Answer:
[-3, 7].
Step-by-step explanation:
do i need to explain all that?
Answer:
The inequality can be rewritten as x-7 ≤ 50, which we can solve by adding 7 to both sides to get x ≤ 57.
Step-by-step explanation:
It seems like there are multiple questions combined in this one prompt. I will break them down and provide solutions for each one.
Solution for O x≤-3 or 2 Ox<-3 or 2 O-3≤x≤2 or x > 7:
To find the solution for this inequality, we need to solve each part separately and then combine the solutions using the union (OR) operation.
a) x ≤ -3: This part is already solved for x. The solution is x ≤ -3.
b) 2x < -3: We divide both sides by 2 to isolate x and get x < -3/2.
c) 2 ≤ x ≤ -3: This is not possible as there is no number that is both greater than or equal to 2 and less than or equal to -3.
d) x > 7: This part is already solved for x. The solution is x > 7.
The solution to the entire inequality is the union of these solutions: x ≤ -3 OR x < -3/2 OR x > 7.
Solution for x²+x-6 < 0
To solve this quadratic inequality, we can factor it as (x-2)(x+3) < 0 and use the sign chart method.
We create a sign chart for the expression (x-2)(x+3) and test the sign of the expression in each interval
-3 2
---|-------|---
- +
(x-2) - 0 + +
(x+3) - - - 0 +
-------------
- + - 0 +
The sign chart tells us that the expression is negative when x is between -3 and 2. Therefore, the solution to the inequality is -3 < x < 2.
Solution for x-7 ≤ 50₂
It seems like the expression "50₂" is intended to represent the number 50 in base 2 (binary). To convert this number to base 10 (decimal), we can write 50₂ as
50₂ = 12^5 + 12^4 + 02^3 + 02^2 + 12^1 + 02^0 = 32 + 16 + 2 = 50
Therefore, the inequality can be rewritten as x-7 ≤ 50, which we can solve by adding 7 to both sides to get x ≤ 57.
Can someone actually see if I got this answer correct please
Instead of 2.00 as mentioned in the question, the semester GPA is 1.38. Please double-check your calculations or provide more details if you made an error when reporting your grades or computing your GPA.
How many credit hours are there in three?Students must devote approximately 135 hours (45 x 3) of class, instructional, and independent time to a three credit unit course. Students who enroll in a course for four credit hours must dedicate around 180 (45 x 4) hours to it, split between in-class and out-of-class work.
You must first translate each letter grade using the common 4.0 scale into its equivalent numerical number before you can determine your semester GPA:
A = 4.0
B = 3.0
C = 2.0
D = 1.0
F = 0.0
E = 0.0 (equivalent to F)
Then, you can use the formula:
(Total grade points) / GPA (total credit hours)
Using this formula, we can calculate your semester GPA as follows:
FYE 105: F (0.0) x 3 credit hours = 0.0 grade points
MAT 150: E (0.0) x 3 credit hours = 0.0 grade points
ENG 101: D (1.0) x 3 credit hours = 3.0 grade points
BIO 112: A (4.0) x 3 credit hours = 12.0 grade points
BIO 113: B (3.0) x 1 credit hour = 3.0 grade points
Total grade points = 0.0 + 0.0 + 3.0 + 12.0 + 3.0 = 18.0
Total credits earned is 13 (3 + 3 + 3 + 3 + 1)
GPA = 18.0 / 13 = 1.3846
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-2,1,4,7 general term
Sure! The general term of a sequence is a formula which describes the nth term of the sequence. In this case, the pattern is that each term is increased by 3 when compared to the previous term. This pattern can be expressed as a formula - an=a1+(n-1)d, where a1 is the first term, n is the term number and d is the common difference.
For the sequence given -2,1,4,7
a1=-2
n=4
d=3
Substituting these values in the formula will give us the general term of the sequence an = -2 + 3(n-1)
Hence, the general term of the sequence -2,1,4,7 is an = -2 + 3(n-1).
what are the relation between point and circle
The relation between a point and a circle is relative to the location of the point relative to the circumference of the circle, which can be inside, at the circumference, or outside.
How to describe the relation between a point and a circle?The relationship between a point and a circle can be described as follows:
A point can be located inside a circle if and only if its distance from the center of the circle is less than the radius of the circle.A point can be located outside a circle if and only if its distance from the center of the circle is greater than the radius of the circle.A point can lie on the circumference of a circle if and only if its distance from the center of the circle is equal to the radius of the circle.More can be learned about points and circles at https://brainly.com/question/25871159
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PLEASE HELP 25 POINTS FOR YOU!
1)Sophie bikes s miles per hour. Her friend Rana is slower. Rana bikes r miles per hour.
a) Yesterday, Sophie biked for t hours. How many miles was Sophie's route?
b)Yesterday Rana biked m miles. How many hours did Rana bike yesterday?
c) Rana and Sophie went for a 20 mile bike ride today. Each girl biked at her usual speed. How long did Sophie wait for Rana at the end of the route?
d)Rana and Sophie each plan to bike 3 hours tomorrow . How much farther will Sophie bike than Rana
Answer: I got you!
Step-by-step explanation:
a) Sophie's distance is given by the formula: distance = rate × time. Therefore, her distance yesterday is s × t miles.
b) Rana's time is given by the formula: time = distance ÷ rate. Therefore, her time yesterday is m ÷ r hours.
c) Sophie's time is given by the formula: time = distance ÷ rate. Let's call the time Sophie waits for Rana "w". Then we have two equations:
Sophie's distance: s × (w + t) = 20
Rana's distance: r × (w + t) = 20 - m
We can solve for "w" by substituting the second equation into the first equation:
s × (w + t) = 20 - r × (w + t) + m
(s + r) × (w + t) = 20 + m
w + t = (20 + m) ÷ (s + r)
w = (20 + m) ÷ (s + r) - t
Therefore, Sophie waits for Rana for (20 + m) ÷ (s + r) - t hours.
d) Sophie's distance tomorrow is s × 3 miles, and Rana's distance tomorrow is r × 3 miles. Therefore, the difference in distance is (s - r) × 3 miles.
Find the total labour charges for a job that takes; 2 1/2hours Time (h) 1/2 1 2 3 4 Charges 1,200 1400 1 800 2,200 2,600
Answer:
The total labor charges for the job are P3,500.
Step-by-step explanation:
To find the total labor charges for a job that takes 2 1/2 hours, we need to look at the labor charges for each hour and a half-hour fraction and add them up.
For the first hour, the charges are P1,200. For the second hour, the charges are P1,400. For the third hour (the half-hour fraction), the charges are P1,800 / 2 = P900.
So, the total labor charges for 2 1/2 hours of work are
P1,200 + P1,400 + P900 = P3,500
Therefore, the total labor charges for the job are P3,500.
Each square has a side length of 12 units. Compare the areas of the shaded regions in the 3 figures. Which figure has the largest shaded region? Explain or show your reasoning.
Answer:
The shaded region in all of the answers are equal.
Step-by-step explanation:
Since squares have equal sides, the area of each square is 12 squared or 144.
The area of the circle in A is pi*radius squared. The diameter is 12, because that is the side length of the square. This means the radius is 6 because the radius of a circle is always half the diameter. So, the area equals 36pi.
The area of the shaded region of A is 144-36pi.
In B, the diameter of each circle is half of what it was in the circles in answer A. So, the diameter is 6 and the radius is 3. The area of each circle is 9pi, and 9 pi * 4 circles is 36pi.
The area of the shaded region of B is 144-36pi.
In C, the diameter of each circle is a third of what it was in the circles in answer A. So, the diameter is 4, and the radius is 2. The area of each circle is 4pi, and 4pi * 9 circles is 36pi.
The area of the shaded region of C is 144-36pi.
find the absolute minimuym value of the function over the clsoed triangular region d having vertices g
The absolute maximum is 56 and absolute minimum values is 24 of a function f given by f(x) = 2x³−15x² + 36x +1 on the interval [1, 5] .
A function is defined as a relationship between a set of inputs, each having an output. In short, a function is a relationship between inputs where each input relates to exactly one output. Each function has a domain and a password domain or scope. Functions are usually denoted by f(x), where x is the input.
Given that:
f(x) = 2x³ −15x²+ 36x+ 1
f'(x) = 6x² −30x + 36
Putting f'(x) = 0
⇒ 6x² − 30x+ 36 = 0
⇒ x² −5x+6 = 0
⇒ (x−2)(x−3) = 0
⇒ x=2 or 3
We are given interval [1,5]
Hence, calculating f(x) at 2, 3, 1, 5,
f(2) = 29
f(3) = 28
f(1) = 24
f(5) = 56
Hence, absolute maximum value is 56 at x=5.
Absolute minimum value is 24 at x=1.
Complete Question:
Find the absolute maximum and absolute minimum values of a function f given by f(x)=2x³−15x² + 36x +1 on the interval [1, 5] .
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Joan’s finishing time for the Bolder Boulder 10k race was 1.84 standard deviations faster than women’s average for her age group There were 395 women who ran in her age group assuming a normal distribution how many women ran faster than Joan(round down your answer to the nearest whole number)
Rounding down to the nearest whole number, we can conclude that about 12 women in her age group ran faster than Joan.
What is a whole number?A whole number is a number that is not a fraction, decimal or negative. Whole numbers include all positive integers (1, 2, 3, ...), as well as zero (0). They are also sometimes referred to as counting numbers, as they are commonly used for counting objects or items.
What is standard normal distribution?A standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1. It is a specific type of normal distribution that has been standardized to have these specific parameters, which makes it easier to calculate probabilities and perform statistical analyses.
In the given question,
We can use the standard normal distribution to solve this problem. Since Joan's finishing time was 1.84 standard deviations faster than the mean for her age group, we know that her finishing time is in the top (100% - 1.84% = 98.16%) of the distribution.
To find the number of women who ran faster than Joan, we need to find the area under the standard normal distribution curve to the right of her z-score. Using a standard normal distribution table or calculator, we can find that the area to the right of a z-score of 1.84 is 0.0322.
Therefore, approximately 395 x 0.0322 = 12.729 women in Joan's age group ran faster than her. Rounding down to the nearest whole number, we can conclude that about 12 women in her age group ran faster than Joan.
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What is the slope of the line in the following graph?
Answer:
1/3
Step-by-step explanation:
using rise over run fron the two dots, we can find 2/6, which simplifies down to 1/3
Use the graphs shown in the figure below. All have the form f(x) = abª. Which graph has the smallest value for b?
Graph D of the given function has the smallest value for b.
Exponential Function: What Is It?As per name signifies, exponents are used in exponential functions. But take note that an exponential function does not have a constant as its base and a variable as its exponent. One of the following forms can be used for an exponential function.
f (x) = aˣ
According to the graph,y=f(x) >0
f(x)=abˣ , where a>0
So, f(x)=abˣ
When, b<1 f(x) decreases
When, b>1 f(x) increases and the larger the b the steeper the graph
So, graph of D is increasing and is steepest
So, graph D has the smallest value for b.
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(06.04 MC) Jake tossed a paper cup 50 times and recorded how it landed. The table shows the results: Position Open Side Up Closed Side Up Landing on Side Number of Times Landed in Position 2 6 42 Based on the table, determine the experimental probability of each outcome (landing open side up, landing closed side up, and landing on its side). Show your work. (10 points)
To find the experimental probability for each outcome, we divide the number of times the cup lands in that position by the total number of tosses:
Experimental probability of landing open side up = number of open side up landings / total number of tosses = 2/50 = 0.04 or 4%Experimental probability of landing closed side up = number of landings closed side up / total number of tosses = 42/50 = 0.84 or 84%Experimental probability of landing on the side = number of landings on the side / total number of tosses = 6/50 = 0.12 or 12%What is a outcome?
An outcome refers to a possible result of an experiment or event that is used to calculate the probability of that result occurring.
What is meant by experimental probability?
Experimental probability is the probability of an event based on actual, repeated trials or experiments rather than theoretical or mathematical calculations.
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Fill in the missing values to make the equations true.
A person invests 5,500 dollars in a bank. The bank pays 4.5% interest compounded annually. To the nearest tenth of a year, how long must the person leave the money
in the bank until it reaches $6,700 dollars?
Work Shown:
A = P*(1+r/n)^(n*t)
6700 = 5500*(1+0.045/1)^(1*t)
6700/5500 = (1.045)^t
1.218182 = (1.045)^t
log( 1.218182 ) = log( (1.045)^t )
log( 1.218182 ) = t*log( 1.045 )
t = log(1.218182)/log(1.045)
t = 4.483724
t = 4.5
It takes about 4.5 years to reach $6700
Find the length of the missing side
10
11
12
13
Answer:
11
Step-by-step explanation:
[tex]61 {}^{2} - {60 }^{2} = 121[/tex]
[tex] \sqrt{121} = 11[/tex]
The linear sf of two similar shapes is 2:5 if the area of the similar shapes is 78cm determine the area of the bigger solid
The area of the bigger solid is 67.24 cm².
How to calculate the area of solid ?Assume the smaller shape has a length of 2x and a width of 2y. The larger shape would then have 5x length and 5y width.
Because the area of a rectangle is the product of its length and width, the area of the smaller shape is:
Area of smaller shape = 2x * 2y = 4xy
We know that the similar shapes have an area of 78 cm2. As a result, we can write:
4xy + larger area = 78
(larger shape area) / (smaller shape area) = (linear scale factor)²
Substituting the values from the problem yields:
(larger shape area) / (4xy) = (5/2)2 = 25/4
When we multiply both sides by 4xy, we get:
larger shape area = (25/4) * 4xy = 25xy
Now we can plug the expression we discovered for the area of the smaller shape into the equation we found earlier:
4xy + 25xy = 78
29xy = 78
xy = 78/29
Substituting this xy value into the expression we discovered for the area of the larger shape yields:
larger shape area = 25xy = 25 * (78/29) = 67.24 cm2 (rounded to two decimal places)
As a result, the larger shape has an area of approximately 67.24 cm2.
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Which of the following quotients are true? Select all that apply. A. 1 2 ÷ 2 = 4 B. 1 3 ÷ 4 = 4 3 C. 1 2 ÷ 6 = 1 12 D. 1 5 ÷ 2 = 10 E. 1 8 ÷ 3 = 1 24
Answer:
A. 1/2 ÷ 2 = 1/4 is true.
B. 1/3 ÷ 4 = 1/12 is true.
C. 1/2 ÷ 6 = 1/12 is true.
D. 1/5 ÷ 2 = 1/10 is true.
E. 1/8 ÷ 3 = 1/24 is true.
Therefore, all the quotients are true.
(please mark my answer as brainliest)
PLEASE HELP!!! 40 points.
Answer:
D. 7/5
Step-by-step explanation:
In right triangle ABC with right angle C,
sinA = 4/5 = cosB
cosA = 3/5 = sinB
sinB + cosB = 3/5 + 4/5 = 7/5
1. Tell whether AB is tangent to OC.
Answer:
It is a tangent
Step-by-step explanation:
A tangent is a straight line that brushes the circumference of a circle.
The radius of a circle is multiplied by 1
4
. Which of the following describes the effect of this change on the area?
a. The area is multiplied by 1
16
.
b. The area is multiplied by 1
4
.
c. The area is multiplied by 1
8
.
d. The area is multiplied by 4
.
The area is multiplied by 1/16 and the correct option is (a) The area is multiplied by 1/16.
When the radius of a circle is multiplied by 1/4, the effect on the area can be calculated using the formula A = πr², where A is the area and r is the radius. The new radius becomes (1/4)r, so the new area can be calculated by substituting (1/4)r for r in the original formula. Simplifying this expression, we get A' = π((1/4)r)² = (1/16)πr². This shows that the area is multiplied by 1/16, so the correct answer is (a) The area is multiplied by 1/16.
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Complete question:
The radius of a circle is multiplied by 1/4. Which of the following describes the effect of this change on the area?
a. The area is multiplied by 1/16.
b. The area is multiplied by 1/4.
c. The area is multiplied by 1/8.
d. The area is multiplied by 4.
need some help on this question
The value of the unknown in triangle is F = 90 degrees, angle D = 37 degrees, angle E = 53 degrees, f = 18.33 units, d = 11 units, and e = 14.59 units.
What are trigonometric identities?Trigonometric Identities are equality statements that hold true for all values of the variables in the equation and that use trigonometry functions. There are several distinctive trigonometric identities that relate a triangle's side length and angle. Only the right-angle triangle is consistent with the trigonometric identities.
Given that, angle F = 90 degrees, angle D = 37 degrees and d = 11 units.
Using the sum of interior angles of triangle we have:
angle F + angle D + angle E = 180
90 + 37 + angle E = 180
angle E = 53 degrees.
Now, using the trigonometric identities we have:
sin (37) = d / f = 11/f
f = 11 / 0.60
f = 18.33
Using tan we have:
tan (37) = d/e = 11 / e
e = 14.59
Hence, the value of the unknown in triangle is F = 90 degrees, angle D = 37 degrees, angle E = 53 degrees, f = 18.33 units, d = 11 units, and e = 14.59 units.
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What is 1 2/3 as an improper fraction
Answer:
5/3
Step-by-step explanation:
1×3=3
3+2=5
So answer is 5/3
A fair coin is tossed five times. What is the theoretical probability that the coin lands on the same side every time?
A) 0.1
B) 0.5
C) 0.03125
D) 0.0625
Answer:
Step-by-step explanation:
The theoretical probability of getting the same side every time in a single coin toss is 1/2. Since we have five independent coin tosses, we can calculate the probability of getting the same side every time by multiplying the probability of getting the same side in each toss:
(1/2) * (1/2) * (1/2) * (1/2) * (1/2) = 1/32
Therefore, the theoretical probability of getting the same side every time in five coin tosses is 1/32, which is equivalent to 0.03125. So, the answer is (C) 0.03125.
T/F. Star clusters with lots of bright, blue stars of spectral type O and B are generally younger than clusters that don't have any such stars.
The given statement "Star clusters with lots of bright, blue stars of spectral type O and B are generally younger than clusters that don't have any such stars." is True. The reason for this is that O and B stars are short-lived and burn through their fuel quickly.
The reason for this is that O and B stars burn through their fuel quickly, causing them to exhaust their nuclear fuel and end their lives in a relatively short period, typically within a few tens of millions of years.
On the other hand, stars of lower mass and cooler temperatures, like G and K type stars like our sun, have longer lifetimes and take billions of years to exhaust their nuclear fuel.
Therefore, clusters without any bright, blue stars are likely to have evolved for longer periods, allowing these short-lived stars to have already expired.
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Which mapping does not represent a function?
Answer: C
Step-by-step explanation:
For any function, a value plugged in (x) cannot have more than 1 outcome (y). C states that when x = 10, y has 2 values; 30 and 35. This means C is not a function.
Which is correct answer?
a
b
c
When g be continuous on [1,6], where g(1) = 18 and g(6): = 11. Does a value 1 < c < 6 exist such that g(c) = 12
Yes, because of the intermediate value theoremWhat is intermediate value theorem?The intermediate value theorem is a fundamental theorem in calculus that states that if a continuous function f(x) is defined on a closed interval [a, b], and if there exists a number y between f(a) and f(b), then there exists at least one point c in the interval [a, b] such that f(c) = y.
According to the intermediate value theorem,
since g(x) is a continuous function on the closed interval [1, 6]
since g(1) = 18 is greater than 12, and
g(6) = 11 is less than 12,
there must be at least one value c between 1 and 6 where g(c) = 12.
Therefore, we can conclude that a value of c does exist such that g(c) = 12.
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Please help! 20 points
Order the simplification steps of the expression below using the properties of rational exponents.
Given: We have the expression [tex]\sqrt[3]{875x^5y^9}[/tex]
Step-1: [tex]\sqrt[3]{875x^5y^9}[/tex]
Step-2: [tex](875\times x^5 \times y)^{1/3}[/tex] [break the cube root as power [tex]1/3[/tex]]
Step-3: [tex](125.7)^{1/3}\times x^{5/3} \times y^{9/3}[/tex] [break [tex]875=125\times7[/tex]]
[tex]125=5^3[/tex]
Step-4: [tex](5^3)^{1/3}\times7^{1/3}\times x^{(1+2/3)}\times y^{9/3}[/tex] [ [tex]\frac{5}{3} =1+\frac{2}{3}[/tex] ]
Step-5: [tex]5^1\times7^{1/3}\times x^1\times x^{2/3}\times y^{3}[/tex] [break the power of [tex]x[/tex]]
Step-6: [tex]5\times x\times y^{3} \ (7^{1/3}\times x^{2/3})[/tex]
Step-7: [tex]5xy^3 \ (7x^2)^{1/3}[/tex]
Step-8: [tex]5xy^3\sqrt[3]{7x^2}[/tex]
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What are the x,y axes of equations and the solution
seven students are competing in a geography bee. how many ways can they finish in first, second, and third place ?
Answer:
what is the value of x if figure below 80 degree and 50 degree x?
for 50 points! On your OWN PIECE OF PAPER, make a stem-and-leaf plot of the following set of data and then find the range of the data.
83, 71, 62, 86, 90, 95, 61, 60, 87, 72, 95, 74, 82, 54, 99, 62, 78, 76, 84, 92
Here is the stem and leaf plot:
5 4
6 0, 1, 2, 2
7 1, 2, 4, 6, 8
8 2, 3, 4, 6, 7,
9 0, 2, 5, 5, 9
The range is 45.
What is a stem and leaf plot?A stem-and-leaf plot is a table that is used to display a dataset. A stem-and-leaf plot divides a number into a stem and a leaf. The stem is the tens digit and the leaf is the units digit. For example, in the number 54, 5 is the stem and 4 is the leaf.
Range is used to measure the variation of a dataset by finding the difference between the highest number and the lowest number.
Range = highest value - lowest value
99 - 54 = 45
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6TH GRADE MATH FIND THE SLOPE OF THE TABLE, TYSM
Answer:
m = -4
Step-by-step explanation:
Slope = rise/run or (y2 - y1) / (x2 - x1)
Pick 2 Points (4,7) (5,3)
We see the y decrease by 4 and the x increase by 1, so the slope is
m = -4
Answer:
-4
Step-by-step explanation:
because the slope goes down by 4 according to the table, from 7 to 3 to -1 to -5. hope that makes sense.