What is the solution to x=√-x+6
a. 2 and -3
b.-2 and 3
c. -3
d.2

The side length x of the triangle rounded to the nearest tenth is 31.3.

The figure in the image is a right triangle.

To determine the value of x, use trigonometric ratio.

Tangent = Opposite / Adjacent

tan( 38° ) = x / 40

Solve for x

x = tan( 38° ) × 40

x = 0.781285 × 40

x = 31.3

Therefore, the value of x is 31.3.

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People with pica, a type of eating disorder, compulsively consume one or more non-food objects like ice, clay, paper, ash, or soil.

Recurrent episodes of binge eating are the hallmark of a specific type of eating disorder called binge eating disorder. Food addiction and compulsive overeating are both symptoms of this eating disorder. Uncontrollable and quick eating without feeling hungry, as well as negative emotions, depressive symptoms, and guilt over the eating, are prominent symptoms of this illness.

given

People with pica, a type of eating disorder, compulsively consume one or more non-food objects like ice, clay, paper, ash, or soil.

Pica is a kind of pagophagia. It entails consuming ice, snow, or ice water excessively.

Individuals who have pica are not forced to consume ice due to a physical condition like anaemia.

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The effective annual rate (EAR) is the actual rate of interest that is earned or paid over a given period of time, taking into account the compounding of interest. For example, a stated rate of 7.80% with 4 compounding periods per year would result in an EAR of 15.30%.

The effective annual rate (EAR) is a measure of the actual rate of interest that is earned or paid over a given period of time. It takes into account the effect of compounding, which is the process of earning interest on both the principal and the accumulated interest. This means that the rate of return can increase over time. The EAR is calculated by taking the stated rate of interest, which is the rate of interest stated by the lender, and multiplying it by the number of compounding periods per year. For example, if the stated rate is 7.80% and the compounding periods per year are 4, then the EAR would be 15.30%. Similarly, if the stated rate is 12.40% and the compounding periods per year are 365, then the EAR would be 11.40%. If the compounding period is infinite, then the EAR will be the same as the stated rate, in this case 12.40%. Therefore, the EAR is the actual rate of return that is earned or paid over a given period of time.

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In this matrix question where percentages are listed, answers to all these questions are written below.

In the matrix given in the image, we can calculate following things:

a. S32 is a value that represents the percentage of sick students in the third grade of the elementary school. From data we can say it is 10%

b. P22 is a value that represents the number of middle school students in the second grade. From data we can say there are 795 such boys.

c. To find[tex][s] * [p][/tex] we need to multiply the percentage of students in each category by the corresponding population in each grade level.

      [tex]\left[\begin{array}{ccc}1190.75&1311.75\\1194&1366.25\\1233&1405.5\end{array}\right][/tex]

Columns: Girls, Boys

Rows: Susceptible, Sick, Infected

d. [tex][[s] * [p]]21[/tex] represents the number of sick students in the second grade of the elementary school.

It represents that 1194 girls are sick.

e. To find the number of sick girls, we need to multiply the number of girls in each grade level by the corresponding percentage of sick students.

1194

f. To find the number of infected boys, we need to multiply the number of boys in each grade level by the corresponding percentage of infected students.

1406

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Complete Question: Image is uploaded for it.

a. Describe what S32 value is and what it will represent

b. Describe what P22 value is and what it will represent

c. Find [tex][s] * [p][/tex]

d. Describe what[tex][[s] * [p]]21[/tex] value is and what it will represent

e. How many sick girls are present?

f. Number of boys infected?

A phase change occurs when the kinetic energy decrease enough so that the attraction between molecules pulls them together.

A substance with weaker molecular attraction will freeze at a lower temperature because it requires more energy to be taken out before the attraction pulls the molecules together.

A substance with stronger molecular attraction will evaporate at a higher temperature because it requires less energy to be added to overcome attraction between the molecules.

In Science, a phase change refers to the change in the state of matter of a given chemical compound or substance. Additionally, some examples of a phase change include the following;

Generally speaking, a change in the state (phase) of matter that results in the release of energy is known as an exothermic reaction and they include:

In conclusion, sublimation, melting, and evaporation are other processes that are associated with a change in the state (phase) of matter.

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Answer:

[tex]x+\sqrt{2}[/tex]

Step-by-step explanation:

The conjugate of [tex]x-\sqrt{2}[/tex] would simply be [tex]x+\sqrt{2}[/tex]. All you have to do is simply change the sign to its opposite.

Computing the surplus producers receive when a $30 per unit price floor is imposed on the market is option C.$25.

To calculate the surplus producers receive, we need to find the difference between the price they receive at a given quantity and the price they would have received in the absence of the price floor.

When a price floor of $30 per unit is imposed on the market, the quantity supplied and demanded at this price are:

QX = (50 - 30)/4 = 5 units (demand)

QX = (30 - 10)/2 = 10 units (supply)

So, the surplus received by the producers is the difference between the price floor and the price they would have received in the absence of the price floor:

Surplus = 30 - (10 + 2 * 10) = 30 - 30 = $0.

However, the surplus for consumers is the difference between the price they would have paid in the absence of the price floor and the price floor:

Surplus = (50 - 4 * 5) - 30 = 25 - 30 = -$5.

So, the total surplus received by producers and consumers combined is $0 + (-$5) = -$5, which means that the price floor imposes a dead weight loss on the market.

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Answer: Option D, "C-E-G-A-Bb-A-G-E" is not an example of a boogie-woogie bass line. Boogie-woogie is a genre of blues music that is characterized by a repetitive bass pattern that usually consists of 8th notes. The bass line is usually made up of the root note, fifth note, and octave of a chord, and it is played in a swung or shuffle rhythm. The most common boogie-woogie bass line consists of the notes of a I-IV-V chord progression in a 12-bar blues structure. Option D deviates from this typical pattern and therefore would not be considered a boogie-woogie bass line.

Step-by-step explanation:

The intersection in the below problem is 13

Given equation is

[1,13] ∩ [13,19]

We need to simplify the expression and tell the intersection of the expression

After doing the intersection, we will  take all the common elements in two sets

so , we have

[1,13] ∩ [13,9 ] = 13

therefore we get the intersection of the given expression by simplifying it as 13.

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Step-by-step explanation:

The translation of triangle P by the vector (2, 3) results in the triangle being moved 2 units to the right and 3 units up. The new coordinates of the triangle are (6, 7), (4, 6), and (3, 5).

37.96 is the average atomic mass of the element in the data table .

What does average mean?

The average is calculated by dividing the total number of values by the total number of values. It can also be described as mean. The mean in statistics is the average value across the specified sample or data set.

                                      Mean, median, and mode are the three primary categories of average. Each of these methods operates a little bit differently and frequently yields values that diverge a little bit from the norm. The most popular type of average is the mean.

the average atomic mass = 35.97 + 37.96 + 39.96/3

                                          = 113.89/3

                                           =  37.96

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Answer:

39.96

Step-by-step explanation: I think

The statement of statistics "the statistical methods of analysis of variance assume that the populations are normally distributed" is true. So the correct answer is (a)True.

Statistics is a branch of applied mathematics that involves collecting, describing, analyzing, and drawing conclusions from quantitative data. It  gives us information to figure out how things work. Statistics are used to conduct research, evaluate results, develop critical thinking, and make informed decisions. Statistics can be used to examine nearly any area of ​​research to find out when and why things happen, and whether their recurrence is predictable. 

Statistics are used in many different applications and professions. Statistics are generated each time data is collected and analyzed. This ranges from government agencies to academic research to investment analysis. 

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Answer: qt=0.6

Step-by-step explanation:

3.5=

60%=0.6

qt=0.6

Statistics is a discipline, principally within applied mathematics, concerned with the systematic study of the collection, presentation, analysis, and interpretation of data.

The measures used in statistics are mean, range, standard deviation, variance etc.

The range can be calculated by finding the difference between the lowest and highest observation i.e. 23 - 12 = 11.

Variance is a measure of dispersion of data points from the mean. In the above given data, the variance is 9.389.

Standard deviation is the square root of the variance, hence, is 3.06.

Mean = sum of data divided by no of observations (10).

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Answer: To determine the length of the paths connecting the entrance to the opposite entrance, we first need to find the midpoint of each side of the park. Then, we will use the distance formula to calculate the distance between each pair of midpoints.

Let's begin by finding the midpoint of each side of the park.

JK: (-3 + 3, 1 + 3) / 2 = (0, 2)

KL: (3 + 5, 3 - 1) / 2 = (4, 2)

LM: (5 - 1, -1 - -3) / 2 = (2, -2)

MJ: (-1 + -3, -3 + 1) / 2 = (-2, -1)

Next, we'll use the distance formula to calculate the distance between each pair of midpoints.

JK: sqrt((4 - 0)^2 + (2 - 2)^2) = sqrt(16 + 0) = 4

KL: sqrt((2 - 4)^2 + (-2 - 2)^2) = sqrt(16 + 16) = 4 sqrt(2)

LM: sqrt((-2 - 2)^2 + (-1 + 2)^2) = sqrt(16 + 9) = sqrt(25) = 5

MJ: sqrt((-2 - 0)^2 + (-1 - 2)^2) = sqrt(4 + 9) = sqrt(13)

The total length of the paths is 4 + 4 sqrt(2) + 5 + sqrt(13), which when rounded to the nearest whole number is 14.

Step-by-step explanation:

The solution of the  the linear equation is y = 3/(x - 9xlnx)

What is the solution to an equation?

In order to make the equation's equality true, the unknown variables must be given values as a solution. In other words, the definition of a solution is a value or set of values (one for each unknown) that, when used as a replacement for the unknowns, transforms the equation into equality.

xy' + y = 3xy², y(1) = -3

This is Bernoulli  equation: y' + (1/x)y = 3y²;

Let u = y^(1 - 2) = 1/y is new function.

Then u' = - y'/y

or

y' = -u'/u²;

y = 1/u.

Substitute all this in our ODE:  - u'/u² +(1/x)/u = 3/u², or u' - (1/x)u = -3.

we get linear, 1st order not homogenies ODE:

integrated factor:

μ = e∫(-1/x)dx = e-lnx = 1/x²

u'·1/x - 1/x2 = -3/x;

(u/x)' = - 3/x; u/x

       = ∫(-3/x)dx;

 u/x = -3lnx + C;

u = - 3xlnx + Cx;

y =1/u = 1/(- 3xlnx + Cx)

To get C ,use initial conditions:

y(1) = 3;

3 = 1/(-3·1·ln1 + C);

C = 1/3;

y = 3/(x - 9xlnx)

The solution of the  the linear equation is y = 3/(x - 9xlnx)

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The solution of the  the linear equation is y = 3/(x - 9xlnx)

What is the solution to an equation?

In order to make the equation's equality true, the unknown variables must be given values as a solution. In other words, the definition of a solution is a value or set of values (one for each unknown) that, when used as a replacement for the unknowns, transforms the equation into equality.

xy' + y = 3xy², y(1) = -3

This is Bernoulli  equation: y' + (1/x)y = 3y²;

Let u = y¹⁻² = 1/y is new function.

Then u' = - y'/y

or

y' = -u'/u²;

y = 1/u.

Substitute all this in our ODE:  - u'/u² +(1/x)/u = 3/u², or u' - (1/x)u = -3.

we get linear, 1st order not homogenies ODE:

integrated factor:

μ = e∫(-1/x)dx = e-lnx = 1/x²

u'·1/x - 1/x2 = -3/x;

(u/x)' = - 3/x; u/x

      = ∫(-3/x)dx;

u/x = -3lnx + C;

u = - 3xlnx + Cx;

y =1/u = 1/(- 3xlnx + Cx)

To get C ,use initial conditions:

y(1) = 3;

3 = 1/(-3·1·ln1 + C);

C = 1/3;

y = 3/(x - 9xlnx)

The solution of the  the linear equation is y = 3/(x - 9xlnx)

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The shortest distance between the two skew lines is equal to 11√38 / 38 units.

According to linear algebra, lines are defined by vectorial equations of the form:

(x, y, z) = P(x, y, z) + t · T(x, y, z)

Where:

And the shortest distance between two skew lines is determined by the following expression:

[tex]d = \frac {|[P_{2} (x, y, z) - P_{1}(x, y, z)] \bullet [T_{1} (x, y, z) \times T_{2} (x, y, z)]|}{|T_{1} (x, y, z) \times T_{2} (x, y, z)|}[/tex]

First, determine the points contained in each line:

P₁(x, y, z) = (3, 2, 1)

P₂(x, y, z) = (2, 4, - 1)

Second, find each vector slope:

T₁(x, y, z) = (2, 1, 0) - (3, 2, 1)

T₁(x, y, z) = (- 1, - 1, - 1)

T₂(x, y, z) = (3, 0, - 2) - (2, 4, - 1)

T₂(x, y, z) = (1, - 4, - 1)

Third, determine the vector subtraction:

P₂(x, y, z) - P₁(x, y, z) = (2, 4, - 1) - (3, 2, 1)

P₂(x, y, z) - P₁(x, y, z) = (- 1, 2, - 2)

Fourth, determine the cross product:

T₁(x, y, z) × T₂(x, y, z) = (- 1, - 1, - 1) × (1, - 4, - 1)

T₁(x, y, z) × T₂(x, y, z) = (- 3, - 2, 5)

Fifth, use the dot product:

[tex][P_{2} (x, y, z) - P_{1}(x, y, z)] \bullet [T_{1} (x, y, z) \times T_{2} (x, y, z)] = (- 1, 2, - 2) \,\bullet\,(- 3, - 2, 5)[/tex]

[tex][P_{2} (x, y, z) - P_{1}(x, y, z)] \bullet [T_{1} (x, y, z) \times T_{2} (x, y, z)] = 3 - 4 - 10[/tex]

[tex][P_{2} (x, y, z) - P_{1}(x, y, z)] \bullet [T_{1} (x, y, z) \times T_{2} (x, y, z)] = - 11[/tex]

Sixth, calculate the norm of the cross product:

|T₁(x, y, z) × T₂(x, y, z)| = √[(- 3)² + (- 2)² + 5²]

|T₁(x, y, z) × T₂(x, y, z)| = √38

Finally, determine the shortest distance between the two skew lines:

d = |- 11| / √38

d = 11 / √38

d = 11√38 / 38

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The best estimate of the difference between the two numbers is 31/12 or 2 7/12.

A mixed fraction is one that is represented by both its quotient and remainder. A mixed fraction is, for instance, 2 1/3, where 2 is the quotient and 1 is the remainder. An amalgam of a whole number and a legal fraction is a mixed fraction.

to transform a mixed fraction into an incorrect fraction.

By denominator, divide the numerator.

Take the quotient as a whole number and use the remaining amount as the proper fraction's numerator while maintaining the original denominator.

Covert the mixed fraction into improper fractions:

5 5/6 = 35/6

3 1/4 = 13/4

The difference between the two numbers is:

35/6 - 13/4

Take the LCM.

70/13 - 39/12

(70 - 39) / 12

31/12 = 2 7/12

Hence, the best estimate of the difference between the two numbers is 31/12 or 2 7/12.

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Based on the data, the total number of people would be 350. So the missing value in the table would be 54.

To find the missing value of people in the graph we must do the following procedure. We must add the number of people who are already registered in the graph in the frequency column.

Additionally, we must establish a total number of people, for example 350. In this case we must subtract the result of the people registered in the graph from the total number of people:

350 - 295 = 54.

Then we can establish that the remaining number of people (54) corresponds to the frequency table.

Note: This question is incomplete. The complete information is here:

Total number of people: 350

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The solution of the system of equations is equal to (3, 4).

In Mathematics, a point of intersection can be defined as the location on a graph where two (2) lines intersect or cross each other, which is primarily represented as an ordered pair containing the point that corresponds to the x-coordinate (x-axis) and y-coordinate (y-axis) on a cartesian coordinate.

By critically observing the graph of the lines representing the given system of equations, we can reasonably and logically deduce that the correct solution set lies in Quadrant II and it is denoted by the point of intersection of both the x-coordinate (x-axis) and y-coordinate (y-axis), which is given by  ordered pair (3, 4).

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Answer:

The cost of 3 tennis balls and 2 golf balls is $7. The cost of 6 tennis balls and 3 golf balls is$12. Find the cost of 1 tennis ball and 1 golf ball.

Step-by-step explanation:

Answer: We can solve the system of equations using the substitution method.

First, we'll isolate "y" in one of the equations and substitute it into the other equation:

Y = x - 11

7x + 7y = -21

Substituting the first equation into the second equation:

7x + 7(x - 11) = -21

7x + 7x - 77 = -21

14x = 56

x = 4

Now that we have found the value of x, we can substitute it back into one of the original equations to find the value of y:

Y = x - 11

Y = 4 - 11

Y = -7

The solution to the system of equations is (x, y) = (4, -7).

Step-by-step explanation:

The value of x and y in the equation is 4 and -7 respectively

Simultaneous equations are two or more algebraic equations that share variables e.g. x and y . They are called simultaneous equations because the equations are solved at the same time. For example, below are some simultaneous equations: 2x + 4y = 14 4x − 4y = 4.

Using substitution method to solve the system,

y = x-11 equation 1

7x+7y = -21 equation 2

substitute x-11 for y in equation 2

7x + 7( x-11) = -21

7x + 7x -77 = -21

14x = -21+77

14x = 56

divide both sides by 14

x = 56/14

x = 4

substitute 4 for x in equation 1

y = 4-11

y = -7

therefore the value of x and y is 4 and -7 respectively

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Solution of equation x² - 6x = 11 are,  x = 7.47 and x = - 1.47

An algebraic equation with the second degree of the variable is called an Quadratic equation.

Given that;

The equation is,

⇒ x² - 6x = 11

Now, Solve the equation by completing the square as,

⇒ x² - 6x = 11

Add 9 both side, we get;

⇒ x² - 6x + 9 = 11 + 9

⇒ (x - 3)² = 20

⇒ x - 3 = √20

⇒ x - 3 = ± 4.47

This gives two solutions,

⇒ x - 3 = 4.47

⇒ x = 4.47 + 3

⇒ x = 7.47

⇒ x - 3 = - 4.47

⇒ x = - 4.47 + 3

⇒ x = - 1.47

Thus, Solution of equation x² - 6x = 11 are,

⇒ x = 7.47 and x = - 1.47

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The function operation f( x + h ) in the function f(x) = x² / (x + 3 ) is ( x + h )² / (x + h + 3 ).

A function is simply a relationship that maps one input to one output.

Given that;

To determine f( x + h ),  replace all the occurrence of x with (x + h) in the function and simplify.

f(x) = x² / (x + 3 )

f(x + h) = ( x + h )² / (( x + h ) + 3 )

f(x + h) = ( x + h )² / (x + h + 3 )

Therefore, the operation f(x + h) equals ( x + h )² / (x + h + 3 ).

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Let V be an inner product space, S and S0 be subsets of V, and W be a finite-dimensional subspace of V. To prove the other side,

1 ) Suppose (e1,…,en) is basis for W. Suppose x∈(W⊥)⊥. Consider the projection w of x onto W, specifically:

w=⟨x,e1⟩e1+…+⟨x,en⟩en∈W.

Then, x−w is perpendicular to each ei, since

⟨x−w,ei⟩=⟨x,ei⟩−∑j=1n⟨⟨x,ej⟩ej,ei⟩=⟨x,ei⟩−∑j=1n⟨x,ej⟩⟨ej,ei⟩=⟨x,ei⟩−∑j=1n⟨x,ej⟩δij=⟨x,ei⟩−⟨x,ei⟩=0.

Since the linear map ⟨⋅,x−w⟩ is constantly 0 on the basis of W, it is constantly zero on all of W, hence x−w∈W⊥.

But then, since x∈(W⊥)⊥, we have ⟨x−w,x⟩=0, and since ⟨x−w,w⟩=0,

∥x−w∥2=⟨x,x−w⟩−⟨w,x−w⟩=0,

i.e. x=w∈W, completing the proof.

2 ) Suppose that w∈(W⊥)⊥

then ⟨w,x⟩=0

for all x∈W⊥

If w∉W, then w=v+v′ where v∈W and v′∈W⊥∖{0}.

Then.

0=⟨w,x⟩=⟨v,x⟩+⟨v′,x⟩=⟨v′,x⟩

for all x∈W⊥.

However, v′∈W⊥ and ⟨v′,v′⟩≠0 so it is a contradiction.

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The given quantity as a single logarithm are as follows:

1. 20.8In(4x)

2. 3cos(3Inx)Inx

3. 4cos'zln'z

Function ve process of state of instruction that text input papa mississippi start x and output function ladki company it's a programming language allow me the code to create the complex command with simple instruction for example function in the used to it to numbers together a generator and i'm number from san also be combined to create more public sequence are instruction.

Express the given quantity as a single logarithm: In(a + b) + In(a - b) - 4Inx = In[(a+b)(a-b)] - 4Inx

Differentiate the function f(x) = 5.2In(4x) - 52: f'(x) = 20.8In(4x)

Differentiate the function f(t) = sin(3Inx): f'(t) = 3cos(3Inx)Inx

Differentiate the function f(x) = ln(4sin'z): f'(x) = 4cos'zln'z

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The amount of sand needed for every 100 square yard of surface would be 1. 1 cubic yards.

The amount of sand needed for 280 square yards would be 4 .18 cubic yards of sand.

The question says that 1. 1 cubic yards of sand are needed for every 100 square yards of surface so this is the amount of sand needed per 100 square yards.

As for 380 square yards, the amount of sand needed can be found by the formula :

= ( 380 square yards of surface x 1. 1 cubic yards of sand ) / 100 square yards of surface

= 418 / 100

= 4 .18 cubic yards of sand

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The ratio of circular chips to square chips is 1:4.

The ratio is a numerical relationship between two values that demonstrates how frequently one value contains or is contained within another.

Given:

A box contains 16 square chips, 12 triangular chips, and 4 circular chips.

The ratio of circular chips to square chips,

= Circular chips / square chips

= 4 / 16

= 1/4

= 1: 4

Therefore, the ratio is 1:4.

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Mr. Garcia's homeroom had a more consistent collection of canned goods.

Ms. Vicario's homeroom varied more widely with the collection of canned goods.

An interquartile range is a measure of the difference between the upper and lower quartiles of a dataset.

W can find the values of the upper and lower quartile and median from a box plot.

The middle line is the median and the first line is the lower quartile and the last line is the upper quartile.

The formula used is Upper quartile - Lower quartile.

We have,

The two daily food drives:

Mr. Garcia:

The mean number of canned goods collected = 18.75.

The median number of canned goods collected = 18.

The range of data for Mr. Garcia's homeroom = 11.

The IQR (interquartile range) of data = 4.25.

Ms. Vicario's homerooms:

The range of data = greater than 11.

The IQR of data = greater than 4.25.

The number of canned goods collected = more variable than the number of canned goods collected by Mr. Garcia's homeroom.

Based on these observations.

We can conclude that,

Mr. Garcia's homeroom had a more consistent collection of canned goods. i.e

Smaller range and IQR.

Ms. Vicario's homeroom varied more widely with the collection of canned goods.

i.e

Wider range and IQR

Thus,

Mr. Garcia's homeroom had a more consistent collection of canned goods.

Ms. Vicario's homeroom varied more widely with the collection of canned goods.

Learn more about the interquartile range here:

https://brainly.com/question/29204101

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