what two numbers add up two 40 but multiply to get 100

Answer:

Step-by-step explanation:

SOH CAH TOA

cos K  = 36/48 = 3/4

SIN L = 36/48 = 3/4

The trigonometric ratios sin(L) is 3/5, cosK is 3/5 and sinL and cosk are equal .

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

The triangle JKL is right angled triangle.

In the triangle KL is the opposite side of angle J.

SinL = Opposite/Hypotenuse

CosK = Adjacent/Hypotenuse

Used here, this means ...

sin(L) = KL/JL = 36/60 =6/10=3/5

cos(K) = KJ/KL = 36/60 = 6/10=3/5

sin(L) and cos(K) are equal

Hence, the trigonometric ratios sin(L) is 3/5, cosK is 3/5 and sinL and cosk are equal .

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Answer:

This would be the range, the interquartile range, the variance, and finally the standard deviation.

Step-by-step explanation:

Hope this helps you, please mark as brainlest.

If two triangles are congruent (as per the given congruency statement), then the corresponding angles of both triangles are also congruent.

Therefore, if angle B = 145, then angle E is also 145.

Answer: C) 145

Hope this helps!

Answer:

When a, b, and c are real numbers, a ≠ 0 and the discriminant is negative, then the roots α and β of the quadratic equation ax2 + bx + c = 0 are unequal and not real. In this case, we say that the roots are imaginary.

If a ≠ 0 and the discriminant is negative, then the roots α and β of the quadratic equation ax² + bx + c = 0 are unequal and not real.

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

Discriminant is √[tex]\sqrt{b^2- 4ac }[/tex]

a ≠ 0 and the discriminant is negative, then the roots α and β of the quadratic equation ax² + bx + c = 0 are unequal and not real.

In this case, we say that the roots are imaginary.

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By taking the quotient between the volumes, we conclude that he must use the blue cup 16 times or the green cup 4 times.

The volume of the sink is 512π in^3.

The blue cup is a cylinder of diameter = 4 in and a height = 8 in, then its volume is:

V = π*(4in/2)^2*8in = 32π in^3

The number of times that he needs to use this cup is given by:

N = (512π in^3)/(32π in^3) = 512/32 = 16

He needs to use 16 times the blue cup.

The green cup has a diameter = 8in and a height = 8in, then its volume is:

V' =π*(8in/2)^2*8in = 128π in^3

The number of times that he must use this cup is:

N' = (512π in^3/ 128π in^3) = 512/128 = 4

He needs to use 4 times the green cup.

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Answer:

The bearing of B from A is 335 Degrees

Step-by-step explanation:

Measure bearings clockwise.

Bearings are measured from the North line.

There are 25 degrees between B and North.

360 Degrees in a circle.

360 - 25 = 335

Answer:

5.1 cm

Step-by-step explanation:

The equation for the circumference of a circle is 2πr or πd.

So, we can plug in 16 and 3.14 to get 16 = 3.14×diameter.

Divide both sides by 3.14 to get approximately 5.1 cm.

Hope that helps! :)

Answer:

$8.52 that should be the answer

Answer:

Step-by-step explanation:

D 18,000

Answer:

D

Step-by-step explanation:

the Fundamental rule of Algebra states that a polynomial of degree n has n zeros, some of which may be complex.

thus for the given cubic function of degree 3 there will be 3 zeros

the graph indicates a zero at x = 4 which is real

thus there will be 2 complex zeros.

that is the cubic function has 1 real zero and 2 complex zeros

Answer:

x = -8

y = 0

Step-by-step explanation:

The experiment of rolling the dice and selecting a card is an illustration of probabilities

The probability of selecting a red card and rolling a number less than 3 is 1/6

From the figure, we have:

Total outcomes = 12

Red card with a number less than 3 = 2

So, the probability of selecting a red card and rolling a number less than 3 is:

p = 2/12

Simplify

p = 1/6

Hence, the probability of selecting a red card and rolling a number less than 3 is 1/6

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[tex]tan(\theta )=\sqrt{3}\implies tan(\theta )=\cfrac{\sqrt{3}}{1}\implies tan(\theta )=\cfrac{\sqrt{3}}{1}\cdot \cfrac{2}{2} \implies tan(\theta )=\cfrac{\sqrt{3}}{2}\cdot \cfrac{2}{1} \\\\\\ tan(\theta )=\cfrac{~~\stackrel{sin(\theta )}{\frac{\sqrt{3}}{2}} ~~}{\underset{cos(\theta )}{\frac{1}{2}}}\implies \theta =tan^{-1}\left( \cfrac{~~\frac{\sqrt{3}}{2} ~~}{\frac{1}{2}} \right)\implies \theta = \begin{cases} \stackrel{I~Quadrant}{60^o}\\\\ \stackrel{III~Quadrant}{240^o} \end{cases}[/tex]

Check the picture below.

The probability that a point chosen at random in the square is in the blue region is given by: Option D: 0.75

When probability is in terms of area or volume or length etc geometric amounts (when infinite points are there), we can use this definition:

Then:

[tex]P(E) = \dfrac{A(E)}{A(S)}[/tex]

where A(E) is the area/volume/length for event E, and similar for A(S).

For this case, we're given that:

The favorable space is the blue shaded region.

The total sample space is the area of the considered square.

Let we take:

E = event of choosing point in the blue shaded region

Now, we have:

Area of blue region = Area of triangle with base = height = 8 inches + Area of right sided triangle which has base of 4 inch (look it upside down), and height of 8 inches

Area of blue region = [tex]\dfrac{1}{2} \times (8 \times 8 + 4 \times 8) = 48 \: \rm in^2[/tex]

Area of the square of sized 8 inches = 64 sq. inches.

Thus, we get:

[tex]P(E) = \dfrac{A(E)}{A(S)} = \dfrac{48}{64} = \dfrac{3}{4} = 0.75[/tex]

Thus, the probability that a point chosen at random in the square is in the blue region is given by: Option D: 0.75

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Step-by-step explanation:

It should be tan(k)=32/40

Tangent is opposite/adjacent and 24/32 is adjacent/opposite which is not a trig function.

[tex]\qquad\qquad\huge\underline{\boxed{\sf Answer}}[/tex]

Let's evaluate ~

[tex]\qquad \sf  \dashrightarrow \: \dfrac{1}{3 {}^{ - 2} \times {x}^{ - 4} \times {y}^{2} } [/tex]

plug in the values :

[tex]\qquad \sf  \dashrightarrow \: \dfrac{1}{3 {}^{ - 2} \times {3}^{ - 4} \times { - 1}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{1}{3 {}^{ - 6} {}^{ } {}^{} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: {3}^{6} [/tex]

[tex]\qquad \sf  \dashrightarrow \:729[/tex]

Therefore, B is the Correct choice ~

・ ．━━━━━━━†━━━━━━━━━．・

Answer:

729

Step-by-step explanation:

Given expression:

[tex]\sf \dfrac{1}{3^{-2}x^{-4}y^2}[/tex]

Apply exponent rule [tex]\sf \dfrac{1}{a^{-b}}=a^b[/tex]

[tex]\sf \implies \dfrac{3^2x^4}{y^2}[/tex]

[tex]\sf \implies \dfrac{9x^4}{y^2}[/tex]

Substituting x = 3 and y = -1:

[tex]\sf \implies \dfrac{9(3)^4}{(-1)^2}[/tex]

[tex]\sf \implies \dfrac{9 \cdot 81}1}[/tex]

[tex]\sf \implies 729[/tex]

Answer:

375 Km

Step-by-step explanation:

1 inch = 50 km

50 x 7.5 = 375 km

Answer:

375 Km

1 inch = 50 km

50 x 7.5 = 375 km

Answer:

Mode = 1

Step-by-step explanation:

Relation between the Central Measures of Tendency

Solving

Therefore,

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

We know the relation between mean, Median and mode. that is :

[tex]\qquad \sf  \dashrightarrow \:mode = 3 \: median - 2 \: mean[/tex]

now, plug in the values ~

[tex]\qquad \sf  \dashrightarrow \:mode = 3(5) - 2(7)[/tex]

[tex]\qquad \sf  \dashrightarrow \:mode = 15 - 14[/tex]

[tex]\qquad \sf  \dashrightarrow \:mode = 1[/tex]

Hence, value of mode is 1

Answer:

Add 1 unit to the X coordinates and Y coordinates for each new pair.

step-by-step explanation:

X: 10 + 1 = 11 + 1 = 12

Y: 20 + 1 = 21 + 1 = 22

Hey there!

Easy word problem

Since there are 84 students total and their goal is to collect 16 cans

We multiply

=> 84 × 16 ⇒ 1,344

Therefore, 1,344 cans will be collected in all if each fifth-grader achieves the goal

Step-by-step explanation:

1. 6 ounce = 1.56 $

So, 1 onuce = 1.56/6 =

2. 14 ounce = 3.36 $

So, 1 ounce = 3.36/14 =

3. 20 ounce = 5.60 $

So, 1 ounce = 5.60/20 =

C(x)=0.25x+14.75

=C(40)=0.25x+14.75

=40c=0.25(40) + 14.75

=40c=10+14.75

=40c=24.75

Using proportions, it is found that it will take Michael 2.625 hours to drive to his mother's house.

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In 1 hour and 45 minutes, which is equivalent in hours to [tex]1 + \frac{3}{4} = \frac{7}{4}[/tex], he is two-thirds of the way. How long it takes him to reach 100% = 1 of the way? The rule of three is given by:

[tex]\frac{7}{4}[/tex] hours - [tex]\frac{2}{3}[/tex] way.

x hours - 1 way

Applying cross multiplication:

[tex]\frac{2}{3}x = \frac{7}{4}[/tex]

[tex]2x = \frac{21}{4}[/tex]

[tex]x = \frac{21}{8}[/tex]

x = 2.625.

It will take Michael 2.625 hours to drive to his mother's house.

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For this case we have the following polynomial:

x2 + x - 12

Factoring we have:

(x-3) (x + 4)

We note that the polynomial is written as:

(x + p) (x + q)

Thus,

p = -3

q = 4

Answer:

The values of p and q that can be used to factor x2 + x - 12 as (x + p) (x + q) are:

C. -3 and 4

Have a nice day ‍

[tex]__________________________[/tex]

Answer:

6p = 42

Step-by-step explanation:

If everybody scores 6 then the possible equation could be 6p = 42.

p represents the people on the team.

Solve for the variable p:

6p = 42

6p/6 = 42/6

p = 7

There are 7 people on the team.

hope this helps and is right!! p.s. i really need brainliest :)

Answer:

46,656

Step-by-step explanation:

6^2x3=

6^6=

6x6x6x6x6x6=

46,656

Hope that helps!

Answer:

1458

Step-by-step explanation:

2×3^6 that is d answer

Answer:

4 minutes

Step-by-step explanation:

4 minutes has 2 dots associated with it . All other times have only 1 dot.

then 4 minutes is the most common out of the 7

The trigonometric ratio will be Cos(n)=12/13

Given is a Right triangle LMN with right angle at M i.e. angle M = 90 degrees.

Given are the sides LM = 15, MN = 36, and LN = 39.

It says to find cos(n) = ?

So opposite side would be LM, adjacent side would be MN, and LN is the hypotenuse.

We know that the cosine ratio is given by :-

[tex]Cos(n)=\dfrac{adjacent}{Hypotenuse}[/tex]

[tex]Cos(n)=\dfrac{MN}{LN}[/tex]

[tex]Cos(n)=\dfrac{36}{39}[/tex]

[tex]Cos(n)=\dfrac{12}{13}[/tex]

Hence the required ratio will be   [tex]Cos(n)=\dfrac{12}{13}[/tex]

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This [tex]4x^2 - 12x + 9[/tex] factors into [tex](2x - 3)^2[/tex], and is thus a perfect square trinomial.

A perfect square is a number system that can be expressed as the

square of a given number from the same system.

Trinomial [tex]Ax^2 + Bx + C[/tex] is a perfect square if

A > 0

C > 0

B = ±2√A√C

1. [tex]36b^2 - 24b - 16[/tex]

C < 0

2. [tex]4a^2 - 10a + 25[/tex]

2√A√C = 2×2×5

              = 20,

B = −10

3. [tex]16x^2 + 24x - 9[/tex]

not a perfect square,

C < 0

4. [tex]4x^2- 12x + 9[/tex]

perfect square

A>0,

C>0,

2√A√C = 2×2×3

-B = 12

= [tex](2x - 3)^2[/tex]

Thus,  [tex]4x^2- 12x + 9[/tex] the polynomial is a perfect square trinomial.

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