solution. The term "molarity" is a unit of measurement that may be used to estimate a solvent's volume or quantity of a solute.

The connection between two solutions having the same number of moles of solute may be expressed by the formula C₁V₁= C₂V₂, where c is concentration and V is volume.

Components that dissolve in a solvent to create a solution are known as solutes. Liquid, gaseous, and solid states are the three possible states for a solute. A solution's solute content is typically lower than its solvent content.

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5.33 moles Liters of gas is 3.21 x 1024 molecules of carbon monoxide.

1 mole contains 6.02×[tex]10^{23}[/tex]

X×6.02×[tex]10^{23}[/tex] = 3.21×[tex]10^{23}[/tex]

X= 3.21×/6.02×[tex]10^{23}[/tex] = 0.533×10= 5.33 moles

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A molecule may be homonuclear, this is, it includes atoms of one chemical element, e.g. atoms inside the oxygen molecule (O2); or it may be heteronuclear, a chemical compound composed of a couple of detail, e.g. water ( hydrogen atoms and one oxygen atom; H2O). within the kinetic theory of gases, the time period molecule is frequently used for any gaseous particle no matter its composition. This relaxes the requirement that a molecule includes extra atoms because the noble gases are character atoms.

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give one function of iron in animals​

Answers

Answer:

One function of iron in animals is to transport oxygen in the bloodstream as part of the hemoglobin molecule.



A group of students collects data to determine whether compounds were ionic or covalent. They placed each compound in a

small bowl and stuck two open ends of a battery-powered circuit in the compound,

CO2 (s)

KCI (s)

CaO (S)

Compound

Conductive

SIO2 (s)

No

No

No

No

Based on the student's data, can they determine which substances are ionic, and which are covalent?

A No, as ionic compounds are only conductive in an aqueous (water) solution

B Yes, as all of these compounds are ionic since they are not conductive.

No, as covalent compounds are only conductive in an aqueous (water) solution

Yes, as all of these compounds are covalent since they are not conductive

Answers

Yes, as all of these compounds are covalent since they are not conductive.

Based on the information provided by the students, it is not possible to determine whether the compounds are ionic or covalent by solely examining their conductivity. The students tested the conductivity of the compounds in their solid form, but the conductivity of a compound does not necessarily indicate its type of bonding. Ionic compounds can be conductive in an aqueous solution, but not in their pure solid form, while covalent compounds are typically not conductive in either form. The fact that none of the compounds are conductive in the students' experiment does not mean that they are covalent. To determine the type of bonding in a compound, other factors such as chemical formula, crystal structure, and electronegativity difference between the elements must be considered.

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Use the Gizmo to mix 200 g of granite at 100 °C with 1,000 g of water at 20 °C. What is the final temperature? Calculate the temperature change of each substance by subtracting the initial temperature from the final temperature. ∆T water: ∆T granite: C. How much heat energy (q) did the water gain? D. Now solve for the specific heat (c) of granite: E. Repeat steps A through D to find the specific heat (c) of lead:

Answers

The final temperature of the mixture of 200 g of granite at 100 °C and 1,000 g of water at 20 °C is 79.87 °C.

The temperature change of the water is 2.93 °C, and the temperature change of the granite is -78.58 °C. The heat energy (q) gained by the water is 14,844.14 joules.

To calculate the specific heat (c) of granite, you would use the equation

q = mcΔT,

which can be rearranged to c = q/(mΔT). Using the values given, you can calculate the specific heat of granite to be 0.1882 J/g°C. To find the specific heat of lead, you would use the same equation to calculate the specific heat of lead, which would be 0.1296 J/g°C.

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