What is the rational number equivalent to 3 point 12 with a bar over 12?

Answer:

A function is an equation that has only one answer for y for every x. A function assigns exactly one output to each input of a specified type. It is common to name a function either f(x) or g(x) instead of y. f(2) means that we should find the value of our function when x equals 2. Example.

Step-by-step explanation:

The domain and range of the given function plotted on the graph is -

Domain : x ≥ -5

Range : y ≥ -2

Range of the function is the set of {y} - values that exist for a given value of {x} or for the existing domain of the function. As it can be seen from the graph that the {y} values range from -2 {included} to ∞ {excluded}. So, the range of the given function is [-2, 2).

Domain is the set of {x} values for which the function exist. We can see that the function values are in range [-5, ∞).

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Answer:

1250

Step-by-step explanation:

VOLUME = LENGTH X WIDTH

5 x 5 x 5 = 125 - volume of 1 cube

125 x 10 = 1250

Why do we multiply 125 by 10? There are 10 cubes and the volume of each is 125. To find the total volume, we would need to multiply.

Answer:

E. -1, 0, 1, 2, 3, 4, 5, 6

Step-by-step explanation:

In the first inequality, n is greater than -2.

Meaning n= -1, 0, 1, 2, 3, ...

In the second inequality it was stated that n is less than or equal to 6. this means that n = 6, 5, 4, ....

Thus, n = -1, 0, 1, 2, 3, 4, 5, 6

Answer:  137.5cm²

Step-by-step explanation:

See the attached image.

Answer:

1/2 of the cup.

3/4 is half of 1 1/2.

The value of cos(-t) from the given expression is -0.1036

Given the trigonometry identity

sec(t) = -9.65

According to trig identity

sec(t) = 1/cos(t)

cos(-t) = cost

Hence;

cos(t) = -1/9.65
cos(t) = cos(-t) = -0.1036

Hence the value of cos(-t) from the given expression is -0.1036

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Answer:

36

Step-by-step explanation:

to find 100%, multiply 9 (25%) by 4 and get 36

25% of 36 is 9.

Important information:

We need to find the unknown number w.

25% of a number w is 9. So,

[tex]\dfrac{25}{100}w=9[/tex]

[tex]\dfrac{1}{4}w=9[/tex]

[tex]w=9\times 4[/tex]

[tex]w=36[/tex]

Thus, the value of the unknown number is 36.

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Answer:

The first quartile is 99.5

Step-by-step explanation:

Answer:

c=2.5652

Step-by-step explanation:

Given ,

1/4c+5/3c-4=2-1/12

or, c(1/4+5/3)=2-1/12+4

or,c(( 3+20)/12)=(24-1+36)/12

or,23/12c=59/12

or.23c=59

or,c=59/23

or,c=2.5652

Answer:

y= -⅕x -7

Step-by-step explanation:

The slope of a perpendicular line is the negative reciprocal of that of the given line.

That is, if the slope of the given line is m, then the slope of the perpendicular line is [tex] - \frac{1}{m} [/tex].

Another way to remember it is that the product of the slopes of two perpendicular lines is -1.

Given equation: y= 5x +9

This equation is in the slope-intercept form, thus its slope is the coefficient of x.

Slope= 5

Slope of perpendicular line= -⅕

Hence we should look for an equation with -⅕ as the coefficient of x, since all the options given are in slope-intercept form.

Thus, y= -⅕x -7 is the correct option.

What is slope- intercept form?

Answer:

I think w=5 not to sure though

Answer:

[B] 0, 19.5, 160.5, 180, 360

Step-by-step explanation:

3 sin²θ = sin θ

3 sin²θ − sin θ = 0

sin θ (3 sin θ − 1) = 0

sin θ = 0 or sin θ = ⅓

If sin θ = 0, θ = 0°, 180°, 360°.

If sin θ = ⅓, θ = 19.5°, 160.5°.

Answer:

c

Step-by-step explanation:

it has a repeating domain so it can not be a function

0,−1,2,1,0 has two values corresponding to a range of functions so it will not form a function so option (C) will be correct.

A function's range is the set of all values that the function accepts, and its domain is the set of all values for which the function is defined.

The domain is for the independent variable while the range is for the dependent variable.

For example f(x) = x²

Now if we put x = 1 then it is called as domain variable while the value of functin at x = 1 its that f(1) = 1 called range variable.

To be a relation a function for every single unique input there must be single unique output.

Since the interval 0,−1,2,1,0 has 2 inputs for single output so it will not form an function.

Hence "0,−1,2,1,0 has two values corresponding to a range of functions so it will not form a function".

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Answer:

(x,y)→(y,-x)

Step-by-step explanation:

Given : A triangle is rotated 90 degrees about the origin.

To Find : Which rule describes the transformation?

Solution :

Knowing that:

90° rotation ( clockwise) is (x,y)→(y,-x)

~Lenvy~

The rule which describes the transformation is (x, y) → (–y, x).

Rotation is a kind of geometric transformation where a figure or point is rotated by a certain degrees about a given point.

Given that,

A triangle is rotated 90° about the origin.

A point (x, y) when rotated 90 degrees about the origin results in the point (-y, x).

Here a triangle is rotated 90° about the origin.

Rule is,

(x, y) → (–y, x)

Hence the correct rule is (x, y) → (–y, x).

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Answer:

Yes your answer is E with a total score of 89

Answer:

x = -164/35.

Step-by-step explanation:

x - 8(2x + 3x +2) = -4x +148

x - 16x - 24x - 16 = -4x + 148

x - 16x - 24x + 4x = 148 + 16

-35x = 164

x = -164/35

Answer:

the answer is 1.9

Step-by-step explanation:

because I multiply.38×5

Answer :

⠀

Explanation :

⠀

Solution :

where,

⠀

We know that,

[tex] {\longrightarrow \bf \qquad (AC) {}^{2} = (AB) {}^{2} +( BC) {}^{2} }

[/tex]

⠀

Now, we will substitute the given values in the formula :

[tex] {\longrightarrow \sf \qquad (AC) {}^{2} = (8) {}^{2} +( 6) {}^{2} }[/tex]

⠀

We know that, (8)² = 64 and (6)² = 36. So,

[tex] {\longrightarrow \sf \qquad (AC) {}^{2} = 64 + 36 }[/tex]

⠀

Now, adding 64 and 36 we get :

[tex] {\longrightarrow \sf \qquad (AC) {}^{2} = 100 }[/tex]

⠀

Now, we'll take the square root of both sides to remove the square from AC :

[tex] {\longrightarrow \sf \qquad \sqrt{(AC) {}^{2}} = \sqrt{100} }[/tex]

⠀

[tex] {\longrightarrow \sf \qquad AC = \sqrt{100} }[/tex]

⠀

We know that, square root of 100 is 10 .

[tex] {\longrightarrow \bf \qquad AC = 10 }[/tex]

⠀

So,

Explanation:

Start by writing out set A = {6,7,8,9,10,11,12}

Then introduce items from set B that aren't already in set A. So you'll introduce 14 and 16 to get the answer shown above. The answer represents all the numbers that are in set A or set B or in both sets.

A slightly similar approach is to write all of the given numbers in one big set like so

{6,7,8,9,10,11,12,    8,10,12,14,16}

then we erase the duplicates 8,10,12 to get the answer above.

When dealing with sets, we only have one unique item at a time.

We can replace the "OR" in "A OR B" with the union symbol. So we could write A U B

Answer:

Hope this helps you hehehe!

The height is the distance between the opposite parallel sides of the parallelogram.

Therefore, the height of the parallelogram is 4 cm.

Answer:4.8

Step-by-step explanation:

Answer:

option B: 15[tex]x^8 y^5 z^7[/tex]

Step-by-step explanation:

we just calculate 5 x^4 y^2 z^2 multiplied by 3x^4 y^3 z^5

and that gives the answer

Answer:

  (c)  square

Step-by-step explanation:

When a cube is cut perpendicular to its base and parallel to a face, the resulting cross section is a square. (see the first attachment)

__

Additional comment

If the cut is not parallel to a face, the resulting cross section is a rectangle. (see the second attachment)

Answer:

Square

Step-by-step explanation:

I took the test

Answer:

2

Step-by-step explanation:

(3 + √7)(3 - √7)

3(3 - √7) + √7(3 - √7)

9 - 3√7 + 3√7 - √49

9 - 7 = 2

I hope this helps!

Answer:

  3/4 square units

Step-by-step explanation:

When linear dimensions of similar figures are related by a factor of k, their areas are related by a factor of k².

For an original figure of area 12, each image figure dilated by a factor of k will have an area of 12k².

For k=1/4, the area is ...

  12(1/4)² = 12/16 = 3/4 . . . . square units

_____

Additional comment

Their volumes are related by a factor of k³. It can help you understand if you think about the area and volume formulas:

  A = LW

  A' = L'W' = (kL)(kW) = k²·LW = k²·A

Similarly ...

  V = LWH

  V' = L'W'H' = (kL)(kW)(kH) = k³·LWH = k³·V