what type of energy transfer occurs when: warm ocean water carries heat from the equator toward the poles


A- Radiation

B- Convection

C- Conduction

Answers

Answer 1

Answer:

radiation

Explanation:


Related Questions

How dose the Sum Of Forces help you

Answers

Answer:

The purpose of adding force vectors is to determine the net force acting upon an object. In the above case, the net force (vector sum of all the forces) is 0 Newton. ... We would say that the object is at equilibrium. Any object upon which all the forces are balanced (Fnet = 0 N) is said to be at equilibrium.

Explanation:

hope that helps you

A ball is thro.d hit the grouvelocity)?

Answers

Answer:

The velocity of the ball is 3.52 m/s.

Explanation:

A projectile is any object that moves under the influence of gravity and momentum only. Examples are; a thrown ball, a fired bullet, a kicked ball, thrown javelin, etc.

Given that the ball was thrown vertically upward on the top of a skyscraper of  height 61.9 m. So that the velocity can be determined by;

      u = [tex]\sqrt{\frac{2H}{g} }[/tex]

Where: u is the velocity of the object, H is the height and g is the gravitational force on the object. Given that: H = 61.9 m and g = 10 m/[tex]s^{2}[/tex], then;

 u = [tex]\sqrt{\frac{2*61.9}{10} }[/tex]

   = [tex]\sqrt{\frac{123.8}{10} }[/tex]

u  = 3.5185

The velocity of the ball is 3.52 m/s.

A 385-g tile hangs from one end of a string that goes over a pulley with a moment of inertia of 0.0125 kg ⋅ m2 and a radius of 15.0 cm. A mass of 710 g hangs from the other end of the string. When the tiles are released, the larger one accelerates downward while the lighter one accelerates upward. The pulley has no friction in its axle and turns without the string slipping. What is the tension in the string on the side of the 710-g tile?

Answers

Answer:

the tension in the string is 5.59 N

Explanation:

Here ,

m_1 = 0.385 Kg

m_2 = 0.710 Kg

Using second law of motion ,

a = F_net / effective mass

a = (0.710- 0.385)×9.8/(0.710 + 0.385 + 0.0125/0.15^2)

a = 1.93 m/s^2

Now , let tension be T ,

then,

mg-T=ma

0.710×g - T = 0.710×1.93

T = 5.59 N

the tension in the string is 5.59 N

A large truck and a small car are moving at the same speed. The truck has a greater kinetic energy because its _________ is greater

Answers

Answer:

The answer is mass .

Explanation:

The kinetic energy formula is :

[tex]k.e = \frac{1}{2} m {v}^{2} [/tex]

So if the mass is higher, the kinetic energy gained is higher .

If a large truck and a small car are moving at the same speed. The truck has greater kinetic energy because its mass is greater, as the kinetic energy of a body depends on the mass as well as the speed of the object.

What is mechanical energy?

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.

The kinetic energy of the Truck is given by the expression,

K.E= 1/2*m*v²

Where K.E is the kinetic energy of the object

m is the mass of the truck

v is the velocity of the truck

Since the speed is the same for both cars and the truck has greater kinetic energy because its mass is greater.

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A proton starts from rest, and moves 1 meter through a constant electric field. The potential difference between its starting and ending points is 500 V. How fast is the proton moving at the end? How large is the electric field? How long does it take the proton to complete its journey? [Late clarification: since the field is accelerating the particle from rest, you can assume that the direction of the particle's motion is parallel to the field.]

Answers

Answer:

E = - 500 V / m,  v = 30.95 10⁴ m / s   and    t = 6.46 10⁻⁶ s

 

Explanation:

For this problem we use the relation

           ΔU = - E s

           E = -ΔU / s

           E = - 500/1

           E = - 500 V / m

Now we can look for the proton approach

           F = q E

let's use Newton's second law

           F = m a

           a = F / m

           a = q E / m

           

Now let's use kinematics relations, where the proton starts from the rest

v₀ = 0

           v² = v₀² + 2 a x

           v = √2 q E / m x

           v = √ (2 1.6 10⁻¹⁹ 500 / 1.67 10⁻²⁷  1)

           v = √ (958.08 108)

           v = 30.95 10⁴ m / s

for time let's use the equation

          x = v₀ t + ½ to t2

          t = √2x / a

          t = √ (2x m / qE)

          t = √ (2 1 1.67 10⁻²⁷ / (1.6 10⁻¹⁹ 500))

          t = √ (0.004175 10⁻⁸)

          t = 0.0646 10⁻⁴ s

          t = 6.46 10⁻⁶ s

PLS ANSWER WILL GIVE BRAINLIEST
An elevator with a person inside weighs a total of 24,450 Newtons. an elevator that rises 12 meters in 30 seconds. How much power is needed for the elevator trip?

Answers

Answer:

9780 W

Explanation:

Power: This can be defined as the rate at which work is done. The S.I unit of power is Watt (W).

From the question,

P = W/t....................... Equation 1

Where P = power, W = work, t = time.

But,

W = F×d.............. Equation 2

Where F = force, d = distance.

Substitute equation 2 into equation 1

P = (F×d)/t................. Equation 3

Given: F = 24450 N, d = 12 m, t = 30 s.

Substitute these vales into equation 3

P = (24450×12)/30

P = 9780 W.

Hence the power needed for the elevator trip = 9780 W

Answer:

9,780Watts

Explanation:

Power is defined as the rate of workdone with respect to time.

The formula for calculating power P needed by the eleveator is expressed as;

Power = [tex]\frac{workdone}{time}[/tex]

Since Workdone = Force*distance then;

[tex]Power = \frac{force * distance}{time}[/tex]

Given the weight of elevator = 24,450Newtons

distance moved by the elevator = 12m

time taken = 12seconds.

Substituting this values in the formula given will give;

[tex]Power = \frac{24,450*12}{30} \\Power = \frac{293,400}{30} \\Power = 9,780Watts\ or\ 9.78kW[/tex]

The amount of power needed for the elevator trip is 9,780Watts

D’andre expends 120W of power in moving a couch 15 meters in 5 seconds. How much force does he exert?

Answers

Answer:

40N

Explanation:

What kind of lens is found in both a magnifying glass and a microscope

Answers

I found this on google hope it’s helps and can I have brainless question

Answer:

convex lens

Explanation:

Which of the choices is not a statement or direct application of the second law of thermodynamics? There are no 100% efficient heat engines. Heat energy naturally transfers from a high temperature substance to a low temperature substance. The change in internal energy of a system can be found by combining the heat energy added to a system minus the work done by the system. All natural processes tend toward states of increased entropy.

Answers

Answer:

Explanation:

Heat energy naturally transfers from a high temperature substance to a low temperature substance.

It  is not a statement or direct application of the second law of thermodynamics.

The change in internal energy of a system can be found by combining the heat energy added to a system minus the work done by the system.

It  is not a statement or direct application of the second law of thermodynamics. This statement is in accordance with first law of thermodynamics.

All the other two statements are in accordance with second law of thermodynamics.

The statement B is not a statement or direct application of the second law of thermodynamics.

Statements given to us:

(a.) There are no 100% efficient heat engines.

(b.) Heat energy naturally transfers from a high temperature substance to a low temperature substance.

(c.) The change in internal energy of a system can be found by combining the heat energy added to a system minus the work done by the system.

(d.) All natural processes tend toward states of increased entropy.

According to the Second Law of Thermodynamics:

heat transfer occurs spontaneously only from higher to lower temperature bodies.Entropy of the entire universe, as an isolated system, will always increase over time. The changes in the entropy in the universe can never be negative.

So, according to the above points statement B is not a statement or direct application of the second law of thermodynamics.

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Jamal has a fan that plugs into the wall. When Jamal plugs in the fan and turns it on, the blades spin and make the air around them move.


Jamal's fan uses _______ energy to cause motion.
A.
electrical
B.
light
C.
sound
D.
heat

Answers

The answer is A,electrical energy
A because when he is plugging it it is using electrical energy to move the fan

If you run the simulation a few times, you should see that for this particular pair of block and disc the block's position has the same numerical value as the disc's angular position, and the block's velocity has the same numerical value as the disc's angular velocity. Which of the following pairs of quantities must also have the same numerical values for the block and disc (assuming we use standard meter-kilogram-second units)? Select all that apply.

a. The work done by the force on the block and the work done by the torque on the disc.
b. The acceleration of the block and the angular acceleration of the disc.
c. The mass of the block and the mass of the disc.
d. The translational kinetic energy of the block and the rotational kinetic energy of the disc.
e. The momentum of the block and the angular momentum of the disc

Answers

Explanation:

C) is incorrect.  The mass is equivalent to the moment of inertia in an angular formula.

The others appear all correct.

T * theta = F * r * theta = F * (r theta) = fx = work

This is the only one that needed explanation.  The others should be obvious.

A professor sits at rest on a stool that can rotate without friction. The rotational inertia of the professor-stool system is 4.1 kg · m2 . A student tosses a 1.5-kg mass with a speed of 2.7 m/s to the professor, who catches it at a distance of 0.40 m from the axis of rotation. What is the resulting angular speed of the professor and the stool? (Assume that when the professor catches the mass, their arm is extended along a line radially outward from the axis of rotation, and the velocity of the mass is perpendicular to that line.)

Answers

Answer:

[tex]\omega=0.37 [rad/s][/tex]  

Explanation:

We can use the conservation of the angular momentum.

[tex]L=mvR[/tex]

[tex]I\omega=mvR[/tex]

Now the Inertia is I(professor_stool) plus mR², that is the momentum inertia of a hoop about central axis.

So we will have:

[tex](I_{proffesor - stool}+mR^{2})\omega=mvR[/tex]

Now, we just need to solve it for ω.

[tex]\omega=\frac{mvR}{I_{proffesor-stool}+mR^{2}}[/tex]

[tex]\omega=\frac{1.5*2.7*0.4}{4.1+1.5*0.4^{2}}[/tex]      

[tex]\omega=0.37 [rad/s][/tex]  

I hope it helps you!

descibe a transferwave

Answers

Answer: I think you meant transverse wave. A transverse wave is a moving wave whose oscillations are perpendicular to the direction of the wave or path of propagation. A simple example is given by the waves that can be created on a horizontal length of string by anchoring one end and moving the other end up and down.

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(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)

An insulating plastic rod is charged by rubbing it with a wool cloth, and then brought to an initially neutral conducting metallic sphere sitting on an insulating stand. The rod touches the sphere for a few seconds, and then is separated from the sphere by a small distance. After the rod is separated, the rod:_____
A) is repelled by the sphere.
B) is attracted to the sphere.
C) feels no force due to the sphere.

Answers

Answer:

A) is repelled by the sphere.

Explanation:

When a charged insulated rod is touched with an insulated conducting sphere , some  charge on the rod gets transferred to the sphere . So they become similarly charged . We all know that there is repulsion when two similarly charged object are brought near to each other . Hence here too there will be repulsion between the rod and the sphere when the rod is brought near the sphere.

A mass weighting 48 lbs stretches a spring 6 inches. The mass is in a medium that exerts a viscous resistance of 27 lbs when the mass has a velocity of 6 ft/sec. Suppose the object is displaced an additional 6 inches and released.

Required:
a. Find an equation for the object's displacement, u(t), in feet after t seconds.
b. What is the mass of the object?
c. What is the damping coefficient?
d. What is the spring constant?

Answers

Answer:

a)

[tex]u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)[/tex]

b)

m = 48lb

c)

b = 144.76lb

Explanation:

The general equation of a damping oscillate motion is given by:

[tex]u(t)=u_oe^{-\frac{b}{2m}t}cos(\omega t-\alpha)[/tex]    (1)

uo: initial position

m: mass of the block

b: damping coefficient

w: angular frequency

α: initial phase

a. With the information given in the statement you replace the values of the parameters in (1). But first, you calculate the constant b by using the information about the viscous resistance force:

[tex]|F_{vis}|=bv\\\\b=\frac{|F_{vis}|}{v}\\\\|F_{vis}|=27lbs=27*32.17ft.lb/s^2=868.59ft.lb/s^2\\\\b=\frac{868.59}{6}lb/s=144.76lb/s[/tex]

Then, you obtain by replacing in (1):

6in = 0.499 ft

[tex]u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)[/tex]

b.

mass, m = 48lb

c.

b = 144.76 lb/s

In a certain electronic device, charged particles must make their way through a magnetic field without experiencing any forces. This can be accomplished if
O A. B is perpendicular to v
B. their charges are negative
O c. they move parallel to the magnetic field
OD. the angle between the charges' velocity and the magnetic field is 90°​

Answers

Answer:

Se mas clara

Explanation:

Which item stores the most electrical potential energy within its capacitors?
A) Cell phone
B) Tablet
C) Television
D) Heating and Cooling system

Answers

Answer:

C. Television

Explanation:

Mostly in cathode ray television, a TV has many of different types of capacitors, used as connections between circuits, as timing components and as electronic filters. TV capacitors perform many functions.

capacitor acts as a reservoir for electric charge, storing and releasing electricity in precise amounts.

What is a Capacitor  ?

A capacitor is a simple device consisting of a pair of metal foils separated by a thin insulator, such as plastic, used basically for storing charge

Answer:

D) Heating and Cooling system

Explanation:

just took the test and got it right :)

Is it true or wrong that if anyone say that, can something that is “speeding up” it means it is also have a negative acceleration? Either true or wrong justify your answer with solid reason.

Answers

Answer:

wrong

Explanation:

it depends your perspective on it

what property of an electromagnetic wave changes when the wave is encoded with analog information?

Answers

Answer:

Amplitude and Frequency

Explanation:

Analog signals are composed of continuous waves that can have any values for frequency and amplitude. These waves are smooth and curved.

Radio transmissions are a combination of two kinds of waves: audio frequency waves that represent the sounds being transmitted and radio frequency waves that "carry" the audio information. All waves have a wavelength, an amplitude and a frequency as shown in the figure. These properties of the wave allow it to be modified to carry sound information.

The two most common types of modulation used in radio are amplitude modulation (AM) and frequency modulation (FM). Frequency modulation minimizes noise and provides greater fidelity than amplitude modulation, which is the older method of broadcasting . Both AM and FM are analog transmission systems, that is, they process sounds into continuously varying patterns of electrical signals which resemble sound waves.

A student standing on a cliff that is a vertical height d = 8.0 m above the level ground throws a stone with velocity v0 = 15 m/s at an angle θ = 31 ° below horizontal. The stone moves without air resistance; use a Cartesian coordinate system with the origin at the stone's initial position.

Required:
With what speed, vf in meters per second, does the stone strike the ground?

Answers

Answer:

The stone strikes the ground in 14.72m/s

Explanation:

The initial vertical velocity of the stone is given by:

Vyo= VSin theta

Given: V = 15m/s , theta = 31°

Vyo = 15 Sin 31

Vyo = 7.73m/s

Final vertical velocity, Vf can be determined by using kinematic equation

Vf^2 - U^2 = 2as

Vf^2 -( 7.73)^2 = 2(9.8×(-8))

Vf^2 = 59.75 + 156.8

Vf^2 = 216.6

Vf = sqrt(216.46)

Vf = 14.72m/s

Therefore,The stone strikes the ground in 14.72m/s

A rigid uniform rod of length 90.0 cm and mass 35.0 kg laying on a horizontal frictionless surface is free to rotate on that surface about an axle through its center. A small puck slides into it at an angle of 90 degrees to its surface at a distance of 30.0 cm from the pivot point at a speed of 20.0 m/s. It rebounds with a speed of 16.0 m/s along the same line. If the angular speed of the rod immediately after the collision is 1.14 rad/s, what was the mass of the puck

Answers

Answer:

m = 0.217 kg

Explanation:

We can solve this exercise using the conservation of angular momentum. For this the system is formed by the bar and the disk, so that the forces during the crash have been internal and the angular momentum is preserved

initial angular mount. Before impact

        L₀ = L_bar + L_ disk

        L₀ = I_bar w₀ + m r v₀

final angular momentum. Right after the crash

         [tex]L_{f}[/tex] = I_bar wf = m r v_{f}

The moment of inertia of a bar that rotates at its ends is

        I_bar = 1/12 M L

how the angular momentum is conserved

       L₀ = L_{f}

      I_barr w₀ + mr v₀ = I_barr w_{f} + m r v_{f}

      I_bar (w₀- w_{f}) = m r (v₀- v_{f})) r

      m = I_bar (w₀ - w_{f}) / r (v₀ -v_{f})

      m = 1/12 M L (w₀ -w_{f} ) / r (v₀ -v_{f})

in the exercise it indicates that the initial speed of the disc is v₀ = 20 m / s and its final speed is v_{f} = -16 m / s, the negative sign is because the disc recoils

we calculate

     m = 1/12 35 0.90 (0 + 1.14) / [0.30 (30- (-16))]

     m = 0.217 kg

According to recent typical test data, a Ford Focus travels 0.240 mi in 19.3 s, starting from rest. The same car, when braking from 62.5 mph on dry pavement, stops in 150 ft. Assume constant acceleration in each part of its motion, but not necessarily the same acceleration when slowing down as when speeding up.(a) Find the magnitude of this car's acceleration while braking.(b) Find the magnitude of this car's acceleration while speeding up.(c) If its acceleration is constant while speeding up, how fast (in mph) will the car be traveling after 0.250 mi of acceleration?(d) How long does it take the car to stop while braking from 59.0 mph?

Answers

Answer:

Explanation:

a )

While breaking initial velocity u = 62.5 mph

= 62.5 x 1760 x 3 / (60 x 60 )  ft /s

= 91.66 ft / s

distance trvelled s = 150 ft

v² = u² - 2as

0 = 91.66²  - 2 a x 150

a = - 28 ft / s²

b ) While accelerating initial velocity u = 0

distance travelled s = .24 mi

time = 19.3 s

s = ut + 1/2 at²

s is distance travelled in time t with acceleration a ,

.24 = 0 + 1/2 a x 19.3²

a = .001288 mi/s²

= 2.06 m /s²

c )

If distance travelled s = .25 mi

final velocity v = ? a = .001288 mi / s²

v² = u² + 2as

= 0 + 2 x .001288 x .25

= .000644

v = .025 mi / s

= .0025 x 60 x 60 mi / h

= 91.35 mph .

d ) initial velocity u = 59 mph

= 86.53 ft / s

final velocity = 0

acceleration = - 28 ft /s²

v = u - at

0 = 86.53 - 28 t

t = 3 sec approx .

A Ferris wheel has a 40-foot radius and the center of the Ferris wheel is 48 feet above the ground. The Ferris wheel rotates in the CCW direction at a constant angular speed of 2 radians per minute. Enrique boards the Ferris wheel at the 3-o'clock position and rides the Ferris wheel for many rotations. Let t represent the number of minutes since the ride started.

Write an expression (in terms of t ) to represent the number of radians Enrique has swept out from the 3-o'clock position since the ride started.

Answers

Answer:

[tex]\theta=\frac{\pi}{4}+2\frac{rad}{s}t[/tex]

Explanation:

To find the expression in terms of time t you take into account the following equation for the angular distance traveled by an object with angular acceleration w and initial angular position θo:

[tex]\theta=\theta_o+\omega t+\frac{1}{2}\alpha t^2[/tex]   ( 1 )

α is the angular acceleration, but in this case you have a circular motion with constant angular speed, then α = 0 rad/s^2. θo is the initial angular position, the information of the question establishes that Enrique is at 3-o'clock. This position can be taken, in radian, as π/4 (for 12-o'clock = 0 rads).

The angular speed is:

[tex]\omega=2\frac{rad}{min}[/tex]

You replace the values of θo, α and w in the equation ( 1 ):

[tex]\theta=\frac{\pi}{4}+2\frac{rad}{s}t[/tex]

Furthermore, the arc length is:

[tex]s=r\theta=(40ft)[\frac{\pi}{4}+2\frac{rad}{s}t][/tex]

A living thing that has a irregular shape is

Answers

Answer:

Amoeba

Explanation:

You may say that the shape appears irregular. Infact, Amoeba has no definite shape, unlike other organisms. It keeps on changing its shape.


2. Water at the Antarctica usually exits as ice, making it very difficult to use the water or conduct experiment requiring the water to be in liquid state. A coffee addicted physicist stationed at a research base requires about 0.8 kg of ice for his coffee on the hour.
a. How much heat is required to convert 0.8 kg of ice at —35 °C into steam at 100°C?

Answers

Answer:

662480 J

Explanation:

The heat required to convert 0.8Kg of ice at -35°c to steam at 100°c is the sum of the heat required to raise the temperature of the ice from -35°c to 0°C, the latent heat of fusion of ice and the heat required to raise the temperature of the ice from 0°c to 100°c.

Latent heat of fusion for ice= 3.36× 10^5 J Kg-1

Specific heat capacity of ice= 2060 J kg−1K−1

Specific heat capacity of water= 4200 JKg-1K-1

Heat required to raise the temperature of the ice to fusion point

H= 0.8 × 2060 × [0-(-35)]

H= 57680 J

Latent heat of fusion of ice;

H= mL

H= 0.8 ×3.36× 10^5

H= 2.688×10^5 J

Heat required to raise the temperature of the water to 100°C

Since mass is conserved, the mass of ice that has melted has been turned into an equivalent mass of water.

Therefore mass of water formed= 0.8Kg

H= 0.8× 4200 × 100

H= 336000J

Therefore total heat required;

H= 57680 + 2.688×10^5 + 336000

H= 662480 J

Answer:

2468,080j

Explanation:

Ned tightens a bolt in his car engine by exerting 15 N of force on his wrench at a distance of 0.45m from the fulcrum. How much torque must Ned produce to turn the bolt?

Answers

Answer:

[tex]T = 6.75\,N\cdot m[/tex]

Explanation:

Vectorially speaking, torque is the cross product between force and distance from fulcrum. Its magnitude is equal to the following expression:

[tex]T = F\cdot r \cdot \sin \theta[/tex]

[tex]T = F_{\bot} \cdot r[/tex]

Let assume that force is perpendicular to the distance from the fulcrum. So, the torque needed to turn the bolt is:

[tex]T = (15\,N)\cdot (0.45\,m)[/tex]

[tex]T = 6.75\,N\cdot m[/tex]

Which medium (1 or 2) is more dense?

Answers

Answer:

The answer is 1

Explanation:

It's fr 1

Sinec the light rays bends away from the normal when it enters into medium 2, the denser medium is medium 1.

What is refraction?

Refraction is the bending of light waves at the boundary of media of different densities.

During refraction, if light travels from less dense to a denser medium, the light rays is bent towards the normal.

However when light travels from denser to less dense medium, the light rays bends away from the normal.

Therefore, since the light rays bends away from the normal when it enters into medium 2, the denser medium is medium 1.

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b. A force 100N makes an angle of Ø with the x axis and has a y component of 30 N. Find both the x and y component of the force and the angle Ø.

Answers

Answer:

Explanation:

The y component of the force is 100 sinØ . But given that y component is 30N

so 100 sinØ = 30

sinØ = 0.3

Ø = 17.5°.

X component of force = 100 cosØ

= 100 cos17.5

= 95.35 N .

Y component of force = 30 N .

Angle Ø = 17.5°.

Which of the following statement(s) is
true about clipper circuits
Select one:
O a. It converts a.c to d.c always
O b. The output is clipped of some
portion of input signal
O c. It converts d.c to a.c
O d. None of these​

Answers

Answer:

Explanation:

A rectifier is an electrical device that converts alternating current (AC) to direct current (DC), a process known as rectification. Rectifiers have many uses including as components of power supplies and as amplitude modulation detectors (envelope detectors) of radio signals. Rectifiers are most commonly made using solid state diodes but other type of components can be used when very high voltages or currents are involved. When only a single diode is used to rectify AC (by blocking the negative or positive portion of the waveform), the difference between the term diode and the term rectifier is simply one of usage. The term rectifier describes a diode that is being used to convert AC to DC. Most rectifier circuits contain a number of diodes in a specific arrangement to more efficiently convert AC power to DC power than is possible with only a single diode.

A person is trying to tighten a bolt of mass 1 kg using a wrench of mass 6 kg and length
15 cm by applying a force of 12 N as shown in the diagram below. What is the torque
applied?

Answers

Answer:

0.18 Nm

Explanation:

Note: Torque is independent of the mass of a body.

From the question,

T = F×d.......................Equation 1

Where T = Torque, F = force applied to the wrench, d = length of the wrench.

Given: F = 12 N, d = 15 cm = 0.015 m

Substitute into equation 1

T = 12(0.015)

T = 0.18 Nm.

Hence the torque applied is 0.18 Nm

Other Questions
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