Answer:
14.3 x 10^8Hz
Explanation:
Using
Frequency= speed of light /wavelength
Then substituting
3*10^8m/s / 0.21m
= 14.3 x10^8 Hz
1. How many inches are in 6 meters?
Answer:
236.22 inches
Explanation:
There are 39.3701 inches in 1 meter. So to find 6 meters, multiply 6 times 39.3701.
6·39.3701=236.22
Answer:
236.22
Explanation:
just because itit's common sense
7. Una locomotora de 80.000 kilogramos de masa, parte del reposo y a los 10 segundos lleva una velocidad de 36Km/h. Halla: A. La aceleración del movimiento. B. La fuerza que causa el movimiento.
Answer:
a) La aceleración del movimiento es 1 metros por segundo al cuadrado, b) La fuerza que causa el movimiento es 80.000 newtons.
Explanation:
a) Supóngase que la locomotora acelera uniformemente, la aceleración se está descrita por la siguiente ecuación cinemática:
[tex]v = v_{o}+a\cdot t[/tex]
Donde:
[tex]v_{o}[/tex] - Rapidez inicial, medida en metros por segundo.
[tex]v[/tex] - Rapidez final, medida en metros por segundo.
[tex]a[/tex] - Aceleración, medida en metros por segundo al cuadrado.
[tex]t[/tex] - Tiempo, medido en segundos.
Se despeja la aceleración:
[tex]a = \frac{v-v_{o}}{t}[/tex]
Si [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v = 10\,\frac{m}{s}[/tex] y [tex]t = 10\,s[/tex], la aceleración del movimiento es:
[tex]a = \frac{10\,\frac{m}{s}-0\,\frac{m}{s}}{10\,s}[/tex]
[tex]a = 1\,\frac{m}{s^{2}}[/tex]
La aceleración del movimiento es 1 metros por segundo al cuadrado.
b) Dado que una locomotora es un sistema de masa constante, la fuerza ([tex]F[/tex]) que genera el movimiento es igual a:
[tex]F = m\cdot a[/tex]
Donde:
[tex]m[/tex] - Masa, medida en kilogramos.
[tex]a[/tex] - Aceleración, medida en metros por segundo al cuadrado.
Dados que [tex]m = 80.000\,kg[/tex] y [tex]a = 1\,\frac{m}{s^{2}}[/tex], la fuerza que causa el movimiento es:
[tex]F = (80.000\,kg)\cdot \left(1\,\frac{m}{s^{2}} \right)[/tex]
[tex]F = 80.000\,N[/tex]
La fuerza que causa el movimiento es 80.000 newtons.
I don't know how to solve this, can I get a little help?
Explanation:
Acceleration is the change in velocity over change in time.
a = Δv / Δt
So it is the slope of the line of a velocity vs. time graph.
a = (10 m/s − 40 m/s) / (12 s − 0 s)
a = -2.5 m/s²
give an example of unbalanced force
Your question has been heard loud and clear.
Well , basically anything that moves in a certain direction is an example of unbalanced forces.
When we kick the football , the force given by our leg is greater than the frictional force by the ball and therefore the ball moves in the direction of the greater force , which is the force given by our leg.
Thank you
Answer:
friction
Explanation:
I can raise a bucket of cement mix of mass 12kg through a vertical height of 8m in 10 seconds.Calculate the average power used in raising the bucket against the gravitational force?
Explanation:
Power = work / time
Power = force × distance / time
P = (12 kg × 10 m/s²) (8 m) / (10 s)
P = 96 Watts
The average power used in raising the bucket against the gravitational force is equal to 94.08 W.
What is power?Power can be defined as the rate of doing work in unit time. The S.I. unit that is used to measure power is Watt (W) or Joule per second. Power can be described as the rate at which work is done.
Power = Work /time
Given, the mass of the bucket, m = 12 kg
The distance traveled by the bucket, d = 8 m
The work is done by the bucket, W = F.d
W = mg.d
W = 12 × 9.8 ×8
W = 940.8 J
Given, the time is taken by the bucket, t = 10 s
The power used in raising the bucket against the gravitational force:
P = W/t
P = 940.8/10
P = 94.08 W
Therefore, the average power is equal to 94.08 W.
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Which one of the two potential differences emf or terminal voltage will be greater in magnitude?Why?
Answer:
True, yes terminal voltage of a battery can never be greater than the emf of the battery. Because due to internal resistance of the current terminal
compare distance and mass
Answer:
The amount of gravity affecting an object depends on two things: the masses of the objects being attracted and the distance between the objects. Mass is the measure of the amount of matter in an object. With distance, we see that the strength of gravity decreases if the distance between two objects increases.
Hope this helps!
A ball is thrown vertically upward from the top of a tower 40m high with velocity 10m/sec find time when it strikes ground
Find time when it strikes ground.
Formula used:-s = ut + 1/2 at²
Solution:-We will first calculate the time taken by the ball to reach the highest point by using the formula:
S = ut + 1/2 at²
★ Substituting the values in the above formula,we get:
⇒ -40 = 10 × t + 1/2 × -10 × t²
⇒ -40 = 10t + ( - 5 ) × t²
⇒ -40 = 10t - 5 t²
⇒ 5t² - 10t - 40
⇒ 5t² - 20t + 10t - 40
⇒ 5t ( t - 4 ) + 10 ( t - 4 )
⇒ t - 4 = 0 and 5t + 10 = 0
⇒ t = 4 and t = -2
Thus,time taken is 4 seconds. [ Ignore negative number. ]
Answer:
[tex]\Huge \boxed{\mathrm{4 \ s}}[/tex]
Explanation:
Displacement ⇒ -40 m (the ball strikes the ground)
Initial velocity ⇒ 10 m/s
Acceleration of gravity ⇒ -10 m/s² (upward acceleration)
We can use a formula to find the time taken.
[tex]s = ut + 1/2 at^2[/tex]
[tex]s = \sf displacement \ (m)[/tex]
[tex]u = \sf initial \ velocity \ (m/s)[/tex]
[tex]a = \sf acceleration \ of \ gravity \ (m/s^2)[/tex]
[tex]t = \sf time \ taken \ (s)[/tex]
Plugging in the values.
[tex]-40 = (10)t + 1/2 (-10)t^2[/tex]
Solve for [tex]t[/tex].
[tex]-40 = 10t-5t^2[/tex]
[tex]5t^2-10t-40=0[/tex]
Factor the quadratic expression.
[tex]5(t+2)(t-4)=0[/tex]
Set the factors equal to 0.
[tex]t+2=0\\t=-2[/tex]
[tex]t-4=0\\t=4[/tex]
t = -2 and t = 4 (time value will not be negative in this case)
The time the ball takes to strike the ground is 4 seconds.
an object is placed at a distance of 10cm from a convex mirror of focal length 15 cm find the position and nature of the image
Answer:
[tex]\boxed{\sf Position \ of \ the \ image = 6 \ cm}[/tex]
[tex]\boxed{\sf Nature \ of \ the \ image = Virtual \ and \ Erect}[/tex]
Given:
Object distance (u) = -10 cm
Focal length (f) = 15 cm
To Find:
Image distance (v) and nature of the image
Explanation:
Mirror Formula:
[tex]\boxed{\bold{\sf \frac{1}{v} + \frac{1}{u} = \frac{1}{f}}}[/tex]
Substituting values of u and f in the equation:
[tex]\sf \implies \frac{1}{v} -\frac{1}{10} =\frac{1}{15}[/tex]
[tex]\sf \implies \frac{1}{v}=\frac{1}{15} +\frac{1}{10}[/tex]
[tex]\sf \implies \frac{1}{v}=\frac{2}{30}+\frac{3}{30}[/tex]
[tex]\sf \implies \frac{1}{v}=\frac{2+3}{30}[/tex]
[tex]\sf \implies \frac{1}{v}=\frac{5}{30}[/tex]
[tex]\sf \implies v=\frac{30}{5}[/tex]
[tex]\sf \implies v=6 \ cm[/tex]
[tex]\therefore[/tex]
Image distance (v) = 6 cm
Nature of the image = Virtual and Erect
To expel hot air out of the kitchen, A has an exhaust fan fitted on the window of her kitchen and B has a similar exhaust fan fitted on the wall near the ceiling of the kitchen. Which one of the exhaust fan will expel the hot air more effectively? Explain why.
Answer:
Kitchen B
Explanation:
This all boils Down to the phenomenon of convection current of àir where warmer air rises up and is replaced by cooler air, the fan is placed higher up in B and because hot air rises higher up it will remove more hot air here
Consider three widely separated galaxies in an expanding universe. Imagine that you are located in galaxy 1 and observe that both galaxies 2 and 3 are moving away from you. If you asked an observer in galaxy 3 to describe how galaxy 2 appears to move, what would he or she say?
Answer:
The observer will say that galaxy 2 is moving away from galaxy 3 where he stands.
Explanation:
Since the galaxies are expanding, each one would move away from the others. Observers on all three galaxies have their frame of reference fixed on their own galaxies. Judging from their own galaxies, each observer will perceive the other galaxies moving away from his/or galaxy.
The observer at galaxy 3 will talk about galaxy 2 by doing is; he will say that galaxy 2 is moving far from him.
We are told that the universe is expanding and as such, the galaxies would be expanding and moving away from each other.
Since the galaxies are expanding, it means that they will be moving away from each other.
From time dilation principle, an observer at galaxy 3 will say that galaxy 2 is moving far from him.
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Whic two types of cells are required during the process of osteogenesis
This Class I’m in is called Anatomy & Phys
Answer:
Bone homeostasis involves multiple but coordinated cellular and molecular events. Two main types of cells are responsible for bone metabolism: osteoblasts (which secrete new bone), and osteoclasts (which break bone down).
Explanation:
The radius of a small ball is around 2.8436 cm. The radius of a basketball is about 4.22 times larger. What is the ratio of the surface areas of the small ball and a basketball? Part 2 What is the ratio of their volumes?
help please
Answer:
Explanation:
Both small ball and a basketball are in form of a sphere. Total surface area of a sphere is gotten using the formula;
surface area of a sphere S = 4πr²
If the radius of a small ball is around 2.8436 cm, its total surface area will be:
S = 4π(2.8436)²
S =4π(8.086)
S = 101.61 cm²
If the radius of a basketball is about 4.22 times larger, the radius will be 4 times larger as well. The radius of the basket ball = 4.22*2.8436
radius of thr basketball = 11.99cm
Surface area of the basketball S2 = 4π(11.99)²
S2 =4π(143.76)
S2 =1806.54cm²
The ratio of the surface areas of the small ball and a basketball S:S2
S:S2 = 101.61 cm² : 1806.54cm²
S:S2 = 0.0562
Hence, the ratio of the surface areas of the small ball and a basketball is approximately 0.0562.
2) The volume of a sphere = 4/3πr³
Volume of the small ball = 4/3π(2.8436)³
Volume of the small ball = 4/3 π * 22.994
Volume of the small ball= 96.315cm³
Similarly;
Volume of the basketball = 4/3π(11.99)³
Volume of the small ball = 4/3 π * 1723.68
Volume of the small ball= 7220.14cm³
The ratio of the volume of the small ball and a basketball V:V2
V:V2 = 96.315 : 7220.14
V:V2 = 0.01333
Hence, the ratio of the volumes of the small ball and a basketball is approximately 0.01333
Simple Harmonic Motion: A simple harmonic oscillator oscillates with frequency f when its amplitude is A. If the amplitude is now doubled to 2A, what is the new frequency
Answer:
The frequency will still remain F
Explanation:
Firstly, we should remember that the frequency of a simple harmonic oscillator doesn't depend on the amplitude. Rather, it depends on the spring constant, k, and the mass of the attached weight, m. This means that the change in amplitude will not lead to a corresponding change in frequency.
the frequency is represented by the formula
f = 1/2π * √(k/m),
where
f = frequency of the oscillator
k = spring constant and
m = mass attached to the spring
From the formula above, we can state that the frequency doesn't depend on the amplitude at all, and as such, the amplitude changing from A to 2A, will effect no change in the frequency F.
Kangaroos have been clocked at speeds of 18 m/s. How far can a kangaroo hop in 192 sec at this speed?
[tex] \bf \underline{ \underline{given : }}[/tex]
Speed of kangaroo = 18 m/s Time taken by a kangaroo = 192 sec[tex]\bf \underline{ \underline{to \: be \: calculated : }}[/tex]
Calculate the distance covered by a kangaroo.
[tex]\bf \underline{ \underline{formula \: applied : }}[/tex]
[tex] \boxed{ \bf{Speed = \frac{Distance}{Time} }}[/tex]
[tex]\bf \underline{ \underline{Solution : }}[/tex]
We know that,
Speed = Distance/Time
=> Distance = Speed × Time
Substituting the values in the above formula,we get;
=> Distance = 18 × 192
=> Distance = 3456 m
Thus,the distance covered by a kangaroo is 3456 meters.
the maximum speed limit on interstate 10 is 75 miles per hour. how many meters per second is this
Answer:
33.53m/sExplanation:
Given the maximum speed limit on interstate 10 as 75 miles per hour, to get the speed in meter per seconds, we need to convert the given speed to meter per seconds.
Using the conversion 1 mile = 1609.34m and 1 hour = 3600 seconds
75 miles perhour = 75miles/1 hour
75miles/1 hour (in m/s) = 75miles*1609.34m* 1 hour/1mile * 1 hour * 3600s *
= 75 *1609.34m* 1 /1 * 1 * 3600s
= 120,700.5m/3600s
= 33.53m/s
Hence the maximum speed limit on interstate 10 in metre per seconds is 33.53m/s
when object goes under acceleration
a).a force always acys on it
b).its speed always increase
c).its velocity always increases
when object goes under acceleration
c).its velocity always increases
Additional information:-★ Acceleration: Rate of increase in velocity.
★ Velocity: Distance travelled by a body per unit time in given direction is called velocity .
Answer: velocity always increase
Explanation: Really dont need any explanation
1. It takes 10 seconds for you to go to the cafeteria from the classroom and to
come back. Cafeteria is 20m away East to the classroom. What is your average
velocity?
Answer:
4 m/s East.
Explanation:
Velocity: This cam be defined as the rate of change of displacement. The unit of velocity is m/s.
From the question,
v = d/t...................... Equation 1
Where v = velocity, d = displacement, t = time.
Given: d = 20 m East, t = 5 seconds.
substitute into equation 1
v = 20/5
v = 4 m/s East.
Hence the average velocity = 4 m/s East.
What is the net force on an object that is experiencing a force of 25 N north, a force of 25 N
south, a force of 50 N to the east and a force of 45 N to the west?
Answer:
net 5N of force will act in east direction.
Explanation:
force acting in North and South direction will cancel each other.
force in east direction - force in west direction = 5N
a child hits a ball with a force of 350 N. (a) If the ball and bat are in contact for 0.12 is, what impulse does the ball receive? (b) what is its change in momentum?
Explanation:
Given that,
Force with which a child hits a ball is 350 N
Time of contact is 0.12 s
We need to find the impulse received by the ball. The impulse delivered is given by :
[tex]J=F\times t\\\\J=350\times 0.12\\\\J=42\ N-m[/tex]
So, the impulse is 42 N-m..
We know that he change in momentum is also equal to the impulse delivered.
So, impulse = 42 N-m and change in momentum =42 N-m.
What is the standard unit for time
standerd unit of time is second
Answer:
The standard unit for time is second (s).
Solve the following numerical problems. a) A load of 400N is liſted up by an effort of 100N. If load distance is 20cm, what will be the effort distance? (Ans 80cm)
Answer:
Solution
Load(L)=400
Effort(E)=100
Load distance (Ld)=20cm
Effort distance(Ed)=?
Now,from the principle of equilibrium
L×Ld=E×Ed
or,Ed=L×Ld/E
or,Ed=400×20/100
:.Ed=80cm and
Therefore,the effort distance will be 80cm
Answer:
80cm
Explanation:
load l = 400
Effort e = 100
load distance Ld = 20
Effort distance Ed = ?
L×ld= E×Ed
Ed=L×Ld \ E
Ed=400×20/100
Ed=80cm Ans
places of hot climate it is advised that outer walls of houses be painted white. Why?
Answer: In places of hot climate it is advised that the outer wall of houses be painted white because white color reflects heat and the houses do not heat up too much.
Which statement best describes the similarities between fundamental forces? a Electromagnetic and strong nuclear forces influence the interaction between charged particles within an atom. b Gravitational and magnetic forces are the most alike because they are both types of charges that occur in nature. c Nuclear and magnetic forces are the most alike because they are both related to mass and weight. d Strong nuclear force is most like electrical force because they are both related to distance.
Answer:
a
Explanation:
............
..............option A
Answer:
A is the answer as electromagnetic and strong nuclear forces influence the interaction between charged particles within an atom the only difference being their intensity! Hope this helps :) and if you dont mind, mark me brainliest so i can get to the next rank :(
If no forces are acting on a moving object, the object will continue to move with constant: Group of answer choices impulse momentum acceleration All of these. None of these.
Answer:
constant acceleration,
Explanation:
when an object is moving without any change in direction,its acceleration is regarded as zero which also means that the object is moving at a constant acceleration.
If no forces are acting on a moving object, the object will continue to move with constant momentum.
To find the answer, we need to know about the force.
What is force?Force is the rate of change of momentum with respect to time.Its SI unit is Newton. It's a vector quantity.What does happen, if force is zero?Force is zero means the rate of change of momentum with respect to time is also zero.Therefore, if the momentum is not changing with time, then it's constant over time.Thus, we can conclude that if no forces are acting on a moving object, the momentum is constant.
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A baseball player up to bat gets hit by a fast ball. What is the predominant type of force generated by the ball on the player? Explain your reasoning.
Answer:
Reaction force
Explanation:
According to Newton's third law of motion, for every action, there is an equal opposite reaction.
Hence the reaction force is often equal in magnitude to the applied force but acts in a direction opposite to the direction of the applied force.
Hence, when a baseball player, gets a hit, the ball exerts a reaction force on the player which is equal in magnitude to the force with which the player hits the ball but opposite in direction.
Find the density of a substance that has a volume of 754 cm3 and a mass of 7,917 grams. Don't forget your units!
Answer:
[tex] \boxed{\sf Density \ of \ the \ substance = 10.5 \ g/cm^3} [/tex]
Given:
Mass (M) = 7917 grams
Volume (V)= 754 cm³
To Find:
Density of the substance
Explanation:
[tex] \boxed{ \bold{\sf Density \ (\rho) = \frac{Mass \: (M)}{Volume \: (V)}}}[/tex]
Substituting values of M & V in the equation:
[tex] \sf \implies \rho = \frac{7917}{754} [/tex]
[tex]\sf \implies \rho = 10.5 \: g/ {cm}^{3} [/tex]
An object on the end of a spring is oscillating in simple harmonic motion. If the amplitude of oscillation is doubled, how does this affect the object’s maximum speed?
Answer:
The maximum speed of the oscillating object doubles as well.
Explanation:
The oscillatory motion of the object on the spring can be modelled using this equation below:
[tex]Vmax= A\omega[/tex]
Where
Vmax = the maximum speed of the oscillating object.
A = Amplitude of the oscillating object.
[tex]\omega[/tex] = angular velocity of the oscillating object.
If the amplitude, A becomes doubled, the new amplitude will be = 2A.
As a result, [tex]Vmax = 2 A \omega[/tex]
This shows that the maximum speed has doubled in its value
Which of these item(s) are NOT mentioned in Stuff Matters? Leather Shoes Microphones Candles Jet Engine Teacup
Answer:
Leather Shoes, Microphones, Candles
Explanation:
Surprisingly, leather Shoes, Microphones, Candles were not mentioned in Stuff Matters a book written by Mark Miodownik which according to him explored "the marvelous things that shape our man-made world."
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Question 4
1 pts
You jog around 180m track 4 times in 30 minutes. What is your average speed in
m/s? (Hint: Convert min to seconds first)
O 0.4 m/s
O 6 m/s
O 24 m/s
O O m/s
Answer:
0.4m/s
Explanation:
It is given speed so it is scalar.
distance covered in 1 round = 180m
therefore, distance covered in 4 rounds = 180*4 = 720m
time = 30 mins = 30*60 = 1800 seconds
average speed = total distance/total time taken
= 720/1800
= 0.4m/s