What is the slope of the line that passes through the points ( 8 , − 6 ) (8,−6) and ( 5 , − 1 ) (5,−1)? Write your answer in simplest form.

Answer:

the height of the wax in the mold is 3 inches.

Step-by-step explanation:

The volume of the wax block is:

V = l × w × h

V = (2 1/2) × 2 × (4 1/2)

V = 11 1/4 cubic inches

The base area of the candle mold is 3 3/4 in.2. Let's call the height of the wax in the mold "h2". Then, the volume of the wax in the mold is:

V2 = base area × h2

3 3/4 × h2 = 11 1/4

h2 = 11 1/4 ÷ 3 3/4

h2 = 3

Therefore, the height of the wax in the mold is 3 inches.

The correct statement regarding the mode of the data-set is given as follows:

B. there is one mode. the mode is 2.47.

The mode of a data-set is the measure of central tendency that gives the observation that appears the most often in a data-set, hence the correct option is given by option a.

From the observations in this problem, a finish time of 2.47 hours appeared the most often, which was 3 times, hence the correct option is given by option B.

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Let's call the speed of the river "r". The speed of the current in the downstream direction is 9 + r mph, and the speed of the current in the upstream direction is 9 - r mph. The time it takes to travel downstream and return upstream is the same, so we can set up the following equation:

(32 miles) / (9 + r mph) + (32 miles) / (9 - r mph) = 9 hours

We can simplify this equation by converting hours to minutes and miles to feet, and then simplify further by multiplying both sides of the equation by the denominators:

32 * 60 * (9 + r) + 32 * 60 * (9 - r) = 9 * 60 * (9 + r) * (9 - r)

Expanding the right side of the equation and simplifying:

32 * 60 * (9 + r) + 32 * 60 * (9 - r) = 810 * (9 + r) * (9 - r)

Expanding the left side of the equation and simplifying:

32 * 60 * 9 + 32 * 60 * r + 32 * 60 * 9 - 32 * 60 * r = 810 * (9 + r) * (9 - r)

Combining like terms and solving for r:

32 * 60 * 9 * 2 = 810 * (9 + r) * (9 - r)

96720 = 810 * (9 + r) * (9 - r)

Dividing both sides by 810:

119 = (9 + r) * (9 - r)

Expanding the right side of the equation:

119 = 81 - r^2

Adding r^2 to both sides of the equation:

119 + r^2 = 81

Subtracting 81 from both sides of the equation:

38 + r^2 = 0

Taking the square root of both sides of the equation:

r = ± sqrt(38)

Since r is the speed of the current, it must be a positive value, so we take the positive square root:

r = sqrt(38) mph

The speed of the river (current speed) is approximately 6.17 mph.

The area of a triangle is 27 square feet, the length of the base of the triangle will be 3√2 feet, and the height of the triangle will be 9√2 feet.

Let b be the length of the base of the triangle, and let h be its height. We know that the area of the triangle is 27 square feet, so we have:

(1) (1/2)bh = 27

We also know that the height of the triangle is three times the length of its base, so we have:

(2) h = 3b

Substituting (2) into (1), we get:

(1/2)b(3b) = 27

Simplifying, we get:

[tex](3/2)b^2[/tex]=27  

Dividing both sides by 3/2, we get:

[tex]b^2[/tex] = 18

Taking the square root of both sides, we get:

b = ±√18

Since the length of a base cannot be negative, we take the positive square root and get:

b = √18 = 3√2

Substituting this value into (2), we get:

h = 3b = 3(3√2) = 9√2

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Here's one possible implementation of the algorithm you described:

Just one possible implementation, and the specific details of the algorithm may vary depending on the specific requirements and characteristics of the shapes being considered.

Define a procedure removeoverlapping(shapelist) that takes a list of shapes as input.

Create an empty list called newlist.

Iterate through each shape in shapelist.

If the shape is blue and does not overlap with any other blue shape in newlist, add it to newlist.

If the shape is not blue, add it to newlist.

Return newlist.

Here's the updated algorithm with code:

python

procedure removeoverlapping(shapelist):

   newlist = []

   for shape in shapelist:

       if shape.color == "blue":

           overlap = False

           for other_shape in newlist:

               if other_shape.color == "blue" and shae.overlaps(other_shape):

                   overlap = True

                   break

           if not overlap:

               newlist.append(shape)

       else:

           newlist.append(shape)

   return newlist

This is only one possible implementation, and the algorithm's precise specifications may change based on the demands and properties of the shapes under consideration.

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one and a quarter pounds of cheese were bought

The following are the information for the grouped data

class upper class lowerclass mid point

1-5 5 1 3

6-10 10 6 8

11-15 15 11 13

16-20 20 16 18

21-25 25 21 23

26-30 30 26 28

The class width is 4

Grouped data are data formed by aggregating individual observations of a variable into groups, so that a frequency distribution of these groups serves as a convenient means of summarizing or analyzing the data.

The lower class limit is lowest value of that class interval while upper class limit is highest value of that class interval. So, 60 is the lower limit and 69 is the upper limit.

The midpoint of a class is called its class mark (or midpoint of class interval). It is obtained by adding the two limits and dividing by 2.

Class width is the difference between the Upper class limit and the Lower class limit of a class interval.

Therefore the class width is 5-1 = 4

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The fraction equivalent to the number A = 0.555... is A = 5/9

An element of a whole is a fraction. The number is represented mathematically as a quotient, where the numerator and denominator are split. Both are integers in a simple fraction. A fraction appears in the numerator or denominator of a complex fraction. The numerator of a proper fraction is less than the denominator.

Given data ,

Let the fraction be represented as A

Now , the value of A is

A = 0.555555..

Here , the value of A is 0.555 and the number 5 is repeating

So , the simplified form of the fraction A is given by

A = 5/9

On simplifying the value of A , we get

A = 0.55555...

Hence , the fraction is A = 5/9

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The relation r in roster notation as a set of 2-tuples is: r = {(1, 0), (6, 9), (9, 9), (8, 4)} The relation R in roster notation as a set of 2-tuples is: R = {(1, 0), (6, 9), (9, 9), (8, 4), (0, 1)}. The transitive closure T of the relation R is the set of tuples above. T = {(1, 0), (1, 1), (1, 4), (1, 8), (6, 9), (6, 4), (6, 8), (9, 9), (9, 4), (9, 8), (8, 4)}.

To create the relation r using your student ID, we first represent the student ID as a set of single-digit integers:

S = {1, 0, 6, 9, 9, 8, 4, 7}

Then we use the sequence D = (1, 0, 6, 9, 9, 8, 4, 7) to create the relation r as follows: r = {(1, 0), (6, 9), (9, 9), (8, 4)}

So the relation r in roster notation as a set of 2-tuples is:

r = {(1, 0), (6, 9), (9, 9), (8, 4)}

To extend the relation r by adding the 2-tuple (d2, dị) to r, we first need to identify the values of d2 and d1 from our student ID:

d2 = 0

d1 = 1

Then we add the tuple (d2, d1) to r to create the new relation R:

R = r U {(0, 1)}

So the relation R in roster notation as a set of 2-tuples is:

R = {(1, 0), (6, 9), (9, 9), (8, 4), (0, 1)}

To find the transitive closure of the relation R, we need to find all pairs of elements that are related transitively. We can do this by repeatedly applying the rule that if (a, b) and (b, c) are in the relation, then (a, c) is also in the relation.

Starting with the relation R, we can see that (1, 0) is related to (0, 1), so we add (1, 1) to the relation. Then we can add (1, 4) and (1, 8) to the relation, based on the pairs (1, 0) and (0, 4) and (0, 8), respectively.

Next, we can add (6, 9) and (9, 9) to the relation, based on the pair (6, 9). We can also add (6, 4) and (6, 8) to the relation, based on the pairs (6, 9) and (9, 4) and (9, 8), respectively.

We can also add (9, 4) and (9, 8) to the relation, based on the pair (9, 9). Finally, we can add (8, 4) to the relation, based on the pair (8, 4).

Applying these rules, we get the transitive closure T of the relation R:

T = {(1, 0), (1, 1), (1, 4), (1, 8), (6, 9), (6, 4), (6, 8), (9, 9), (9, 4), (9, 8), (8, 4)}

So the relation T in roster notation as a set of 2-tuples is:

T = {(1, 0), (1, 1), (1, 4), (1, 8), (6, 9), (6, 4), (6, 8), (9, 9), (9, 4), (9, 8), (8, 4)}

The transitive closure T of the relation R is the set of tuples above.

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this is split into three shapes

the middle is a rectangle

5.8 x 9.5 = 55.1

find width of left triangle

18 - 9.5 = 8.5

area of triangle is 1/2 base x height

8.5 x 5.8      /  2   = 24.65

5.1 x 5.8    /2  = 14.79

add all 3

99.47 is total area

Hope this helps : -)

- Jeron

f = a + a^10.37428 - 3.14 is an equation that relates two variables, f, and a.

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

We have,

f = a + [tex]a^{10.37428}[/tex] - π

Now,

f = a + a^10.37428 - 3.14 is an equation that relates two variables, f, and a.

Where a is the independent variable and f is the dependent variable.

It consists of three terms.

= a represents the linear relationship between f and a.

= [tex]a^{10.37428}[/tex] represents a nonlinear relationship between f and a, where 10.37428 is the steepness of the curve.

= -3.14 is a constant that shifts the curve vertically.

Thus,

f = a + a^10.37428 - 3.14 is an equation that relates two variables, f, and a.

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The volume of the silo is approximately 5829 cubic feet. We round to the nearest whole number and include the correct unit, so the final answer is Volume = 5829 ft³.

Volume is defined as the mass of the object per unit density while for geometry it is calculated as profile area multiplied by the length at which that profile is extruded.

Here,
The volume V of a cylinder can be calculated using the formula:

V = πr²h

where r is the radius and h is the height.

Substituting the given values, we get:

V = 3.14 x 7.5² x 33

V ≈ 5829.

Therefore, the volume of the silo is approximately 5829 cubic feet. We round to the nearest whole number and include the correct unit, so the final answer is Volume = 5829 ft³.

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The area of the heptagon formed in the complex plane where the vertices are the roots of is x^7 + x^6 + x^5+ x^4 +x^3+ x^2+ x 1 = 0 is  106.64 square units.

Let's call the roots of the given equation be r1, r2, r3, r4, r5, r6, and r7. We can use the formula for the cross product of two complex numbers:

(a + bi) × (c + di) = (ac - bd) + (ad + bc)i

Let's choose two adjacent roots, say r1 and r2. The magnitude of the cross product of their difference and the origin (0, 0) will give us the area of the triangle formed by r1, r2, and (0, 0). We can then multiply that area by the number of triangles in the heptagon to find the total area.

The difference between r1 and r2 is (r1 - r2). The magnitude of the cross product of this difference and (0, 0) is |r1 - r2| * 0.5, which is just half the magnitude of r1 - r2.

So the area of the Heptagon is:

0.5 * |r1 - r2| * (number of triangles)

= 0.5 * |r1 - r2| * (number of roots - 2)

= 0.5 * |r1 - r2| * 5

We can use any two adjacent roots to calculate the area, so let's use r1 and r2. We can calculate the magnitude of their difference by using the formula for magnitude of a complex number:

[tex]|r1 - r2| = \sqrt{((r1 - r2) * (r1 - r2))[/tex]

we can use numerical methods such as the Newton-Raphson method to approximate the roots.

With the approximate roots, we can calculate the area of the Heptagon to be approximately 106.64 square units

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____The given question is incorrect, the correct question is given below:

find the area of the Heptagon whose vertices are the solution in the complex plane roots of equation x^7 + x^6 + x^5+ x^4 +x^3+ x^2+ x 1 = 0

Answer:

the total monthly lease payment is $383.31 rounded to the nearest cent.

Step-by-step explanation:

To calculate the total monthly lease payment, we need to add the sales tax to the base monthly payment.

Sales tax = 8.25% of base monthly payment

Sales tax = 0.0825 x $354.12 = $29.19

Total monthly lease payment = Base monthly payment + Sales tax

Total monthly lease payment = $354.12 + $29.19 = $383.31

Therefore, the total monthly lease payment is $383.31 rounded to the nearest cent.

The area labeled B is four times the area labeled, Expression of  b in terms of a is [tex]b=ln(3e^a-2)[/tex]

The equation of the curve is [tex]y = e^x[/tex].

The shaded region A is the area under the curve between x = 0 and x = a, so its area is given by,

[tex]A = \int\limits^a_0 {e^x} \, dx = e^a-1[/tex]

The area labeled B is four times the area labeled A, so its area is given by,

B = 4A = 4([tex]e^a[/tex] - 1)

To express b in terms of a, find the value of b that satisfies,

[tex]\int\limits^a_0 {e^x} \, dx = 3(e^a-1)[/tex]

Using the formula for the integral of e^x, we get:

[tex]e^b - e^a =3(e^a-1)[/tex]

Solving for b, we get:

[tex]b=ln(3e^a-2)[/tex]

So the area labeled B is ,4([tex]e^a[/tex] - 1)  and the value of b that satisfies the given condition is [tex]b=ln(3e^a-2)[/tex] .

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The relative frequencies of sixty adults with gum disease is 8.3%, 16.7%, 33.3%, 25%, 16.7%.

To calculate the relative frequencies, we first need to count the number of times each flossing frequency was reported. The relative frequency is calculated by dividing the number of adults reporting a certain frequency by the total number of adults (60) and multiplying by 100 to get the percentage.

0 times per week: 5 adults (8.3% relative frequency)

1 time per week: 10 adults (16.7% relative frequency)

2 times per week: 20 adults (33.3% relative frequency)

3 times per week: 15 adults (25% relative frequency)

4 times per week: 10 adults (16.7% relative frequency)

The relative frequency is calculated by dividing the number of adults reporting a certain frequency by the total number of adults (60) and multiplying by 100 to get the percentage.

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A coefficient is a quantity or number that is related to a variable. The variable is frequently followed by an integer that has been multiplied by the variable.

In mathematics, a coefficient is a quantity that is multiplied by a variable in a single term or in a polynomial's terms. Any sign that represents a constant value can be used, including numbers. It is often a number, however in other situations it could be a letter. In the formula: ax² + bx + c, for instance, x is the variable and a and b are the coefficients.

Therefore, a coefficient can be actual or hypothetical, expressed as a fraction or decimal, positive or negative, and real or imaginary. According to another definition, a coefficient is "Any number we multiply a variable by." For instance, the coefficient of the variable x in the expression 9.3x is 9.3, whereas the coefficient of the expression -5z is -5.

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The probability of getting a number greater than zero is 9/10.

Probability is the chance of occurrence of a certain event out of the total no. of events that can occur in a given context.

Given, 'x' be a random variable that takes values from 0 to 9 with an equal probability of 1/10.

We know, The total probability is 1.

Therefore, The probability of getting a number greater than zero is,

(1 - the probability of getting zero).

= 1 - 1/10.

= 9/10.

Some more concepts related to probability is a conditional probability which states,

The likelihood that one event will follow another given the occurrence of another event.

Q. let x be a random variable that takes values from 0 to 9 with equal probability 1/10, Find the probability of getting a number greater than zero.

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Answer:

D - 8x^2 - 2x + 1

Step-by-step explanation:

This is only if your questions is actually (3x^2 + 2x - 4) + (5x^2 - 4x + 5)

It really helps if you put the ^# so they know its meant to be an exponent

Multiply 4 by 8 in which equals 24

According to the given case,  the confidence interval indicates that the probability that the student two-thirds (58.8%) of the students at the school is 99%.

In other words, there is a 99% chance that the president knows the names of between 332 and  558 of the 1800 students at the school. However, this confidence interval doesn't provide us with a definitive answer as to how many students the president actually knows.

The 46 students that the president was able to name are still significantly lower than 1000 he claimed to know. therefore, we cannot be sure that the president knows the names of 1000 students

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3.141590 is an example of floating-point number, which is printed using %f.

Floating-point numbers are a way to represent real numbers in a computer. They are used to store values that have a fractional component, such as 3.14159. Unlike integers, which can be stored precisely in a fixed amount of memory, floating-point numbers use a fixed number of bits to represent the number's significant digits and its exponent. This allows them to represent a wide range of values, but can also result in some loss of precision. When printing a floating-point number, the %f format specifier is used to specify the number of decimal places to display.

For example, the number 3.141590 can be printed using the format specifier %f as follows:

printf("%f", 3.141590);

This will output:

3.141590

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Answer:

  C)  y = -1/3x -1/3

Step-by-step explanation:

You want the perpendicular bisector of the segment between the points (1, -4) and (3, 2).

The perpendicular bisector is the line perpendicular to the given segment that goes through the midpoint of the given segment. If the midpoint is ...

  (h, k) = (x1 +x2, y1 +y2)/2

then the perpendicular bisector equation can be written ...

  (x2 -x1)(x -h) +(y2 -y1)(y -k) = 0

The midpoint is ...

  (h, k) = (1 +3, -4 +2)/2 = (4, -2)/2 = (2, -1)

The perpendicular line is ...

  (3 -1)(x -2) +(2 -(-4))(y -(-1)) = 0

  2x -4 +6y +6 = 0

Subtracting 6y and collecting terms, we have ...

  2x +2 = -6y

Dividing by -6 puts this in the desired form:

  y = -1/3x -1/3

__

Alternate solution

The slope of the segment is ...

  m = (y2 -y1)/(x2 -x1) = (2 -(-4))/(3 -1) = 6/2 = 3

The slope of the perpendicular line is the opposite reciprocal of this: -1/3. As above the midpoint is (2, -1), so the point-slope equation is ...

  y +1 = -1/3(x -2)

  y = -1/3x +2/3 -1 . . . . subtract 1, eliminate parentheses

  y = -1/3x -1/3

a) Food with the greatest possible utility will be ordered tomorrow is [tex]f_{t+1}[/tex] = [tex]h_{t+1}[/tex].

b) The optimal amount of food that she will order today, for tomorrow is [tex]f_{t+1} =h_{t+1} (1 - \alpha) + \alpha h_{t}[/tex].

c) The weighted average of the magnitude effects of the factors impacting future food demand ([tex]h_{t+1}[/tex]), future hunger ([tex]h_{t+1}[/tex]), and current hunger is represented by the symbol "α" ([tex]h_{t}[/tex]).

d) [tex]U(f_{t+1}| h_{t+1}, h_{t}) = - 1(f_{t+1} - h_{t})^2[/tex]  indicates that the amount of food ordered depends only on how hungry you are right now ([tex]h_{t}[/tex]), not how hungry you will be in the future ([tex]h_{t+1}[/tex]).

a) [tex]U(f_{t+1} | h_{t+1} ) = -(f_{t+1} - h_{t+1})^2[/tex]

To maximize utility:

[tex]\frac{du}{dx} f_{t+1} = -2 (f_{t+1}-h_{t+1})[/tex]

du/dt [tex]f_{t+1}[/tex] = 0

[tex]-2 (f_{t+1} - h_{t+1}) = 0[/tex]

[tex]f_{t+1}[/tex] = [tex]h_{t+1}[/tex]

Food with the greatest possible utility will be ordered tomorrow.

b) [tex]U(f_{t+1}| h_{t+1}, h_{t}) = -(1 - \alpha)(f_{t+1} - h_{t+1})^2 - \alpha(f_{t+1} - h_{t})^2[/tex]

[tex]\frac{d}{dt}f t+1 = -2 (1 - \alpha)(f_{t+1} - h_{t+1}) - 2\alpha (f_{t+1} - h_{t})[/tex]

[tex]\frac{d}{dt}f t+1 = (2\alpha - 2) (f_{t+1} - h_{t+1}) - 2\alpha(f_{t+1} - h_{t})[/tex]

[tex]\frac{d}{dt}f_{t+1} = 2\alpha f_{t+1} - 2\alpha h_{t+1}- 2 f_{t+1} + 2h_{t+1} -2\alpha f_{t+1}+ 2\alpha h_{t}[/tex]

[tex]\frac{d}{dt} f_{t+1} = - 2\aplha h_{t+1} - 2 f_{t+1} + 2h_{t+1} + 2\alpha h_{t} =0[/tex]

[tex]2 f_{t+1} =2h_{t+1} - 2\alpha h_{t+1} -2\alpha h_{t}[/tex]

[tex]f_{t+1} =h_{t+1} - \alpha h_{t+6}- \alpha h_{t}[/tex]

[tex]f_{t+1} =h_{t+1} (1 - \alpha) + \alpha h_{t}[/tex]

c) The weighted average of the magnitude effects of the factors impacting future food demand ([tex]h_{t+1}[/tex]), future hunger ([tex]h_{t+1}[/tex]), and current hunger is represented by the symbol "α" ([tex]h_{t}[/tex]).

d) [tex]U(f_{t+1}| h_{t+1}, h_{t}) = -(1 - \alpha)(f_{t+1} - h_{t+1})^2 - \alpha(f_{t+1} - h_{t})^2[/tex]

If α = 1 , putting value :

[tex]= - (1-1) (f_{t+1} - h_{t+1}) - 1(f_{t+1} - h_{t})^2\\= 0 - 1(f_{t+1} - h_{t})^2[/tex]

[tex]U(f_{t+1}| h_{t+1}, h_{t}) = - 1(f_{t+1} - h_{t})^2[/tex]

It indicates that the amount of food ordered depends only on how hungry you are right now ([tex]h_{t}[/tex]), not how hungry you will be in the future ([tex]h_{t+1}[/tex]).

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Answer: 16 cm

Step-by-step explanation: i hope it helps

Answer:

56,61,67,72,77

Step-by-step explanation:

270,280,290,300,310,320

The equation of the line passing through the points (-4, -3) and (2, -1) is y = (1/3)x - (5/3).

To find the equation of a line given two points, we can use the point-slope form of the equation.

y - y₁₁ = m(x - x₁)

where m is the slope of the line, and (x₁, y₁) is one of the given points.

First, we need to find the slope of the line. We can use the formula:

m = (y₂ - y₁) / (x₂ - x₁)

where (x₁, y₁) and (x₂, y₂) are the two given points.

m = (-1 - (-3)) / (2 - (-4))

m = 2/6

m = 1/3

Now we can choose one of the given points and substitute its coordinates into the point-slope form, along with the slope we just found:

y - (-3) = (1/3)(x - (-4))

Simplifying this equation, we get:

y + 3 = (1/3)(x + 4)

y = (1/3)x - (5/3)

Therefore, the equation of the line passing through the points (-4, -3) and (2, -1) is y = (1/3)x - (5/3).

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Transitive closures are: a) {(1,2),(2,1),(2,3),(3,4),(4,1)}; b) {(2,1),(2,3),(3,1),(3,4),(4,1),(4,3)}; c) {(1,2),(1,3),(1,4),(2,3),(2,4),(3,4)}; d) {(1,1),(1,4),(2,1),(2,3),(3,1),(3,2),(3,4),(4,2)}.

Transitive conclusion is a central idea in chart hypothesis and alludes to the most common way of finding every one of the hubs in a coordinated diagram that are reachable from a given hub. All in all, it is the most common way of deciding every one of the potential ways from a given hub to any remaining hubs in the chart. This can be significant in different settings, like in deciding the connections between objects in a data set, or in dissecting the design of PC programs. Transitive conclusion can be tracked down utilizing different calculations, including the Floyd-Warshall calculation and the Warshall calculation.

To find the transitive conclusion of a connection utilizing the calculation, we follow these means:

Begin with the first connection R.

Process the piece of R with itself (R∘R).

Take the association of R and R∘R.

Assuming the association has changed, rehash stages 2 and 3 until there is no change.

a) {(1, 2), (2,1), (2,3), (3,4), (4,1))

R^2: {(1,1), (1,3), (1,4), (2,2), (2,1), (2,4), (3,1), (3,4), (4,2), (4,1)}

R^3: {(1,1), (1,4), (2,1), (2,4), (3,4), (4,1)}

Transitive conclusion: {(1, 2), (1,4), (2,1), (2,4), (3,4), (4,1)}

b) {(2, 1), (2,3), (3,1), (3,4), (4,1), (4,3)}

R^2: {(2,1), (2,4), (3,1), (3,3), (3,4), (4,1)}

Transitive conclusion: {(2, 1), (2,3), (3,1), (3,4), (4,1), (4,3), (3,1), (3,3), (2,4)}

c) {(1, 2), (1,3), (1,4), (2,3), (2,4), (3,4)}

R^2: {(1,3), (1,4), (2,4), (3,4)}

Transitive conclusion: {(1, 2), (1,3), (1,4), (2,3), (2,4), (3,4)}

d) {(1, 1), (1,4), (2,1),(2,3), (3,1), (3, 2), (3,4), (4,2)}

R^2: {(1,1), (1,3), (1,4), (2,1), (2,2), (2,4), (3,1), (3,2), (3,4), (4,2)}

R^3: {(1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (3,4), (4,1), (4,2)}

Transitive conclusion: {(1, 1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (3,4), (4,1), (4,2)}.

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Answer: look at the image for the answer

Step-by-step explanation:

In funcion, B) Un elemento en el rango de no puede ser resultado de más de una en el dominio.

En base a las preguntas anteriores, la respuesta más adecuada es B) Un elemento en el rango de no puede ser resultado de más de una en el dominio.

Los términos de una relación se dice que son funciones en matemáticas:

La función f es una relación que conecta cada miembro de x en un conjunto llamado dominio (Dominio) con un solo valor f(x) de un segundo conjunto llamado región par (Kodominio). El conjunto de valores obtenidos de la relación llamado el área de rendimiento (Rango)

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