Answer:
his is an example of a first-year chemistry question where you must first convert two of the pressures to the units of the third and add them up, per Dalton’s law of additive pressures. There are three possible answers, one for each of the three pressure units.
1 atm = 760 torr …… torr and mm Hg are the same
1 atm = 101.3 kPa
Dalton’s law:
P(total) = P(O2) + P(N2) + P(CO2)
Explanation:
Gases will assume whatever pressure depending on the equation of state of the mixture (in this case) and the volume htey are contained in. That could be the ideal gas law and simple mixing law, If you are quoting the partial pressures which you call simply “the pressure” of each gas, and that these refer to their values in the present mixture, then yes, we would add them up. The pressures are low enough for the ideal gas law to apply provided the temperature is not extremely low as well .
It is often possible to change a hydrate into an anhydrous compound by heating it to drive off the water (dehydration). A 45.91 gram sample of a hydrate of MnSO4 was heated thoroughly in a porcelain crucible, until its weight remained constant. After heating, 37.07 grams of the anhydrous compound remained. What is the formula of the hydrate
Answer: The formula of the hydrate is [tex]MnSO_4.2H_2O[/tex]
Explanation:
Decomposition of hydrated manganese sulphate is given by:
[tex]MnSO_4.xH_2O\rightarrow MnSO_4+xH_2O[/tex]
Molar mass of [tex]MnSO_4[/tex] = 151.0 g/mol
According to stoichiometry:
(151.0+18x) g of [tex]MnSO_4.xH_2O[/tex] decomposes to give 151.0 g of [tex]MnSO_4[/tex]
Thus 45.91 g of [tex]MnSO_4.xH_2O[/tex] decomposes to give= [tex]\frac{ 151.0}{151.0+18x}\times 45.91g[/tex] of [tex]MnSO_4[/tex]
Also we are given : 37.07 g of [tex]MnSO_4[/tex] is produced
Thus we can equate the two equations:
[tex]\frac{ 151.0}{151.0+18x}\times 45.91=37.07[/tex]
[tex]x=2[/tex]
Thus the formula of the hydrate is [tex]MnSO_4.2H_2O[/tex]
1) Give all the mole-to-mole relationships (ratios) that exist in fraction form for the following reaction. (12 total) 2 Li2O2 + 2 CO2 2 Li2CO3 + O2
Answer:
1 mol Li₂O₂/mol CO₂ or 1 mol CO₂/mol Li₂O₂
2 mol Li₂CO₃/mol O₂ or 1 mol O₂/2 mol Li₂CO₃
1 mol Li₂O₂/mol Li₂CO₃ or 1 mol Li₂CO₃/mol Li₂O₂
2 mol Li₂O₂/mol O₂ or 1 mol O₂/2 mol Li₂O₂
1 mol CO₂/mol Li₂CO₃ or 1 mol Li₂CO₃/mol CO₂
2 mol CO₂/mol O₂ or 1 mol O₂/2 mol CO₂
Explanation:
The balanced chemical equation is:
2 Li₂O₂ + 2 CO₂ → 2 Li₂CO₃ + O₂
The mole-to-mole relationships are provided by the chemical stoichiometric coefficients (2 for Li₂O₂, 2 for CO₂, 2 for Li₂CO₃ and 1 for O₂).
We have to relate the moles of 1 compound to the moles of another compound in the equation. So, we can start writing the relationships between reactants (Li₂O₂ and CO₂)
2 moles of Li₂O₂ react with 2 moles of CO₂ → 2 mol Li₂O₂/2 mol CO₂= 1 mol Li₂O₂/mol CO₂ or 1 mol CO₂/mol Li₂O₂
Now, the relationships between products (Li₂CO₃ and O₂):
2 moles of Li₂CO₃ are produced when 1 mol of O₂ produced → 2 mol Li₂CO₃/1 mol O₂= 2 mol Li₂CO₃/mol O₂ or 1 mol O₂/2 mol Li₂CO₃
Finally, between reactants and products:
2 moles of Li₂O₂ produce 2 moles of Li₂CO₃ → 2 mol Li₂O₂/2 mol Li₂CO₃= 1 mol Li₂O₂/mol Li₂CO₃ or 1 mol Li₂CO₃/mol Li₂O₂
2 moles of Li₂O₂ produce 1 mol of O₂ → 2 mol Li₂O₂/1 mol O₂= 2 mol Li₂O₂/mol O₂ or 1 mol O₂/2 mol Li₂O₂
2 moles of CO₂ produce 2 moles of Li₂CO₃ → 2 mol CO₂/2 mol Li₂CO₃= 1 mol CO₂/mol Li₂CO₃ or 1 mol Li₂CO₃/mol CO₂
2 moles of CO₂ produce 1 mol of O₂ → 2 mol CO₂/1 mol O₂= 2 mol CO₂/mol O₂ or 1 mol O₂/2 mol CO₂
Calculate the [OH-] in a solution that has a pH of 3.08.
a. 1.2x10-9
b. 8.3x10-3
C. 1.2x10-11
d. 8.3x10-4
Answer:
C. 1.2 x 10^-11
Explanation:
pOH = 14 - pH = 14 - 3.08 = 10.92
[OH-] = 10^-pOH = 10^-10.92 = 1.2 x 10^-11
Use the following balanced reaction to solve:
P4 (s) + 6H2 (g) → 4PH3 (g)
How many grams of phosphorus trihydride will be formed by reacting 60 L of Hydrogen gas with an excess of P4?
Answer: 60.7 g of [tex]PH_3[/tex] will be formed.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given volume}}{\text{Molar volume}}[/tex]
[tex]\text{Moles of} H_2=\frac{60L}{22.4L}=2.68moles[/tex]
The balanced chemical reaction is
[tex]P_4(s)+6H_2(g)\rightarrow 4PH_3(g)[/tex]
[tex]H_2[/tex] is the limiting reagent as it limits the formation of product and [tex]P_4[/tex] is the excess reagent.
According to stoichiometry :
6 moles of [tex]H_2[/tex] produce = 4 moles of [tex]PH_3[/tex]
Thus 2.68 moles of [tex]H_2[/tex] will produce=[tex]\frac{4}{6}\times 2.68=1.79moles[/tex] of [tex]PH_3[/tex]
Mass of [tex]PH_3=moles\times {\text {Molar mass}}=1.79moles\times 33.9g/mol=60.7g[/tex]
Thus 60.7 g of [tex]PH_3[/tex] will be formed by reactiong 60 L of hydrogen gas with an excess of [tex]P_4[/tex]
POS MOLECULES SPEED UP WHEN ENERGY IS CREATED AND SLOW DOWN WHEN ENERGY IS DESTROYED True False? explain why
Answer: Scientists use the term bioenergetics to describe the concept of energy flow (Figure 4.2) through living systems, such as cells. Cellular processes such as the building and breaking down of complex molecules occur through stepwise chemical reactions. Some of these chemical reactions are spontaneous and release energy, whereas others require energy to proceed. Just as living things must continually consume food to replenish their energy supplies, cells must continually produce more energy to replenish that used by the many energy-requiring chemical reactions that constantly take place. Together, all of the chemical reactions that take place inside cells, including those that consume or generate energy, are referred to as the cell’s metabolism.
what are the twa parts of central nervous system ?
Answer:
The nervous system has two main parts: The central nervous system is made up of the brain and spinal cord.
Explanation:
Which compound is more soluble in water at 25°C?
A.
MgF2 (Ksp = 5.2 x 10-11)
B.
SrF2 (Ksp = 7.9 x 10-10)
C.
AgBr (Ksp = 5.0 x 10-13)
D.
Agl (Ksp = 1.5 * 10-16)
Answer:
B
Explanation:
The solubility depends on the ksp. As the value of ksp increases the compound becomes more and more soluble.
In the options, the highest ksp value is 10^-10, thus that one is the most soluble.
Consider the fatty acid. A carboxylate salt is attached to a 19 carbon chain, where double bonds are present between carbons 5 and 6, between carbons 8 and 9, between carbons 11 and 12, and between 14 and 15. The carboxylate carbon is carbon 1. All double bonds are cis. Which of the designations are accurate for the fatty acid
Answer:
ω-3 fatty acid and 19:4(Δ5,8,11,14)
Explanation:
From the image attached below:
We can see the structure of the delta nomenclature showing the numbers of carbons, numbers of double bonds, and the locations of the double bonds in the structure of the carboxylate salt.
Also, we can see the structure of the fatty acid where; the location of the first double bond from the methyl end is shown.
Hence, the designation which are accurate for these structures are:
ω-3 fatty acid and 19:4(Δ5,8,11,14)
what is hydrogen ion concentration of an acid solution whose PH is 3.4?
Given that C = n/V. And you have n=2 and C=4 what does V= ??
1...0.5
2...2
3...4
4...8
or5...Dont know
Calculate the [H+] concentration for a solution with a pH of 6.4
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Answer: 3.98 x 10^-7
Explanation:
I hope this helped!
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can you help me please I would love that
Answer:
what are you confused on?
Which environment can occur for a short while and usually found in low level areas along rivers, lakes, and streams?
Desert
Mountain
Rainforest
Wetland
Answer:The answer is wetland or rainforest
Explanation:
It’s wetland or rainforest because its with the tropical zone and there will be no such thing as desert and mountain have those but the rainforest is with the tropic to so Goodluck with any of your test and hope this did not make sense xdd
Calculate the mass of calcium chloride that contains 3.20 x 1024 atoms of chlorine.
Answer:
294.87 gm CaCl_2
Explanation:
The computation of the mass of calcium chloride is shown below:
But before that following calculations need to be done
Number of moles of chlorine atom is
= 3.20 × 10^24 ÷ 6.022 × 10^23
= 5.314 moles
As we know that
1 mole CaCl_2 have the 2 moles of chlorine atoms
Now 5.341 mole chloride atoms would be
= 1 ÷ 2 × 5.314
= 2.657 moles
Now
Mass of CaCl_2 = Number of moles × molar mass of CaCl_2
= 2.657 moles × 110.98 g/mol
= 294.87 gm CaCl_2
Which is a similarity between a fish embryo and a bird embryo in the early stages of development?
Gill slits
forelimbs
jaw bones
hindlimbs
Answer:
Gill Slits
Explanation:
For the one who asked what hind limbs are they are back legs :)
Chromium is manufactured by heating a mixture of chromium(III) oxide with aluminium powder.
Cr2O3(s) + 2Al(s) → 2Cr(s) + Al2O3(s)
a=Calculate the mass of aluminium needed to react with 50 g of Cr2O3.
b=Calculate the mass of chromium produced from 50 g of Cr2O3.
c=Calculate the mass of chromium produced from 5 kg of Cr2O3.
d=Calculate the mass of chromium produced from5 tonnes of Cr2O3.
Note: 1 tonne = 1,000,000 g
Ar: Cr = 52, O = 16, Al = 27
The fizz in the soda that we drink is carbonic acid. Leaving the soda can open to the environment separates the carbonic acid into water and carbon dioxide. What type of reaction is this and what is the resulting product?
Answer:
The reactionnis known as a decomposition reaction
The equation of the reaction is given below as:
H₂CO₃ -----> H₂O + CO₂
Explanation:
A reaction in which a single compound is split into two or more simpler substances is known as a decomposition reaction.
In the reaction in which when a soda can is opened and left to the environment, the fizz in the soda, carbonic acid, separates into water and carbon dioxide is an example of a decomposition reaction.
The equation of the reaction is given below:
H₂CO₃ -----> H₂O + CO₂
In the reaction above, a larger molecular weight compound, carbonic acid with the molecular, H₂CO₃ is splits into two simpler substances of smaller molecular weight, water, H₂O and carbon dioxide, CO₂.
This reaction rate is made faster by an increase in temperature and by a decrease in pressure of the soda.
MATch THE BOXED PLEASEEEE
Answer:
Transform = The third one
Convergent = the first one
Divergent = the second one
Explanation:
Does Borax pure substance?
Answer:
Borax is a natural mineral with a chemical formula Na2B4O7 • 10H2O. Borax also is known as sodium borate, sodium tetraborate, or disodium tetraborate. It is one of the most important boron compounds. The International Union of Pure and Applied Chemistry (IUPAC) name for borax is sodium tetraborate decahydrate.
How many non bonding electrons is in OH-
Answer:
There are 8 valence electrons
Explanation:
In a neutralization reaction, bases donate.
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Answer: I think it is hydroxide ion but im not sure
Explanation:
I hope this helped!
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If 3 moles of NaOH is dissolved in 4L of water, what is the
molarity of the solution?
Answer:
0.75mol/LNaOH
Explanation:
Data: Soln:
M= ? M= n/ V(l)
n= 3moles. M= 3mol/ 4L
V= 4L. M = 0.75 mol/LNaOH
Do molecules move in all phases? (yes/no)
Answer: sorta
Explanation:
In fact, they do not flow at all: they simply vibrate back and forth. Because the atoms in a solid are so tightly packed, solid matter holds its shape and cannot be easily compressed
What is Heat? What is Cold?
Answer:
Heat is the process of something getting hot(temperatures going up). Cold is when something gets cold(temperature decreases).
Explanation:
Calculate the wavelength for the transition from n = 4 to n = 2, and state the name given to the spectroscopic series to which this transition belongs?
Answer:
The wavelength for the transition from n = 4 to n = 2 is 486nm and the name name given to the spectroscopic series belongs to The Balmer series.
Explanation
lets calculate -
Rydberg equation- [tex]\frac{1}{\pi } =R(\frac{1}{n_1^2} -\frac{1}{n_2^2})[/tex]
where ,[tex]\pi[/tex] is wavelength , R is Rydberg constant ( [tex]1.097\times10^7[/tex]), [tex]n_1[/tex] and [tex]n_2[/tex]are the quantum numbers of the energy levels. (where [tex]n_1=2 , n_2=4[/tex])
Now putting the given values in the equation,
[tex]\frac{1}{\pi }=1.097\times10^7\times(\frac{1}{2^2} -\frac{1}{4^2} )[/tex][tex]=2056875m^-^1[/tex]
Wavelength [tex]\pi =\frac{1}{2056875}[/tex]
=[tex]4.86\times10^-^7[/tex] = 486nm
Therefore , the wavelength is 486nm and it belongs to The Balmer series.
7x[(7+7)divide7]
PLEASE HELP
Answer:
ik this isnt the answer but mathwa will solve all yours problems
Explanation:
How many moles of silver atoms are in the piece of jewelry?
The number of moles of silver atoms in the piece of jewelry is 0.08784 moles
Here is the complete question:
Suppose a piece of jewelry contains 5.29 × 10²² atoms of silver . How many moles of silver atoms are in the piece of jewelry?
From the question,
A piece of jewelry contains 5.29 × 10²² atoms of silver.
To determine number of moles of silver atoms in the piece of jewelry,
We will use the formula
[tex]Number \ of \ moles = \frac{Number \ of \ atoms }{Avogadro's \ number}[/tex]
From the question
Number of atoms of silver = 5.29 × 10²² atoms
and
Avogadro's number = 6.022 × 10²³ atoms/mole
∴ [tex]Number \ of \ moles \ of \ silver \ atoms= \frac{5.29 \times 10^{22} }{ 6.022 \times 10^{23} }[/tex]
Number of moles of silver atoms = 0.08784 moles
Hence, the number of moles of silver atoms in the piece of jewelry is 0.08784 moles
Learn more here: https://brainly.com/question/10982975
A characteristic used to describe something is called a
Calculate the number of molecules in 100. g of O2 *
Name each of the following molecular binary compounds:
01. CaCl2 01. hydroiodic acid
02. HI (g) 02. hydrogen monoiodide gas
03. HI (aq) 03. diiodine tetraoxide
04. BH3 04. bromine monofluoride
05. Cl2O6 05. silicon tetrahydride
06. ClF 06. tetraphosphorus hexaoxide
07. P2Cl4 07. disulfur monoxide
08. I2O5 08. carbon monooxide
09. BrF5 09. hydrogen monochloride gas
10. HBr (aq) 10. tetraphosphorus decaoxide
11. IF7 11. dibromine monoxide
12. NF3 12. dinitrogen tetrafluoride
13. H2Se (aq) 13. disilicon hexahydride
14. BrCl 14. tetraarsenic hexaoxide
15. H2Se (g) 15. hydrochloric acid
16. SnO2 16. arsenic trihydride
17. HBr (g) 17. iodine heptafluoride
18. AsF3 18. bromine dioxide
19. N2O3 19. disulfur decafluoride
20. IF5 20. dichlorine heptaoxide
Answer:
Explanation:
From the given information; we are to assign the correct naming for the molecular binary compounds.
01. CaCl2 → Calcium CHloride
02. HI (g) → Hydrogen mono iodide gas
03. HI (aq) → Hydroiodic acid
04. BH3 → Borontrihydride
05. Cl2O6 → Dichlorine hexoxide
06. ClF → Chlorine monoflouride
07. P2Cl4 → Phosphorus tetrachloride
08. I2O5 → Diiodine pentaoxide
09. BrF5 → Bromine pentaflouride
10. HBr(aq) → Hydrobromic acid
11. IF7 → Iodine heptaflouride
12. NF3 → nitrogen triflouride
13. H2Se(aq) → hydroselenic acid
14. BrCl → Bromine monochloride
15. H2Se(g) → Hydrogen Selenide
16. SnO2 → Tindeoxide
17. HBr(g) → Hydrogenbromide gas
18. AsF3 → Arsenic triflouride
19. N2O3 → Dinitrogentrioxide
20. IF4 → Iodine pentafluoride
01. hydroiodic acid → HI (aq)
02. hydrogen monoiodide gas → HI (g)
03. diiodine tetraoxide → I2O4
04. bromine monofluoride → BrF
05. silicon tetrahydride → SiH4
06. tetraphosphorus hexaoxide → P4O6
07. disulfur monoxide → S2O
08. carbon monooxide → CO
09. hydrogen monochloride gas → Hcl
10. tetraphosphorus decaoxide → P4O10
11. dibromine monoxide → Br2O
12. dinitrogen tetrafluoride → N2F4
13. disilicon hexahydride → SiH6
14. tetraarsenic hexaoxide → As4O6
15. hydrochloric acid → HCl (aq)
16. arsenic trihydride → AsH3
17. iodine heptafluoride → IF7
18. bromine dioxide → BrO2
19. disulfur decafluoride → S2F10
20. dichlorine heptaoxide → Cl2O7