What’s the equation of the line that passes through the point (5,1) and has a slope of 1

Step-by-step explanation:

In a direct proportion, the ratio between matching quantities stays the same if they are divided. (They form equivalent fractions). In an indirect (or inverse) proportion, as one quantity increases, the other decreases.  In an inverse proportion, the product of the matching quantities stays the same.

Answer:

Both direct and indirect proportion are a comparison between two quantities (usually with different units).

In a direct proportion, as one quantity increases, the other also increases.

Examples would include:

If you buy more packets, it will cost more money.

If you have further to travel it will take more time.

If more people are to be fed, more food will be need.

If more people are to be transported, more cars/buses are needed.

More petrol is needed for longer distances.

Bigger area of floor will require more tiles/paint/wood.

A longer distance will need more paces to cover.

More dresses to be made will require more material.

In a direct proportion, the ratio between matching quantities stays the same if they are divided. (They form equivalent fractions).

k

=

x

y

In an indirect (or inverse) proportion, as one quantity increases, the other decreases.

If more people share a task, it will be done in less time.

Travelling at a faster speed means a trip will take less time.

If sugar is packed in smaller packets, more packets will be needed for the same mass.

For the same amount of money, a small parcel can be sent further than a bigger parcel.

If more people are being fed, food will be used up quicker.

For a fixed amount of money, as the price of presents increases, fewer can be bought.

Walking with longer strides means fewer paces are needed.

In an inverse proportion, the product of the matching quantities stays the same.

k

=

x

×

y

A hyperbola is the graph of inverse proportion.

Step-by-step explanation:

, .

Answer:

Right answer = 52

Wrong answers = 8

Step-by-step explanation:

Every correct answer = + 3

Every wrong answer = - 2

Number of correct answers = x

Number of wrong answers = y

x + y = 60 - - - (1)

3x - 2y = 140 - - - (2)

From (1) :

x = 60 - y

Put x = 60 - y into (2)

3(60 - y) - 2y = 140

180 - 3y - 2y = 140

180 - 5y = 140

-5y = 140 - 180

-5y = - 40

y = 8

x = 60 - y

x = 60 - 8

x = 52

Right answer = 52

Wrong answers = 8

Answer:

it is what it is

Step-by-step explanation:

Answer:

2nd one, 3rd one and last one

The y-coordinate of the red point is -3.

Answer:

250 + 200h = 300 + 180h

200h – 180h = 300 – 250

20h = 50

H = 2.5 credit hours

Step-by-step explanation: Hope this helps and good luck :))

Answer:

[tex]Bike = 7[/tex]

[tex]Car = 8[/tex]

[tex]Walk = 9[/tex]

[tex]Bus = 12[/tex]

Step-by-step explanation:

Given

[tex]Bus = 120^o[/tex]

[tex]Walk = 90^o[/tex]

[tex]Car = 80^o[/tex]

[tex]n = 36[/tex] --- pupils

Required

Determine the number of students in each category

This is calculated by dividing the measure of each category by 360; then multiply the result by the number of pupils:

So, we have:

[tex]Bus = \frac{120}{360} * 36 = \frac{1}{3} * 36 = 12[/tex]

[tex]Walk = \frac{90}{360} * 36= \frac{1}{4} * 36 = 9[/tex]

[tex]Car = \frac{80}{360} * 36 = \frac{80}{10} = 8[/tex]

To calculate the number of students that travel by bike, we have:

[tex]Car + Bike + Walk + Bus= n[/tex]

Substitute values

[tex]8 + Bike + 9+ 12= 36[/tex]

Collect like terms

[tex]Bike = 36 - 8 - 9 - 12[/tex]

[tex]Bike = 7[/tex]

Answer:

Look at picture

Step-by-step explanation:

10a+46-(3a+2b)

= 10a + 46 - 3a - 2b

= 7a - 2b + 46

Answer:

Assume x greater-than-or- equal-to 0 and y ... 0 StartRoot x squared y cubed EndRoot + 2 StartRoot x cubed y Superscript 4 Baseline EndRoot + x y StartRoot y EndRoot.

Step-by-step explanation:

Option (b) is correct.

The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy is  2xy\sqrt{y}+2xy^2\sqrt{x}2xyy+2xy2x

Step-by-step explanation:

Given:Expression \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy

We have to find the sum of the given expression and choose the correct from the given options.

Consider the given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy .

\sqrt{x^2y^3}x2y3 can be written as \sqrt{x^2y^2y}=xy\sqrt{y}x2y2y=xyy

Also, 2\sqrt{x^3y^4}2x3y4 can be written as 2\sqrt{x^3y^4}=2\sqrt{x^2x(y^2)^2}=2xy^2\sqrt{x}2x3y4=2x2x(y2)2=2xy2x

Now, the given expression becomes,

x2y3+2x3y4+xyy

=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}=xyy+2xy2x+xyy .

Now, adding like term, terms having same variable with same degree.

=2xy\sqrt{y}+2xy^2\sqrt{x}=2xyy+2xy2x .

Thus, The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy is  2xy\sqrt{y}+2xy^2\sqrt{x}2xyy+2xy2x

Answer:

4,5,5,7

Step-by-step explanation:

The answer is 4,5,5,7

Answer:

4

−

4

+

8

2

+

8

Step-by-step explanation:

Answer:

it is 20 vecause I say so yeah hey guts

Answer:

240 If its wrong pleas correct me

(x - [3])² + (y- [2])² = 16

Answer:

5.6 days

Step-by-step explanation:

We are given;

Initial Mass; N_o = 25 g

Mass at time(t); N_t = 25/2 = 12.5 (I divide by 2 because we are dealing with half life)

k = 0.1229

Formula is given as;

N_t = N_o•e^(-kt)

Plugging in the relevant values;

12.5 = 25 × e^(-0.1229t)

e^(-0.1229t) = 12.5/25

e^(-0.1229t) = 0.5

(-0.1229t) = In 0.5

-0.1229t = -0.6931

t = -0.6931/-0.1229

t = 5.6 days

[tex]\displaystyle\bf 2^{2x+1}-9\cdot 2^x+4=0 \quad ; \qquad \boxed{ 2^x=t \; ; \; 2^{2x}=t^2} \\\\2t^2-9t+4=0 \\\\D=81-32 =49 \\\\ t_1=\frac{9+7}{4} =4 \\\\ t_2=\frac{9-7}{4} =\frac{1}{2} \\\\1) \ 2^x=4 \Longrightarrow x_1=2 \qquad 2) \ 2^x=2^{-1}\Longrightarrow x_2=-1 \\\\Answer: \boxed{x_1=2 \quad ; \quad x_2=-1}[/tex]

Answer:

[tex]C(n)=30-20n[/tex]

Step-by-step explanation:

Arithmetic sequence given in the question is,

10, -10, -30, -50........

Explicit formula of an Arithmetic sequence is given by,

[tex]C(n)=C(1)+(n-1)d[/tex]

Here, [tex]C_1=[/tex] First term

[tex]n=[/tex] number of terms

[tex]d=[/tex] common difference

From the given sequence,

[tex]C(1)=10[/tex]

[tex]d=-10-10[/tex]

  [tex]=-20[/tex]

Substitute the values in the formula,

[tex]C(n)=10+(n-1)(-20)[/tex]

[tex]C(n)=10-20n+20[/tex]

[tex]C(n)=30-20n[/tex]

Answer:

7.5         30

45         180

Step-by-step explanation:

The given line has x = 1.25 and y = 5.

y/x = 5/1.25 = 4

x is multiplied by 4 to get y since 1.25 * 4 = 5.

That means the equation is

y = 4x

For a proportional function, every value of x must be multiplied by 4 to get y.

x = 7.5

y = 4x = 4(7.5) = 30

7.5          30

We need to find the values for the last line.

11 * 4 = 44

There is no 44

13.75 * 4 = 55

There is no 55.

17.5 * 4 = 70

There is no 70

30 * 4 = 120

There is no 120.

45 * 4 = 180

There is a 180.

45         180

Answer:

7.5         30

45         180

Answer:

-2 0 2 3 this is the domain of the ordered pairs shown in the graph above

Answer:

-25.2

Step-by-step explanation:

by replacing -6 on the place of x we get4.2(-6)=-25.2

Answer:

D

Step-by-step explanation:

because 3x - 12y = 15 has only numbers that are divisible by 3 leaving just one single x term, and the other terms simply reduce their used numbers to still integer numbers (4 and 5).

this makes it easier to be used in the other equation.

Answer:

1: 16

2: 4940

3: 24

4: 25

5: 9

Step-by-step explanation:

A permutation is a method of calculating the number of possible outcomes. It follows the following general formula;

[tex]_nP_r=\frac{n!}{(n-r)!}[/tex]

There (n) is the number of objects, and (r) is the number of objects selected.

1. Arranging 4 pots with different plants in a row

In order to solve this, one needs two pieces of information, the number of objects, and the number of objects selected. One is given the number of objects; (4), but when the problem states "in a row" it never specifies how many plants are in a row. Thus, let one assume that a "row" can have an infinite amount of space, but in this case, only (4) space will be used. Therefore there are (4) objects with (4) objects selected. However, the drawback is that the combination formula doesn't work when the two parameters (n) and (r) are the same. Hence, to solve this special case, one simply multiplies the two numbers to get the answers:

[tex]n*r\\\\=4*4\\\\=16[/tex]

2. Forming a four-digit ATM pin

One is given that there are (4) digits in the ATM pin, this is the number of objects selected. One is also given that number of objects, there are (10) digits including (0). Set up the permutation and solve;

[tex]_nP_r=\frac{n!}{(n-r)!}[/tex]

[tex]_1_0P_4=\frac{10!}{(10-4)!}\\\\=\frac{10!}{6!}\\\\=\frac{10*9*8*7*6*5*4*3*2*1}{6*5*4*3*2*1}\\\\=10*9*8*7\\\\=4940[/tex]

3. Securing a motorcycle with a three-digit combination lock using the numbers (1), (2), (3), and (6).

There are (4) digits to choose from on the lock. But there are (3) numbers that can be selected.

[tex]_4P_3=\frac{4!}{(4-3)!}\\\\=\frac{4!}{1!}\\\\=\frac{4*3*2*1}{1}\\\\=4*3*2*1\\\\=24[/tex]

4. Displaying 3 identical small vases, 1 figure, and a photo frame in a row.

There are (5) objects, and (5) spaces (read problem (1) for an explanation for the objects being put in a row). Thus, this is a special case; multiply the two numbers to get the result;

[tex]n*r\\=5*5\\=25[/tex]

5. 3 girls sitting around a circular table

There are (3) subjects, and (3) spaces in this problem. Apply the same logic applies to a row in this problem. Therefore, this is another special case; multiply the two numbers to get the result;

[tex]n*r\\=3*3\\=9[/tex]

Answer:

the square of hypotenuse rs eqaul to the sum of the square of the legs

Answer:

Answer would be

D: 7

Answer:

See Explanation

Step-by-step explanation:

(For Diagram please find in attachment)

Since DE∥BC

∴ By Basic Proportionality Theorem,

AD/DB  = AE/EC

​ Since it is Given, AD=DB

∴ AE/EC  =1

∴ AE=EC  (Proved)