Answer:
The original volume of the metal sphere is approximately 1 cm³
Explanation:
The given parameters are;
The temperature change of the metal ball, ΔT = 30°C = 30 K
The new volume of the metal ball, V₂ = 1.0018 cm³
The linear expansivity of the material ball, α = 2.0 × 10⁻⁵ K⁻¹
We have;
d₂ = d₁·(1 + α·ΔT)
Where;
d₁ = The original diameter of the metal ball
d₂ = The new diameter of the ball
From the volume of the ball, V₂, we have;
V₂ = 1.0018 cm³ = (4/3)×π×r₂³
Where;
r₂ = The new radius = d₂/2
∴ V₂ = 1.0018 cm³ = (4/3)×π×(d₂/2)³
∴ d₂ = ∛(2³ × 1.0018 cm³/((4/3) × π)) ≈ 1.241445 cm
d₁ = d₂/(1 + α·ΔT)
∴ d₁ ≈ 1.241445 cm/(1 + 2.0 × 10⁻⁵·K × 30 K) ≈ 1.24070058 cm
The original volume of the metal ball, V₁ = (4/3)×π×(d₁/2)³
∴ V₁ = (4/3)×π×(1.24070058/2)³ ≈ 0.99999902845 cm³ ≈ 1 cm³
The original volume of the metal sphere, V₁ ≈ 1 cm³.
what is it called when a body covers certain distance per unit time
Explanation:
Hey there!
The answer is Speed.
Reason:
Simply we know that distance (d) = speed*time
and speed = distance/ time. And according to the question, when a body covers certain distance/unit time, it's speed.
Hope it helps!
a condenser of capacitor 50 micro coulomb is charged to 10 volt the energy stored is can you do derivation please
Answer:
2.5x10^-3 J
Explanation:
C=50mC
V=10V
U=1/2 C (V)^2
=1/2(50)(10)^2 x (10)^-6
=25(100)/1000000
=2.5x10^-3
Why does Quito, Equator has very little changes to the daylight hours
throughout the year?
Because of the position on the equator, the change in rotation of the Earth on its axis throughout the year doesn't affect it much. Unlike the poles, Quito is almost constantly in direct view of the sun. So, because of lack of change in rotation, the daylight hours are hardly varied as Quito is almost constantly in more or less the same spot in relation to the sun.
Does the nucleus of animal or plant cells contain chromosomes?
Answer:
both animal and plant cells contain chromosomes
The hull of a sunken boat, laying on the seabed, is 9 m below the surface of the sea, where the sea water has an average density of 1,025 kg/m3. The hull’s surface area is 12 m2. What is the total force exerted by seawater on the hull?Required to answer. Single line text.
Answer:
1084860 N
Explanation:
Applying,
P = ρgh................ Equation 1
Where P = pressure, ρ = density, h = height, g = acceleration due to gravity.
From the question,
Given: ρ = 1025 kg/m³, h = 9 m
Constant: g = 9.8 m/s²
Substitute these values into equation 1
P = (1025)(9)(9.8)
P = 90405 N/m²
Also,
P = F/A.............. Equation 2
Where, F = Force, A = Area.
Make F the subject of the equation
F = PA............... Equation 2
Given: A = 12m²
F = 12(90405)
F = 1084860 N
Complete the wording of the Law of Conservation of Matter and Energy (as defined in the text).
"Neither _____ nor _____ can be created or destroyed, but they can be changed from one form to the other."
distance
weight
motion
density
energy
matter
(more than one answer choice)
Answer:
Neither "matter" nor "energy" can be created or destroyed, but they can be changed from one form to the other.
Explanation:
1. The algebraic letter 'dy' stands for
can someone please help me I will mark you as brilliant.
The current in a resistor is 5 A and the voltage between its terminals is 40 V. Calculate the resistance.
An iron wire has a resistance of 24 Ω. If the voltage across its ends is 12 V, calculate the current in the wire.
Answer:
1=8 ohms 2=0.5 Amps
Explanation:
if a current of 0.3 ampere flows through a conductor of resistance of 11.7 ohm's,the voltage across the ends of the conductor is what
Here,
Resistance = 11.7
Ampere = 0.3
Voltage = ?
Now,
R = V/A
11.7 = V/0.3
11.7*0.3 =V
V = 3.51
I hope it's help you...
Mark me as brainliest...
¿Cuál es el valor del coeficiente de roce estático entre dos superficies, sabiendo que para poner en movimiento un cuerpo de 35kg. Es necesario, vencer una fuerza de resistencia de 45 Newton?
Answer:
El coeficiente de roce estático entre las dos superficies es 0.131.
Explanation:
El coeficiente de roce estático entre dos superficies ([tex]\mu_{s}[/tex]), sin unidad, es igual a la fuerza de resistencia ([tex]F[/tex]), en newtons, dividida por el peso del cuerpo a mover ([tex]W[/tex]), en newtons.
[tex]\mu = \frac{F}{m\cdot g}[/tex] (1)
Donde:
[tex]m[/tex] - Masa, en kilogramos.
[tex]g[/tex] - Aceleración gravitacional, en metros por segundo al cuadrado.
Si sabemos que [tex]F = 45\,N[/tex], [tex]m = 35\,kg[/tex] y [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], entonces el coeficiente de roce estático es:
[tex]\mu = \frac{45\,N}{(35\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}[/tex]
[tex]\mu = 0.131[/tex]
El coeficiente de roce estático entre las dos superficies es 0.131.
when a volcano is about to erupt, the nearby places may also experience an earthquake
TRUE OR FALSE
Answer:
True
Explanation:
Volcanically-caused long period earthquakes are produced by vibrations generated by the movement of magma or other fluids within the volcano. Pressure within the system increases and the surrounding rock fails, creating small earthquakes.
a sphere of mass 5kg and volume 2×10-5completely immersed in water find the buoyant force exerted water
Answer:
Buoyant force exerted water = 0.196 Newton
Explanation:
Given:
Mass of sphere ball = 5 kg
Volume = 2 x 10⁻⁵
Find:
Buoyant force exerted water
Computation:
Buoyant force exerted water = Gravity due to acceleration x volume of object x density of given liquid
Buoyant force exerted water = 9.8 x 2 x 10⁻⁵ x 1000
Buoyant force exerted water = 0.196 Newton
Which of the following is NOT accelerating?
Group of answer choices
A Ferris wheel turning at a constant speed
A plane gaining speed down a runway
A runner speeding around the curve toward the finish line
A car traveling down a straight highway at constant speed
A 45.2 kg softball player slides across dirt with Uk=0.340. What is her acceleration?
Answer:
The answer is -3.34 m/s^2.
Explanation:
I used another brainly question to help me find the answer. It was pretty similar to this one so yeah. Good luck to you nonetheless.
https://brainly.com/question/25065591
least count of vernier caliper is dash
Answer:
0.02 is the count of vernier caliper.
Answer:
0.01 mm
A Vernier calliper scale can have a minimum count of 0.01 mm, while a micrometre can have a minimum count of 0.001 mm.
calculate the answer to the correct number of significant digits
0.055 * 5.1 =
Answer:
0.055 * 5.1 = 0.2805
Explanation:
I used a calculator so it should be accurate! yw!! :D
what two forces contribute to the nuclear tug of war in an atom
Answer:2 protons and 2 neutrons
Explanation:In Nuclei, There are 2 forces. 1 force is electrostatic and acts as repulsion between 2 protons. The other is force of attraction called Nuclear force between 2 neutrons.
(Please help if you can, I need this last answer done by tonight.)
Use the universal law of gravitation to solve the following problem.
Hint: mass of the Earth is = 5.97 x 1024 kg
A scientific satellite of mass 1300 kg orbits Earth 200 km above its surface. If Earth has a radius of 6378 km, what is the force of gravity acting on the scientific satellite?
a. Write out the formula for this problem.
b. Plug in the values from this problem into the formula.
c. Solve the problem, writing out each step.
d. Correct answer
Answer:
11963.43 N
Explanation:
From the question given above, the following data were obtained:
Mass of the earth (Mₑ) = 5.97x10²⁴ Kg
Mass of satellite (Mₛ) = 1300 Kg
Radius of the earth (R) = 6378 km
Distance between the earth and satellite (r) = R + 200 Km = 6378 + 200 = 6578 Km
Force of gravity (F) =?
Next, we shall convert 6578 Km to m. This can be obtained as follow:
1 Km = 1000 m
Therefore,
6578 Km = 6578 Km × 1000 m / 1 Km
6578 Km = 6578000 m
Finally, we shall determine the force of gravity. This can be obtained as follow:
Mass of the earth (Mₑ) = 5.97x10²⁴ Kg
Mass of satellite (Mₛ) = 1300 Kg
Distance apart (r) = 6578000 m
Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
Force of gravity (F) =?
F = GMₑMₛ / r²
F = (6.67×10¯¹¹ × 5.97x10²⁴ × 1300) / (6578000)²
F = 11963.43 N
Therefore, the force of gravity on the scientific satellite 11963.43 N
Which of the following would have the greatest force of gravitational attraction?
a 10 kg object 2 meters from a 5 kg object
a 10 kg object 1 meter from a 5 kg object
two 5 kg objects 2 meters apart
two 10 kg objects 1 meter apart
Answer:
two 5kg objects 2 meters apart✨
state the factor that affect the gravity of a planet
Answer:
The planet's mass and size determine the gravity of a planet
Explanation:
The smaller and less mass a planet has, the less gravitational pull it has on things and vice versa. The same can be applied with all living things, we all have an extremely small gravitational pull.
True or false please help I’ll give brainliest
Answer:
7. F
8. T
Explanation:
7. An anion is indicated by a negative superscript charge (- something) to the right of the atom. For example, if a sodium atom loses one electron, it will have one more proton than electron, giving it an overall +1 charge. The chemical symbol for the sodium ion is Na+1 or just Na+
8.Like charges repel each other; unlike charges attract. Thus, two negative charges repel one another, while a positive charge attracts a negative charge. The attraction or repulsion acts along the line between the two charges
1.) False
2.) True
hope this helped,, good luck!! :]
A person is pushing a box across a table. The measured forces on the box are 10N, 14N, -7N, -10N.
Which force is represented by -7N?
A) force of friction
B) normal force
C) force of gravity
D) push force
Answer:
the answer to this question is c
Answer:
A) force of friction
Explanation:
frictional forces are always negative, they are an opposing force they act opposite to the applied force.
if escape velocity and orbital velocity of a satellite for Orbit close to the Earth's surface then these are related by
Answer:
The ratio of the escape velocity to the orbital velocity is [tex]\sqrt 2[/tex].
Explanation:
The minimum velocity given to an object so that it escapes from the earth's gravitational pull is called escape velocity.
The formula of the escape velocity is
[tex]v=\sqrt\frac{2GM}{R}[/tex]
The velocity of an object in the orbit around the earth is called orbital velocity.
The formula of the orbital velocity is
[tex]v=\sqrt\frac{GM}{R}[/tex]
The ratio of the escape velocity to the orbital velocity is
[tex]\frac{v_e}{v_o}=\sqrt 2[/tex]
A -0.00125 C charge is placed 3.62 m from a +0.00333 C charge. What is the magnitude of the electric force between them?
Answer:
The magnitude of the force between the charges is approximately -2,858.77 N
Explanation:
The given details are;
The magnitude of the given charges;
q₁ = -0.00125 C, q₂ = +0.00333 C
The distance between the charges, r = 3.62 m
The magnitude of the electric force between the charges, 'F', between two charged particles or objects is given as follows;
[tex]F = \dfrac{k \cdot q_1 \cdot q_2}{r^2}[/tex]
Where;
k = Constant = 9 × 10⁹ N·m²/C²
q₁ = The magnitude of charge on the first charged object = -0.00125 C
q₂ = The magnitude of charge on the second charged object = +0.00333 C
r = The distance between the charges = 3.62 m
Plugging in the values, gives;
[tex]F = \dfrac{9 \times 10^9 \ \dfrac{N \cdot m^2}{C^2} \times (-0.00125 \, C) \times (+0.00333 \, C)}{\left( 3.62 \, m \right)^2} \approx -2,858.77 \, N[/tex]
The magnitude of the force between the charges, F ≈ -2,858.77 N
the acceleration of a moving vehicles is 10 metre per second square what does it means
Answer:
Acceleration is the rate of change of velocity. What is commonly said as ‘ten meter per second squared’ can bee broken down into ‘ten meter per second per second.’ This gives us the true meaning of the term acceleration.
Just like ‘ten meter per second’ means increasing the displacement by ten meters every second, ‘ten meter per second per second’ means increasing the velocity by ten meters per second every second.
So, basically if you consider the case of a free fall motion, where ‘t’ stands for time and ‘v’ stand for velocity at that instant:
At,
t=0, v=0 m/s
t=1, v=0+10 m/s;
t=2, v=0+10+10 m/s;
t=3, v=0+10+10+10 m/s;
This can also be thought as a Arithmetic Progression where common difference ‘D’ is the acceleration(a), since it adds a 10 m/s to velocity every second and the first term ‘A’ stands for the initial velocity (u). Using this approach we can derive to the first equation of motion:
v = u + at
Hope this Answer Helps!!
Explanation:
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It means that the vehicle's speed increases at the rate of 10m/s every second.
At any time, it's speed is 10 m/s faster than it was 1 second earlier.
A cheetah runs at a speed of 27.6 m/s. If the
cheetah runs for 9.30 s, what is the distance the
cheetah runs? Show all your work.
Answer:
256.68m
Explanation:
that is the procedure above
A cheetah runs at a speed of 27.6 m/s. If the cheetah runs for 9.30 s, then the distance covered by the cheetah would be 256.68 metes
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is meter/second. The generally considered unit for speed is a meter per second.
The mathematical expression for speed is given by
speed = distance /Total time
As given in the problem A cheetah runs at a speed of 27.6 m/s. If the cheetah runs for 9.30 s, we have to calculate the distance covered by the cheetah
Distance=?
speed=27.6 m/s
time= 9.30 s
speed = distance /Total time
27.6 m/s = Distance /9.30 s
Distance = 27.6×9.30
=256.68 metes
Thus, the distance covered by the cheetah would be 256.68 metes
Learn more about speed from here
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The symbol for the hydroxide ion is
Он*
Оно
ОН(ОН)
ООН
NEXT QUESTION
ASK FOR HELP
A diverging lens will always produce an image with _______.
a) a negative focal length and a magnification more than 1
b) a positive focal length and a magnification more than 1
c) negative focal length and magnification less than 1
d) a positive focal length and a magnification less than 1
Answer:
Option C
Explanation:
Diverging lens are negative lens as they have negative focal length. Their
magnification is smaller than one.
They produce virtual image in which the refracted rays extended back in order to meet
Hence, option C is correct
Tâm ống dẫn đặt dưới đường phân giới giữa nước và thuỷ ngân h1 = 820mm, chênh lệch chiều cao cột thuỷ ngân h2 = 880mm (Hg = 13,6). Ap suất dư tại điểm A trong ống dẫn (at)?
Answer:
P = 79993.43245
Explanation:
Được -
Vị trí tâm ống dẫn dưới đường thuỷ ngân h1 = 820 mm
Chênh lệch chiều cao của cột thủy ngân h2 = 880mm
Tỷ trọng của thủy ngân = 13,5951 g / cm3
P = mật độ * gia tốc do trọng lực a * h
Thay thế các giá trị đã cho, chúng ta nhận được -
P = 13,5951 g / cm3 * 980,665 cm / s2 * (88-82) cm
P = 79993.43245
IV. The table below shows how the speed of a car changes with time. 1 What is the acceleration of the car? please help! :(