What is the remainder when f(x) = 2x^4 + x^3- 8x - 1 is divided by x - 2?
A. -23
B. 23
C. -3
D. 3

Answers

Answer 1

By the remainder theorem, dividing [tex]f(x)[/tex] by [tex]x-2[/tex] leaves a remainder of [tex]f(2)[/tex], which is

[tex]f(2)=2(2)^4+(2)^3-8(2)-1=\boxed{23}[/tex]

which makes B the correct answer.

Answer 2

The remainder when f(x) = 2x^4 + x^3- 8x - 1 is divided by x - 2 is 23

A polynomial is an expression consisting of the operations of addition, subtraction, multiplication of variables.

Polynomial based on degree is linear, quadratic, cubic.

The remainder theorem states that when a polynomial, f(x), is divided by a linear polynomial x - a, the remainder of is to f(a)

Given that f(x) = 2x⁴ + x³ - 8x - 1 is divided by x - 2

x - 2 = 0

x = 2

f(2) = 2(2)⁴ + (2)³ - 8(2) - 1 = 23

Hence The remainder when f(x) = 2x^4 + x^3- 8x - 1 is divided by x - 2 is 23

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Answer:

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Step-by-step explanation:

Let

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B be the set of students in dance class

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n(B) = 57      

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n(A ∪ B) = n(A) + n(B) - n(A ∩ B) = 35 + 57 - 12 = 80

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n(A ∪ B) = n(A) + n(B) - n(A ∩ B) = n(A) + n(B)  = 35 + 57 = 92

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Step-by-step explanation:

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First try was incorrect
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Answers

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Answers

Step-by-step explanation:

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