Answer:
Baguette. :)
Step-by-step explanation:
Answer:
I don't know you lollollollll
can you do 3 pages of work for me?
Answer:
if it is easy i can do it
hope it helps
Answer:
3
Step-by-step explanation:
I will help
An auto insurance company concludes that 30% of policyholders with only collision coverage will have a claim next year, 40% of policyholders with only comprehensive coverage will have a claim next year, and 50% of policyholders with both collision and comprehensive coverage will have a claim next year. Records show 60% of policyholders have collision coverage, 70% have comprehensive coverage, and all policyholders have at least one of these coverages. Calculate the percentage of policyholders expected to have an accident next year.
Answer:
40% of policyholders are expected to have an accident next year
Step-by-step explanation:
Given the data in the question;
P( collision coverage ) = 60% = 0.6
P( comprehensive coverage ) = 70% = 0.7
Now, we make use of the Law of addition of probability, so
P( collision coverage and comprehensive coverage ) = P( collision coverage ) + P( comprehensive coverage ) - P( collision coverage or comprehensive coverage )
P( collision coverage and comprehensive coverage ) = 0.6 + 0.7 - 1
P( collision coverage and comprehensive coverage ) = 0.3
Now,
P( comprehensive coverage only ) = P( comprehensive coverage ) - P( collision coverage and comprehensive coverage )
P( comprehensive coverage only ) = 0.7 - 0.3
P( comprehensive coverage only ) = 0.4
And
P( collision coverage only) = P( collision coverage ) - P( collision coverage and comprehensive coverage )
P( collision coverage only) = 0.6 - 0.3 = 0.3
Next we make use of the Law of total probability;
P( accident ) = [P( accident ║ collision coverage only) × P( collision coverage only)] + [P( accident ║ comprehensive coverage only) × P( comprehensive coverage only)] + [P( accident ║ collision coverage and comprehensive coverage only) × P( collision coverage and comprehensive coverage only)]
so we substitute in our values;
P( accident ) = [ 30% × 0.3 ] + [ 40% × 0.4 ] + [ 50% × 0.3 ]
P( accident ) = [ 0.3 × 0.3 ] + [ 0.4 × 0.4 ] + [ 0.5 × 0.3 ]
P( accident ) = 0.09 + 0.16 + 0.15
P( accident ) = 0.4 or 40%
Therefore, 40% of policyholders are expected to have an accident next year
15-9x 1/2
I’ll give Brainiest
Answer:
-9x/2 + 15/2
Step-by-step explanation:
(15-9x)* 1/2
15(1/2)-9x 1/2
15/2 -9x *1/2
15/2-9x/2
-9x/2 + 15/2
Answer:
21/2 ( SEE IMAGE BELOW)
Step-by-step explanation:
Calculate the product
15- 9/2
Calculate the Differnce
21/2
so the answer is 21/2
A line passes through (1, - 1) and (3, 5). What is the equation of the line in slope-intercept form?
Answer: a+b+c=0 and 3a+5b+c=0
Step-by-step explanation:
If you find a solution to these equations, you will find an equation of your line. Please notice that (a,b,c) defines the same line as (ka,kb,kc) and for any non-zero k, and a=b=c=0 defines no line equation at all. Now you can take a=1 and solve for b and c, or take b=1 and solve for a and c, or take c=1 and solve for a and b, at least one of these will work.
19. Which of the following would best be solved using factoring the difference of squares?
O x^3 + 5x^2 - 9x - 45 = 0
O 3x² + 12x = 8
O x^2 - 25 = 0
O x^2 + 3x – 10 = 0
Please hurry!
Answer:
x² + 3x - 10 = 0
x² - 25 = 0
What is the sum of -2 and -18
Answer:
-2+-18 = -2 - 18= -20
hope that helped
1. Find the equation of variation where a varies jointly as b and c, and a = 36 when b = 3 and c = 4.
1. Find the equation of variation where a varies jointly as b and c, and a = 36 when b = 3 and c = 4.
Solution:-[tex]\sf{a = kbc}[/tex]
[tex]\sf\rightarrow{36= k(3)(4)}[/tex]
[tex]\sf\rightarrow{K= \frac{36}{12}}[/tex]
[tex]\sf\rightarrow{K={\color{magenta}{3}}}[/tex]
Answer:-Therefore, the required equation of variations is a = 3bc.[tex]{\large{——————————————————}}[/tex]
#CarryOnMath⸙
Can someone help 12 points on the line
Answer:
x=6
Step-by-step explanation:
We can write this as a ratio
x 9
---- = --------
10 15
Using cross products
15x = 10*9
15x = 90
Divide by 15
15x/15 = 90/15
x =6
HELP!! Emma made punch with
1
4
How many gallons of ginger ale does she need to add to make a total of 4 gallons of punch?
Part A
Which diagram can Emma use to help find the number of gallons of ginger ale she needs?
O
B.
A.
4 gal
g
g
9
g
1
2
7
8
3
4
g
O
D.
g
g
Part A
Answer: Choice B (upper right corner)Explanation: Simply add the fractions mentioned, plus the g term, and that leads to a total of 4 gallons overall.
=====================
Part B
Answer: Choice A. 7/8 of a gallon (upper left corner)Explanation:
The mixed number 1 & 1/2 converts to the improper fraction 3/2
Adding the fractions gets us to
(3/2) + (7/8) + (3/4)
(12/8) + (7/8) + (6/8)
(12+7+6)/8
25/8
So far, 25/8 of a gallon is accounted for. Add on the g to get (25/8)+g
Set this equal to the 4 gallons we want and solve for g
(25/8)+g = 4
g = 4 - (25/8)
g = (32/8) - (25/8)
g = (32-25)/8
g = 7/8
She needs 7/8 of a gallon of ginger ale
BC=
Round your answer to the nearest hundredth.
Answer:
1.71 = BC
Step-by-step explanation:
take 70 degree as reference angle
using cos rule
cos 70 = adjacent / hypotenuse
0.3420 = BC / 5
0.3420*5 = BC
1.71 = BC
Find the selling price of a $32 item after a 50% markup.
The selling price is $
Answer:
The seelijg price is $48.
Step-by-step explanation:
Markup is the amount a store adds to its cost of an item to come up with the selling price.
store cost + markup = selling price
If the markup on an item is 50%, then the store adds 50% of its cost to its cost to arrive at the selling price.
$32 + 50% of $32 =
= $32 + 0.5 * $32
= $32 + $16
= $48
Answer:
50% of 32 is 16 so it it 16$
20 POINT MATH PROBLEM HELP
Answer:
x=50
Step-by-step explanation:
EFI=HFG (diagonals bisect angles)
125=3x-25
125+25=3x
150=3x
150/3=3x/3
50=x
What is the approximate weight of a baby at the 84th percentile
Answer: 144 pounds and 3 cents to the fourth.
Step-by-step explanation: some guy
5/8 + 3/4 / -2/3- 5/6.
Answer:
-5/16 or -0.3125
Step-by-step explanation:
Answer:
-11/12
Step-by-step explanation:
Fyi you can use the app photo math you just take a pic of the problem and it gives you the answer and explains the steps and it is free.
describe when it is and when it is not necessary to use a common denominator when adding, subtracting, multiplying, and dividing rational expressions.
Step-by-step explanation:
For Adding and Subtraction:
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator).
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.3. Find the new numerator (top number) for each fraction. To find the new numerators for each fraction, compare the denominator of each of the original fractions to the LCD and write down everything different about the LCD in the numerator of the fraction. (you should also consider using the letters "LCD" in the denominator instead of the actual LCD as it will be less tempting to reduce them).
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.3. Find the new numerator (top number) for each fraction. To find the new numerators for each fraction, compare the denominator of each of the original fractions to the LCD and write down everything different about the LCD in the numerator of the fraction. (you should also consider using the letters "LCD" in the denominator instead of the actual LCD as it will be less tempting to reduce them). 4. combine the fraction by adding or subtracting the numerators and keeping the LCD. When subtracting, notice that the subtraction sign is moved into the numerator so it can be distributed later if needed.
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.3. Find the new numerator (top number) for each fraction. To find the new numerators for each fraction, compare the denominator of each of the original fractions to the LCD and write down everything different about the LCD in the numerator of the fraction. (you should also consider using the letters "LCD" in the denominator instead of the actual LCD as it will be less tempting to reduce them). 4. combine the fraction by adding or subtracting the numerators and keeping the LCD. When subtracting, notice that the subtraction sign is moved into the numerator so it can be distributed later if needed. 5. simplify the numerator by distributing and combining like terms.
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.3. Find the new numerator (top number) for each fraction. To find the new numerators for each fraction, compare the denominator of each of the original fractions to the LCD and write down everything different about the LCD in the numerator of the fraction. (you should also consider using the letters "LCD" in the denominator instead of the actual LCD as it will be less tempting to reduce them). 4. combine the fraction by adding or subtracting the numerators and keeping the LCD. When subtracting, notice that the subtraction sign is moved into the numerator so it can be distributed later if needed. 5. simplify the numerator by distributing and combining like terms. 6. Factor the numerator if can and replace the letters "LCD" with the actual LCD.
1. Find the denominator (bottom number) of each fraction to find the LCD (least common denominator). 2. find the LCD.3. Find the new numerator (top number) for each fraction. To find the new numerators for each fraction, compare the denominator of each of the original fractions to the LCD and write down everything different about the LCD in the numerator of the fraction. (you should also consider using the letters "LCD" in the denominator instead of the actual LCD as it will be less tempting to reduce them). 4. combine the fraction by adding or subtracting the numerators and keeping the LCD. When subtracting, notice that the subtraction sign is moved into the numerator so it can be distributed later if needed. 5. simplify the numerator by distributing and combining like terms. 6. Factor the numerator if can and replace the letters "LCD" with the actual LCD. 7. simplify or reduce the rational expression of you can. Remember, to reduce rational expressions, the factors must be exactly the same in both the numerator and the denominator.
To Multiply:
first determine the GCF of the numerator and denominator. Then, regrouping the fractions to make fractions equal to One. Then, multiply any remaining factors.To Divide:
First, rewriting the division as multiplication by the reciprocal of the denominator. The remaining steps are the same for multiplication.9514 1404 393
Answer:
necessary: addition and subtractionnot necessary: multiplication and divisionStep-by-step explanation:
For multiplication and division, the denominator of the result is developed as part of the algorithm for performing these operations on rational expressions. For example, ...
(a/b)(c/d) = (ac)/(bd)
(a/b)/(c/d) = (ad)/(bc)
It is not necessary to make the operands of these operations have a common denominator before the operations are performed. That being said, in some cases, the division operation can be simplified if the operands do have a common denominator or a common numerator:
(a/b)/(c/b) = a/c
(a/b)/(a/c) = c/b
__
If the result of addition or subtraction is to be expressed using a single denominator, then the operands must have a common denominator before they can be combined. That denominator can be developed "on the fly" using a suitable formula for the sum or difference, but it is required, nonetheless.
(a/b) ± (c/d) = (ad ± bc)/(bd)
This formula is equivalent to converting each operand to a common denominator prior to addition/subtraction:
[tex]\dfrac{a}{b}\pm\dfrac{c}{d}=\dfrac{ad}{bd}\pm\dfrac{bc}{bd}=\dfrac{ad\pm bc}{bd}[/tex]
Note that the denominator 'bd' in this case will not be the "least common denominator" if 'b' and 'd' have common factors. Even use of the "least common denominator" is no guarantee that the resulting rational expression will not have factors common to the numerator and denominator.
For example, ...
5/6 - 1/3 = 5/6 -2/6 = 3/6 = 1/2
The least common denominator is 6, but the difference 3/6 can still be reduced to lower terms.
If we were to use the above difference formula, we would get ...
5/6 -1/3 = (15 -6)/18 = 9/18 = 1/2
Zoe prepares some lemonade for the party.
She needs to use of a kilogram of sugar.
Zoe knows that 1 kg is 2.2 pounds.
(a) What is of a kilogram in pounds?
Show a check of your working.
(3)
Use the space below to show clearly how you get your answer.
Answer:
eyeey
Step-by-step explanation:
hehhehehheheuueueuueue
4. A certain bacteria doubles every day. If there are 810 bacteria on day one, how long will it take the bacteria to grow to 206550?
Answer:
255 daysStep-by-step explanation:
810 ÷ 206550 = 255What is the difference between equation and function?
A. All of the options
B. An equation tells us in a clear term the nature of relationship between one variable and the other variable(s), but a function may not be explicit enough
C. An equation and a function is that, for an equation each of the values of independent variable should give a corresponding value of a dependent variable , that is not compulsory tor a function.
D. All equations are functions but not all functions are equations
Answer:
A is the answer........
The function f(x) = { x + 1 is used to complete this Which statements are true of the given function? Check all that apply. table. f(x) 012) --2 -1 1 Of(0) = } f(1) = -1 0 کی ادN Of(2)= 1 1 2 Of(4) = ? 2 2 Na
Answer:
Options (1) and (5)
Step-by-step explanation:
Expression that defines the function is,
[tex]f(x)=\frac{1}{2}x+\frac{3}{2}[/tex]
Option 1
[tex]f(-\frac{1}{2})=\frac{1}{2}(-\frac{1}{2})+\frac{3}{2}[/tex]
[tex]=-\frac{1}{4}+\frac{3}{2}[/tex]
[tex]=-\frac{1}{4}+1+\frac{1}{2}[/tex]
[tex]=1+\frac{1}{4}[/tex]
[tex]=1\frac{1}{4}[/tex]
So, [tex]f(-\frac{1}{2} )=-2[/tex] is false.
Option 2
f(0) = [tex]\frac{1}{2}(0)+\frac{3}{2}[/tex]
= [tex]\frac{3}{2}[/tex]
True.
Option 3
f(1) = [tex]\frac{1}{2}(1)+\frac{3}{2}[/tex]
= [tex]\frac{3+1}{2}[/tex]
= 2
Therefore, f(1) = -1 is false.
Option 4
[tex]f(2)=\frac{1}{2}(2)+\frac{3}{2}[/tex]
[tex]=1+1+\frac{1}{2}[/tex]
[tex]=2\frac{1}{2}[/tex]
Therefore, f(2) = 1 is false.
Option 5
f(4) [tex]=\frac{1}{2}(4)+\frac{3}{2}[/tex]
[tex]=2+\frac{3}{2}[/tex]
[tex]=\frac{4+3}{2}[/tex]
[tex]=\frac{7}{2}[/tex]
True.
Options (1) and (5) are the correct options.
I’ll give brainlist to best answer
Answer:
12.25
Step-by-step explanation:
Expression
x^2 + 2y
x = 2.5
y = 3
x^2 = 6.25
2y = 3*2 = 6
x^2 + 2y = 6.25 + 6
x^2 + 2y = 12.25
Answer:
12.25
Step-by-step explanation:
We find the equation x^2 + 2y when x = 2.5 and y = 3.
We just have to replace x with 2.5 and y with 3 in the equation:
x^2 becomes 2.5^2
2y becomes 2 * 3 (When a variable is next to a number it means multiply)
So we get 2.5^2 + 2 * 3
We first do 2.5^2. 2.5^2 is the same as 2.5 * 2.5, which equals 6.25
Next we do 2 * 3 which equals 6
So it is 6.25 + 6, which is 12.25
I am having a lot of difficulty in solving this question, so please help me..
Answer:
216
Step-by-step explanation:
=>log 36 = -2/3
m
=>36=(m)^-2/3
=>(root(-36))^3=m
=>m=(root(36))^3
=>m=6^3
=>m=216
The vector w=ai+bj is perpendicular to the line ax+by=c and parallel to the line bx−ay=c. It is also true that the acute angle between intersecting lines that do not cross at right angles is the same as the angle determined by vectors that are either normal to the lines or parallel to the lines. Use this information to find the acute angle between the lines below.
2x+5y=4, 7x+3y=8
Answer:
The angle between the liens is 135 degree.
Step-by-step explanation:
Equation of first line
2 x + 5 y = 4 ...... (1)
Equation of second line
7 x + 3 y = 8 ..... (2)
The slope of a line is given by
[tex]m = \frac{- coefficient of x}{coefficient of y}[/tex]
Slope of first line
[tex]m = -\frac {2}{5}[/tex]
Slope of second line
[tex]m'= - \frac{7}{3}[/tex]
The angle between the two lines is given by
[tex]tan\theta = \frac{m- m'}{1 + m m'}\\\\tan\theta = \frac{-\frac{2}{5}+\frac{7}{3}}{1+\frac{2}{5}\times \frac{7}{3}}\\\\tan\theta = -1 \\\\\theta = 135^o[/tex]
1. The curved surface area of a cylinder of height 21cm is
660cm", find its radius. please help me .....
I will give brainliest.
Answer:
21 times 660 and then you will get the answer
Chad has a rope that is 15 yards long. How many pieces of rope measuring 5/7 of a yard can he divide his rope into?
A. 28
B. 21
C. 35
D. 14
Answer:
Chad can divide his rope in 21 pieces. (Answer B)
Step-by-step explanation:
To solve we divide.
15 divided by 5/7 is what we need to know.
When dividing fractions it is the same thing as multiplying by the reciprocal (flipped version of the fraction).
[tex]15[/tex] ÷ [tex]\frac{5}{7}[/tex] = 15 × [tex]\frac{7}{5}[/tex]
[tex]\frac{15}{1}[/tex] × [tex]\frac{7}{5}[/tex] = [tex]\frac{105}{5}[/tex]
[tex]\frac{105}{5}[/tex] = 21
Chad can divide his rope in 21 pieces.
Answer:
21 pieces
Step-by-step explanation:
Divide (5/7 yd / piece) into 15 yds:
15 yds
----------------------- = 21 pieces
(5/7 yd / piece)
Segment [tex]$s_1$[/tex] has endpoints at [tex]$(3+\sqrt{2},5)$[/tex] and[tex]$(4,7)$[/tex]. Segment [tex]$s_2$[/tex] has endpoints at [tex]$(6-\sqrt{2},3)$[/tex] and[tex]$(3,5)$[/tex]. Find the midpoint of the segment with endpoints at the midpoints of [tex]$s_1$[/tex] and [tex]$s_2$[/tex]. Express your answer as [tex]$(a,b)$[/tex].
Answer:
The midpoint of the segment with endpoints at the midpoints of s1 and s2 is (4,5).
Step-by-step explanation:
Midpoint of a segment:
The coordinates of the midpoint of a segment are the mean of the coordinates of the endpoints of the segment.
Midpoint of s1:
Using the endpoints given in the exercise.
[tex]x = \frac{3 + \sqrt{2} + 4}{2} = \frac{7 + \sqrt{2}}{2}[/tex]
[tex]y = \frac{5 + 7}{2} = \frac{12}{2} = 6[/tex]
Thus:
[tex]M_{s1} = (\frac{7 + \sqrt{2}}{2},6)[/tex]
Midpoint of s2:
[tex]x = \frac{6 - \sqrt{2} + 3}{2} = \frac{9 - \sqrt{2}}{2}[/tex]
[tex]y = \frac{3 + 5}{2} = \frac{8}{2} = 4[/tex]
Thus:
[tex]M_{s2} = (\frac{9 - \sqrt{2}}{2}, 4)[/tex]
Find the midpoint of the segment with endpoints at the midpoints of s1 and s2.
Now the midpoint of the segment with endpoints [tex]M_{s1}[/tex] and [tex]M_{s2}[/tex]. So
[tex]x = \frac{\frac{7 + \sqrt{2}}{2} + \frac{9 - \sqrt{2}}{2}}{2} = \frac{16}{4} = 4[/tex]
[tex]y = \frac{6 + 4}{2} = \frac{10}{2} = 5[/tex]
The midpoint of the segment with endpoints at the midpoints of s1 and s2 is (4,5).
The volume of a cone with a diameter of 9 and a height of 120
Answer: 15268.1403 unit^3 (unit: cm,m,mm)
Step-by-step explanation:
volume of a cone= 1/2*pi*r^2*h
r= radius (unit: cm,m,mm)
h= perpendicular height (unit: cm,m,mm)
volume= 1/2*pi* (9)^2* 120 = 15268.1403 unit^3
Write the equation of the line in Point-Slope Form given the information below. Slope =−1/5 Y-Intercept =−3 Point-Slope Form:
Answer:
[tex]y - 0= \frac{ - 1}{5}( x + 15)[/tex]
which figure shows the radius of circle O?
Answer:
D
Step-by-step explanation:
The radius of a circle refers to a segment connecting the center of the circle to the circumference of the circle. This can be seen in selection D), as a segment connects the center of the circle (O) to the circumference or outer edge of the circle.
FLIGHT TO TOKYO TAKE 2 HOURS 20 MINUTES U ARRIVE AT 4:15PM WHICH TIME DID HE SET OFF
Answer: 1:55 PM
Step-by-step explanation:
Turn 4:15 to 24-hr clock system which is 1615hrs
16:15 - 02:20 = 1355hrs
Refer to the Lincolnville School District bus data. Information provided by manufacturers of school buses suggests the mean maintenance cost per year is $4,400 per bus with a standard deviation of $1,000. Compute the mean maintenance cost for the Lincolnville buses. Does the Lincolnville data seem to be in line with that reported by the manufacturer? Specifically, what is the probability of Lincolnville’s mean annual maintenance cost, or greater, given the manufacturer’s data?
Answer:
Step-by-step explanation:
Add all of the Maintenance costs up, divide by 80. (the number of costs).
Excel formula =SUM(F2:F81) 364151.00/80 = 4551.8875 Rounded to 4552 is your answer.