The water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.
The given parameters;
Pressure on the 13 th floor, P₁ = 35 PSIDistance between each floor, d = 10 ftThe vertical pressure of the water is calculated as follows;
[tex]P = \rho gh\\\\\frac{P}{h} = \rho g\\\\\frac{P}{h} = k\\\\\frac{P_1}{h_1} = \frac{P_2}{h_2} \\\\[/tex]
The vertical height of the first floor from the 13th floor = 130 ft
The vertical height of the 13 ft floor = 10 ft
[tex]P_1 = \frac{P_2 h_1}{h_2} \\\\P_1 = \frac{35 \times 130}{10} \\\\P_1 = 455 \ PSI[/tex]
Thus, the water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.
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A bullet of mass 6.00 gg is fired horizontally into a wooden block of mass 1.20 kgkg resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.190. The bullet remains embedded in the block, which is observed to slide a distance 0.270 mm along the surface before stopping.
(a) What was teh initial speed of the bullet?(b) What kind of collision took place between the bullet and the block? Explain your answer comparing the values of the kinetic energy before and after the collision.(c) Calculate the impulse of the block from the moment just after the impact to his final position. Analyze the result.
Answer:
A 5.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.230 m along the surface before stopping.
Explanation:
Please help! Question is attached.
Answer:
a. 6
b. 6 m/s²
c. 300 m to the right
d. 30 secs
Explanation:
slope = rise /run
60-0/10-0
= 6
b. slope = acceleration = 6 m/s²
c. d=ut+1/2at²
t=10 (segment A last for 10 secs)
u - initial velocity = 0
so d = 0(10)+1/2*6*10²
=300 m
An object is at rest. There are several forces acting on the object, but the net force is zero. If all the
forces acting on the object were to suddenly double in size, would the object start moving? Why or why not?
Answer:
no
Explanation:
because the heaver an object the harder it is to move s the force will not be able to move it
weight of 1 kg becomes 1/6 on moon. If radius of moon is 1.76×10^6 m, then the mass of moon will be
Answer:
7.65 x 10^22kg
sorry if im wrong!
help plz
Stop and go traffic means a lot of opportunities for acceleration. This assignment looks at a typical experience of a car in typical rush hour traffic. Calculate the different accelerations from the graph, interpret what your answers mean and show you really understand acceleration.
A car traveled through rush hour traffic in a city. There was a lot of starting and stopping. The graph below shows the motion of the car for a 16 second interval of time.
Explain what is going on between point B and C in terms of velocity and acceleration.
Velocity:
Acceleration:
help -----------------------------------------
Answer:
H,G,E,D,C,B,A,I,F
Explanation:
F is an ignious intrusion and I cross cuts H to A so it must be newer.
calculate the density, in g/l, of sf6 gas at 27°c and 0.500 atm pressure.
The density of the SF₆ gas at the given pressure and temperature is 2.96 g/l.
The given parameters:
temperature of the SF₆ gas, T = 27 ⁰C = 273 + 27 = 300 Kpressure of the SF₆ gas, P = 0.5 atmThe molecular mass of the SF₆ gas is calculated as follows;
M of SF₆ = 32 + (6 x 19) = 146 g/mol
The density of the SF₆ gas is calculated by applying ideal gas law as follows;
[tex]PV = nRT\\\\PV = \frac{m}{M} RT\\\\PM = \frac{m}{V} RT\\\\PM = \rho RT\\\\\rho = \frac{PM}{RT}[/tex]
where;
[tex]\rho[/tex] is the density of the gasR is the ideal gas constant = 0.0821 L.atm/mol.K[tex]\rho = \frac{0.5 \times 146}{0.0821 \times 300} \\\\\rho = 2.96 \ g/l[/tex]
Thus, the density of the SF₆ gas at the given pressure and temperature is 2.96 g/l.
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what is the net force on a car moving in a straight line with a constant velocity
Answer:
For example, when a car travels at a constant speed, the driving force from the engine is balanced by resistive forces such as air resistance and friction in the car's moving parts. The resultant force on the car is zero.
Explanation:
hope this helps
Answer:
zero
Explanation:
The acceleration of the car is zero, and and in this case the velocity is also zero. When your car is moving at constant velocity down a street, the net force must also be zero, according to Newton's First Law.
helppp mee pllleasse
Answer:
up swelling moves water horizontally
Gold density = 19.30,
Silver density = 10.49,
Lead density = 11.34.
They have the same mass but are made of different metals. Each one is lowered into a beaker of water. Use the data above to decide which one will cause the biggest rise in water level.
A) Gold
B) Silver
C) Lead
D) All will cause the same rise in water level
Density of water=1g/cm^3
Now all metals has greater mass in comparison to water.
Higher the mass higher the rise[tex]\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}[/tex]
[tex]\\ \sf\longmapsto Density\propto Mass[/tex]
Higher the density higher the massGold has higher mass hence it will cause the biggest rise.
Option A
Silver will cause biggest rise in water
What is density ?Density of an object is a measure of its mass per unit volume.
density = mass / volume
since all have same mass , so metal which have higher volume will cause the biggest rise in water level .
since , density is inversely proportional to volume , hence material having low density will have higher volume
hence , silver will cause biggest rise in water
correct option B) Silver
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Evidence of liquid water in mars' distant past suggests that it had a substantial atmosphere compared to what it has presently. What happened to its water vapor?.
Answer:
The atmosphere has frozen out into the polar ice caps and permafrost as Mars has cooled.
Explanation: Good luck box BrokenTag27
How to find average velocity on a graph.
Answer:
Answer is below….
Explanation:
The velocity is represented by the slope of a position-time graph. The faster the motion changes, the steeper the slope. The change in position divided by the corresponding change in time may be used to compute average velocity from a position-time graph.
_________________________________________________________
(hope this helps can I pls have brainlist (crown)☺️
How to find velocity from acceleration time graph.
Answer:
We can only find the change in velocity by the area under the acceleration time graph by calculating the area under the curve to the given time. Then by the formula of the difference in the final and initial velocity you can find the final velocity of the object in the given time period.
A 2 kg mass starts from rest and slides down an inclined plane 4 m long in 1 second. What net force is acting on the mass along the incline *.
The net force acting on the mass along the incline is equal to 16 Newton.
Given the following data:
Mass = 2 kgDistance = 4 metersTime = 1 secondsTo determine the net force acting on the mass along the incline:
First of all, we would find the acceleration of the mass by using the second equation of motion:
[tex]S = ut+ \frac{1}{2} at^2\\\\4 = 0(1) + \frac{1}{2} a(1)^2\\\\4=\frac{a}{2}\\\\a=2\times 4[/tex]
Acceleration, a = 8 [tex]m/s^2[/tex]
For the net force, we would apply Newton's Second Law of Motion:
[tex]F_{net} = mass \times acceleration\\\\F_{net} =2 \times 8[/tex]
Net force = 16 Newton.
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Why does the blue force have a negative sign?
-20 N
50 N
Because 50 is smaller than 20
Because 20 is smaller than 50
Because it is pointing to the left
Because it is blue
A narrow slit is illuminated with sodium yellow light of wavelength 598 nm. If the central maximum extends to latex: \pm30^\circ± 30 â, how wide is the slit?.
Answer:
because of the gravity of the earth
Question #4
What is the charge on Can 2 at the moment
shown in panel B?
Question #5
What is the charge on the ball at the
moment shown in panel B?
A. Same as Van de Graaff
B. Opposite of Van de Graaff
C. Neutral
A. Same as Van de Graaff
B. Opposite of Van de Graaff
C. Neutral
Answer:
Q4
A
Q5
B
Explanation:
BRAINLIEAST IW8W9 HAHAH YAN NA PO TALAGA
A boulder of mass 10 kg rolls over a cliff and reaches the beach below with a velocity of 15 m/s. Find:
a. the kinetic energy of the boulder as it lands;
b. the potential energy of the boulder when it was at the top of the cliff
c. the height of the cliff.
Answer:
formular kinetic energy=1/2 ×vWhich wave has the longest wavelength?
Answer:
A
Explanation:
Why are people so rude???
Answer:
It could be low self-esteem
Explanation:
There probably insecure have problems and issues of their own could be that were abused growing up and weren’t treated right who knows.
Which object is moving faster?
A
Answer:
A
Explanation:
Answer:
A
Explanation:
Propose a hypothesis for how the position of the ball will affect the amount of its gravitational pull energy
throwing a ball up initially has a lot of kinetic energy because it is moving upwards ( kinetic energy is energy which a body possesses by virtue of being in motion.) this all then get converted to gravitational potential energy, and for a moment it is stationary before it begins to fall again. by the time it has returned again, all the gravitational potential energy has turned back into kinetic.
Can someone help me with the entire magnetism gizmo. I can’t get on gizmo, but it has to be done
Answer:
sure how can i help my g gggg
if the velocity of gas molecules is doubled the its kinetic energy will be
Answer: Quadrupled
Explanation:
Because when it’s doubled they are going to make another pair so 2+2=4
The half life of carbon-14 is 5730 years. How old is a bone if it presently contains 0.3125 g of carbon-14, but it was estimated to have originally contained 80 g of carbon-14?
The age of the bone is 45840 years.
We'll begin by calculating the number of half-lives that has elapsed.
Amount remaining (N) = 0.3125 g
Initial amount (N₀) = 80 g
Number of half-lives (n) =?N × 2ⁿ = N₀
0.3125 × 2ⁿ = 80
Divide both side by 0.3125
2ⁿ = 80 / 0.3125
2ⁿ = 256
2ⁿ = 2⁸
n = 8Thus, 8 half-lives has elapsed
Finally, we shall determine the age of the bone.
Half-life (t½) = 5730 years
Number of half-lives (n) = 8
Time (t) =?t = n × t½
t = 8 × 5730
t = 45840 yearsTherefore, the age of the bone is 45840 years.
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What is the mass (in kg) of an object which accelerates at 3 m/s^2 when acted upon by a 15 N force?
[tex]\purple{\longrightarrow \sf Force = Mass \times Acceleration}[/tex]
[tex] \longrightarrow \sf Mass = \dfrac{Force}{Acceleration }[/tex]
[tex]\longrightarrow \sf Mass = \dfrac{15}{3}[/tex]
[tex]\longrightarrow \sf Mass = \cancel{\dfrac{15}{3}} [/tex]
[tex]\longrightarrow {\pink{\underline{\underline{\sf{ Mass = 5 \: Kg }}}}}[/tex]
Henceforth :-
The mass of the object is 5 kg.▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
The magnitude of vector A is 2.5 m and is directed towards east. The magnitude and direction of A /2 will be
The magnitude and direction of half of the given vector A is 1.25 m east.
The given parameters;
magnitude of vector A = 2.5 m eastA vector can be described with both magnitude and direction. The magnitude of the vector is the scalar or numeric representation of the vector.
When the scalar representation has direction, we term the quantity a vector quantity.
The magnitude of half of the given vector is calculated as follows;
[tex]\frac{A}{2} = \frac{2.5 \ m}{2} = 1.25 \ m\ east[/tex]
Thus, the magnitude and direction of half of the given vector A is 1.25 m east.
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Dave and Alex push on opposite ends of a car that has a mass of 875 kg. Dave pushes the car to the right with a force of 250 N, and Alex pushes to the
left with a force of 315 N. Assume there is no friction.
What is the net force on the car in the x-direction? Help meee please
The net force acting on the car is 65 N to the left
The net force acting on an object is simply defined as the resultant force acting on the object.
From the question given, we obtained the following data:
Force applied to the right (Fᵣ) = 250 NForce applied to the left (Fₗ) = 315 NNet force (Fₙ) =?The net force acting on the car can be obtained as follow:
Fₙ = Fₗ – Fᵣ
Fₙ = 315 – 250
Fₙ = 65 N to the leftTherefore, the net force acting on the car is 65 N to the left
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Since there is no friction, the net force on the car in the x - direction will be 65 Newtons
Given that Dave and Alex push on opposite ends of a car that has a mass of 875 kg.
Dave pushes the car to the right with a force of 250 N, which is positive direction and Alex pushes to the left with a force of 315 N which is negative direction. Since there is no friction, only the horizontal forces will be considered.
To calculate the net force on the car in the x-direction, we will find the difference between the two forces because of their directions are opposite to each other.
Net force = 315 - 250
Net force = 65 Newtons
Therefore, the net force on the car in the x - direction will be 65 Newtons
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A 0.5kg ball falls from a building that Is 50m high. how much kinetic energy will it have when it has fallen half way to the ground?
What type of machine is used to measure the location of an earthquake epicenter.
Answer:
Seismometer
Explanation:
Seismometer measures Earth quake epicenter while seismograph measures Earth quake size