Answer:
the mantel
Explanation:
the asthenosphere is the part of the mantle that flows and moves the plates of the earth. the mantle is the layer located directly under the sima. it is the largest layer of the earth, 1800 miles thick.
hope this helps :) have a nice day !!
to calculate the voltage, current, power and energy for an inductor and also to examine the behavior of an inductor under dc conditions. an inductor is a passive circuit element that opposes any change in electric current. a time-varying current induces a voltage in any conductor linked by a magnetic field. an inductor is a passive circuit element that stores energy in its magnetic field.
Answer:
To calculate the voltage, current, power and energy for an inductor and also to examine the behavior of an inductor under dc conditions.
an inductor is a passive circuit element that stores energy in its magnetic field.
Explanation:
An inductor has been described as a passive electronic component that stores electrical energy in a magnetic form. It uses a conductor that is wound into a coil to produce DC current, acting as a short circuit when direct current is applied. When electricity flows into the coil from the left to the right, a current is generated through a magnetic field in the clockwise direction. It is also called a choke because of its frequency regulation.
The mass and weight of box is 25 Kg and 245 N respectively when on Earth. What is the value of mass and weight of the box when it is brought to the moon?
Answer:
25 (kg) and 40.5 (N).
Explanation:
1) the value of 'g' on the Earth is ~9.81 (N/kg), the value of 'g' on the Moon is ~1.62 (N/kg).
It means, the mass is not depended on the value of 'g', but the weight is depended on it.
2) the mass on the Moon is the same, 25 kg.
the weight is 25*1.62=40.5 N
1When you look through a magnifying glass, the objects you are looking at
seem larger and you can see them in morsetail. The lenses in a magnifying
glass are
convex lenses.
eyeglasses with convex lenses increase refraction, and accordingly reduce the focal lenght
Three point charges are fixed in place in a right triangle, as shown in the figure.
What is the magnitude of the electric force on the +1.00-C charge due to the other two charges?
What angle does the force make with the -x-axis? A positive angle is counterclockwise from the -x-axis.
For the three-point charges fixed in a right triangle, we have:
1. The magnitude of the electric force on the +1.00 μC charge is 1.79 N.
2. The force does an angle of 21.68° with the x-axis.
1. Magnitude of the electric forceFirst, let's denote the charges as is shown in the picture below:
q₁: is the charge 1 = +0.800 μC = +0.800x10⁻⁶ Cq₂: is the charge 2 = +1.00 μC = +1.00x10⁻⁶ Cq₃: is the charge 3 = -0.600 μC = -0.600x10⁻⁶ C
The magnitude of the electric force on the charge 2 (+1.00 μC) is given by:
[tex]|F_{net}| = \sqrt{(\Sigma\vec{F}_{x})^{2} + (\Sigma\vec{F}_{y})^{2}}[/tex] (1)
Where:
[tex]\Sigma\vec{F}_{x}[/tex]: is the sum of the forces acting on the x-axis[tex]\Sigma\vec{F}_{y}[/tex]: is the sum of the forces acting on the y-axisWe can calculate the electrical forces with Coulomb's law:
[tex]\vec{F} = \frac{Kq_{1}q_{2}}{d^{2}}[/tex]
Where:
K is the Coulomb's constant = 9.00x10⁹ Nm²/C² q₁ and q₂ are the chargesd is the distance between the charges
Forces in the x-axis ([tex]\Sigma\vec{F}_{x}[/tex])
The forces in the x-component are given by:
[tex]\Sigma\vec{F}_{x} = \vec{F}_{21}_{x} + \vec{F}_{23}_{x}[/tex]
[tex]\Sigma\vec{F}_{x} = \vec{F}_{21}_{x}cos(\theta) + \vec{F}_{23}_{x}[/tex]
[tex]\Sigma\vec{F}_{x} = \frac{Kq_{1}q_{2}}{d_{12}^{2}}cos(\theta) + \frac{Kq_{2}q_{3}}{d_{23}^{2}}[/tex] (2)
Where:
θ: is the angle of the force F₂₁ with the x-axisd₁₂ = z = 9.60 cm = 0.0960 m d₂₃ = xWe can calculate the angle θ with the following trigonometric function:
[tex]sin(\theta) = \frac{y}{z}[/tex]
[tex]\theta = sin^{-1}(\frac{y}{z}) = sin^{-1}(\frac{8.10 cm}{9.60 cm}) = 57.5 ^\circ[/tex]
To find the distance x (d₂₃), we need to use Pythagoras:
[tex]x = \sqrt{z^{2} - y^{2}} = \sqrt{(0.0960 m)^{2} - (0.0810 m)^{2}} = 0.051 m[/tex]
After entering θ and x (d₂₃) into equation 2, we have:
[tex]\Sigma\vec{F}_{x} = \frac{9.00\cdot 10^{9} Nm^{2}C^{-2}(0.800 \cdot 10^{-6} C)(1.00 \cdot 10^{-6} C)}{(0.0960 m)^{2}}cos(57.5) + \frac{9.00 \cdot 10^{9}Nm^{2}C^{-2}(1.00 \cdot 10^{-6} C)(-0.600 \cdot 10^{-6} C)}{(0.051 m)^{2}}[/tex]
[tex]\Sigma\vec{F}_{x} = [0.78*cos(57.5) + (-2.08) N] = -1.66 N[/tex]
Hence, the x-component of the force is -1.66 N.
Forces in the y-axis ([tex]\Sigma\vec{F}_{y}[/tex])
The only force acting on the y-axis is the y-component of the force F₂₁, so:
[tex]\Sigma\vec{F}_{y} = -\vec{F}_{21}_{y} = -\vec{F}_{21}sin(\theta)[/tex]
The minus sign is because the vector is pointing in the negative y-direction (see the picture below).
[tex]\Sigma \vec{F}_{y} = -\frac{9.00\cdot 10^{9} Nm^{2}C^{-2}(0.800 \cdot 10^{-6} C)(1.00 \cdot 10^{-6} C)}{(0.0960 m)^{2}}sin(57.5) = -0.66 N[/tex]
Hence, the y-component of the force is -0.66 N.
Finally, the magnitude of the electric force on the charge +1.00 μC is (eq 1):
[tex]|F_{net}| = \sqrt{(-1.66 N)^{2} + (-0.66 N)^{2}} = 1.79 N[/tex]
Therefore, the magnitude of the electric force on the +1.00 μC charge is 1.79 N.
2. Direction of the force with the x-axisAccording to the picture below, the angle of the force with respect to the x-axis is given by:
[tex]tan(\beta) = \frac{\Sigma\vec{F}_{y}}{\Sigma\vec{F}_{x}}[/tex]
[tex]\beta = tan^{-1}(\frac{-0.66 N}{-1.66 N}) = 21.68 ^\circ[/tex]
Therefore, the force does an angle of 21.68° with the x-axis.
Find more about Coulomb's law here:
brainly.com/question/506926
I hope it helps you!
Why could the beam of particles not have a neutral charge?
Answer:
The positive and negative charges balance each other. Overall, the atom is uncharged (neutral). However, if something happens to make an atom lose or gain an electron then the atom will no longer be neutral. An atom that gains or loses an electron becomes an ion.
Explanation:
I think this is the answer : D
if the earth's atmosphere were 50times denser than it is, would sunlight still be while or would it be some other colour? explain
Could I please get some help on this question I don’t understand .
Answer:
12.5 m/s
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 0 m/s
Height (h) = 8 m
Final velocity (v) at 8 m above the lowest point =?
NOTE: Acceleration due to gravity (g) = 9.8 m/s²
The velocity of the roller coaster at 8 m above the lowest point can be obtained as follow:
v² = u² + 2gh
v² = 0² + (2 × 9.8 × 8)
v² = 0 + 156.8
v² = 156.8
Take the square root of both side
v = √156.8
v = 12.5 m/s
Therefore, the velocity of the roller coaster at 8 m above the lowest point is 12.5 m/s.
The bus is heading southwest at 56 miles per hour is it veloctiy or speed
Answer:
Its velocity
Explanation:
Velocity is speed with a direction.
Speed is the rate at which someone or something is able to move or operate.
In the question its telling us that the bus is going 56 miles per hour but it aslo gives us a direction, in this case is southwest.
How much work is done against gravity when lifting a 2-kg sack of groceries a distance of 2.5 meters?
A child throws a ball with an initial speed of at an angle of 40.0° above the horizontal. The ball leaves her hand 1.00 m above the ground and experience negligible air resistance. (a) What is the magnitude of the ball's velocity just before it hits the ground? (b) At what angle below the horizontal does the ball approach the ground?
Complete Question
A child throws a ball with an initial speed of 8.00 at an angle of 40.0° above the horizontal. The ball leaves her hand 1.00 m above the ground and experience negligible air resistance. (a) What is the magnitude of the ball's velocity just before it hits the ground? (b) At what angle below the horizontal does the ball approach the ground?
Answer:
[tex]v=9.16m/s[/tex]
[tex]\theta=48.1 \textdegree[/tex]
Explanation:
From the question we are told that
Angle of ball [tex]\angle=40 \textdegree[/tex]
Height of ball h=1m
Generally the equation for vertical component is mathematically given by
[tex]v_y=vsin \theta[/tex]
[tex]v_y=8sin 40 \textdegree[/tex]
[tex]v_y=5.14m/s[/tex]
Generally the equation for horizontal component is mathematically given by
[tex]v_x=vcos \theta[/tex]
[tex]v_x=8cos 40 \textdegree[/tex]
[tex]v_x=6.12m/s[/tex]
Generally the equation for vertical displacement of ball is mathematically given by
[tex]y=1+v-yt-\frac{1}{2}gt^2[/tex]
[tex]0=1+5.14t-\frac{1}{2}*9.87*t^2[/tex]
[tex]t=1.22sec[/tex]
[tex]v_yt=v_yt-gt[/tex]
[tex]5.14-(9.8*1.22)=-6.816m/s[/tex]
[tex]v_yt=-6.816m/s[/tex]
Generally the velocity of ball before it hits the ground is mathematically given by
Magnitude
[tex]v=\sqrt{6.12^2 +(-6.816)^2}\\[/tex]
[tex]v=9.16m/s[/tex]
Direction of ball
[tex]\theta=tan^{-1}(\frac{-6.816}{6.12} )[/tex]
[tex]\theta=48.1 \textdegree[/tex] beneath the horizontal
give two differences between sextusl reproduction and asextual reproduction
Answer:
Sexual reproduction you need two organisms to reproduce.
Asexual is when you can multiply yourself and there is nothing different about the offspring and the parent.
What does the speedometer in a moving car measure?
A cyclist rides 3 km west and then turns around and rides 2 km east. What is her displacement?
Answer:
1km west
Explanation:
Because if the cyclist is going back 2km then its 3-2=1km
Which type of wave needs a medium to travel?
ANSWER: sound waves, because they travel by oscillating molecules
What do both sound and light waves transfer?
ANSWER: Energy
How does an increase in amplitude affect sound and light waves?
ANSWER: louder sound and brighter light
What happens to the wavelength and speed of the waves when the frequency increases?
ANSWER: The wavelength decreases, but speed remains the same.
Which statement about sound waves is correct?
ANSWER: The animated particles are more concentrated along wave crests and less dense along wave troughs.
Answer:
Mechanical Waves
Why I Know:
Science Class
A type of wave that needs a medium to travel is sound wave because it travels through oscillating molecules.
What is a sound wave?A sound wave can be defined as a form of mechanical wave that requires a medium for its propagation and it creates a disturbance in the medium. Also, the energy of a sound wave travels in a perpendicular direction.
This ultimately implies that, a sound wave needs a medium to travel and it creates a disturbance when it travels through any medium.
In conclusion, a type of wave that needs a medium to travel is sound wave because it travels through oscillating molecules.
Read more on sound wave here: https://brainly.com/question/19250621
Which of the following has the most kinetic energy?
A.
A car traveling at 80 kph.
B.
A tractor trailer traveling at 80 kph.
C.
A cheetah running at 80 kph.
D.
A notorcycle traveling at 80 kph.
Answer:
B
Explanation:
A tractor is the heaviest
Why do we prefer a sharp knife to a blunt one to cut vegetables ?
A ball is thrown horizontally from a height of 1 m and lands 5 m away.What is the initial velocity of the ball?
Answer:
11.06797181 ms^-1 only.......
Shine the flashlight on the liquid sheet. Did you observe evidence that light carries energy
Answer:
Think of an object you have observed ... Work with your group to gather evidence that light carries energy, then answer the questions below. Shine the flashlight on the liquid crystal sheet.
Which diagram is the best model for a solid?
Substance A
Substance B
О Substance C
Answer:
This link was diagram
Explanation:
https://doubtnut.app.link/FnsNC80Dccb
What is the equation of the line that is perpendicular to y= -4x +5 and passes through the point (4,-3)?
An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only a rope and a bag of tools. First he tries to throw a rope to his fellow astronaut, but the rope is too short. In a last ditch effort, the astronaut throws his bag of tools in the direction of his motion, away from the space station. The astronaut has a mass of ma=102 kgma=102 kg and the bag of tools has a mass of mb=10.0 kg.mb=10.0 kg. If the astronaut is moving away from the space station at vi=2.10 m/svi=2.10 m/s initially, what is the minimum final speed vb,fvb,f of the bag of tools with respect to the space station that will keep the astronaut from drifting away forever?
Answer:
The answer is "[tex]2.352 \ \frac{m}{s}[/tex]"
Explanation:
[tex]\to mass(m_1)=102 \ kg\\\\\to mass(m_2)=10 \ kg \\\\\to v=2.10\ \frac{m}{s}\\\\[/tex]
momentum before:
[tex]\to p=(m_1+m_2)v[/tex]
[tex]=(102+10)2.10\\\\=(102\times 2.10 +10 \times 2.10)\\\\=214.2+21\\\\=235.2[/tex]
momentum After:
[tex]\to p=(m_1+m_2)v[/tex]
[tex]=(102\times 0 +10 \times v)\\\\ =(0 +10v)\\\\=10v\\[/tex]
Calculating the conservation of momentum:
[tex]\to \text{momentum before = momentum After}[/tex]
[tex]\to 235.2=10v\\\\\to v= \frac{235.2}{10}\\\\ \to v=2.352 \ \frac{m}{s}[/tex]
How many significant figures are there in the number
2.3409500?
An ice skater of mass 82 kilograms stands at rest in her skates on the ice rink. Someone throws a 5-kg ball at her at a speed of 17.4 m/s and she catches it. At what speed will she(and the ball) slide backwards?
Answer:
1 m/s
Explanation:
I showed my work in the picture attached.
This web page helped me solve this problem and understand inelastic collisions a little better:
https://byjus.com/physics/inelastic-collision/
She slide(and the ball) backwards at the speed of 1m/s when she catches the ball of 5-kg coming at speed of 17.4 m/s.
What is momentum ?Momentum is defined as mass times velocity. it tells about the moment of the body. it is denoted by p and expressed in kg.m/s. mathematically it is written as p = mv. A body having zero velocity or zero mass has zero momentum. its dimensions is [M¹ L¹ T⁻¹].
Momentum is conserved throughout the motion.
According to conservation law of momentum initial momentum is equal to final momentum.
Given,
mass of the skater m₁ = 82 kg
mass of the ball m₂ = 5kg
initial velocity of the ball v'₂ = 17.4 m/s
initial velocity of the skater v''₂= v'₁= 0
final velocity of the ball & skater = v''₁ = ?
According to law of conservation of momentum,
initial momentum = final momentum
m₁v'₁ +m₂v'₂ = m₁v₁'' + m₂v''₂
putting all values in the equation.
0+ 5×17.4 = 82×v₁'' + 5×v₁''
v₁''(82+5) = 87
v₁'' = 1 m/s
Hence he(and the ball) slide backwards at 1m/s
To know more about conservation of momentum click :
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1 A boy kicks a ball with 40m/s at an angle of 30° with the ground. find the range the ball travels after 6 s.
240 m
208 m
120 m
139 m
Answer and I will give you brainiliest.
Answer:
208m
Explanation:
since the angle is with the ground which gives a horizontal component to the velocity = v(cos)30°
so the velocity equals 40(cos)30°= 34.64m/s
range(distance) = speed × time
34.64m/s × 6s = 207.8m = 208m
8. Which phase of matter is most common in the
universe?
a. Plasma b. Solid c. Liquid d. Gas
Need this now
Answer:
plasma
Explanation:
Cause in the universe many exist in either in gaseous or plasma form but plasma is greater
Explain the theory of plate tectonics and how they have changed Earth’s surface over time. Include the role of plate tectonics in the creation of landforms.
Plate tectonic theory is the movement of the plates or slabs of rigid rocks over the surface of the earth or the molten rocks that is the mantel.
It explains how the continents have drifted over time due to the changes in the earth's geology over the years. It also explains how earthquakes, volcanic eruptions, and mountain ranges are created. Hence the arrangement and formation of the present shape of the earth continents.Learn more about plate tectonics and how they have changed Earth.
brainly.com/question/19649061.
help help help help help help help help help
A dolphin has a mass of 740 kg. He swims along the water at a velocity of 12 m/s and
jumps out of the water so that he has Gravitational Potential Energy of 53000 J.
How high does the dolphin jump?
Answer:
I dunno
Explanation:
I really wanted to help you, but then I realized i didnt know how to
11. What is the mass of an object which has 2400 J of KE when traveling at 5 points
6 m/s?
63 kg
130 kg
270 kg
400 kg
Answer:
270 Kg e 130 kg
Explanation:
how many times is the number put together
An inflated spherical beach ball with a radius of 0.4000 m and average density of 10.65 kg/m3 is being held under water in a pool by Janelle. The density of the water in the pool is 1000.0 kg/m3. When Janelle releases the ball, it begins to rise to the surface. If the drag coefficient of the ball in the water is 0.520 and the constant upward force on the ball is 2630 N, what will be the terminal speed of the ball as it rises
Answer:
3.71 m/s
Explanation:
Given data :
radius of the spherical ball = 0.400 m
Density of the ball material = 10.65 Kg/m^3
Density of water = 1000 Kg/m^3
Drag coefficient C_d= 0.520
Constant upward force F_up= 2630
Concept: The moment before it starts to rise Upward force must be equal to downward drag force
⇒ F_up = F_D
F_D =C_d× 0.5 ×ρ_w×V^2×A
where V= terminal velocity and A= area πR^2
equating the forces we get
2630= 0.52× 0.5×1000×V^2×π(0.4)^2
V= 3.171 m/s
Therefore, the terminal velocity of the ball = 3.71 m/s
The ball while moving through the water in the pool, experiences a drag force. Then, the magnitude of terminal speed during the rise of the ball is 3.171 m/s.
What is terminal speed?When an object is made to fall through a liquid medium, then the maximum velocity achieved at that instant is known as terminal velocity or terminal speed.
Given data-
The radius of the spherical beach ball is, r = 0.4000 m.
The density of the ball is, [tex]\rho'=10.65 \;\rm kg/m^{3}[/tex].
The density of water in the pool is, [tex]\rho =1000.0 \;\rm kg/m^{3}[/tex].
The drag coefficient of the ball in water is, [tex]C_{d}=0.520[/tex].
The magnitude of the constant upward force is, F = 2630 N.
As per the concept of Buoyancy, "The moment before the ball starts to rise upward force must be equal to downward drag force".
F = Fd
Here,
F is the upward force.
Fd is the downward force.
[tex]F=\dfrac{1}{2} \times C_{d} \times \rho \times v^{2} \times A[/tex]
Here,
A is the area of the ball.
Solving as,
[tex]2630=\dfrac{1}{2} \times 0.520 \times 1000 \times v^{2} \times (\pi r^{2})\\\\2630=\dfrac{1}{2} \times 0.520 \times 1000 \times v^{2} \times (\pi \times 0.4000^{2})\\\\v=3.171 \;\rm m/s[/tex]
Thus, we can conclude that the magnitude of terminal speed during the rise of the ball is 3.171 m/s.
Learn more about the terminal speed here:
https://brainly.com/question/26505185