What is the systematic name and molecular formula of these two:

Answer:

equal to ​

Explanation:

This question is depicting the LAW OF CONSERVATION OF MASS/MATTER, which states that matter can neither be created nor destroyed. Hence, in an isolated system, the original mass of the reactants must be EQUAL TO the final mass of the products formed.

In other words, the law states that no matter the change in chemical composition of the reactants in a chemical process, the mass does not change or it remains constant.

Answer:

D

Explanation:

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Answer:

C. the ice cube and the glass of water have higher heat capacity than the swimming pool

Answer:

not chemical only that's classifying reactions

and figures equations

Explanation:

that may answer

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The reaction of the different metals together to form a new compound is called a chemical reaction.

According to the question, we have to color the region which shows the behavior of the reaction.

Hence, these are the answer to the question.

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Answer:

b is the answer my brudaa

Explanation:

b or c

i think c im not sure

i hope it's right!!

A solute that has been dissolved in a solvent b) can be recovered by a process involving its chemical properties.

A substance that is dissolved in a solution is referred to as a solute. In fluid solutions, the quantity of solvent present is extra than the quantity of solute. One best example of solute in our each day hobby is salt and water. Salt dissolves in water and therefore, salt is the solute.

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Answer:

D.

Explanation:

Because force and energy are used to move.

Answer:

That is extremely confusing. Try contacting your prof.

Explanation:

Answer:

C-The principal because he or she controls all the activity in the school

Answer:

b i think im sorry if im wrong

Explanation:

The gravitational potential energy of a basketball  : PE = 18.375 J

Given

height = h = 3 m

mass = 0.625 kg

Required

The potential energy

Solution

The energy produced from its position is called potential energy (PE)  

which can be formulated as:  

PE = m. g. h (g = 9.8 m/s²)

Input the value :

PE = 0.625 x 9.8 x 3

PE = 18.375 J

Answer:

The mass of silver is 49 g (0.049 kg).

Explanation:

Initial temperature = [tex]30^{o}[/tex]C

Final temperature = [tex]40^{o}[/tex]C

Quantity of heat required = 117.5 J

Specific heat capacity of silver = 0.240 J/g[tex]^{o} C[/tex]

mass of the silver can be determined by;

Q = mcΔθ

Where: Q is the quantity of heat required, m is the mass of substance, c is the specific heat capacity of the substance and Δθ is the change in temperature.

So that,

117.5 = m x 0.240 x (40 - 30)

117.5  = m x 0.24 x 10

        = 2.4m

m = [tex]\frac{117.5}{2.4}[/tex]

   = 48.9583

m ≅

m = 49 g

The mass of silver is 49 g (0.049 kg).

Answer:

A. carbon dioxide

Explanation:

Answer: 5 moles of NaF would be produced when 550 grams of Sodium bromide are used.

Explanation:

From the question, the balanced chemical formula is illustrated below:

2NaBr + CaF2 → 2NaF + CaBr2

From the equation above;

Molecular mass of NaBr = 23 + 80 = 103g/ mol

Molecular mass of CaF2= 40+ (19×2)= 78g/ mol

Molecular mass of NaF = 23+19 = 42g/ mol

From the balanced chemical equation;

2 moles of NaBr reacted with 1mole of CaF to give 2 moles of NaF.

That is, 2 moles of NaBr= 2× 103 = 206g

2moles of NaF = 2×42= 84g

If 206g of NaBr yielded 84g of NaF

Therefore 550g of NaBr will yield Xg of NaF

X= 550×84/206

X= 224.27g of NaF

But 42g = 1 mole of NaF

Therefore 224.27g = X mole of NaF

X= 224.27 ×1/42

X is approximately 5moles.

Answer:

Given

[HONH2] = 0.45M

[OH-] = 5.26 x 10-6 M

                                           HONH2 + H2O -------------> HONH3+ + OH-

Initial                                     0.45           55                         0             0

at equilibrium                        0.45-x        55-x                      x             x

Given

[OH-] = x =  5.26 x 10-6 M

Therefore [HONH3+] = x =  5.26 x 10-6 M

pOH = -log[OH-] = -log(5.26 x 10-6) = 5.279

=> pH = 14- pOH = 8.72

From hendersen-hasselbach equaiton

8.72 = pKa + log(0.45/5.26 x 10-6)

=> pKa = 3.788

=> pKb = 14-3.788 = 10.21

percent of ionization = 5.26 x 10-6 * 100/0.45 = 1.17 x 10-3 %

concentration of NaOH required to make the same pH= [OH-] = 5.26 x 10-6 M

Percent of ionization of NaOH = [OH-]*100/NaOH = 5.26 x 10-6 *100/5.26 x 10-6 = 100%

Answer:

the mass of the copper piece is 110.2976 grams

Answer:

the called potential energy because the potential energy is the latentenergy in an object at rest

as it breaks down the surface , it reshapes it

Answer:

1. Renewable Resource

2. Carbonate

3. Fossil Fuel

4. Nonrenewable Resource

5. Carbon Cycle

Answer:

1. Renewable Resource

2. Carbonate

3. Fossil Fuels

4. Non-renewable Resource

5. Carbon Cycle

Answer: Thus 44 g of [tex]CO_2[/tex] will be produced  if 30 g of [tex]C_6H_{12}O_6[/tex] were reacted with an excess of oxygen

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} C_6H_{12}O_6 =\frac{30g}{180g/mol}=0.17moles[/tex]

The balanced chemical equation is:  

[tex]C_6H_{12}O_6 +6O_2(g)\rightarrow 6CO_2+6H_2O(g)[/tex]

As [tex]C_6H_{12}O_6[/tex] is the limiting reagent as it limits the formation of product and [tex]O_2[/tex] is the excess reagent.

According to stoichiometry :

1 mole of [tex]C_6H_{12}O_6[/tex] produce =  6 moles of [tex]CO_2[/tex]

Thus 0.17 moles of [tex]C_6H_{12}O_6[/tex] will produce=[tex]\frac{6}{1}\times 0.17=1.0mole[/tex]  of [tex]CO_2[/tex]

 Mass of [tex]CO_2=moles\times {\text {Molar mass}}=1.0moles\times 44g/mol=44g[/tex]

Thus 44 g of [tex]CO_2[/tex] will be produced  if 30 g of [tex]C_6H_{12}O_6[/tex] were reacted with an excess of oxygen.

Answer:

It will have 5 valence electrons as its in group 5.

The atom will gain as its closer to the full configuration 8.

The charge will be 3- as it will gain 3 electrons.

Answer:

Explanation:

Acid rain that seeps into the ground can dissolve nutrients, such as magnesium and calcium, that trees need to be healthy. Acid rain also causes aluminum to be released into the soil, which makes it difficult for trees to take up water. ... The acidic clouds and fog strip important nutrients from their leaves and needles.

Answer:

The percent yield for ethanol in this process is 95.2%

Explanation:

Yield is the ratio between the amount of product actually obtained in the reaction and the maximum amount of product that could have been obtained if the reagents had been completely consumed.

The theoretical yield is the yield is the maximum you can get in a reaction.

On the other hand, the actual performance shows what you really get in experimentation. It is generally less than the theoretical yield.

So, the percentage return is the actual return times the theoretical return multiplied by 100.

So, in this case the percentage yield will be calculated as:

[tex]percent yield=\frac{4,760 kg}{5,000 kg} *100[/tex]

percent yield=  95.2%

The percent yield for ethanol in this process is 95.2%

Answer:

Explanation:

you can watch this video and understand

Answer:

Mass = 96g

Explanation:

Molarity = number of moles/volume of solvent

According to the provided information, volume = 1.55L, Molarity = 1.55M

number of moles (n) = molarity × volume

n = 1.55 × 1.55

n = 2.4025

n = 2.40mol

For NaOH, molar mass = 23 + 16 + 1 = 40g/mol

mole = mass/molar mass

Mass = molar mass × mole

Mass = 40 × 2.40

Mass = 96g

The noble gas that precedes a given partial electron configuration must itself have an electron configuration that is complete up to the partial electron configuration. The noble gas's electron configuration should, when fully written out right before the partial electron configuration, give us a valid electron configuration for some element.

For the first series, the highest principal energy level has the number 4, so our noble gas should at least be one that is in the third period (numerically, the energy level is the same as the period number). That noble gas would be argon. The partial electron configuration given is not that of a noble gas (note: all noble gases have an electron configuration that contains Np⁶, where N = the highest principal energy level). So, the noble gas that appropriately precedes our first partial electron configuration is [Ar].

Argon's electron configuration is 1s²2s²2p⁶3s²3p⁶. Using the Aufbau Principle, 4s² would correctly follow 3p⁶. [Ar]4s²3d¹⁰4p² is equivalent to writing out 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p²; either way, this would happen to be the electron configuration of germanium.

Now that we hopefully have our fundamentals down, we can apply them to figure out the noble gases that precede the remaining partial electron configurations.

[Kr]5s²4d¹⁰5p⁵: This is the electron configuration of iodine.

[He]2s²2p⁵: This is the electron configuration of fluorine.

[Xe]6s²4f¹⁴5d¹⁰6p²: This is the electron configuration of lead.

[Ne]3s²2: This is the electron configuration of magnesium.