What type of function is represented by the table of values below?
х
1
2
3
4
5
у
2
4
8
16
32
A. exponential
B. quadratic
C. cubic
D. linear
Answers
Answer:
Step-by-step explanation:
This is exponential. I'll show you how I found it. After many attempts at other types of functions, I realized the points were either forming a quadratic or an exponential. Definitely not a line.
the standard form of an exponential function is
[tex]y=a(b)^x[/tex] so we sub in coordinates from the table to determine what the equation is and then test it on another set of points to see if it works. Using the first coordinate of (1, 2):
[tex]2=a(b)^1[/tex] so
[tex]a=\frac{2}{b}[/tex] . The next coordinate is (2, 4), so:
[tex]4=\frac{2}{b}(b)^2[/tex] which simplifies down to
4 = 2b so
b = 2. Now we plug in 2 for b and solve for a:
a = 2/2 which is 1. So the equation, if this is exponential, is
[tex]y=1(2)^x[/tex] Let's test the next point in line and see if it works, (3, 8):
[tex]8?=?1(2)^3[/tex] and yes, 8 is equal to 2 cubed. And the next point says that 16 should equal 2 to the 4th, and it does, as well. So this is exponential...growth to be specific.
Related Questions
Math help please I will give brainlist if correct
Answers
Answer:
A=48
B=25
C=44
D=67
im stumped by e srry
help me please help me plz help me plz
Answers
2. 3, 1 and then 2
3.a
4. b
Si: Tg θ =√2 ∧ θ es agudo √7 Calcular: A = 3(Sen θ + Cos θ) - √7
Answers
Answer:
[tex]A \approx 1.488[/tex]
Step-by-step explanation:
Por definición de razones trigonométricas, tenemos las siguientes identidades:
[tex]\tan \theta = \frac{y}{x} = \sqrt{2}[/tex] (1)
[tex]\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}[/tex] (2)
[tex]\cos \theta = \frac{x}{\sqrt{x^{2}+y^{2}}}[/tex] (3)
Si [tex]\theta[/tex] es agudo, entonces [tex]x, y > 0[/tex].
De (1), suponemos [tex]x = 1[/tex] que [tex]y = \sqrt{2}[/tex], entonces los valores de las funciones seno y coseno:
[tex]\sin \theta = \frac{\sqrt{2}}{\sqrt{5}} = \sqrt{\frac{2}{5} }[/tex]
[tex]\sin \theta = \frac{\sqrt{10}}{5 }[/tex]
[tex]\cos \theta = \sqrt{\frac{1}{5} }[/tex]
[tex]\cos \theta = \frac{\sqrt{5}}{5}[/tex]
Por último, calculemos [tex]A[/tex]:
[tex]A = 3\cdot \left(\frac{\sqrt{10}}{5} + \frac{\sqrt{5}}{5} \right) - \sqrt{7}[/tex]
[tex]A \approx 1.488[/tex]
A) m + n
B) 0
C) m - 1
D) -(m+n)
Answers
Answer:
D
Step-by-step explanation:
Lsh=rhs
U solve using algebra
Question 2 of 10
A rectangle's width is 5 feet less than its length. Write a quadratic function
that expresses the rectangle's area in terms of its length.
O A. A(1) = lw
B. A(1)=12 + 51
C. All) = w(w+5)
O D. All) = 12 - 51
A rectangle's width is 5 feet less than its length. Write a quadratic function
that expresses the rectangle's area in terms of its length.
O A. A(1) = lw
B. A(1)=12 + 51
C. All) = w(w+5)
O D. All) = 12 - 51
Answers
Find the area and the perimeter of this square
2√3x
Answers
The perimeter of a square is equal to 4 times the side length.
=4
P
=
4
s
where
P
is the perimeter and
s
is the side length of the square.
If the side length of the square is 3−2
3
x
−
2
units, then let =3−2
s
=
3
x
−
2
The perimeter would be:
=4(3−2)
P
=
4
(
3
x
−
2
)
=4(3)−4(2)
P
=
4
(
3
x
)
−
4
(
2
)
=12−8
P
=
12
x
−
8
Therefore the perimeter of the square is: 12−8
12
x
−
8
units.
Regards,
. ℎ
A
a
r
o
n
M
.
C
h
a
o
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Profile photo for Arturo Ordonez-Hernandez
Arturo Ordonez-Hernandez, Associate Programmer/Analyst at Weber State University (2018-present)
Answered March 8
A square is an equilateral rectangle.
So, we know that, for a rectangle,
=2+2
P
=
2
l
+
2
w
For a square,
=
l
=
w
so,
=4=4
P
=
4
l
=
4
w
Therefore,
=4(3−2)
P
=
4
(
3
x
−
2
)
=12−4
P
=
12
x
−
4
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Profile photo for Len Fyfe
Len Fyfe, B.Ed. Mathematics & Physics, Chemistry, Maths, and Computer Science, Lakehead University (2005)
Answered March 4
side length is 3x-2
each of the four sides is the same length
P = 4(3x-2) factored form
P = 12x - 8 expanded form
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Answers
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Hehehejdjkskjsknssnnsnajsbsb
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Answers
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Answers
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Answers
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Answers
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Answers
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Answers
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Step-by-step explanation:
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ED and BA
Answer:
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