when propane undergoes complete combustion, the products are carbon dioxide and water. c3h8(g) o2(g) co2(g) h2o(g) what are the respective coefficients when the equation is balanced with the smallest whole numbers?

Answers

Answer 1

These coefficients represent the number of moles of each substance that are present in a given amount of propane that undergoes complete combustion.  

When propane undergoes complete combustion, the balanced equation is:

C₃H₈ + 7O2 → 4CO₂ + 4H₂O

To determine the coefficients for each compound, we can use the balanced equation and the mole ratios of the products.

The mole ratio of carbon dioxide to propane is 4:1, since there are four moles of carbon dioxide for every mole of propane that undergoes combustion.

The mole ratio of water to propane is 4:1, since there are four moles of water for every mole of propane that undergoes combustion.

The mole ratio of carbon dioxide to oxygen is 1:4, since there is one mole of carbon dioxide for every four moles of oxygen that participate in the reaction.

The mole ratio of hydrogen to oxygen is 2:4, since there are two moles of hydrogen for every four moles of oxygen that participate in the reaction.

We can use these mole ratios to write the balanced equation with the smallest whole numbers:

C₃H₈ + 7O₂ → 4CO₂ + 4H₂O

The coefficients in this equation are the same as the mole ratios, so the coefficients for each compound are:

C3H8: 1

O2: 7

CO2: 4

H2O: 4

Therefore, the coefficients for shako-avatar

When propane undergoes complete combustion, the balanced equation is:

C3H8 + 7O2 → 4CO2 + 4H2O

To determine the coefficients for each compound, we can use the balanced equation and the mole ratios of the products.

The mole ratio of carbon dioxide to propane is 4:1, since there are four moles of carbon dioxide for every mole of propane that undergoes combustion.

The mole ratio of water to propane is 4:1, since there are four moles of water for every mole of propane that undergoes combustion.

The mole ratio of carbon dioxide to oxygen is 1:4, since there is one mole of carbon dioxide for every four moles of oxygen that participate in the reaction.

The mole ratio of hydrogen to oxygen is 2:4, since there are two moles of hydrogen for every four moles of oxygen that participate in the reaction.

We can use these mole ratios to write the balanced equation with the smallest whole numbers:

C3H8 + 7O2 → 4CO2 + 4H2O

The coefficients in this equation are the same as the mole ratios, so the coefficients for each compound are:

C3H8: 1

O2: 7

CO2: 4

H2O: 4

Therefore, the coefficients for propane, carbon dioxide, oxygen, and water when the equation is balanced with the smallest whole numbers are:

C₃H₈: 1

O₂: 7

CO₂: 4

H₂O: 4

These coefficients represent the number of moles of each substance that are present in a given amount of propane that undergoes complete combustion.  , carbon dioxide, oxygen, and water when the equation is balanced with the smallest whole numbers are:

C₃H₈: 1

O₂: 7

CO₂: 4

H₂O: 4

These coefficients represent the number of moles of each substance that are present in a given amount of propane that undergoes complete combustion.  

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Explanation:

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The given reaction is an example of displacement reaction. Here, one mole of oxygen reacts with one mole of oxygen molecules. Hence theoretically 32 g of sulphur needs 32 g of oxygen.

What is displacement reaction?

Displacement reactions are a kind of reactions where one element or group is displaced with other element or group. There are both single displacement and double displacement reaction.

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The English translation of your question is as follows:

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why an aspirin tablet works faster if it is crushed rather than swallowed whole?​

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Answer: because the tablet is already crushed and is easy for the organism to absorb instead of having to break it down

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Answers

Answer:

Explanation:

6CO2 + 6H2O = 0C6H12O6 + 6O2

First you note how much u got of everything in front of and behind the arrow

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As you can see, the equation is already balanced.

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Answer:

Dihydrogen Monoxide (DHMO) is perhaps the single most prevalent of all chemicals that can be dangerous to human life. Despite this truth, most people are not unduly concerned about the dangers of Dihydrogen Monoxide. Governments, civic leaders, corporations, military organizations, and citizens in every walk of life seem to either be ignorant of or shrug off the truth about Dihydrogen Monoxide as not being applicable to them. In 1997, the Dihydrogen Monoxide Research Division was formed and went online spreading the truth about DIHYDROGEN MONOXIDE. As word has spread, so too has the public awareness of Dihydrogen Monoxide and its implications involving the Internet and accessibility of such information. To that end, the DMRD's web site at DHMO.org continues to provide the most comprehensive collection of Dihydrogen Monoxide information available anywhere.

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Answer:

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Answer:

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Your answer would be C. :)

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Answer:

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Answers

Answer:

The empirical formula simply states the ratios of the elements that make up the molecule, while molecular formulas specify the amounts of each element exactly, not just giving the ratio. Let's take ethane (C2H6) as an example.

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Answers

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Explanation:

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Answers

The question is incomplete, the complete question is;

Choose the aqueous solution that has the highest boiling point. These are all solutions of nonvolatile solutes and you should assume ideal van't Hoff factors where applicable. 0.100 m C6H12O6 0.100 m AlCl3 0.100 m NaCl 0.100 m MgCl2 They all have the same boiling point.

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AlCl3 0.100 m

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Answer:

A divergent boundary!

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The answer is Divergent boundaries

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Answer:

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Answers

Answer:

1. 1 mole of NaCl.

2. 1 mole of H₂O.

Explanation:

The balanced equation for the reaction is given below:

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

1 mole of HCl reacted with 1 mole of NaOH to produce 1 mole of NaCl and 1 mole of H₂O.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above, we can see that 1 mole of HCl reacted completely with 1 mole of NaOH. Therefore, HCl is the limiting reactant and NaOH is the excess reactant since we have 3.6 moles of NaOH.

1. Determination of the amount of NaCl produced from the reaction.

NOTE: The limiting reactant is used to determine the maximum amount produced since all of it is consumed in the reaction.

The limiting reactant is HCl and the amount of NaCl produced can be obtained as follow:

From the balanced equation above, we can see that 1 mole of HCl reacted to 1 mole of NaCl.

Thus, 1 mole of NaCl was produced.

2. Determination of the amount of H₂O produced from the reaction.

From the balanced equation above, it is evident that 1 mole of HCl reacted to produce 1 mole of H₂O.

Thus, 1 mole of H₂O was produced.

I need help with this question ASAP

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Answer:

I think its A)

Explanation: im not sure im sorry

A quanta of electromagnetic energy is called *

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Answer: A quantum of electromagnetic energy is called a photon. Also, do you mean a quantum because I don't think a quanta is a thing

Explanation:

What is the freezing point of a solution of 498mL of water (solute) dissolved in 2.50 L of ethanol (solvent), C2H5OH? The density of C2H5OH is 0.789g/cm3. (Remember that water has a density of 1.0 g/cm3.)

Answers

Answer:

Freezing T° of solution is -142.4°C

Explanation:

This excersise is about colligative properties, in this case freezing point depression,

ΔT = Kf . m . i

Where ΔT = Freezing T° of solvent - Freezing T° of solution

Kf = Cryoscopic constant

m = mol/kg (molality)

i = Number of ions dissolved.

Water is not ionic, so i = 1

Let's find out m.

We determine mass of water, by density

498ml . 1 g/mL = 498 g

We convert the mass of water to moles → 498 g . 1mol/18g = 27.6 moles

We determine mass of solvent by density

2500 mL . 0.789 g/mL = 1972.5 g

Notice, we had to convert L to mL to cancel units.

1 cm³ = 1 mL

We convert the mass from g to kg → 1972.5 g . 1kg /1000g = 1.97kg

We determine m = mol/kg → 27.6mol / 1.97kg = 13.9 m

Kf for ethanol is: 1.99 °C/m

Freezing T° for ethanol is: -114.6°C

We replace at formula: - 114.6°C - Freezing T° solution = 1.99 °C/m . 13.9 m . 1

- 114.6°C - Freezing T° solution = 27.8 °C

- Freezing T° solution  = 27.8°C + 114.6°C

Freezing T° Solution = - 142.4 °C

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