What is the value of x? 4/5 times 1/10 =3/10

Answer:

Hey there!

Your answer is close- but not quite! You chose y=10x, however, if you look closely, the cost is 10 at 2 sandwiches. Thus, the slope should be 5, and correct answer would be y=5x.

Let me know if this helps :)

Answer:

the answer should be C

Answer:

y = 9

Step-by-step explanation:

6.4x + 2.8y = 44.4

6.4(3) + 2.8y = 44.4

19.2 + 2.8y = 44.4

2.8y = 25.2

y = 9

Answer:

f(x)=x^2+8x+24

Step-by-step explanation:

The reason that it is the 4th one is because there is an x^2 which indicates a quadratic and it is negative because the quadratic is going down

Answer:

2 2/3 or 24/9

Step-by-step explanation:

3 2/9 - 5/9 = 24/9 = 2 6/9

3*9+2 = 29/9

29/9 - 5/9 = 2 6/9

2 6/9 turns into 2 2/3

2 2/3 is equal to 24/9

Answer:

2 2/3

Step-by-step explanation:

What you do is make 3 2/9 into an improper fractions --> 9 * 3 + 2 = 29/9

29/9 - 5/9 = 24/9

So, now you're going to make 24/9 into a mixed number which is 2 6/9 --> 2 2/3

angle FHG = 42 degrees

angle GHI = 100 degrees

=========================================================

Explanation:

FHI is the largest angle. It is split into two pieces FHG and GHI which have measures of (3x+6) and (9x-8) degrees respectively.

Put another way, those two smaller angles (FHG and GHI) combine to form the larger angle (FHI)

This is the angle addition postulate.

------------------

(angle FHG) + (angle GHI) = angle FHI

(3x+6) + (9x-8) = 142

3x+6+9x-8 = 142

(3x+9x) + (6-8) = 142

12x - 2 = 142

12x-2+2 = 142+2 ... adding 2 to both sides

12x = 144

12x/12 = 144/12 .... dividing both sides by 12

x = 12

------------------

Use that x value to find the angles we're after

angle FHG = 3x+6 = 3*12+6 = 36+6 = 42

angle GHI = 9x-8 = 9*12-8 = 108-8 = 100

Note how

(angle FHG) + (angle GHI) = 42 + 100 = 142

which is the measure of angle FHI. This confirms the answers.

Hi there! :)

Answer:

[tex]\huge\boxed{x = -4, -2}[/tex]

x² + 6x + 8 = 0

Factor the equation by finding two numbers that sum up to 6 and multiply into 8:

4 + 2 = 6

4 ×2 = 8

Rewrite in factored form:

(x + 4) (x + 2) = 0

Find the roots using the Zero-Product Property:

x + 4 = 0

x = - 4

x + 2 = 0

x = -2.

Therefore, the roots of this equation are at x = -4 and -2.

Answer:

a.   3x+3y

b.  -2x-1

c.  -4x-12y

Step-by-step explanation:

basically u just multiply

a. 3(x + y)  

=3x+3y

b. −(2x + 1)

=-2x-1

c. −4(x + 3y)

=-4x-12y

HOPE I HELPED

PLS MARK BRAINLIEST  

DESPERATELY TRYING TO LEVEL UP

✌ -ZYLYNN JADE ARDENNE

JUST A RANDOM GIRL WANTING TO HELP PEOPLE!

                        PEACE!

Answer:

a)3x+3y

b)-2x-1

c)-4x-3y

Step-by-step explanation:

a)3(x+y)

3x+3y

b)-(2x+1)

-2x-1

c)-4(x+3y)

-4x-12y

Note:

-&+=-

+&+=+

+&-=-

-&-=+

Hope this helps ;) ❤❤❤

hi

40 students

30 read chemistry

20 read physics

so logical deduction is that 10 read chemistry and physics.  

So only 20 read only chemistry and only 10 read only physics.  

So read only chemistry is  20/40 = 1/2

Answer as a fraction =  1/2

Answer in decimal form = 0.5

Answer in percent form = 50%

All three represent the same idea, but in a different form.

=======================================================

Work Shown:

30 read chem, 20 read physics

30+20 = 50 read either one, but this is over 40, so 50-40 = 10 students must read both

From that,

30-10 = 20 read chem only

20-10 = 10 read physics only

This makes the venn diagram you see below

Divide the number of people who read chemistry only (20) over the total number of people (40). This gives 20/40 = 2/4 = 1/2

Then you would use your calculator to find 1/2 = 0.5 = 50%

Answer:

A. 0.25 B. 625/1000 C. 0.875

Answer:

ONE IS DA ANSWR 1

Step-by-step explanation:

so 5/12 +5/6 simpify 5/6 you get 5/12 + 10/12 = 15/12 and 15/12 is 1 and 3/12 1/3

Answer:

1. line

2. line segment

Answer:

mark the other girl brainiest

Step-by-step explanation:

Answer:

Either of the following square values:

[tex]8^{2} =64 \,\,in^2\\15^2= 225\,\,in^2\\17^2=280\,\,in^2[/tex]

Step-by-step explanation:

The three possible answers correspond to the square of the sides of the triangles via the Pythagorean theorem. And these are:

[tex]8^{2} =64 \,\,in^2\\15^2= 225\,\,in^2\\17^2=280\,\,in^2[/tex]

Answer:

This is a third-degree trinomial.

Step-by-step explanation:

To find the degree of a polynomial, simply look at the term with the highest power.  In the case of this polynomial, the term with the highest power is 2x^3 which is a third power.  Hence, this is a 3rd degree trinomial.

Cheers.

Answer:

Hey there!

[tex]8x^3+2x^2-20x-5[/tex]

[tex](8x^3+2x^2)+(-20x-5)[/tex]

[tex]2x^2(4x+1)+(-5)(4x+1)[/tex]

[tex](2x^2-5)(4x+1)[/tex]

Let me know if this helps :)

The solution of the expression are,

⇒ (4x + 1) (2x² - 5)

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The expression is,

⇒ 8x³ + 2x² - 20x - 5

Now, We can simplify as;

⇒ 8x³ + 2x² - 20x - 5

⇒ (8x³ + 2x² )  + (- 20x - 5)

⇒ 2x² (4x + 1) - 5 (4x + 1)

⇒ (4x + 1) (2x² - 5)

Thus, The solution of the expression are,

⇒ (4x + 1) (2x² - 5)

Learn more about the mathematical expression visit:

brainly.com/question/1859113

#SPJ7

The inequality expression is :

16 + 8B ≥ 50

Least amount that could be spent = $4500

The total number of rooms required should be atleast 50

Already booked = 16

Number of rooms per block = 8

If the number of blocks = B

Summing together :

Then we have :

16 + 8B ≥ 50

The leat additional amount to be spent:

(50 - 16) / 8

34/8 = 4.25

Least number of blocks, B = 5

Least amount = $900 * 5 = $4500

Learn more : https://brainly.com/question/15974141

Inequalities are used to represent unequal expressions.

Given that:

[tex]Room = 50[/tex] at least

[tex]Reserved = 16[/tex]

[tex]Rate = 8[/tex] per block

A. The inequality

Let the number of blocks be B.

"At least" means, greater than or equal to. So, we have:

[tex]Rate \times B + Reserved \ge 50[/tex]

Substitute known values

[tex]8 \times B + 16 \ge 50[/tex]

[tex]8B + 16 \ge 50[/tex]

So, the inequality that describes the scenario is:

[tex](b).\ 8B + 16 \ge 50[/tex]

B. The least amount

Solve for B in: [tex]8B + 16 \ge 50[/tex]

[tex]8B \ge 50 - 16[/tex]

[tex]8B \ge 34[/tex]

Divide both sides by 8

[tex]B \ge 4.25[/tex]

The number of blocks cannot be a decimal. So, we round 4.25 to the smallest integer greater than 4.25

This gives:

[tex]B \ge 5[/tex]

The least number of block is 5.

Given that:

[tex]Cost = \$900[/tex] per block

The least amount is calculated as follows:

[tex]Least = B \times Cost[/tex]

So, we have:

[tex]Least = 5 \times \$900[/tex]

[tex]Least = \$4500[/tex]

Hence, the least additional money is: $4500

Read more about inequalities at:

https://brainly.com/question/17675534

Answer:

∠ PQR = 143°

Step-by-step explanation:

∠ PQR and ∠ SQR are adjacent angles and are supplementary, thus

∠ PQR = 180° - 37° = 143°

Answer:

Step-by-step explanation:

She

She

Her

He

Their

They

They

Their

We

They

Him

Answer:

C. -7f > -9 because -7f is warmer than -9f

Step-by-step explanation:

Process of Elimination

You can rule out B and D because the answer contradicts itself.

Previous Knowledge

We know -7f is warmer than -9f because its closer to 0 so we can rule out A

Therefore through the process of elimination you can conclude the answer is C

Answer:

15/28

Step-by-step explanation:

Answer:

Step-by-step explanation:

Hello friend!!!!!

Third option is the correct answer.

Hope this helps

plz mark as brainliest!!!!!!!

Step-by-step explanation:

Hey, there!!

Option 3 is the correct answer.

here,

when we cube the sum of 5 and 3 times y^2 it looks like,

=[tex] {(5 + 3 {y}^{2}) }^{3} [/tex]

now, when we divide it by cube of the product of 4 and y we get,

=[tex] \frac{ {(5 + 3 {y}^{2}) }^{3} }{ {4y}^{3} } [/tex]

so, answer is option 3.

Hope it helps..

Answer:

36[tex]\sqrt{3}[/tex] + 72

Step-by-step explanation:

The length of the rectangle = diameter of 2 circles = 4 × 3 = 12 mm

The width of the rectangle = 2 radii + distance d between radii ( lower to upper )

Using the right triangle formed by joining the 3 centres with legs 3 and d and hypotenuse 6

Using Pythagoras' identity, then

d² + 3² = 6²

d² + 9 = 36 ( subtract 9 from both sides )

d² = 27 ( take the square root of both sides )

d = [tex]\sqrt{27}[/tex] = 3[tex]\sqrt{3}[/tex]

Thus width of rectangle = 3 + 3[tex]\sqrt{3}[/tex] + 3 = 6 + 3[tex]\sqrt{3}[/tex]

Hence

area = length × width

        = 12 × (6 + 3[tex]\sqrt{3}[/tex] ) = 36[tex]\sqrt{3}[/tex] + 72 mm ²

36 [tex]\sqrt{3}[/tex]+ 72

The length of the rectangle = diameter of 2 circles = 4 × 3 = 12 mm

The width of the rectangle = 2 radii + distance d between radii ( lower to upper )

Using the right triangle formed by joining the 3 centres with legs 3 and d and hypotenuse 6

Using Pythagoras' identity, then

d² + 3² = 6²

d² + 9 = 36 ( subtract 9 from both sides )

d² = 27 ( take the square root of both sides )

d =  = 3

Thus width of rectangle = 3 + 3 + 3 = 6 + 3

Hence

area = length × width

       = 12 × (6 + 3 ) = 36 + 72 mm ²

Answer: D: 3.

Step-by-step explanation:

Ok, vamos a contar los dígitos de derecha a izquierda.

El dígito que ocupa el lugar de la centena de millón va a ser el 9. (o el primero contando de izquierda a derecha).

en el numero 341,427,538 el noveno dígito es un 3.

Entonces el numero que esta en el lugar de la centena de millón es un 3

La opción correcta es D

Answer:

Option (C)

Step-by-step explanation:

x and y are two rational numbers.

Two inequalities which define these numbers are,

x + y < 5 ------(1)

3 < x < 5 -------(2)

In this question we will substitute the values of y given in the options in the inequality (1) to get the value of x. If the value of x satisfies the inequality (2), it will be the answer.

Option (A). y = [tex]\frac{8}{3}[/tex]

From inequality (1),

[tex]x+\frac{8}{3}<5[/tex]

[tex]x<5-\frac{8}{3}[/tex]

x < [tex]\frac{7}{3}[/tex]

x < 2.33

But 3 < x < 5, therefore, y = [tex]\frac{8}{3}[/tex] is not the answer.

Option (B). y = 2

x + 2 < 5

x < 3

But x is greater than 3. Therefore, Option (B) will not be the answer.

Option (C). y = 0

x + 0 < 5

x < 5

Inequality (2) states the same thing.

Therefore, Option (C) will be the answer.

Option (D). y = 3

x + 3 < 5

x < 5 - 3

x < 2

But x > 3, therefore, Option (D) will not be the answer.

Answer:

C is correct because if x is less than 5 and greater than 3 than is would most likely be 4 and 4 plus 0 equals 4 the problem says x plus y should be less than 5 and 4 plus 0 is less than 5

Step-by-step explanation:

Long answer short the answer is c

Answer:

12,500 euro = 61,250 cedis

Step-by-step explanation:

1 euro = 4.9 cedis

12500 euro = 4.9 * 12500 cedis

12,500 euro = 61,250 cedis

Answer:

the domain is {0, 1, 2, 3, 4... to positive infinity}

The range is {-1, -3, 0, -4 and so on}

this is not a function

Step-by-step explanation:

domain is a set of all x values, so just write the x values based on the graph

range is a set of all y values, so just write y values based on the graph

not function because it doesnt satisfy with the vertical line test.

i hop it help u

Merhaba ;))

Answer:

4.952

#Başarılar

Answer:

Step-by-step explanation:

[tex]\begin{matrix}\space\space&2&3&8&9&\textbf{1}\\ -&1&8&9&3&\textbf{9}\end{matrix}\\\mathrm{The\:bottom\:number\:is\:larger\:than\:the\:upper\:number.\:\:\\Try\:to\:'borrow'\:a\:digit\:from\:the\:left.}\\\mathrm{Borrow\:}1\mathrm{\:from\:}9\mathrm{.\:\:The\:remainder\:is\:}8\\\begin{matrix}\space\space&\space\space&\space\space&\space\space&\textbf{8}&10\\ \space\space&2&3&8&\textbf{\linethrough{9}}&1\\ -&1&8&9&\textbf{3}&9\end{matrix}[/tex]

[tex]\begin{matrix}\space\space&\space\space&\space\space&\space\space&8&\textbf{11}\\ \space\space&2&3&8&\linethrough{9}&\textbf{\linethrough{1}}\\ -&1&8&9&3&\textbf{9}\end{matrix}[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&\space\space&\textbf{8}&11\\ \space\space&2&3&8&\textbf{\linethrough{9}}&\linethrough{1}\\ -&1&8&9&\textbf{3}&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\space\space&\textbf{5}&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&\space\space&8&11\\ \space\space&2&\textbf{3}&8&\linethrough{9}&\linethrough{1}\\ -&1&\textbf{8}&9&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&\space\space&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&\textbf{1}&10&\space\space&8&11\\ \space\space&\textbf{\linethrough{2}}&3&8&\linethrough{9}&\linethrough{1}\\ -&\textbf{1}&8&9&3&9\end{matrix}}{\begin{matrix}\space\space&\textbf{\space\space}&\space\space&\space\space&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&1&\textbf{13}&\space\space&8&11\\ \space\space&\linethrough{2}&\textbf{\linethrough{3}}&8&\linethrough{9}&\linethrough{1}\\ -&1&\textbf{8}&9&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&\space\space&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&1&\textbf{12}&10&8&11\\ \space\space&\linethrough{2}&\textbf{\linethrough{13}}&8&\linethrough{9}&\linethrough{1}\\ -&1&\textbf{8}&9&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&\space\space&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&1&12&\textbf{18}&8&11\\ \space\space&\linethrough{2}&\linethrough{13}&\textbf{\linethrough{8}}&\linethrough{9}&\linethrough{1}\\ -&1&8&\textbf{9}&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{\space\space}&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&1&12&\textbf{18}&8&11\\ \space\space&\linethrough{2}&\linethrough{13}&\textbf{\linethrough{8}}&\linethrough{9}&\linethrough{1}\\ -&1&8&\textbf{9}&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{9}&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&1&\textbf{12}&18&8&11\\ \space\space&\linethrough{2}&\textbf{\linethrough{13}}&\linethrough{8}&\linethrough{9}&\linethrough{1}\\ -&1&\textbf{8}&9&3&9\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{4}&9&5&2\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&\textbf{1}&12&18&8&11\\ \space\space&\textbf{\linethrough{2}}&\linethrough{13}&\linethrough{8}&\linethrough{9}&\linethrough{1}\\ -&\textbf{1}&8&9&3&9\end{matrix}}{\begin{matrix}\space\space&\textbf{0}&4&9&5&2\end{matrix}}\\\\=4952[/tex]