Answer:
71.3 g
Explanation:
molar mass of C₇H₆O₃ = 138.13 g
molar mass of [tex]C_{9}H_{8}O_{4}[/tex] = 180.17 g
find the moles of reactant: C₇H₆O₃
C₇H₆O₃ that reacted = mass/molar mass = 57.6 g C₇H₆O₃ / 138.13 g C₇H₆O₃
= 0.417 mol [tex]C_{7}H_{6}O_{3}[/tex]
From the reaction equation, 1 mole of C₇H₆O₃ yields one mole of aspirin
find theoretical yield of aspirin:
0.417 mol C7H6O3 x 180.17 g C9H8O4 / 1 mol C9H8O4[tex]\frac{0.417 mol C_{7}H_{6}O_{3}}{} x \frac{180.17 g C_{9}H_{8}O_{4}}{1 mol C_{9}H_{8}O_{4}}[/tex]
= 75.1 g C9H8O4
Actual yield= % yield × theoretical yield/100
Actual yield = 95.0 × 75.1/100
Actual yield = 71.3 g
Taking into account the reaction stoichiometry and actual yield, the mass of C₉H₈O₄ produced from 57.6 g of C₇H₆O₃ assuming 95.0% yield is 57.0285 grams.
The balanced reaction is:
22 C₇H₆O₃ (s) + 32 C₄H₆O₃ (s) → 24 C₉H₈O₄ (s) + 33 HC₂H₃O₂ (aq)
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
C₇H₆O₃: 22 moles C₄H₆O₃: 32 moles C₉H₈O₄: 24 moles HC₂H₃O₂: 33 molesThe mass molar of each compound is:
C₇H₆O₃: 138 g/moleC₄H₆O₃: 102 g/mole C₉H₈O₄: 180 g/moleHC₂H₃O₂: 60 g/moleThen by reaction stoichiometry, the following amounts of mass of each compound participate in the reaction:
C₇H₆O₃: 22 moles× 138 g/mole= 3036 gramsC₄H₆O₃: 32 moles× 102 g/mole= 3264 grams C₉H₈O₄: 24 moles× 180 g/mole= 4320 gramsHC₂H₃O₂: 33 moles× 60 g/mole= 1980 gramsThen you can apply the following rule of three: if by stoichiometry 3036 grams of C₇H₆O₃ produce 3264 grams of C₉H₈O₄, 57.6 grams of C₇H₆O₃ will produce how many mass of C₉H₈O₄?
[tex]mass of C_{9} H_{8} O_{4} =\frac{57.6 grams of C_{7} H_{6} O_{3} x3264 gramsof C_{9} H_{8} O_{4} }{3036 grams of C_{7} H_{6} O_{3}}[/tex]
mass of C₉H₈O₄= 60.03 grams
On the other side, actual yield is the amount of product actually obtained from a reaction. Assuming 95.0% yield and considering the previously calculated mass the maximum amount of product that can be produced in the reaction, you can apply the following rule of three: If 100% equals 60.03 grams of the compound produced, 95% equals how much mass of the compound?
[tex]mass of C_{9} H_{8} O_{4} =\frac{95 percentx60.03gramsof C_{9} H_{8} O_{4} }{100 percent}[/tex]
mass of C₉H₈O₄= 57.0285 grams
Finally, the mass of C₉H₈O₄ produced from 57.6 g of C₇H₆O₃ assuming 95.0% yield is 57.0285 grams.
Learn more:
brainly.com/question/16487206?referrer=searchResults brainly.com/question/14446695?referrer=searchResults brainly.com/question/11564309?referrer=searchResults brainly.com/question/4025026?referrer=searchResults brainly.com/question/18650135?referrer=searchResultsWhat is the pH of a solution made by mixing 30.00 mL 0.10 M HCl with 40.00 mL of 0.10 M KOH? Assume that the volumes of the solutions are additive.
Answer:
pH = 12.15
Explanation:
To determine the pH of the HCl and KOH mixture, we need to know that the reaction is a neutralization type.
HCl + KOH → H₂O + KCl
We need to determine the moles of each compound
M = mmol / V (mL) → 30 mL . 0.10 M = 3 mmoles of HCl
M = mmol / V (mL) → 40 mL . 0.10 M = 4 mmoles of KOH
The base is in excess, so the HCl will completely react and we would produce the same mmoles of KCl
HCl + KOH → H₂O + KCl
3 m 4 m -
1 m 3 m
As the KCl is a neutral salt, it does not have any effect on the pH, so the pH will be affected, by the strong base.
1 mmol of KOH has 1 mmol of OH⁻, so the [OH⁻] will be 1 mmol / Tot volume
[OH⁻] 1 mmol / 70 mL = 0.014285 M
- log [OH⁻] = 1.85 → pH = 14 - pOH → 14 - 1.85 = 12.15
The pH of the solution is 12.15.
Calculation of the pH of the solution:The following equation should be
HCl + KOH → H₂O + KCl
Here we have to measured the moles of each compound i.e.
M = mmol / V (mL) → 30 mL . 0.10 M = 3 mmoles of HCl
M = mmol / V (mL) → 40 mL . 0.10 M = 4 mmoles of KOH
So, it be like
3 m 4 m -
1 m 3 m
Now the pH should be like
= [OH⁻] 1 mmol / 70 mL
= 0.014285 M
Now
= - log [OH⁻] = 1.85
pH = 14 - pOH
= 14 - 1.85
= 12.15
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According to the following reaction, how many moles of dichloromethane (CH2Cl2) will be formed upon the complete reaction of 0.766 moles methane (CH4) with excess carbon tetrachloride?
methane (CH4) (g) + carbon tetrachloride (g) → dichloromethane (CH2Cl2) (g)
Answer:
[tex]1.53~moles~CH_2Cl_2[/tex].
Explanation:
We can start with the reaction, if we know the formula for each compound:
-) Methane: [tex]CH_4[/tex]
-) Carbon tetrachloride: [tex]CCl_4[/tex]
-) Dichloromethane: [tex]CH_2Cl_2[/tex]
With this in mind, we can write the reaction:
[tex]CH_4~+~CCl_4~->~CH_2Cl_2[/tex]
Now, we can balance the reaction:
[tex]CH_4~+~CCl_4~->~2CH_2Cl_2[/tex]
After this, we have 2 carbon atoms on each side, 4 hydrogen atom on each side, and 4 chlorine atoms on each side.
If we want to know how many moles of [tex]CH_2Cl_2[/tex] would be produced with .766 moles of [tex]CH_4[/tex], we have to check the balanced reaction and use the molar ratio. In this case, the molar ratio is 1 mol [tex]CH_4[/tex] will produce 2 moles of [tex]CH_2Cl_2[/tex] (1:2). So:
[tex]0.766~moles~CH_4\frac{2~moles~CH_2Cl_2}{1~mol~CH_4}=1.53~moles~CH_2Cl_2[/tex]
We wil have [tex]1.53~moles~CH_2Cl_2[/tex].
I hope it helps!
Calculate the [Cu2') remaining in 425 mL of a solution that was originally 0.366 M CuSO4 after passage of 2.68 A for 282 s and the deposition of Cu at the cathode.
Answer:
[tex][Cu]^{remaining}=0.357 M[/tex]
Explanation:
Hello,
In this case, we may use the following equation in order to compute the moles of copper that are processed, considering it goes from Cu⁰ to Cu²⁺, so two electrons are transferred:
[tex]n_{Cu}=\frac{2.68C/s*282s}{96500C/mol*2} =3.9x10^{-3}mol[/tex]
After that, we compute the initial moles of copper in the solution, considering that the concentration of copper (II) equals the concentration of copper:
[tex]n_{Cu,0}=0.366mol/L*0.425L=0.156mol[/tex]
In such a way, we can subtract the process moles to the initial moles to compute the remaining moles of copper:
[tex]n_{Cu}^{remaining}=0.156mol-0.0039mol=0.152mol[/tex]
Finally, the concentration is:
[tex][Cu]^{remaining}=0.152mol/0.425L[/tex]
[tex][Cu]^{remaining}=0.357 M[/tex]
Regards.
This graduated cylinder is being used to measure an amount of a liquid. The numbers represent milliliters. What is the most precise measurement of the volume of this liquid? 37.0 ml 37.1 ml 37.2 ml 37.3 ml
Answer:
37.1 mL
Explanation:
To accurately read the measurement using a cylinder, we read the measurement at the meniscus i.e measurement under the curve as shown in the diagram above.
The meniscus i.e the measurement under the curve as shown above is 37.1 mL.
Therefore, the volume of the liquid as obtained from the cylinder is 37.1 mL
Answer:
37.1 ml
Explanation:
a graduated cylinder's measurement is taken at the bottom of the meniscus
Which method did Dalton use to develop his atomic theory?
He changed atoms of one element into atoms of a different element.
He split individual atoms to identify the particles inside them.
He searched for natural materials that did not contain atoms.
He studied the way in which elements combined during chemical reactions.
Answer:
He studied the way in which the elements combined during chemical reactions
Explanation:
Which method did Dalton use to develop his atomic theory?
D.) He studied the way in which elements combined during chemical reactions.
Answer: It’s D
Explanation:
Draw a Lewis structure for BCl3 and answer the following questions based on your drawing.
1. For the central boron atom:
A. The number of lone pairs = ___
B. The number of single bonds = ___
C. The number of double bonds = ___
2. The central boron atom __
A. Obeys the octet rule
B. Has an incomplete octet.
C. Has an expanded octet.
Answer:
1. For the central boron atom:
A. The number of lone pairs = 0.
B. The number of single bonds = 3.
C. The number of double bonds = 0.
2. The central boron atom B. Has an incomplete octet.
Explanation:
Hello,
In this case, as shown on the attached picture containing the required Lewis structure of boron chloride, we can see that:
1. For the central boron atom:
A. The number of lone pairs = 0 since all the three valance electrons are bonded with the chlorine atoms.
B. The number of single bonds = 3 as each chlorine atom needs only one bond to obey the octet.
C. The number of double bonds = 0 considering the previous explanation.
2. The central boron atom B. Has an incomplete octet since it reaches six electrons only from its initial three and other three provided by the three chlorine atoms.
Regards.
Calculate the molar solubility of magnesium fluoride (MgF2) in a solution that is 0.250 M in NaF. For magnesium fluoride, Ksp = 5.16 * 10 - 11.
Answer:
Molar solubility of magnesium fluoride (MgF2) = 8.26 × 10⁻¹⁰ M
Explanation:
Given:
Ksp = 5.16 × 10⁻¹¹
NaF = 0.250
Find:
Molar solubility of magnesium fluoride (MgF2)
Computation:
Molar solubility of magnesium fluoride (MgF2) = Ksp / NaF²
Molar solubility of magnesium fluoride (MgF2) = 5.16 × 10⁻¹¹ / (0.250)²
Molar solubility of magnesium fluoride (MgF2) = 8.26 × 10⁻¹⁰ M
The molar solubility of magnesium fluoride (MgF2) is 8.26 × 10⁻¹⁰ M.
Calculation of the molar solubility:Since
Ksp = 5.16 × 10⁻¹¹
NaF = 0.250
Now we know that
Molar solubility of magnesium fluoride (MgF2) = Ksp / NaF²
= 5.16 × 10⁻¹¹ / (0.250)²
= 8.26 × 10⁻¹⁰ M
hence, The molar solubility of magnesium fluoride (MgF2) is 8.26 × 10⁻¹⁰ M.
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Nonmetallic elements form ions by _______ valence electrons to complete their outer shell. The ______ valence electrons an element has in its outer shell, the easier it is to complete. The _______ electron shells an element has, the easier it is to fill its outermost shell. Reactivity in nonmetals _______ as you go from left to right in a group, and ______ as you go from top to bottom.
Answer:
Nonmetallic elements form ions by gaining valence electrons to complete their outer shell.
The more valence electrons an element has in its outer shell, the easier it is to complete.
The fewer electron shells an element has, the easier it is to fill its outermost shell.
Reactivity in nonmetals increases as you go from left to right in a group, and
decreases as you go from top to bottom.
Explanation:
Nonmetallic elements form ions by gaining valence electrons to complete
their outer shell.
The more valence electrons an element has in its outer shell, the easier it is to complete.
The fewer electron shells an element has, the easier it is to fill its outermost shell.
Reactivity in nonmetals increases as you go from left to right in a group, and decreases as you go from top to bottom.
When there are more valence electrons then it makes it easy for the element
to complete its outermost shell as against if it was less as it would be harder
due to a bigger number of electrons needed.
Non metals are elements which accepts valence electrons to complete its
outermost shell and becomes negatively charged when this happens.
When an element has fewer electron shells then filling the outermost shell
will be easier as the electron shells require a lesser number of electrons and
increases as the number of shells increases.
This is because the tendency to accept electrons increases from left to right
and decreases down the group.
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LiAlH4 reacts with acid chlorides to yield secondary alcohols after hydrolysis.
a. True
b. False
Answer:
a. True
Explanation:
In this reaction, we will have a hydride transfer to the carbon of the carbonyl group, moving the electrons of the double bond towards the oxygen producing a negative charge. The double bond is then regenerated by removing the chlorine atom from the molecule, producing an aldehyde.
Then, another molecule the LiAlH4 transfers another hydride to the carbon of the carbonyl group, again producing a negative charge on the oxygen. Finally, the hydrogen is protonated producing a primary alcohol.
See figure 1
I hope it helps!
Given: There are 39.95 grams of Argon (39.95 g/1 mole) and one mole has a volume of 22.4 Liters (1 mole/22.4 L). What is the volume, in Liters, of 34.3 grams of Argon?
Answer:
[tex]V_2=19.23L[/tex]
Explanation:
Hello,
In this case, by using the Avogadro's law which allows us to understand the volume-moles behavior as a directly proportional relationship:
[tex]\frac{V_2}{n_2} =\frac{V_1}{n_1}[/tex]
We can compute the volume of 34.3 g of argon by representing it in mole as shown below:
[tex]n_1=1 mol\\\\n_2=34.3g*\frac{1mol}{39.95g} =0.859mol[/tex]
Thus, we find:
[tex]V_2=\frac{V_1*n_2}{n_1}=\frac{22.4L*0.859mol}{1mol} \\\\V_2=19.23L[/tex]
Best regards.
A certain solution has a molarity of M = 3.14 mol/L and has a volume of V = 0.760 L . What is the value of n? Express your answer numerically in moles.
Answer:
Thinking...
o-O
(ﾉ◕ヮ◕)ﾉ*:･ﾟ✧
Which of the following reactions should have the larger emf under standard conditions? Why?
CuSO4(aq)+Pb(s) ⇌ PbSO4(s)+Cu(s)
Cu(NO3)2(aq)+Pb(s) ⇌ Pb(NO3)2(aq)+Cu(s)
Answer:
Cu(NO3)2(aq)+Pb(s) ⇌ Pb(NO3)2(aq)+Cu(s)
Explanation:
If we look at the both reactions closely, we will quickly discover that the reaction CuSO4(aq)+Pb(s) ⇌ PbSO4(s)+Cu(s) involves PbSO4.
The compound PbSO4 is insoluble in water and sinks to the bottom of the reaction vessel. When this occurs, the concentration of Pb^2+ becomes low. This will bring about a low voltage in the cell.
On the other hand, Pb(NO3)2 is soluble in water hence the cell voltage in this case is higher than the former.
In the case when we look at both reactions so here we discovered that the reaction of
CuSO4(aq)+Pb(s) ⇌ PbSO4(s)+Cu(s) includes PbSO4.
The compound PbSO4 should be insoluble in water and sinks to the bottom of the reaction vessel. At the time When this occurs, the concentration of Pb^2+ becomes low. This will bring about a low voltage in the cell.
On the other hand, Pb(NO3)2 is soluble in water so the cell voltage in this case is more than the former.
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Calculate the mole fraction of KI in a solution made by dissolving 3.4 g of KI in 5.8 g of water. (Step by step)
A. 0.060
B. 0.064
C. 0.37
D. 0.59
E. 6.4
Answer:
The correct answer is 0.058
Step-by-step explanation:
The mole fraction of KI (X) in the solution is the number of moles of KI divided into the total number of moles of the solution (nt):
X= moles KI/nt
First we have to calculate the molecular weights of the components of the solution: KI and water (H₂O):
Molecular weight (Mw) of KI:
Mw(KI)= 39 g/mol + 127 g/mol = 166 g/mol
Molecular weight of H₂O:
Mw(H₂O)= (1 g/mol x 2) + 16 g/mol = 18 g/mol
Then, we calculate the number of moles there is of each component in the solution by dividing the mass into Mw:
Moles of KI= mass KI/Mw(KI) = 3.4 g/166 g/mol = 0.020 mol KI
Moles of H₂O= mass H₂O/Mw(H₂O)= 5.8 g/18 g/mol = 0.322 mol H₂O
Thus, the total moles of solution will be:
nt= moles KI + moles H₂O= 0.020 mol + 0.322 mol = 0.342 mol
Finally, we divide the moles of KI into the total moles of solution (nt) to obtain the mole fraction (X):
X= moles KI/nt = 0.020 mol/0.342 mol = 0.058
What is a Spontaneous charge
This means a release of free energy from the system corresponds to a negative change in free energy, but to a positive change for the surroundings.
Which one of the following would produce 2-ethoxypropane in high yield?
a. t-butyl chloride + sodium methoxide
b. t-butanol + methanol in presence of H2SO4 at 140 C
c. t-butyl bromide + bromomethane in presence of NaOH
d. sodium t-butoxide + bromomethane
Answer:
d. sodium t-butoxide + bromomethane
Explanation:
Sodium t-butoxide is a strong base with the chemical formula (CH3)3CONa and it is a non-nucleophilic base while bromomethane with the chemical formula CH3Br.
They both together gives 2-ethoxypropane (C5H12O).
(CH3)3CONa + CH3Br => C5H12O + NaBr
Hence, the correct option is "d".
Vegetable oil has a specific heat of 1.67/* Calculate the heat required (in kilojoules) to raise the temperature of 500 g of
vegetable oil from room temp (20.0°C) to 150.0°C
Answer:
[tex]Q=108.55kJ[/tex]
Explanation:
Hello,
In this case, we can compute the required heat by using the following equation:
[tex]Q=mCp(T_2-T_1)[/tex]
Thus, by considering the given mass, specific heat and both initial and final temperature, we obtain:
[tex]Q=500g*1.67\frac{J}{g\°C} *(150.0\°C-20.0\°C)*\frac{1kJ}{1000J} \\\\Q=108.55kJ[/tex]
Regards.
The tosylate of (2S,3S)-3-phenylbutan-2-ol undergoes an E2 elimination on treatment with sodium ethoxide. Draw the structure of the alkene that is produced
Answer:
Please find the attachment to this question:
Explanation:
By eliminating the agent produced in the reaction, it will give a structure of the alkene. please find the given attachment.
Balance this reaction ch3oh+02 c02 h20
Answer:
2CH3OH + 3O2 --> 2CO2 + 4H2O
This is called Combustion of Methanol
Explanation:
Count the numbers of atoms on each sides and try to get the same amount of quantity on each sides, so you'll eventually get "balanced".
or
Watch this video: "How to Balance CH3OH + O2 = CO2+ H2O (Combustion of Methanol)"
Good luck with future work! Keep studying chemistry!
- D
The cylinder of aluminum in class was approximately 13mm in circumference and 42mm in length. What would be it's approximate mass?
Answer:
Mass, m = 1.51 grams
Explanation:
It is given that,
The circumference of Aluminium cylinder, C = 13 mm = 1.3 cm
Length of the cylinder, h = 4.2 cm
We know that the density of the Aluminium is 2.7 g/cm³
Circumference, C = 2πr
[tex]r=\dfrac{C}{2\pi}\\\\r=\dfrac{1.3}{2\pi}\\\\r=0.206\ cm[/tex]
Density is equal to mass per unit volume.
[tex]d=\dfrac{m}{V}[/tex]
m is mass of the cylinder
V is the volume of the cylinder
[tex]V=\pi r^2h\\\\V=\dfrac{22}{7}\times0.206^2\times 4.2\\\\V=0.5601\ cm^3[/tex]
So,
[tex]m=d\times V\\\\m=2.7\times 0.5601\\\\m=1.51\ g[/tex]
So, the mass of the cylinder is 1.51 grams.
Calculate the solubility of BaCO3 (a) in pure water and (b) in a solution in which [CO32-] = 0.289 M. Solubility in pure water = M Solubility in 0.289 M CO32- = M
Answer:
(a). The solubility of [tex]BaCO_{3}[/tex] in pure water is [tex]4.4\times10^{-5}\ M[/tex]
(b). The solubility of [tex]BaCO_{3}[/tex] in solution is [tex]6.92\times10^{-9}\ M[/tex]
Explanation:
Given that,
(a). The solubility of [tex]BaCO_{3}[/tex] in pure water
(b). The solubility of [tex]BaCO_{3}[/tex] in a solution
Solubility of [tex]CO_{3}^{-2}[/tex] is 0.289 M
We know that,
The solubility product constant of [tex]BaCO_{3}[/tex] is [tex]2\times10^{-9}[/tex]
Let the solubility of [tex]BaCO_{3}[/tex] is s.
We need to calculate the solubility of [tex]BaCO_{3}[/tex] in pure water
Using formula of solubility
[tex]ksp=s\times s[/tex]
[tex]ksp=s^2[/tex]
[tex]s=\sqrt{ksp}[/tex]
Put the value into the formula
[tex]s=\sqrt{2\times10^{-9}}[/tex]
[tex]s=4.4\times10^{-5}\ M[/tex]
(b). We need to calculate the solubility of [tex]BaCO_{3}[/tex] in solution
Using formula of solubility
[tex]ksp=s\times s[/tex]
Put the value into the formula
[tex]2\times10^{-9}=s\times 0.289[/tex]
[tex]s=\dfrac{2\times10^{-9}}{0.289}[/tex]
[tex]s=6.92\times10^{-9}\ M[/tex]
Hence, (a). The solubility of [tex]BaCO_{3}[/tex] in pure water is [tex]4.4\times10^{-5}\ M[/tex]
(b). The solubility of [tex]BaCO_{3}[/tex] in solution is [tex]6.92\times10^{-9}\ M[/tex]
Which of the following is considered a form of technology?
Select one:
a. A line of thought used to explain logically what happened in an experiment.
b. A beaker used in an experiment.
C. A series of procedures followed in an experiment.
d. The ethical practice of considering human and animal rights in research studies.
Answer:
B. a beaker used in an experiment
Explanation:
Which number has four significant figures? 0.05730 meters 40.007 meter 0.00073 meter 8765 meter
Answer:
All non-zero digits are significant
Explanation:
How many moles of UF6 would have to be decomposed to provide enough fluorine to prepare 8.99 mol of CF4? (Assume sufficient carbon is available).
Answer:
5.99 moles of [tex]UF_6[/tex]
Explanation:
In this case, we can start with the decomposition of [tex]UF_6[/tex], so:
[tex]UF_6~->~U~+~3F_2[/tex] (Reaction 1)
The [tex]F_2[/tex] can react with carbon to produce [tex]CF_4[/tex]:
[tex]CF_4~+~2F_2~->~CF_4[/tex] (Reaction 2)
If we 8.99 mol of [tex]CF_4[/tex], we can calculate the moles of [tex]F_2[/tex] that we need. In reaction 2 we have a molar ratio of 1:2 (2 moles of [tex]F_2[/tex] will produce 1 mol of [tex]CF_4[/tex]):
[tex]8.99~mol~CF_4\frac{2~mol~F_2}{1~mol~CF_4}~=~17.98~mol~F_2[/tex]
With this value and using the molar ratio in reaction 1 (3 moles of [tex]F_2[/tex] are producing by each mol of [tex]UF_6[/tex]), so:
[tex]17.98~mol~F_2\frac{1~mol~UF_6}{3~mol~F_2}~=~5.99~mol~UF_6[/tex]
So, we will need 5.99 moles of [tex]UF_6[/tex] to produce 8.99 mol of [tex]CF_4[/tex].
I hope it helps!
what is point group of allene?
Allene (1,2-propadiene) has point group D2d, itself is achiral because it has two planes of symmetry. ... An allene with substituents on one terminal carbon atom are unlike and substituent on other terminal carbon atoms are same, allene will be achiral. It will have one symmetry plane.
Hope this helped :)
A liquid boils when its:_________
a. Temperature is equal to 273 K (standard temperature).
b. Vapor pressure is equal to, or greater than, the external pressure pushing on it.
c. Temperature is greater than room temperature.
d. Vapor pressure is exactly 1 atmosphere.
Answer:
option a. Temperature is equal to 273 k. Is the correct one
A boils when its vapour pressure is equal to, or greater than, the external pressure pushing on it. Therefore, option (b) is correct.
What is the boiling point?A boiling point of a liquid can be defined as the temperature at which the vapour pressure becomes equal to the atmospheric pressure of the liquid. The liquid is converted into a vapour at this temperature.
With the addition of heat that the liquid changes into vapour without any increase in temperature. The vapour pressure increases until it is equal to the pressure of the gas surrounding it as a liquid is heated. Bubbles of vaporized liquid are formed within the liquid and rise to the surface.
At the boiling temperature, the vapour inside the bubble will exert enough pressure to prevent the bubble from collapsing. The molecules of a liquid will able to overcome the forces of attraction between molecules to create vapour.
Therefore, at boiling point, the vapour pressure is equal to, or greater than, the external pressure pushing on it.
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8. An unknown mixture that is uniform, does show the Tyndall Effect, and does
not have any particles settling out is a... *
solution
colloid
suspension
pure substance
Answer:
B. Colloid
Explanation:
Colloid is a mixture that is made up of very small homogeneous particles, thus can not be separated into fractions. Its particles do not settle as other solution, but are evenly dispersed in the medium. Some examples are: liquid milk, jelly, rubber etc
Since colloid is a solution, thus it is made up of two parts; its particles and dispersing medium.
Which of the following substances has the strongest intermolecular forces?
a. HCl
b. C8H18
c. CH3OH
d. CH4
e. CO2
Answer:
HCl.
Explanation:
Of all the type of bond, Ionic bonds are the strongest. Among all the compounds in the options only HCl has ionic bond, rest have covalent bonds. So, the strongest intermolecular forces is in HCl. Ionic bond are formed with the transfer of electrons, one atom is donor and the other is acceptor.
The internal energy of 10 moles of helium (a monatomic gas) is 15 kJ. What is the rms speed of the molecules? (The molar mass of helium is 4.00 g/mole.)
Answer:
[tex]v_{rms}=866.32m/s[/tex]
Explanation:
Hello,
In this case, since the rms speed of the molecules is computed by:
[tex]v_{rms}=\sqrt{\frac{3RT}{M} }[/tex]
Whereas the absolute temperature is computed from the internal energy (by using the Cp of helium (3.1156 J/g*K) as shown below:
[tex]U=nCvT\\\\T=\frac{U}{nCv}=\frac{15kJ*\frac{1000J}{1kJ} }{10mol*\frac{4.00g}{1mol} *3.1156\frac{J}{g*K} } \\\\T=120.36K[/tex]
Thereby, the rms speed results:
[tex]v_{rms}=\sqrt{\frac{3*8.314\frac{kg*m^2}{s^2*mol*K}*120.36K}{4.00\frac{g}{mol}*\frac{1kg}{1000} } } \\\\v_{rms}=866.32m/s[/tex]
Regards.
A family pool holds 10,000.0 gallons of water. How many cubic meters is this?
264.2 gal = 1.0 cubic meter
Answer:
Hey there!
10000 gallons would be 37.85 cubic meters.
Let me know if this helps :)
Answer: 37.8501 m³
Explanation:
10000.0 gal × 1 m³/264.2 gal
=37.8501 m³ (significant digits)
Will the addition of NaC2H3O2 to a CH3COOH solution cause the pH to increase or decrease? Explain.
Answer:
pH will be increased.
Explanation:
When you mixed sodium acetate and acetic acid, pH will be maintained and will have slight changes. This constitutes what is known as a buffer solution.
But if you analize the reactions:
First of all, you have a weak acid, acetic:
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺ Ka
And the salt can be dissociated as:
NaCH₃COO → CH₃COO⁻ + Na⁺
As you are adding acetate, this is the conjugate strong base from the weak acid and as every base, it brings hydroxides to medium, so the pH will be increased. Protons from the acid will be neutralized, thouhgh.
CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻ Kb