Answer:
2.8 L
Explanation:
From the question given above, the following data were obtained:
Number of mole (n) = 0.109 mole
Pressure (P) = 0.98 atm
Temperature (T) = 307 K
Gas constant (R) = 0.0821 atm.L/Kmol
Volume (V) =?
The volume of the helium gas can be obtained by using the ideal gas equation as follow:
PV = nRT
0.98 × V = 0.109 × 0.0821 × 307
0.98 × V = 2.7473123
Divide both side by 0.98
V = 2.7473123 / 0.98
V = 2.8 L
Thus, the volume of the helium gas is 2.8 L.
How many O2 molecules react with 47 CH4 molecules according to the preceding equation CH4 + O2 → CO2 + H2O
if slowing down is the response to seeing a blinking yellow light is it conditioned or unconditioned?
Answer:
Conditioned
Explanation:
Naturally, you do not slow down when you see a yellow light. That response is learned, therefore it is a conditioned response.
1. When a solution of an acid contains larger amount of acid, it is said to be
Answer:
highly concentrated solution of acid
What are the steps for writing the formula for an ionic compound? Naming an ionic compound?
Answer:
i hope it will help you
Explanation:
To find the formula of an ionic compound, first identify the cation and write down its symbol and charge. Then, identify the anion and write down its symbol and charge. Finally, combine the two ions to form an electrically neutral compound.
I am doing a lab and I am not sure how to calculate the concentration of the chemical formulas used in the lab. Would I need to use the 15ml and add it to the 10 ml of the first solution to find the concentration. Thank you
Answer:
C = m/V
Explanation:
In order to calculate the concentration of a mixture you would need to use the formula for concentration, which is the following...
C = m/V
In this formula C is the concentration, m is the mass of the compound that is being added and mixed into the solution, and V is the total volume of the mixture. The mass of m is in terms of number of moles. Therefore, we would need more information in order to calculate the actual concentration of the mixture that you are trying to find in this scenario. Using the formula above should be enough using the values that you have in your actual workbook.
Which of the following make up an atom of gold? Select all that apply.
a
photons
b
electrons
c
neutrinos
d
protons
e
neutrons
Answer:
b, d, e
Explanation:
An atom is made up of electrons, protons and neutrons. Gold is an atom thus has the above particles.
Read the temperatures shown to the nearest 0.5°C.
I’ll mark you as brainlister
Answer:
The temperature to the nearest 0.5°C is 98.5°C
2002040_MIJ COMP SCI 1_SEM 1 CR_PY
The three main types of scientific investigations are descriptive, comparative, and experimental. Which components
are included in all three types of investigations?
a scientific question
an independent variable
a dependent variable
a procedure
a control group
a conclusion
Answer:
a scientific question
Procedure
Conclusion.
Explanation:
Scientific investigation is usually carried out to explain and give answers to natural phenomenon. Now, this scientific investigation is performed through the three main types as described in the question.
With that being said, the most common parts of all types of investigation are :
1. Scientific question: In this stage, questions are usually asked on the basis of observation made which could be answered.
2. Procedure: In this stage, the dimension of the steps are followed to answer and test the scientific question.
3. Conclusion: This is the primary aim that we check when done with our sample values
When naming acids such as HCl, HBr, and HI, the prefix "hydro-" is added and the "ine" of the element is replaced with which of the following suffixes before the word "acid" is added?
Select one:
a. "-ic"
b. "-ate"
c. "-ite"
d. "-ide"
Answer:
a. "-ic"
Explanation:
The correct answer is a. "-ic".
For example:
For HCl, the name is Hydrochloric acid. As you can see, the suffix "-ine" of the element (originally chlorine) is changed to "-ic".Following the same logic, the name for HBr is Hydrobromic acid; and the name for HI is Hydroiodic acid.