What random question should I do for 100 technically 50 points? ​

Answer:

840

Step-by-step explanation:

if it can hold 70 in 20 minutes it can hold 210 in 1 hour and 4x210 equals 840

it's 88 I've been getting so mix up forgive me So the area of the square is 64. When you find the area of the triangle you multiply the base by its height, which is 6 by 8 and then you divide by two. 64+24=88

Answer:

szdg

Step-by-step explanation:

hesre

Answer:

-5×x=4(x-2)

-5x=4x-8

-5x-4x=-8

-9x=-8

Divide both sides by -9x

x=8/9

Step-by-step explanation:

Answer:

0.7

Step-by-step explanation:

-4 - x1

3 - y1

2- x2

-1- y2

-1 - 3

2 - -4

-4

6

-4/6 = 0.7

Answer:

-4/6

Step-by-step explanation:

-1-3/2-(-4)=-4/6

Answer:

whats that

Step-by-step explanation:

Answer:

[tex]x=\frac{5+\sqrt{19}}{2}\text{ and } x=\frac{5-\sqrt{19}}{2}[/tex]

Step-by-step explanation:

If we have the standard form [tex]ax^2+bx+c[/tex], then we can use the quadratic formula:

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

First, let's identify our coefficients. We have [tex]2x^2-10x+3[/tex].

This can be rewritten as [tex](2)x^2+(-10)x+(3)[/tex].

Therefore, a=2, b=-10, and c=3.

Substitute these values into the quadratic formula. This yields:

[tex]x=\frac{-(-10)\pm\sqrt{(-10)^2-4(2)(3)}}{2(2)}[/tex]

From here, simplify. Evaluate the expression under the square root:

[tex]x=\frac{10\pm\sqrt{100-24}}{4}[/tex]

Evaluate:

[tex]x=\frac{10\pm\sqrt{76}}{4}[/tex]

Note that:

[tex]\sqrt{76}=\sqrt{4\cdot 19}=\sqrt{4}\cdot\sqrt{19}=2\sqrt{19}[/tex]

Therefore:

[tex]x=\frac{10\pm2\sqrt{19}}{4}[/tex]

We can factor out a 2 from both the numerator and the denominator:

[tex]x=\frac{2(5\pm\sqrt{19})}{2(2)}[/tex]

Simplify:

[tex]x=\frac{5\pm\sqrt{19}}{2}[/tex]

Therefore, our roots are:

[tex]x=\frac{5+\sqrt{19}}{2}\text{ and } x=\frac{5-\sqrt{19}}{2}[/tex]

Answer:

120

Step-by-step explanation:

Answer:

$120

Step-by-step explanation:

20 × 6= 120

(it said my answer had to be 20 characters long so I typed this.)

Answer: 40%

Steps: Forty percent of $30 is $18.

Plz mark brainliest:)

Answer:

25%

Step-by-step explanation:

[tex] \huge{\boxed{\sf{32}}}[/tex]

Step by step explanation:

Step 1:

→[tex]4(8-6)+2(4+8)[/tex]

Info: + × - = -

Step 2:

→[tex]32 - 24 + 8 + 16[/tex]

Step 3:

→[tex]56 - 24[/tex]

Step 4:

→[tex]\green{32✓}[/tex]

Answer: The slope is m = -[tex]\frac{4}{3}[/tex]

Step-by-step explanation:

Answer: - 4,3

Step-by-step explanation:

Answer:

x=4

Step-by-step explanation:

Answer:

x = 4 :)

Step-by-step explanation:

Answer:

Step-by-step explanation:

5x-(0)=30

add 0 to both sides to cancel

5x=30

divide by 5 on both sides to cancel

x=6

Answer:

2 ans is 7 2x_4+2x_7=17

52 tacos

3.5x<180

Step-by-step explanation:

it would be bigger than symbol because the minimum they need to sell is 52 but they could sell more

Answer:-2.3

Step-by-step explanation:

-8 + 4.5 = -3.5

-3.5 -(-1.2)= -2.3

9514 1404 393

Answer:

  9x -10y = 75

Step-by-step explanation:

The least common denominator is the least common multiple of the denominators. Here, that is 5×3 = 15. Multiplying both sides of the equation by that gives ...

  15(3/5x -2/3y) = 15(5)

  9x -10y = 75

Answer:

b. 8.6

Step-by-step explanation:

Given:

B = 49° 13'

b = 10

Required:

Find a

SOLUTION:

The reference angle given = 49° 13'. Converted to degrees, we have 49.2167°.

b = Opposite side to the reference angle B = 10

a = adjacent side to angle B = ?

To find a, apply the following trigonometric ratios formula:

[tex] tan(B) = \frac{opp.}{adj.} [/tex]

[tex] tan(49.2167) = \frac{10}{a} [/tex]

Multiply both sides by a

[tex] tan(49.2167)*a = \frac{10}{a}*a [/tex]

[tex] tan(49.2167)*a = 10 [/tex]

Divide both sides by tan(49.2167)

[tex] \frac{tan(49.2167)*a}{tan(49.2167)} = \frac{10}{tan(49.2167)} [/tex]

[tex] a = \frac{10}{tan(49.2167)} [/tex]

[tex] a = 8.6 [/tex] (nearest tenth)

Answer:

B.

Step-by-step explanation:

8.6

Answer:

Step-by-step explanation:

The answer is because when rounding it should be b

Answer: 2 seconds

Step-by-step explanation:

An object take 2 seconds to reach to the ground. option A is correct.

An object that is projected straight downward with initial velocity v feet pee second.
s = vt + 16t2
s = 84 feet and v = 10

Velocity is ratio of displacement to the time.

We have equation.
s = vt + 16t2
Now, put s =  84 and v = 10
84 = 10t+16t2
8t2+10t-42=0
Taking roots of equation.
We get t = 2 and -21/8
Since time couldn't be negative.
So,
t = 2  

Thus, An object take 2 seconds to reach to the ground.

Learn more about Velocity here:
https://brainly.com/question/18084516

#SPJ2

Answer:

468

Step-by-step explanation:

and this is how you spell answers

The value of 78 × 6 is 468

Multiplication is the process of calculating the product of two or more numbers. The result of multiplication is called product.

If a × b = c , this means that a and b are the factors and c is the product.

For example if each student has 5 apples and there are 100 students in the camp, the total number of apples in the camp is

100 × 5 = 500 mangoes.

Similarly, 78 × 6

= 70 × 6 + 8 × 6

= 420 + 48

= 468

Therefore the product of 78 and 6 is 468

learn more about multiplication is

https://brainly.com/question/10873737

#SPJ6

Answer:

Step-by-step explanation:

espera y termino y te ayudo vale que me falta poco vale

Answer:

Step-by-step explanation:

(X+2)(x-7)

Answer:

onse sec and ill help

Step-by-step explanation:

Answer:

20

Step-by-step explanation:

Answer:

[tex](0,-1)[/tex]

Step-by-step explanation:

[tex](x^{2} -x^{1} )(y^{2} -y^{1} )[/tex]- the formula

[tex](-1 - -1) = 0[/tex]

[tex](-8 - -7) =-1[/tex]

So, the answer is:

[tex](0,-1)[/tex]

or

[tex]0=-1[/tex]

  ^

this is the swiggly line

Answer:The answer has to be 9

(

Step-by-step explanation: Because 2 plus 9 equals 11 and this is an addition problem

Answer:

9

Step-by-step explanation:

To solve subtract 2 from both sides (subtraction property of equality)

2-2+y=11-2, then simplify

y=9

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

Answer:

x= 1, y = 1, z=  0

Step-by-step explanation

-2x + 2y + 3z = 0

2x + 3y + 3z = 5

-2x - y + z = -3

2x + 3y + 3z = 5

(solving systems)

5y + 6z = 5

2y + 4z = 2

(rewriting)

z = 0

y = 1

-2x + 2 x 1 + 3 x 0

x=1