What is the power of 600j of work done in 4 seconds?

Answers

Answer 1

Explanation:

Power = change in work/change in time

P = 600 joules/ 4 seconds

P= 150 watts

hope this helps :)


Related Questions

Hurry helping me just look the picture ​

Answers

Answer:

Mindfulness meditation. ...

Spiritual meditation. ...

Focused meditation. ...

Movement meditation. ...

Mantra meditation. ...

Transcendental Meditation. ...

Progressive relaxation. ...

Loving-kindness meditation.

People tend to be stressed, and feel relaxed when meditating.

roteins are denatured by treatment with alkaline or acid, oxidizing or reducing agents, and certain organic solvents. Interesting among denaturing agents are those that affect the secondary and tertiary structure without affecting the primary structure. The agents most frequently used for this purpose are urea and guanidinium chloride. These molecules, because of their high affinity for peptide bonds, break the hydrogen bonds and the salt bridges between positive and negative side chains, thereby abolishing the tertiary structure of the peptide chain.

Explanation:

Explanation:

1.For example, suppose buying pizza for a work party leads to positive morale and to the work being done in half the time. Pizza is the independent variable, Work speed is the dependent variable, The mediator, the middle man without which there would be no connection, is positive morale.

.For example, suppose buying pizza for a work party leads to positive morale and to the work being done in half the time. Pizza is the independent variable, Work speed is the dependent variable, The mediator, the middle man without which there would be no connection, is positive morale.2.The word denature means to render food unpleasant or dangerous to consume, it is denatured by adding a substance known as a denaturant. Aversive agents—primarily bitterants and pungent agents—are used to produce an unpleasant flavor.

A car sits in an entrance ramp to a freeway, waiting for a break in the traffic. Then the driver accelerates with constant acceleration along the ramp and onto the freeway. The car starts from rest, moves in a straight line, and has a speed of 19 m/s when it reaches the end of the 110-m-long ramp. The traffic on the freeway is moving at a constant speed of 19 m/s. What distance does the traffic travel while the car is moving the length of the ramp

Answers

Answer:

the distance travelled by the traffic, while the car is moving the length of the ramp is 220 m

Explanation:

Given the data in the question;

first we determine acceleration  using the kinematic equation below;

v² - u² = 2as

a = v² - u² / 2s

our initial velocity is zero, v is 19 m/s and distance s is 110 m

so we substitute

a = (19² - 0²) / 2×110

a = 361 / 220

a = 1.6409 m/s²

Next, the time t taken by the car to travel along the length of the ramp will be;

t = v - u / a

we substitute

t = (19 - 0) / 1.6409

t = 11.579 sec

so the distance travelled by a body moving with constant speed u is given by following expression:

s = ut + [tex]\frac{1}{2}[/tex] at²

so we substitute 19 m/s for u, 11.579 sec for t and 0 m/s² for a

s = (19 m/s × 11.579 s) + [tex]\frac{1}{2}[/tex] × 0 × (11.579)²

s = (19 m/s × 11.579 s) + 0

s = 220 m

Therefore, the distance travelled by the traffic, while the car is moving the length of the ramp is 220 m

A nuclear physicist studies the particles ejected by a beam of radioactive nuclei. According to a proposed theory, the average rates at which particles are ejected in the forward and backward directions should be equal. To test this theory, he counts the total number ejected forward and backward in a certain 10-hour inter- val and finds 998 forward and 1,037 backward. (a) What are the uncertainties asso- ciated with these numbers

Answers

i’m not sure butting maybe

The uncertainty associated in counting of these numbers is ± 39

The given parameters;

the amount of particles counted forward = 998the amount of particles counted backward = 1037

The uncertainty associated in these numbers is the error margin that exist when counting the numbers forward or backward. This uncertainty is calculated as follows;

uncertainties = ± (1,037 - 998)

uncertainties = ± 39

This uncertainty is plus 39 or minus 39

Thus, the uncertainty associated in counting of these numbers is ± 39

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A baseball player hits a 0.15 kg 0.15kg0, point, 15, start text, k, g, end text baseball that is initially at rest, changing its momentum by 11 kg ⋅ m s 11 s kg⋅m ​ 11, start fraction, start text, k, g, end text, dot, start text, m, end text, divided by, start text, s, end text, end fraction.

Answers

Answer:

73.3m/s

Explanation:

We can find the velocity of the player.

Momentum = mass * velocity

Given

Mass = 0.15kg

Momentum = 11kgm/s

Get the velocity

Velocity = Momentum/Mass

Velocity = 11/0.15

Velocity = 73.3m/s

Hence the velocity of the player is 73.3m/s

Later in the game, the quarterback throws a pass to the wide receiver with a defender in hot pursuit. If the pass does not arrive to the wide receiver in two seconds, the pass will be intercepted. If the receiver is 30 yards away and the pass is thrown at a 10 degree angle from the ground, how fast must the ball be thrown to reach the receiver

Answers

Answer:

Explanation:

In projectile motion , formula for range is as follows

R = u² sin 2 α / g , where u is initial velocity of throw , α is angle of throw

Given R , range = 30 yards , α = 10°

30 = u² sin 20 / 9.8

u² x .342 = 294

u² = 859.65

u = 29.32 m / s

A person in a laboratory is asked to taste and describe her conscious experience of two different drinks. The person talks about how sweet each drink tastes to her, what the drinks remind her of, and which one she finds most pleasant.

Answers

Answer:

The laboratory testing is done on metrics. The research will help find the preference of a person among various drinks.

Explanation:

The laboratory testing is for research purposes. When a person is introduced with two different drinks he may have different experiences. The taste of two different drinks is sweet. A persons behavior towards the taste is psychological also. If he is already informed that the drinks will be sweet, he might start feeling sweeter when he tastes it even if the drink has no taste.

What aspect of solar radiation causes Cleveland to have more solar radiation than Miami in June and July

Answers

Answer:

miami because it is closer to the equator26. cleveland because of its location 27. The top of the atmosphere absorbs and reflects the radiation before it can reach the surface.Explanation:

In the month of June and July, Cleveland will have solar radiation more than that of Miami.

The figure attached below clearly shows the solar radiation of the atmosphere at Miami and Cleveland throughout the year.On June solstice, the noon altitude of the sun is  [tex]88^\circ[/tex]  at Miami's latitude and  [tex]72^\circ[/tex] at Cleveland's latitude.The number of daylight hours is  [tex]13.8[/tex]  hours at Miami's altitude and the number of daylight hours is  [tex]15.1[/tex]  hours at Cleveland's altitude.

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Two identical spheres of mass M are fastened to opposite ends of a rod of length 2 L. The radii of the spheres are negligible when compared to the length 2L, and the rod has negligible mass. This system is initially at rest with the rod horizontal and is free to rotate about a frictionless axis through the center of the rod. The axis is horizontal and perpendicular to the plane of the page. A bug of mass 3M lands gently on the sphere on the left. Assume that the size of the bug is small compared with the length of the rod.

After the bug lands, the rod begins to rotate. What correctly describes the change in the magnitude of the angular momentum of the bug-rod-spheres system and the change in gravitational potential energy of the bug-rod-spheres-Earth system as the rod rotates but before the rod becomes vertical?

Answers

Answer:

Angular Momentum increase

Gravitational Potential Energy decrease

Explanation:

given data

mass = 3M

length = 2L

solution

when rod is rotate till it become vertical

so torque is counter clockwise

and there therefore angular speed goes on increase and there angular moment also increase

but as that gravitational potential energy will be decrease

The angular momentum of the system will increase, while the potential energy of the system will decrease after the bug lands.

The given parameters;

mass of the two identical spheres, = Mlength of the rods, = 2Lmass of the bug, = 3M

The change in the angular momentum is calculated as;

[tex]\Delta L = \Delta I\omega[/tex]

After the bug lands, the total mass of the system increases and the angular speed increases from zero. Consequently, the angular momentum of the system will increase.

The change in potential energy is calculated as;

[tex]\Delta P.E = mg(\Delta h)[/tex]

After the bug lands, the height of the system decreases to zero, which leads to a decrease in the potential energy of the system.

Thus, we can conclude that the angular momentum of the system will increase, while the potential energy of the system will decrease after the bug lands.

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Convert an acceleration of 12m/s^2 to km/h^2​

Answers

Answer:

43.2

because to convert from m/sec to kmph we need to multiply by 3600/1000

What are the two main ways in which chemical bonds are formed

Answers

Answer:

The two main types of bonds formed between atoms are ionic bonds and covalent bonds.

Explanation:

Hope this helped <3

Pam rubs a balloon on her head to generate a static charge. She holds the balloon up against a wall. Which of the following describes the electric charges and forces at work if the balloon sticks to the wall?

Electrons move from Pam’s hair to the balloon and attract electrons in the wall.

Electrons move from Pam’s hair to the balloon and attract protons in the wall.

Protons move from Pam’s hair to the balloon and attract protons in the wall.

Protons in the balloon form chemical bonds with protons in the wall.

Answers

Answer:

c

Explanation:

If the balloon sticks to the wall then electrons move from Pam’s hair to the balloon and attract protons in the wall.

One of the ways of producing static electricity is by the use of friction. Friction occurs when two surfaces are rubbed together. This leads to the loss of electrons from one of the surface which attracts the protons on another surface.

If the balloon sticks to the wall then electrons move from Pam’s hair to the balloon and attract protons in the wall.

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How is the speed of light measured when it is light years away?

Answers

Answer:

In a vacuum, light travels at 670,616,629 mph (1,079,252,849 km/h). To find the distance of a light-year, you multiply this speed by the number of hours in a year (8,766). The result: One light-year equals 5,878,625,370,000 miles (9.5 trillion km).

An engineer is designing the runway for a new airport. The lowest
acceleration rate of the plane's that will use the airport is likely to
be 3.0 m/s2. The takeoff speed for that plane is 65 m/s. What is
the minimum runway length needed for this plane to successfully
takeoff?

Answers

Answer:

Given, initial velocity, u=0m/s and final velocity v=65m/s

Acceleration a=3m/s

2

If d be the allowed length for the runway.

Using formula v

2

−u

2

=2aS

(65)

2

−0

2

=2(3)d

⟹ d=65

2

/6=704.16∼704m

at the vertices of a square with a side of 5 cm, there are identical positive charges q = 2 nC. determine the strength of the electrostatic field in the middle of one of the sides of the square

Answers

Answer:

Explanation:

To make this problem the easiest way possible, draw a picture and choose the side between the charges. The field will be zero at that point, and I'll prove it in just a second.

[tex]E=\frac{kq}{r^2}[/tex]

k is a constant with a value of [tex]8.99*10^9Nm^2/C^2[/tex]

q is the magnitude of the charge producing the field

r is the distance from the source charge to the test charge

So first determine the electric field from the charge on the bottom left corner, then we'll determine the electric from the bottom right corner.

Convert the centimeters to meters and nano-Coulombs to Coulombs

5cm = 0.05m

2 nC = 2 x 10^-9 C

[tex]E=(8.99*10^9)(2*10^-^9)/(0.025)^2=2.8768*10^4N/C[/tex]

This is pointing to the right because electric field lines point away from positive charges.

[tex]E=(8.99*10^9)(2*10^-^9)/(0.025)^2=-2.8768*10^4N/C[/tex]

This is pointing to the left because of the same reason. Field lines point away from positive charges.

You are able to sum them up because they are both in the x-direction. Their sum will be a net field value of zero.

Block A, mass 250 g , sits on top of block B, mass 2.0 kg . The coefficients of static and kinetic friction between blocks A and B are 0.34 and 0.23, respectively. Block B sits on a frictionless surface. What is the maximum horizontal force that can be applied to block B, without block A slipping

Answers

Answer:

  F = 69.3 N

Explanation:

For this exercise we use Newton's second law, remembering that the static friction force increases up to a maximum value given by

               fr = μ N

We define a reference system parallel to the floor

block B  ( lower)

Y axis  

            N - W₁-W₂ = 0

            N = W₂ + W₂

            N = (M + m) g

X axis

              F -fr = M a

for block A (upper)

X axis

              fr = m a                 (2)

so that the blocks do not slide, the acceleration in both must be the same.

Let's solve the system by adding the two equations

             F = (M + m) a          (3)

             a =[tex]\frac{F}{ M+m}[/tex]

the friction force has the formula

            fr = μ N

             fr = μ (M + m) g

let's calculate

            fr = 0.34 (2.0 + 0.250) 9.8

            fr = 7.7 N

we substitute in equation 2

             fr = m a

             a = fr / m

             a = 7.7 / 0.250

             a = 30.8 m / s²

we substitute in equation 3

             F = (2.0 + 0.250) 30.8

             F = 69.3 N

Someone please help me, I’m so lost my brain hurts

Answers

-- It takes 100 calories of heat to make 10 grams of the stuff 20° warmer.

How much of the heat warms each gram ?

-- It takes 10 calories of heat to make each gram of the stuff 20° warmer.

How much of the heat warms that gram each degree ?

-- It takes 1/2 calorie of heat to make each gram of the stuff 1° warmer.

The specific heat of that stuff is

(1/2 calorie) per gram per °C.

That's choice-3 .

Explanation:

The answer is No. 3

0.5 cal/g°C

Fred's lightbulb is 45% efficient, and Fran's is 75% efficient. If they both use the same amount of electric energy, which produces more light energy? ​

Answers

Answer:

Frank's 75% efficient light bulb will shine brighter.

Explanation:

The brightness of a bulb is gotten from the power equation;

P = I²R

The more the power rating in watts, the more the brightness.

Now, if they both use the same amount of energy but yet have different efficiency, it means we will just multiply the efficiency by the power.

Thus, 75% efficiency will yield more power than a 45% efficient one.

Therefore, Frank's light bulb will shine brighter.

What fitness component is plank exercises?

Answers

Answer:

The plank (also called a front hold, hover, or abdominal bridge) is an isometric core strength exercise that involves maintaining a position similar to a push-up for the maximum possible time.

Explanation:

please mark me has brainllest

HELP ASAP WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST!!!!
You pushed a shopping cart with 75 N of force. The cart accelerated at 5 m/s^2. What is the mass of the shopping cart?

Answers

Answer:

the mass of the shopping cart is 15 kg

Explanation:

The computation of the mass of the shopping cart is shown below:

As we know that

Force = mass × acceleration

So,

Mass = Force ÷ Acceleration

=75 N ÷  5 m/s^2

= 15 kg

Hence, the mass of the shopping cart is 15 kg

Students perform an experiment in which they drop two eggs with equal mass from a balcony. In the first trial, the egg hits the ground and breaks. In the second trial, the egg hits a foam cushion and does not break or bounce.

Answers

Gravity causes an object to fall to Earth when dropped. Drop an egg from eye level so that it breaks.
When the egg hits the ground with a given force, the ground exerts the same force back on the egg. The faster the egg falls, the greater this force is. If too large a force is delivered to the egg shell, the egg will crack.
To keep the egg from cracking, we need to minimize the force on the egg shell when it hits the ground.

Reducing the impact speed also reduces the impact force. Distributing the impact force over enclosure also reduces the force exerted on the egg.

Since the change in momentum is fixed, impulse can be controlled by increasing the impact time.
Impulse is a force applied over time and is equal to the change in momentum, for a constant mass.

The impulse was greater in the first experiment because the egg broke.
The impulse was greater in the second experiment because the egg did not break.
The impulse was the same in both experiments because the egg came to a stop.
The impulse cannot be determined without the mass and velocity of the eggs.
The impulse was the same in both experiments because the egg came to a stop.

Hope this helps

Answer: C

Explanation: Because it is just got the same question on the Impulse and Momentum quiz

Can someone help me answer please

Answers

Answer:

4=Conduction by convection by radiation.

Explanation:

Hope it will help you! It may be short but I don't know how to write it in blank aafai milayera lekha Hai blanks ma

Two positive charges are fixed a distance apart.the sun of their charges is Qt.what charge must each have in order to maximise the electric force between them

Answers

Answer:

Both charges must have the same charge, Qt/2.

Explanation:

Let the two charges have charge Q1 and Q2, respectively.

Use Coulombs's Law to find an expression for the force between the two charges.

[tex]F = k_e\frac{Q_1Q_2}{r^2}[/tex], where

Ke is Coulomb's contant and

r is the distance between the charges.

We know from the question that

Q1 + Q2 = Qt

So,

Q2 = Qt - Q1

[tex]F = k_e\frac{Q_1(Q_t - Q_1)}{r^2}[/tex]

Simplify to obtain,

[tex]F = \frac{k_e}{r^2} (Q_tQ_1 - Q_1^2)[/tex]

In order to find the value of Q1 for which F is the maximum, we will use the optimization technique of calculus.

Differentiate F with respect to Q1,

[tex]\frac{dF}{dQ_1} = \frac{k_e}{r^2} (Q_t - 2Q_1)[/tex]

Equate the differential to 0, to obtain the value of Q1 for which F is the maximum.

[tex]\frac{k_e}{r^2} (Q_t - 2Q_1) = 0\\Q_t - 2Q_1 = 0\\2Q_1 = Q_t\\Q1 = \frac{Q_t}{2}[/tex]

It follows that

[tex]Q_2 = \frac{Q_t}{2}[/tex].

PLEASE HELP ME EXPLAIN THESE QUESTIONS IT'S FOR ANATOMY AND PHYS

Let’s put the information you just learned into practice: perform a respiration check on a partner who is at least 12 years old. You may, as recommended by the sites, “sneak” the respiration check while checking their pulse as long as your partner has consented for you to check their “vital signs.” Telling someone you are checking their pulse, but instead are planning to check their respiratory rate, would be unethical. Based on your experiences, answer the following questions.
1.Pretend you are entering the respiration rate into a medical record. How would you record it?
2.Was the subject’s respiration rate in a health range?
3.What would be different about detecting an abnormal respiration rate if you were checking the respiration rate of a four year old?
4.Do you think you got an accurate respiration rate? Is there any reason to think the subject might have altered their breathing?
5.What exact steps did you take to measure the respiration rate, including any questions you asked or instructions you gave?
6.How long did you measure for?
7. Which parts of the DRABC acronym deal directly with the respiratory system?
8.Some first-aid practitioners also recommend a secondary assessment, which involves a head-to-toe inspection of the patient. Why would this assessment be important?
9.Under which conditions should CPR be performed? What checks or actions should be performed first?

Answers

Answer:

I tried

Explanation:

You have to check a 12 year olds respiration rate by Siting them down and trying to relax.  It's best to take the respiratory rate while sitting up in a chair or in bed.  Measure their breathing rate by counting the number of times their chest or abdomen rises over the course of one minute.  Then Record this number. Now you have to answer the first few  questions based on that.

Heart rate, blood pressure, respiratory rate and temperature are the big four vital signs.

8.  Secondary assessments are used in order to determine the injury, how the injury occurred, how severe the injury is, and to eliminate further injury and that is why it is important.

9. It should only be performed when a person shows no signs of life or when they are unconscious, unresponsive, not breathing or not breathing normally.  

In order to perform CPR, you need to check the scene and the person. Make sure the scene is safe, then tap the person on the shoulder and shout "Are you OK?" to ensure that the person needs help. Then pen the airway,  Check for breathing,  Push hard, push fast, deliver rescue breaths, continue CPR steps.

The normal respiration rate is in the range from 12 to 16 breaths per minute.

How to record respiration rate?

The respiration rate is measured when a person is present at rest. For recording the respiration rate, we just count the number of breaths for one minute by counting how many times the chest rises.

The subject’s respiration rate will be considered in a health range if its respiration rate in the range from 12 to 16 breaths per minute.

Exact steps that you take to measure the respiration rate is to count the number of breaths for an entire minute or count for 30 seconds and multiply that number by two. We can measure the respiration rate for about one minute.

DRABC is an abbreviation that stands for Danger, Response, Airway, Breathing and Circulation. Airway, Breathing and Circulation are the parts of DRABC acronym that deal directly with the respiratory system.

A secondary assessment that involves a head-to-toe inspection of the patient is also necessary because it is done to do inspection of the whole body in order to check the physical condition of the patient. CPR should be performed when a person is unconscious, having abnormal breathing and not breathing.

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Describe how global context (scientific and technical innovation) is connected with force, friction,energy and motion in 200 words.

Answers

The global context of scientific inquires are technical innovation answers. It is connected with force friction energy and even motion.The global context is currently expiring in the worlds disruption. The comical diseases of the global stature human body semantically indecent

Calculate the amount of potential difference in a capacitor of 0.9 MF , If the amount of charge is 1.4x10^-4 C .(Show all the work)

Answers

Answer:

1.56×10¯¹⁰ V.

Explanation:

From the question given above, the following data were obtained:

Capicitance (C) = 0.9 MF

Quantity of electricity (Q) = 1.4x10¯⁴ C

Potential difference (V) =?

Next, we shall convert 0.9 MF to farad (F). This can be obtained as follow:

1 MF = 10⁶ F

Therefore,

0.9 MF = 0.9 MF × 10⁶ F / 1 MF

0.9 MF = 9×10⁵ F

Finally, we shall determine the potential difference. This can be obtained as follow:

Capicitance (C) = 9×10⁵ F

Quantity of electricity (Q) = 1.4x10¯⁴ C

Potential difference (V) =?

Q = CV

1.4x10¯⁴ = 9×10⁵ × V

Divide both side by 9×10⁵

V = 1.4x10¯⁴ / 9×10⁵

V = 1.56×10¯¹⁰ V

Therefore, the potential difference is 1.56×10¯¹⁰ V.

Tara goes kayaking at sunrise. She rows 50 feet in 20 seconds. She transfers
100 joules of energy. What is Tara's power?
5 W 10 W
50 W
2 W

Answers

100J/20s= 5 joules per second

Or 5 watts

What is the maximum height achieved if a 0.400 kg mass is thrown straight upward with an initial speed of 40.0 m⋅s−1? Ignore the effect of air resistance

Answers

The maximum height : 81.63 m

Further explanation

Given

0.4 kg mass

vo = initial speed = 40 m/s

Required

the maximum height

Solution

We can use the law of conservation energy(ME=PE+KE) or use parabolic motion

For parabolic motion :

h max = (vo²sin²θ)/2g

θ = 90°(straight upward)

Input the value :

h max = (40²sin²90°)/2 x 9.8

h max = 81.63 m

Q 19.23: A proton is initially moving at 3.0 x 105 m/s. It moves 3.5 m in the direction of a uniform electric field of magnitude 120 N/C. What is the kinetic energy of the proton at the end of the motion

Answers

Answer:

The kinetic energy of the proton at the end of the motion is 1.425 x 10⁻¹⁶ J.

Explanation:

Given;

initial velocity of proton, [tex]v_p_i[/tex] = 3 x 10⁵ m/s

distance moved by the proton, d = 3.5 m

electric field strength, E = 120 N/C

The kinetic energy of the proton at the end of the motion is calculated as follows.

Consider work-energy theorem;

W = ΔK.E

[tex]W =K.E_f - K.E_i[/tex]

where;

K.Ef is the final kinetic energy

W is work done in moving the proton = F x d  = (EQ) x d = EQd

[tex]K.E_f =EQd + \frac{1}{2}m_pv_p_i^2[/tex]

[tex]m_p \ is \ mass \ of \ proton = 1.673 \ \times \ 10^{-27} kg \\\\Q \ is \ charge \ of \ proton = 1.6 \times 10^{-19} C[/tex]

[tex]K.E_f = 120\times 1.6 \times 10^{-19} \times 3.5 \ + \ \frac{1}{2}(1.673\times 10^{-27})(3\times 10^5)^2 \\\\[/tex]

[tex]K.E_f = 6.72\times 10^{-17} \ + \ 7.53 \times 10^{-17} \\\\K.E_f = 14.25 \times 10^{-17} J\\\\K.E_f = 1.425\times 10^{-16} \ J[/tex]

Therefore, the kinetic energy of the proton at the end of the motion is 1.425 x 10⁻¹⁶ J.

An isolated, irregularly shaped piece of platinum carries -8.89 × 10-9 C of charge and is in electric equilibrium. The size of this body is about 4 mm. When the electric potential at some point on the metal\'s surface has the value V, the potential at a different point on the surface (indicate one):________.a) May equal Vb) always differs from V.c) equals V

Answers

Answer:

c) equals V

Explanation:

This is because, since the isolated, irregularly shaped piece of platinum is in electric equilibrium, the electric potential at all points on its surface is V. So that, the potential difference across any point is zero. This implies that diametrically opposite sides have the same potential and thus, the potential at other points of the surface is V since it is in electric equilibrium.

How much time does it take for a car traveling 19.1 m/s to cover a distance of 1200 m?

Answers

Answer:

63

Explanation:

it would take around 63 if ur asking for 1200/19.1

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