What is the scale of the y-axis in this coordinate graph?


A. 1 tick mark represents 1 unit
B. 1 tick mark represents 8 units
C. 1 tick mark represents 12 units
D. 1 tick mark represents 16 units

Answer:

-5x + 2y=2

Step-by-step explanation:

[tex]- 7x + 3y = 2 \\ - 2x + y = 0 \\ subtracting \: this.we \: have \\ ( - 7x \: + 3y - 2) - ( - 2x + y) \\ - 7x + 2x + 3y - y - 2 \\ - 5x + 2y - 2 \\ therefore \: we \: have \\ - 5x + 2y = 2[/tex]

Answer:

4(x - [tex]\frac{1}{2}[/tex] )² = 0

Step-by-step explanation:

Given

4x² - 4x + 1 = 0 ( factor out 4 from the first 2 terms )

4(x² - x) + 1 = 0

To complete the square

add/subtract ( half the coefficient of the x- term)² to x² - x

4(x² + 2(- [tex]\frac{1}{2}[/tex] )x + [tex]\frac{1}{4}[/tex] - [tex]\frac{1}{4}[/tex] ) + 1 = 0

4(x - [tex]\frac{1}{2}[/tex] )² - 1 + 1 = 0

4(x - [tex]\frac{1}{2}[/tex] )² = 0

Hi there!

[tex]\large\boxed{\text{ B. 2}}[/tex]

f(x) = 2x + 6

Differentiating 2x = 2 (Power rule, dy/dx xⁿ =  nxⁿ⁻¹)

Differentiating a constant always equals 0.

Thus:

f'(x) = 2

Answer:

2144

formula us v = 3/4 × pi × half of the diameter (radius)

(i) the number of students who passed in the first and in the second division

         76+95=171 students

(ii) The ratio of the number of students who passed in the first second and in the third division.

RATIO  is    4:5:(25/19)       or          4:5: 1.3157894…….

225-29=196 (29students failed)

196-25=171. (Subtract 25 students from the 3rd division)

4x+5x= 171 (171 students from 1st and second division)

9x=171

         X=19

4x19=76        5x19= 95         1.31578.....x19= 25

Answer:

-24.4 ≥ w

Step-by-step explanation:

-13.4 ≥ 6.7 + 4.3 + w

-13.4 - 6.7 - 4.3 ≥ w

-24.4 ≥ w

Answer:

Neither (Answer)

Step-by-step explanation:

Comparing both the equations with slope-intercept form (y = mx + c), where 'm' is the (slope/gradient) and and 'c' is the (y-intercept).

Note: If the slopes are equal as well as the y-intercepts then they are same lines (overlapping) i.e lines are scaler multiple of each other.

Slope of line 1 = m1 = 7

slope of line 2 = m2 = 1/7

neither the slopes are equal nor the their product is equal to '-1'

Step-by-step explanation:

Try Photo-math app or Math-way app.

Answer:

15child tickets

Step-by-step explanation:

$113.60÷4=28.4

28.4×3=85.2

113.60-85.2=100:6.3=15

Answer:

mean=14

median =4

Range=3

Step-by-step explanation:

Mean = 4+6+3+1+9+0+5/2

=28/2

=14

Median = ( N+1/2 )th item

= ( 7+1 )/2

= 8/2

= 4

Range = largest no- lowest no

= 9-6

= 3

Answer:

El pelotero ha bateado imparables en el 35% de sus intentos.

Step-by-step explanation:

Dado que un pelotero profesional ha bateado 14 imparables en 40 turnos al bate, para hallar la razón entre las veces que ha bateado imparables y los turnos que ha tenido que batear se debe realizar el siguiente cálculo:

14 / 40 = X

0.35 = X

0.35 x 100 = 35

Por lo tanto, el pelotero ha bateado imparables en el 35% de sus intentos.

Answer:

400 miles

Step-by-step explanation:

825 - 425 = 400

Answer:

Step-by-step explanation:

825 - 425= 400 which is what she is going to drive on the second day

Answer:

a) [tex]-\frac{21}{18}[/tex], b) [tex]\frac{2}{8}[/tex].

Step-by-step explanation:

Let be [tex]u[/tex] a real number, its additive inverse is a real number [tex]v[/tex] so that:

[tex]u+v = 0[/tex]

That is,

[tex]v = - u[/tex] (1)

Then, the additive inverses of [tex]\frac{21}{18}[/tex] and [tex]-\frac{2}{8}[/tex] are, respectively:

a) [tex]-\frac{21}{18}[/tex], b) [tex]\frac{2}{8}[/tex].

Answer:

5/6

Step-by-step explanation:

Answer:

5/6

Step-by-step explanation:

Any negative number couldn't count as more than a positive. 5 is more than 1, so the correct answer has to be 5/6.

Answer:

just do 64 * 118 = 7552

count the decimal points in BOTH the items 1 for the 6.4

and 2 in the 1.18 1+2 = 3

so starting from the right move in "3" positions and

put a decimal point

7.552

Step-by-step explanation:

Answer:

Step-by-step explanation:

Since the coordinates of P are (0, 1), this makes P the y-intercept of that line. The y-intercept exists where x = 0. And in the coordinate (0, 1), x does in fact equal 0.

Since the one coordinate given in Q is (?, 0), this means that Q is the x-intercept of the line. The x-intercept exists where y = 0. And in the coordinate (?, 0), y does in fact equal 0. So in order to solve for the x coordinate of Q, we plug in a 0 for y and solve for x:

3(0) - 4x = 12 and

-4x = 12 so

x = -3

Answer:

x^2 + 3x + 5

Step-by-step explanation:

sum of the two given side = 2x^3 + 3x^2 + 3x -2

missing side = 2x^3 + 4x^2 + 6x + 3 - 2x^3 - 3x^2 - 3x + 2 = x^2 + 3x + 5

Answer:

Supongo que la pregunta completa es:

"Una recta pasa por los puntos A(-4, 0) y B(2, -3)"

Luego dice "calcular su área", pero una recta es un elemento unidimensional (los cuales no tienen área, el área es un concepto bidimensional).

Por lo que el área de esta recta no está definida.

Ignorando esto, podemos encontrar la ecuación que define a nuestra recta.

Sabemos que una recta se escribe como:

y = a*x + b

donde a es la pendiente y b es la ordenada al origen.

Sabemos que para una recta que pasa por los puntos (x₁, y₁) y (x₂, y₂), la pendiente será:

a = (y₂ - y₁)/(x₂ - x₁)

Entonces, para nuestra recta que pasa por los puntos (-4, 0) y (2, - 3) la pendiente será:

a = (-3 - 0)/(2 - (-4) )

a = -3/6 = -1/2

Entonces nuestra línea es algo como:

y = (-1/2)*x + b

para encontrar el valor de b, usamos el hecho de que esta línea pasa por el punto (2, -3)

esto significa que cuando x = 2, tenemos que tener y = -3

reemplazando esos dos valores obtenemos

-3 = (-1/2)*2 + b

-3 = -1 + b

-3 + 1 = b

-2 = b

La ecuación que define a esta recta es:

y = -(1/2)*x  - 2

Nuevamente, el área de esta recta no está definida, por lo que no podemos calcular el área de esta recta.

Answer:

hi.

Step-by-step explanation:

download photo math

The cue ball needs to be hit at a point that is 21.66 inches from the top bumper and 13 inches from the right bumper.

The first step is to calculate the angle at which the cue ball will hit the top bumper. We know that the angle of incidence is equal to the complement of the angle of reflection, so the angle of incidence is equal to 90 - 13/50 = 77 degrees.

The next step is to calculate the distance that the cue ball will travel along the top bumper before it strikes the other ball. We know that the angle of incidence is equal to the angle of reflection, so the angle of reflection is also 77 degrees. We also know that the distance between the cue ball and the other ball is 50 inches.

Using the law of sines, we can write the following equation:

sin(77) = (50 / d) * sin(180 - 77)

where d is the distance that the cue ball will travel along the top bumper before it strikes the other ball.

Solving for d, we get:

d = 50 * sin(77) / sin(103)

≈ 21.66 inches

Therefore, the cue ball needs to be hit at a point that is 21.66 inches from the top bumper and 13 inches from the right bumper.

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Answer:

1.2055 × 10⁴

Step-by-step explanation:

10,000 + 2,000 + 50 + 5

= 12,055

Writing 12,055 in standard form

The first digit in standard form should be between 1 and 10

Therefore, the first digit in 12,055 is 1 then point other numbers

As in 1.2055

There are 4 digits after the decimal point.

So we have 10⁴

12,055 = 1.2055 × 10⁴

Check:

1.2055 × 10⁴

= 1.2055 × 10,000

= 12,055

From online research, the article is;

As days get shorter and colder in the autumn, chlorophyll molecules break down. Leaves quickly lose their green color. Some leaves begin to look yellow or orange because they still contain pigments called carotenoids. One such pigment, carotene, gives carrots their bright-orange color.

But red is special. This brilliant color appears only because the leaves of some plants, including maples, actually produce new pigments, called anthocyanins.

That’s a strange thing for a plant to do without a reason, says Bill Hoch of the University of Wisconsin in Madison. Why? Because it takes a lot of energy to make anthocyanins.

Why red?

To figure out the purpose of the red pigment, Hoch and his coworkers bred mutant plants that can’t make anthocyanins and compared them with plants that do make anthocyanins. They found that plants that can make red pigments continue to absorb nutrients from their leaves long after the mutant plants have stopped.

This study and others suggest that anthocyanins work like a sunscreen. When chlorophyll breaks down, a plant’s leaves become vulnerable to the sun’s harsh rays. By turning red, plants protect themselves from sun damage. They can continue to take nutrients out of their dying leaves. These reserves help the plants stay healthy through the winter.

The more anthocyanins a plant produces, the redder its leaves become. This explains why colors vary from year to year, and even from tree to tree. Stressful conditions, such as drought and disease, often make a season redder.

Now, Hoch is breeding plants for a new set of experiments. He wants to find out whether turning red helps plants survive cold weather.

“There’s a clear correlation between environments that get colder in the fall and the amount of red produced,” he says. “Red maples turn bright red in Wisconsin. In Florida, they don’t turn nearly as bright.”

More protection

Elsewhere, scientists are looking at anthocyanins in other ways. A recent study in Greece, for instance, found that as leaves grow redder, insects eat them less. On the basis of this observation, some scientists argue that red pigments defend a plant against bugs.

Leaves may turn red in the autumn to protect themselves from the sun’s ultraviolet rays.

J. Miller

Hoch rejects that theory, but Lee thinks that it might make sense. He points out that red leaves contain less nitrogen than green ones do. “It may actually be that insects avoid red leaves because they’re less nutritious,” Lee says.

However, “it’s pretty confusing at this point,” Lee admits. “People debate back and forth.”

To settle the debate, scientists will need to look at more species under more conditions, Lee says. So, he’s now researching leafy plants rather than trees. He’s especially interested in tropical plants, whose leaves turn red when they’re young rather than old.

Answer:

As seen in the Explanation, different people have given reasons why bright red leaves in the fall help protect the trees in the winter. Thus, there is sufficient evidence to conclude that bright red leaves in the fall help protect the trees in the winter.

Step-by-step explanation:

From the article, we can see that Hoch and his coworkers carried out an experiment on mutants and they discovered that plants that can make red pigments tend to continue absorbing nutrients from their leaves a long time after the mutant plants have stopped.

This study and other believe that plants make anthocyanins which acts as a kind of sunscreen to the plants. They also discovered that by the plants turning red, they protect themselves from sun damage

Also, we see that some scientists in Greece found out that as leaves grow redder, insects eat them less and they argued that red pigments defend a plant against bugs and as such Leaves may turn red in the autumn to protect themselves from the sun’s ultraviolet rays.

My Answer: One study said that anthocyanins are pigments that make leaves turn red. And some trees don’t absorb as many nutrients as trees with red leaves. That particular study focused on trees that don’t produce anthocyanins. So i believe there's some evidence, but not a definitive conclusion.

Edmentum Answer: There’s some evidence, but not a definitive conclusion. One study focused on trees that don’t produce anthocyanins. Anthocyanins are pigments that make leaves turn red. The study said that these trees don’t absorb as many nutrients as trees with red leaves.

Another study found that insects are generally not inclined to eat red leaves on trees. There seems to be a trend that suggests that red leaves are important for the trees’ survival in the fall. This trend needs to be validated by conducting more tests.

Step-by-step explanation:

Paraphrased

Answer:

D

Step-by-step explanation:

First find h(3)

2(3)-2= 4

then find g(4)

4³-5= 59

Answer:

there would be many diffrent answers

Step-by-step explanation:

provide the full question, i can deduct that there are many ice cream flavors.

Answer:

x=29°

Step-by-step explanation:

as lines are parallel.

external alternate angles are equal.

7x-86=4x+1

7x-4x=1+86

3x=87

x=87/3=29

Answer:

x=15

Step-by-step explanation:

The 60 degree angle and the (x+45) degree angle are both the same degree because they are vertical angles.

So to solve, just subtract 45 from 60

60-45=15

That's your answer!

Hope this helps!

Answer:

The expressions that give the value of y are A - 3B and (1/3)A - B

The solution is (27/13, -60/13)

Step-by-step explanation:

We can see both equation A and equation B.

Equation A: 2x + (1/4)y = 3

Equation B: (2/3)x - y = 6

To find the value of y, we have to solve both equations A and equation B simultaneously. This is done by multiplying equation B by 3 and subtracting from equation A (A - 3B) to get:

(13/4)y = -15

y = -60/13

you can also get y by dividing equation A by 3 and subtracting equation B (1/3A - B)

Put y = -60/13 in equation A to get x:

2x + (1/4)(-60/13) = 3

2x = 3 + 15/13

2x = 54/13

x = 27/13

The solution is (27/13, -60/13)

(a) ∠AEC = ∠CFD, by transitive property of equality

(b) ∠CDE = 108°, ∠DCB = 108°, ∠ABC = 108°,∠EAB = 144°, ∠AED = 72°

The reason the above values are correct is as follows:

(a) The given parameters are;

Figure ABCDE is a pentagon

The sides AE is parallel to side CD

Line EC is parallel to side BC

The point of intersection of the extension off side ED and BC = Point F

∠ABC = ∠CDE

Required:

To show that ∠AEC = ∠CFD

Method:

Draw the pentagon ABCDE and include the added construction

Analyze the drawing

Solution:

∠ECF and ∠ABC are corresponding angles between parallel lines EC ║BC

∴ ∠ECF ≅ ∠ABC by corresponding angles formed by parallel lines are congruent

∠ECF = ∠ABC by definition of congruency

∠ABC = ∠CDE = ∠ECF by transitive property

∠ECD ≅ ∠AEC by alternate angles formed between parallel lines having a common transversal

∠ECD = ∠AEC by definition of congruency

∠ECF = ∠FCD + ∠ECD by angle addition postulate

∠CDE = ∠FCD + ∠CFD by exterior angle theorem

From ∠CDE = ∠ECF above, we have;

∠ECF = ∠FCD + ∠ECD = ∠FCD + ∠CFD

∴ ∠ECD = ∠CFD by addition property

∠ECD = ∠AEC, therefore;

∠AEC = ∠CFD, by transitive property

(b) Given that ΔEDC and ΔDFC are both isosceles triangles, with sides;

ED = DC, and DF = FC;

Let r represent ∠CFD, we have;

∠FCD = ∠CDF by base angles of isosceles triangle ΔDFC

∠ECD = ∠CED by base angles of isosceles triangle ΔEDC

∠AEG = ∠CDE by corresponding angles formed by parallel lines having a common transversal

∠AEC = ∠ECD by alternate angles

∴ ∠AEG + ∠AEC + ∠CED = 180° Sum of angles on a straight line

∠CDE = ∠CFD + ∠FCD

∠CDE + ∠CDF = 180° (linear pair angles)

∴ ∠AEG + ∠CDF = 180° by transitive property

∠AEC + ∠CED = ∠CDF by transitive property

∠AEC = ∠ECD = ∠CED = ∠CFD = r

∴ ∠CFD + ∠CFD = ∠CDF

2·r = ∠CDF

∠CDE = ∠FCD + ∠CFD

∠FCD = ∠CDF = 2·r

∴ ∠CDE = 2·r + r = 3·r

∠CDE = 3·r

The angles of the pentagon are;

∠CDE + ∠DCB + ∠ABC + ∠EAB + ∠AED = 540° sum of angles in a pentagon

∠DCB = 180° - ∠FCD

∠DCB = 180° - 2·r

∠ABC = ∠CDE = 3·r

∠EAB = ∠CEH corresponding angles

∠CEH = 180 - ∠AEC

∴ ∠EAB = 180° - ∠AEC

∴ ∠EAB = 180° - r

∠AED = ∠AEC + ∠CED = r + r = 2·r

∠AED = 2·r

Therefore, we have;

3·r + 180° - 2·r + 3·r + 180° - r + 2·r = 540°

5·r + 360° = 540°

r = (540° - 360°)/5 = 36°

r = 36°

∠CDE = 3 × 36° = 108°

∠DCB = 180° - 2×36° = 108°

∠ABC = 3 × 36° = 108°

∠EAB = 180° - 36° = 144°

∠AED = 2 × 36° = 72°

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