What piece of information is needed to prove the triangles are congruent through AAS?

Answer:

1. x + 4 = 9

Hint: the word 'sum' generally refers to addition.

2. 10a = 70

3. [tex]\frac{3}{4} t[/tex] = 15

4. [tex]\frac{1}{4} x[/tex] - 4 = 4

Answer:

They can buy up to 240 drinks.

Step-by-step explanation:

Let x = number of drinks

The price of 1 drink is 75¢ = $0.75

The price of x drinks is 0.75x

The store gives a discount of $100.

The rice of x drinks is

0.75x - 100

The total price of the drinks must be less than or equal to $80.

0.75x - 100 ≤ 80

Add 100 to both sides.

0.75x ≤ 180

Divide both sides by 0.75

x ≤ 240

Answer: They can buy up to 240 drinks.

Hello!

(6x⁵z)³/4x⁴z² =

= 216x¹⁵z³/4x⁴z² =

= 54x¹¹z

Good luck! :)

Answer:

39+4x

Step-by-step explanation:

Since two opposites add up to zero, remove them from the expression

2x3-5x+2+4x2+6x-2x+7x5

Calculate the sum or difference

39+6x-2x

Answer:

The sum of squared errors for the regression equation is 62.

Step-by-step explanation:

The sum of squared errors can be computed as follows:

X            Y           Y* = 2 + 3X         Y - Y*           (Y - Y*)^2

0            5                  2                      3                    9

3            5                  11                     -6                  36

7            27               23                     4                    16

10          31                32                    -1                     1  

20         68               68                     0                   62

From the above, we have:

Error = Y -  Y*

Error^2 = (Y - Y*)^2

Sum of squared errors = Sum of Error^2 = Total of (Y - Y*)^2 = 62

Therefore, the sum of squared errors for the regression equation is 62.

Answer:

c

Step-by-step explanation:

9514 1404 393

Answer:

  3, 6, 12, 24

Step-by-step explanation:

It helps if the formula is properly written.

  Tn = a·r^(n-1)

Fill in the given values for a, r, and use n = 1 to 4.

  T1 = 3·2^(1-1) = 3

  T2 = 3·2^(2-1) = 6

  T3 = 3·2^(3 -1) = 12

  T4 = 3·2^(4 -1) = 24

__

Additional comment

The value a=3 tells you the first term is 3. The value r=2 tells you each term is 2 times the previous one. Knowing this, you can write down the sequence based on your knowledge of multiplication tables (×2). You can use the formula as we did above, but it isn't necessary.

  3, 6, 12, 24, ...

Step-by-step explanation:

Given: [tex]f'(x) = x^2e^{2x^3}[/tex] and [tex]f(0) = 0[/tex]

We can solve for f(x) by writing

[tex]\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx[/tex]

Let [tex]u = 2x^3[/tex]

[tex]\:\:\:\:du=6x^2dx[/tex]

Then

[tex]\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du[/tex]

[tex]\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k[/tex]

We know that f(0) = 0 so we can find the value for k:

[tex]f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}[/tex]

Therefore,

[tex]\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)[/tex]

Answer:

35

Step-by-step explanation:

square root of 1225 is 35

Answer:

Write 1225 as 5 x 5 x 7 x 7

So, 52 x 72 = 1225

So (5 x 7)2 = 1225

So √1225 = 5 x 7 = 35

Answer:

3

Step-by-step explanation:

From the diagram

AD = 9 units and AB = 3 units , then

[tex]\frac{AD}{AB}[/tex] = [tex]\frac{9}{3}[/tex] = 3

Answer: Tis 0

Step-by-step explanation:

The measure of angle ∠AOB is 180°. The correct option from the following is (A).

A turn's angle is quantified using degrees or °. A full turn encompasses 360°. A protractor can be used to determine the size of an angle. The term "acute" refers to an angle smaller than 90°. Obtuse refers to an angle between 90° and 180°. Reflex is an angle larger than 180 degrees. Right angles have an angle of exactly 90 degrees.

A quadrilateral is an enclosed form created by uniting four points, any three of which cannot be collinear. A quadrilateral is a polygon that has four sides, four angles, and four vertices. Let us study more about quadrilaterals' shapes, their characteristics, and the various kinds of quadrilaterals, as well as some examples of quadrilaterals.

For the given quadrilateral, the sum of angles is:

∠A + ∠O + ∠B = ∠AOB

60° + 60° + 60° = 180°

Hence, the correct option is (A).

To learn more about Angle, here:

https://brainly.com/question/17039091

#SPJ4

Answer:

Outlier therefore could only be values below  - 12.75

or could only be values above + 121.125

Step-by-step explanation:

0, 4, 6, 14, 17

inner quartile range of 0 - 17 is 1/2 of 17 subtracted from the higher number = 17 - 1/2 of 8.5 =  8.5 - 4.25 = 4.25 - 4.25 x 3

= 4.25 to 12.75 for inner quartile

inner quartile range is 12.75-4.25 = 8.5

We then 1.5 x 8.5 to show the outlier

= 12.75 meaning there is no outlier if is below.

Lower quartile fences  = 4.25 - 1.5 = 2.75

or -1.5 x 8.5 (the range) =   -12.75

Upper quartile fence = 12.75 + 1.5 = 14.25 x 8.5 =   121.125  this would be an outlier if it is 12.75 higher than 121.125 or 12.75 lower than 5.50.

Outlier therefore could only be values below  - 12.75

or could only be values above + 121.125

An observation is considered an outlier if it exceeds a distance of 1.5 times the interquartile range (IQR) below the lower quartile or above the upper quartile. The values of the lower quartile - 1.5 x IQR and upper quartile + 1.5 x IQR are known as the inner fences.

An observation is an outlier if it falls more than above the upper quartile or more than below the lower quartile. The minimum value is so there are no outliers in the low end of the distribution. The maximum value is so there are no outliers in the high end of the distribution.

Step-by-step explanation:

2x+60°= 110°

2x= 110-60

2x= 50

x= 25°

Answer:

95816.666667

explained

1÷3*287450

9514 1404 393

Answer:

  h = -4.79(t -0.58)^2 +3.26

Step-by-step explanation:

The coordinates (t1, h1) are the time and height at the maximum. Then 'a' can be found from ...

  h = a(t -t1)^2 +h1

  1.65 = a(0 -0.58)^2 +3.26

  -1.61 = 0.3364a . . . . . subtract 3.26

  -4.786 = a . . . . . . . divide by the coefficient of a

The equation is ...

  h = -4.79(t -0.58)^2 +3.26

Answer:

t / 6 = # of shirts in each package.

Step-by-step explanation:

total amount of shirts / total packages = # of shirts in each package

Answer:

52/3

Step-by-step explanation:

Use basic Thales therom,

[tex]\frac{3x}{4x}=\frac{3x+7}{5x-8}\\\\\frac{3}{4}=\frac{3x+7}{5x-8}\\[/tex]

Cross multiply,

3*(5x-8)=4*(3x+7)

3*5x - 3*8 = 4*3x + 4*7

15x - 24 = 12x +28

Add 24 to both sides

15x = 12x + 28 + 24

15x = 12x + 52

Subtract 12x from both sides

15x-12x =52

3x = 52

Divide both sides by 3

x = 52/3

Answer:

125x=(62.50+(62.50)×0

Answer:

4, 8, 16, 32, ...

Step-by-step explanation:

8 / 4 = 2

16 / 8 = 2

32 / 16 = 2

Common ratio is 2

So, The sequence 4, 8, 16, 32, …. is geometric.

Answer:

Slope = [tex]\frac{4}{3}[/tex]

Equation of the line → [tex]y=\frac{4}{3}x[/tex]

Step-by-step explanation:

Let the equation of diagonal OA is,

y = mx + b

Here, m = Slope of the line OA

b = y-intercept

Slope of a line passing through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,

m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Therefore, slope of the line passing through O(0, 0) and A(3, 4) will be,

m = [tex]\frac{4-0}{3-0}[/tex]

m = [tex]\frac{4}{3}[/tex]

Since, line OA is passing through the origin, y-intercept will be 0.

Therefore, equation of OA will be,

[tex]y=\frac{4}{3}x[/tex]

Answer:

15

Step-by-step explanation:

Answer:

The domain of the function is all real values of x, except [tex]x = 4[/tex] and [tex]x = 2[/tex]

Step-by-step explanation:

We are given the following function:

[tex]f(x) = \frac{x+1}{x^2-6x+8}[/tex]

It's a fraction, so the domain is all the real values except those in which the denominator is 0.

Denominator:

Quadratic equation with [tex]a = 1, b = -6, c = 8[/tex]

Using bhaskara, the denominator is 0 for these following values of x:

[tex]\Delta = (-6)^2 - 4(1)(8) = 36-32 = 4[/tex]

[tex]x_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4[/tex]

[tex]x_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2[/tex]

The domain of the function is all real values of x, except [tex]x = 4[/tex] and [tex]x = 2[/tex]

The largest rate of change occurs in the same direction as the gradient of f at the point.

∇f(x, y, z) = (∂f/∂x, ∂f/∂y, ∂f/∂z) = (y, x, -1/z)

==>   ∇f (1, 1, 1) = (1, 1, -1)

In other words, f changes at the highest rate in the direction of the vector (1, 1, -1).

Answer:

The last choice: 68/5 - 22/5 = 9 1/5

Step-by-step explanation:

Solve each problem:

9 3/7 = 10 3/7

The fractions are the same so look at the whole numbers.

Does 9 equal 10? No, it doesn't so this is a false statement.

332/4 = 1/83

Simplify 332/4:

332/4 = 83/1

83 does not equal 1/83 so this is a false statement.

37/5 = 5 2/5

Convert the improper fraction into a mixed number:

7 2/5 = 5 2/5

These numbers do not equal each other so this is a false.

68/5 - 22/5 = 9 1/5

Subtract the numerators on the left side of the equation:

46/5 = 9 1/5

Convert the improper fraction into a mixed number:

9 1/5 = 9 1/5

These numbers equal each other so this is a true statement!

Answer:

a. difference of means

Step-by-step explanation:

Given that :

Mean , x = 9.4

Standard deviation, [tex]s.d_1[/tex] = 2.5

Number, [tex]n_1[/tex] = 12

Mean, y = 6.5

standard deviation, [tex]s.d_2[/tex] = 2.4

Number, [tex]n_2[/tex] = 12

The null hypothesis is : [tex]$H_0: \mu_1=\mu_2$[/tex]

The alternate hypothesis is : [tex]$H_1: \mu_1>\mu_2$[/tex]

Level of significance, [tex]\alpha[/tex] = 0.1

From the [tex]\text{standard normal table, right tailed,}[/tex] [tex]$t_{1/2}$[/tex] = 1.363

Since out test is right tailed.

Reject [tex]H_0[/tex], if [tex]$T_0>1.363$[/tex]

We use the test statics,

[tex]$t_0=\frac{(x-y)}{\sqrt{\frac{s.d_1}{n_1}+\frac{s.d_2}{n_2}}}$[/tex]

[tex]$t_0=\frac{(9.4-6.5)}{\sqrt{\frac{6.25}{12}+\frac{5.76}{12}}}$[/tex]

[tex]$t_0=2.899$[/tex]

[tex]$|t_0|=2.899$[/tex]

[tex]\text{Critical value}[/tex]

The value of [tex]$|t_{1/2}|$[/tex] with minimum [tex]$\left(n_1-1,n_2-1)$[/tex] that is 11 df is 1.363

We go [tex]$|t_0|=2.899$[/tex] and [tex]$|t_{1/2}|$[/tex] = 1.363

Decision making:

Since the value of [tex]|t_0|>|t_{1/2}|$[/tex]  and we reject the [tex]H_0[/tex]

The p-value : right tail [tex]H_a:(p>2.8988)[/tex]

                                      = 0.00724

Therefore the value of [tex]$p_{0.1} > 0.00724$[/tex], and so we reject the [tex]H_0[/tex]

Thus we are testing 'the difference of means" in this problem.

Answer:

2×(6ײ+3×-1)=18.

2×(6×3×+4)(6×4×-3)=144

2×(6×3×-2)(4×2+4×-6)=1154..

12×2=24

12×2+7×-12=60

12×2+25×-12=276

12×3+4×2-10×+12=76

12×3+4×2-26×+12=8

12×3+6×2-2=46