What system of units is used by only a small number of countries in the world, including the U.S.?

Answer:

Li

Explanation:

The element, Neon (Ne), is the smallest among the given elements

From the question,

We are to determine which of the given elements is the smallest.

The given elements are

Be - Beryllium  

Ne - Neon  

O - Oxygen

Li - Lithium

B - Boron

From the periodic table, we can observe that all of the given elements belong to period 2.

Using the trend of atomic size on the periodic table,

We know that, atomic size decreases across the period.

This means, the atomic sizes of the elements will decrease in the order

Li > Be > B > O > Ne

Hence, the element, Neon (Ne), is the smallest among the given elements

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Answer:

Energy per mole of photons = 2.31 × 10^2 KJ/mol

Explanation:

Energy, E = hf;

Where h is Planck's constant = 6.63 ×10^-34, and f is frequency of the photons.

E = 6.63 × 10^-34 × 5.8 × 10^14

E = 3.84 × 10^-22 KiloJoules

I mole of photons contains Avogadro's number of particles, 6.02 × 10^23

Therefore, the energy per mile of photon is 3.84 × 10^-22 KJ × 6.02 × 10^23

Energy per mile of photon = 2.31 × 10^2 KJ/mol

Answer:

1. ELECTRON MOVES FROM THE n = 4 to n = 1 LEVEL

2. ENERGY IS EMITTED

3. THE ELECTRON MOVES CLOSER TO THE NUCLEUS

Explanation:

the question is incomplete as the picture is not shown but here is the picture and the solution.

Bohr model of the hydrogen atom shows that electrons would not emit energy but emit or absorb protons as it moves to a lower or higher energy levels respectively. In this question as shown in the picture below, the hydrogen atom moves from energy level 4 to energy level 1 and in such transition, energy is emitted and returns to its ground state after been excited to a higher level o n equals to 4. The energy emitted follows the law of conservation of energy. That is the amount of energy needed to excite the atom to a higher level is emitted upon transition back to the ground state.

The size of the hydrogen atom will also reduce and the electron will move closer to the nucleus. This is because as energy increases, the electron is found at a greater distance away from the nucleus and vice versa. And as the electron moves farther away the electrostatic force between it and the nucleus reduces and it is loosely held by the nucleus and vice versa, As the case of the question, the electron moves closer to the nucleus and it is strongly attached to the nucleus due to increase electrostatic attraction between it and the nucleus.

Answer:

In this transition, energy is emitted

The electron moves closer to the nucleus

Explanation:

In the Bohr's model of the atom, electrons occupy specific energy levels shown by the principal quantum number. An electron that is stationary in its orbit does not radiate energy.

However, an electron may absorb energy and be excited to higher energy levels or emit energy when descending from a higher to a lower energy level. This energy is usually observed as a photon of light of appropriate wavelength and frequency.

In the image, the electron descends from energy level n=4 to energy level n=1. Since it has moved from a higher to a lower energy level, energy is emitted. Recall that energy levels increase outwards from the nucleus. Since n=1 is closest to the nucleus, the electron has moved closer to the nucleus. Hence the answers above.

Answer:

(a) [tex]m_{gold}=7.322g[/tex]

(b)

[tex]V_{gold}=0.379cm^3[/tex]

[tex]V_{copper}=0.122cm^3[/tex]

(c) [tex]\rho _{coin}=15.94g/cm^3[/tex]

Explanation:

Hello,

(a) In this case, with the given formula we easily compute the mass of gold contained in the sovereign  as shown below:

[tex]m_{gold}=\frac{m_{tota}*karats}{24}=\frac{7.988g*22}{24}=7.322g[/tex]

(b) Now, by knowing the density of gold and copper, 19.32 and 8.94 g/cm³ respectively, we compute each volume, by also knowing that the rest of the coin contains copper:

[tex]V_{gold}=\frac{m_{gold}}{\rho_{gold}} =\frac{7.322g}{19.32g/cm^3}=0.379cm^3[/tex]

[tex]m_{copper}=7.988g-7.322g=1.09g\\V_{copper}=\frac{m_{copper}}{\rho_{copper}}=\frac{1.09g}{8.94g/cm^3} \\\\V_{copper}=0.122cm^3[/tex]

(c) Finally, the volume is computed by dividing the total mass over the total volume containing both gold and copper:

[tex]\rho _{coin}=\frac{m_{total}}{V_{gold}+V_{copper}}=\frac{7.988 g}{0.379cm^3+0.122cm^3}\\ \\\rho _{coin}=15.94g/cm^3[/tex]

Best regards.

Answer:

a

The mass of gold is  [tex]L = 7.322 *10^{-3} \ kg[/tex]

b

     The volumes of gold and copper is  [tex]V_g = 3.794 *10^{-7} \ m^3[/tex]  , [tex]V_c = 7.426 *10^{-8} \ m^3[/tex]

c

      The density of the British sovereign coin

          [tex]\rho = 17.593*10^{3} \ kg/m^3[/tex]

Explanation:

From the question we are told that

    The total mass of the gold is  [tex]K = 7.988 \ g = 7.988 * 10^{-3} \ kg[/tex]

      The karat of the British gold sovereign is  [tex]z = 22[/tex]

Let the mass of gold in the alloy be  L  

Now we are told that

       [tex]z = 24 * \frac{L}{K}[/tex]

substituting value  

        [tex]22 = 24 * \frac{L}{7.988 * 10^{-3}}[/tex]

  So  [tex]L = \frac{22}{24} * 7.899*10^{-3}[/tex]

        [tex]L = 7.322 *10^{-3} \ kg[/tex]

The volume of the gold coin is  mathematically represented as

         [tex]V_g = \frac{L}{\rho_g }[/tex]

Where   [tex]\rho_g[/tex] is the density of the gold which a constant with value  

     [tex]\rho_g = 19.3 *10^{3} \ kg /m^3[/tex]

So

         [tex]V_g = \frac{7.322 *10^{-3}}{19.3 *10^{3} }[/tex]

         [tex]V_g = 3.794 *10^{-7} \ m^3[/tex]

The mass of copper is mathematically evaluated as

        [tex]m_c = K - L[/tex]

        [tex]m_c = 7.988*10^{-3} - 7.322 *10^{-3}[/tex]

        [tex]m_c = 6.657 *10^{-4} \ kg[/tex]

Volume of the copper is  

          [tex]V_c = \frac{m_c}{\rho_c}[/tex]

Where   [tex]\rho_c[/tex] is the density of the copper which a constant with value  

        [tex]\rho_c = 8.92 * 10^{3} \ kg/m^3[/tex]

So

       [tex]V_c = \frac{6.657 *10^{-4}}{8.92 *10^{3}}[/tex]

       [tex]V_c = 7.426 *10^{-8} \ m^3[/tex]

The total volume of the British gold sovereign coin is  \

        [tex]V = V_g + V_c[/tex]

substituting values

        [tex]V = 3.7939 *10^{-7} + 7.4626 *10^{-7}[/tex]

        [tex]V = 4.54 *10^{-7} \ m^3[/tex]

The density of the British gold sovereign coin is

      [tex]\rho = \frac{K}{V}[/tex]

substituting values

         [tex]\rho = \frac{7.988 *10^{-3}}{4.54 *10^{-7}}[/tex]

         [tex]\rho = 17.593*10^{3} \ kg/m^3[/tex]

The given question is not complete, the complete question is:

Solving applied density problems Mr. Auric Goldfinger, criminal mastermind, intends to smuggle several tons of gold across International borders by disguising it as lumps of iron ore. He commands his engineer minions to form the gold into little spheres with a diameter of exactly 6 cm and paint them black However, his chief engineer points out that customs officials will surely notice the unusual weight of the "iron ore" if the balls are made of solid gold (density 19.3 g/cm'). He suggests forming the gold into hollow balls Instead (see sketch at right), so that the fake "Iron ore" has the same density as real iron ore (5.15 g/cm'). One of the balls of fake iron ore," sliced in half Calculate the required thickness of the walls of each hollow lump of iron ore. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.

Answer:

The correct answer is 0.29 cm.

Explanation:

To produce fake iron balls that is, formed of gold there is a need to make sure that the mass of the iron ball should be equivalent to the mass of the fake ball.  

To calculate the volume of iron ball with the help of the given diameter, the formula to be used is 4/3πr³. The diameter of the spheres mentioned in the given question is 6 cm, so the radius will be 6/2= 3 cm.  

Now, the volume of the iron ball would be = 4/3 × 3.14 × 3³ = 113.04 cm³

To determine the mass of the iron ball, the formula to be used is volume * density. Now putting the values we get,  

113.04 × 5.15 g/cm³ = 582.156 grams (The density of the iron ore is 5.15 g/cm³)

Now, the mass of the gold ball should also be equal to 582.156 g. The density of the solid gold is 19.3 g/cm³, therefore, the volume of the gold ball by using the above formula would be,  

mass of gold ball = Volume × density

Volume = mass of gold ball / density

Volume = 582.156 g / 19.3 g/cm³

= 30.1635 cm³

Thus, the volume of the hollow sphere would be 30.1635 cm³ with the outer radius as 3 cm, now there is a need to find the inner radius.  

Volume of hollow ball = 4/3π [R³ -r³]

30.1635 cm^3 = 4/3 pie [3³ = r³]

30.1635 × 3/4 × 3.14 = 27-r³

7.2046 = 27-r³

r³ = 19.7954

r = 2.7051 cm

Hence, the thickness would be outer radius - inner radius = 3-2.7051 = 0.2949 cm or 0.29 cm.  

Answer:

The male cones appear on the trees in the spring time.  The male cones are smaller than the female cones that we typically think of when we think of pine cones.  These cones are softer and are only on the trees in the spring.  After they release their pollen they die away and disappear.

Explanation:

Answer:

A gas sample into a vacuum diffuses faster than a gas sample into an air-filled container.

Explanation:

Diffusion

When a gas is introduced into a closed space, the molecules of the gas move freely and spread throughout the closed space.

The gas molecules tend to move from higher concentration to lower concentration area so that the concentration of gas throughout the closed space comes in equilibrium. This happens because higher concentration spaces have a greater number of gas molecules and vice-versa. In other words, gas molecules move towards the spaces having less concentration, i.e., they have a smaller number of gas molecules, and hence, can accommodate additional gas molecules.

This process of dispersion of gas molecules, as a result of difference in concentration, is called diffusion. The speed of diffusion is affected by the collisions suffered by the gas molecules.

When the molecules of gas disperse in any space, they have a tendency to travel in a straight line. In this process, they hit the molecules of other gases in the same space which causes a decrease in the speed of the molecules of gas hence, slowing the process of dispersion or diffusion.

Diffusion in air-filled container

When a gas is introduced into a closed container which is already filled with air, the molecules of the newly-introduced gas, as per their tendency, tend to move throughout the closed container irrespective of the concentration gradient.

Diffusion in a vacuum container

Whereas, in vacuum, the molecules of the introduced gas do not face any collisions with any molecules of other gas. The molecules of gas move freely until they collide with the sides of the container. The only collision occurring in a vacuum container is when the molecules hit the containers. Hence, gas diffusion takes place faster in a closed container having vacuum than a closed container which is already filled with air.  

Answer:

A hole

Explanation:

put a hole in the barrel and let some water out

The thing you would add to the barrel would be holes which would cause water to fall out of the barrel.

Pound is defined as the basic unit for weight in the Foot Pound Second (F.P.S) system and is equal to 16 ounces.

An example of a pound is a man weighing 186 pounds.

The thing you would add to the barrel would be holes which would cause water to fall out of the barrel.

The amount of holes you would add and where you would add them would depend all on how much the barrel weighs without the water.

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Answer:

3Mg(s) +2P(s) -------> Mg3P2(s) + energy

Keq= [Mg3P2]/[Mg]^3 [P]^2

Explanation:

The equation for the formation of magnesium phosphide from its elements is;

3Mg(s) +2P(s) -------> Mg3P2(s) + energy

Hence we can see that three moles of magnesium atoms combines with two moles of phosphorus atoms to yield one mole of magnesium phosphide. The equation written above is the balanced chemical reaction equation for the formation of the magnesium phosphide.

The equilibrium expression for the reaction K(eq) will be given by;

Keq= [Mg3P2]/[Mg]^3 [P]^2

Answer:

Well, for one thing,I played football for 7 years. Gatorade wouldn't be Gatorade without electrolytes. The electrolytes in that bottle of Gatorade give you energy. Those electrolytes Are what propel you through whatever you are doing at that time. Those are what give you energy.

Explanation:

Answer:

second option and last option

Explanation:

Know how to do an electron configuration. This is correct because it adds up to 8 and is in the correct order.

All valence electrons are in the last shell. In this case, 2p is the last shell.

Answer:

It's the second and the second to last

Explanation:

Answer:

The question lacks options, the options are:

A) Energy is transferred to consumers, which convert it to nitrogen and use it to make amino acid

B) Energy from producers is converted into oxygen and transformed to consumers.

C) Energy from the sun is stored by green plants and transferred to consumers.

D) Energy is transferred to consumers, which use it to produce food.

The answer is C

Explanation:

Organisms obtain energy in an ecosystem by feeding on one another in a chain called FOOD CHAIN. Energy is transferred when one organism feeds on another. A food chain always begins with a PRODUCER, which is an autotrophic organism capable of producing its own food via light energy from the sun.

In a terrestrial ecosystem, the energy a plant captures via Its Chlorophyll is used to produce food during photosynthesis. This energy is stored in the plants and transferred when a set of organisms called PRIMARY CONSUMER feeds on the plant. The transfer continues in that order till decomposers.

Answer:

See explaination

Explanation:

please kindly see attachment for the step by step solution of the given problem

The number of atoms which are present exactly in 12 grams of carbon-12 is called Avogadro's number.

Avogadro's number is the number of atoms which are present in 1 mole of any substance and it is equal to 6.022×10²³.

And moles will be calculated as:

Moles of Carbon-12 = 12g / 12g/mol = 1mole

In 1 mole of Carbon-12 = 6.022×10²³ atoms are present.

Hence, the number of atoms in exactly 12 grams of carbon-12 is called Avogadro's number.

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Answer:

The acid must be a concentrated acid

Explanation:

Ethene is prepared in the laboratory by heating ethanol with excess concentrated tetraoxosulphate VI acid at 170°C . The reactionoccursc in two stages;

1) when the ethanol and sulphuric acid are mixed in a ratio of 1:2, ethyl hydrogentetraoxosulpate VI is formed

2) The compound formed in the first step is heated in the presence of excess concentrated sulphuric acid to give ethene and sulphuric acid.

The overall reaction can be perceived as the dehydration of ethanol. The gas produced (ethene) is usually passed through sodium hydroxide solution to remove any gaseous impurities present.

concentrated sulphuric acid is used in this process since it is a good dehydrating agent.

The amount of weathering by the freezing and thawing process of water is the most effective weathering.

Weathering is a process in which breaking or dissolving of rocks and minerals present on the earth surface.

Weathering by the freezing effect of water causes more effect on the breaking as compare to the pressure release weathering.

Hence Freezing & thawing weathering is most powerful weathering.

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Answer:

1. m₁C₁ΔT₁ + m₂C₂ΔT₂ = 0

2. 207 g

Explanation:

This is a problem in calorimetry — the measurement of the quantities of heat that flow from one object to another.

It is based on the Law of Conservation of Energy — Energy can be transformed from one type to another, but it cannot be destroyed or created.

If heat flows out of one object, the same amount of heat must flow into another object.

Since there is no change in total energy,

Heat₁ + heat₂ + heat₃+ … = 0

The symbol for the quantity of heat transferred is q, so we can rewrite the word equation as

q₁ + q₂ + q₃ + … = 0

The formula for the heat absorbed or released by an object is

 q = mCΔT, where

m = the mass of the sample

C = the specific heat capacity of the sample, and

ΔT = T_f - T_i = the change in temperature

1. Equation

There are two heat flows in this problem,

Heat from steel rod + heat absorbed by water = 0

               q₁               +                  q₂                    = 0

           m₁C₁ΔT₁           +            m₂C₂ΔT₂             = 0

2. Data:

m₁ = ?;               C₁ = 0.452 J°C⁻¹g⁻¹;T_f = 21.20 °C; T_i =   2.50 °C

V₂ = 150.0 mL; C₂ = 4.184 J°C⁻¹g⁻¹; T_f = 21.20 °C; T_i = 24.00 °C

3. Calculations

(a) m₂

The density of water is 0.9982 g/mL, so  

m₂ = 150.0 mL × 0.9982 g/mL = 149.7 g

(b) Temperature changes  

[tex]\Delta T_{1} = T_{\text{f}} - T_{\text{i}} = 21.20 \, ^{\circ}\text{C} - 2.50 \, ^{\circ}\text{C} = 18.70 \, ^{\circ}\text{C}\\\Delta T_{2} = T_{\text{f}} - T_{\text{i}} = 21.20 \, ^{\circ}\text{C} - 24.00 \, ^{\circ}\text{C} = -2.80 \, ^{\circ}\text{C}[/tex]

(c) q₁

q₁ = m₁C₁ΔT₁ = m₁ × 0.452 J°C⁻¹g⁻¹ × 18.70 °C = 8.452m₁ J·g⁻¹

(d) q₂

q₂ = m₂C₂ΔT₂ = 149.7 g × 4.184 J°C⁻¹g⁻¹ × (-2.80 °C) = -1754 J

(e) m₁

[tex]\begin{array}{rcl}q_{1} + q_{2} & = & 0\\8.452m_{1} \, \text{J}\cdot\text{g}^{-1} + (-\text{1754 J}) & = & 0\\8.452m_{1}\,\text{g}^{-1} - 1764 &=& 0\\m_{1} & = & \dfrac{1764}{8.452 \,\text{g}^{-1}}\\\\ & = & \textbf{207 g}\\\end{array}\\\text{ The mass of the steel rod is $\large \boxed{\textbf{207 g}}$}[/tex]

Answer:

1, 2, 1

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

Answer:

1,2,1

Explanation:

just did the assigment

Answer:

  0.2 M

Explanation:

The molarity is the number of moles per liter:

  (0.05 moles)/(0.25 liter) = 0.2 moles/liter = 0.2 M

Answer:

most common non metal is chlorine

Answer:

5.12 L

Explanation:

P1V1/T1 = P2V2/T2

1.71 atm *10.0L /100 K = 9.70 atm *x/290.29 K

x = 1.71 atm *10.0L*290.29K /(100 K * 9.70 atm)= 5.12 L

Answer:

i need help with this and the answer above is wrong

Explanation:

pls

Answer:

The mass of PbI2 will be 18.2 grams

Explanation:

Step 1: Data given

Volume solution = 99.8 mL = 0.0998 L

mass % KI = 12.0 %

Density = 1.093 g/mL

Volume of the other solution = 96.7 mL = 0.967 L

mass % of Pb(NO3)2 = 14.0 %

Density = 1.134 g/mL

Step 2: The balanced equation

Pb(NO3)2(aq) + 2 KI(aq) ⇆ PbI2(s) + 2 KNO3(aq)

Step 3: Calculate mass

Mass = density * volume

Mass KI solution = 1.093 g/mL * 99.8 mL

Mass KI solution = 109.08 grams

Mass KI solution = 109.08 grams *0.12 = 13.09 grams

Mass of Pb(NO3)2 solution = 1.134 g/mL * 96.7 mL

Mass of Pb(NO3)2 solution = 109.66 grams

Mass of Pb(NO3)2 solution = 109.66 grams * 0.14 = 15.35 grams

Step 4: Calculate moles

Moles = mass / molar mass

Moles KI = 13.09 grams / 166.0 g/mol

Moles KI = 0.0789 moles

Moles Pb(NO3)2 = 15.35 grams / 331.2 g/mol

Moles Pb(NO3)2 = 0.0463 moles

Step 5: Calculate the limiting reactant

For 1 mol Pb(NO3)2 we need 2 moles KI to produce 1 mol PbI2 and 2 moles KNO3

Ki is the limiting reactant. It will completely be consumed ( 0.0789 moles). Pb(NO3)2 is in excess. There will react 0.0789/2 = 0.03945 moles. There will remain 0.0463 - 0.03945 = 0.00685 moles

Step 6: Calculate moles PbI2

For 1 mol Pb(NO3)2 we need 2 moles KI to produce 1 mol PbI2 and 2 moles KNO3

For 0.0789 moles KI we'll have 0.0789/2 = 0.03945 moles PbI2

Step 7: Calculate mass of PbI2

Mass PbI2 = moles PbI2 * molar mass PbI2

Mass PbI2 = 0.03945 moles * 461.01 g/mol

Mass PbI2 = 18.2 grams

Answer:

in all green plants and most algae

Answer:

less soluble

Explanation:

As n increases, the non polar hydrocarbon tail increases in length, while there is only one polar carboxylic group at the end. Since only the carboxylic group can form hydrogen bond with water, and the non polar hydrocarbon tail cannot, the long tail will hinder the formation of hydrogen bond between acid and water molecules, hence solubility decreases.

The carboxylic acids with general formula CH3(CH2)nCOOH to become  less water soluble as n increases.

An organic acid that has a carboxyl group joined to an R-group is said to be carboxylic. A carboxylic acid's general formula is RCOOH or RCO2H, where R stands for an alkyl, alkenyl, aryl, or other group. Carboxylic acids are frequently present.

The carboxylic acids do not produce dimers when introduced to water. Instead, individual acid and water molecules create hydrogen bonds with one another. These interactions allow carboxylic acids to disintegrate in water to create acidic solutions.

Similar to how alcohols, aldehydes, and ketones are soluble in water, carboxylic acids are as well. Acids with fewer than five carbons dissolve in water; those with a higher molecular weight are insoluble because they include a greater proportion of hydrocarbons.

Thus, The carboxylic acids with general formula CH3(CH2)nCOOH to become  less water soluble as n increases.

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A FAULT is a fracture or break in Earth's surface

Answer:

a) Total vapor pressure = 68.948 Kpa

b) Mole fraction of A = 41%, mole fraction of B = 59%

Explanation:

Find the given attachments.

Answer:

Intertidal zone

Neritic zone

Open-ocean zone

Note: the correct questions are found below;

In which zone do you find marshes and mangrove forests?

In which zone are plankton plentiful, providing plenty of food for the fish that live there?

In which zone would you find very little plant or animal life compared to other zones?

Explanation:

The intertidal zone, sometimes called the littoral zone, is the area of the marine shoreline that is exposed to air at low tide, and covered with seawater when the tide is high. Intertidal zonation refers to the tendency of plants and animals to form distinct communities between the high and low tide lines. Some microclimates in the littoral zone are moderated by local features and larger plants such as mangroves.

The neritic zone is the region of shallow water (200 meters depth) above the continental shelf where light penetrates to the sea floor.

Due to the abundant supply of sunlight and nutrients such as plankton in this zone, it is the most productive ocean zone supporting the vast majority of marine life.

The open oceans or pelagic ecosystems are the areas away from the coastal boundaries and above the seabed. It encompasses the entire water column and lies beyond the edge of the continental shelf. It extends from the tropics to the polar regions and from the sea surface to the abyssal depths.

Answer:

Intertidal zone

Neritic zone

Open-ocean zone

Explanation:

Answer:

D. Ultraviolet light should have a short wavelength, not a long wavelength.

Explanation:

just took the quiz on Ed

The mistake Gino made is, ultraviolet light should have a short wavelength, not a long wavelength.

Electromagnetic spectrum is the arrangement of electromagnetic radiations in the order of increasing frequency or decreasing wavelength.

Examples electromagnetic radiations based on increasing wavelength  include;

Thus, the mistake Gino made is, ultraviolet light should have a short wavelength, not a long wavelength.

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Answer:

Molecules of oxygen [tex]= 6.86 * 10^{23}[/tex]

Explanation:

The balanced equation of reaction between iron and oxygen is  

4 Fe     +  3 O2  → 2 Fe2O3

4 moles of iron react with 3 moles of oxygen.

Mass of one mole of iron is 55.845

number of iron moles in 84.9 grams of solid iron is equal to

[tex]\frac{84.9}{55.845} \\= 1.52[/tex]

Now 1 mole of iron will react with [tex]\frac{3}{4} = 0.75[/tex] mole of oxygen

Thus 1.52 moles of iron will react with [tex]0.75 * 1.52 = 1.14[/tex] moles of oxygen

Number of atoms of oxygen in 1.14 moles

[tex]1.14* 6.02 * 10^{23}\\[/tex]

[tex]= 6.86 * 10^{23}[/tex]