Answer:
67%Explanation:
Thus the % composition of glucose by mass is carbon 40.0 % oxygen 53.3 % hydrogen 6.7 % in this way, the % composition by mass of any compound can be calculated provided that is formed is known.what is another name for horse
Answer:
Mount, Charger, Colt, Pony, and Folt
Explanation:
Answer:
A stallion or a mare
Explanation:
Select the description of a galvanic (voltaic) cell. An electrochemical cell that uses electricity to produce an oxidation-reduction reaction. An electrochemical cell that produces electricity from a spontaneous oxidation-reduction reaction. One-half of an electrochemical cell in which either oxidation or reduction occurs. Connects the two half-cells in an electrochemical cell to maintain electrical neutrality.
Answer: An electrochemical cell that produces electricity from a spontaneous oxidation-reduction reaction
Explanation:
Galvanic cell is a device which is used for the conversion of the chemical energy produced in a redox reaction into the electrical energy.
Galvanic cell consists of two half cells known as anode and cathode. Oxidation takes place at anode and reduction takes place at cathode. The two half cells are connected by a salt bridge which contains an electrolyte which maintains the electrical neutrality.
how many atoms are in 0.5 mole of aluminum
According to the Avogadro's number, there are 3.011×10²³ atoms in 0.5 mole of aluminium.
What is Avogadro's number?Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.
It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .
According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.
Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number, on substituting values in formula, 0.5×6.023×10²³=3.011×10²³ atoms.
Thus, there are 3.011×10²³ atoms in 0.5 mole of aluminium.
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When sodium hydroxide NaOH dissociates in water, the oxygen atoms on the hydroxide anions will interact with:
Answer:
Hydroxide ions ( OH−) are negatively charged, and the formal negative charge is on the oxygen atom. Since opposite charges attract, the oxygen atoms will interact with the positive end of water's dipole.
Explanation:
If anyone could help I’d appreciate it
Answer: 2.00 mol
Explanation:
The balanced chemical equation is:
[tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(g)[/tex]
According to stoichiometry :
2.00 moles of [tex]H_2[/tex] require = 1.00 moles of [tex]O_2[/tex]
Thus 2.00 moles of [tex]H_2[/tex] will require=[tex]\frac{1}{2}\times 2.00=1.00moles[/tex] of [tex]O_2[/tex]
Thus both will act as limiting reagents and will be fully consumed.
2.00 moles of [tex]H_2[/tex] will form = 2 moles of [tex]H_2O[/tex]
Thus 2.00 moles of [tex]H_2[/tex] will form = [tex]\frac{2}{2}\times 2.00=2.00moles[/tex] of [tex]H_2O[/tex]
Thus 2.00 moles of [tex]H_2O[/tex] will be produced from the given masses of both reactants.
How many fluorine atoms are there in 39.4 moles of CF4?
Answer:
here
Explanation:
Answer: 4
A molecule of carbon tetrafluoride, CF4 , is made up of 1 carbon atom bonded to 4 fluorine atoms. Each carbon atom weighs 12.0 amu and each fluorine atom weighs 19.0 amu so 1 CF4 molecule weighs 1×12.0 amu + 4×19.0 amu = 88.0 amu. This number, 88.0, is called the molecular weight (or molecular mass) of CF4.
If 0.000066 moles of 0.01 M solution of carbonic acid dissociates, then what is Ka of carbonic acid
Answer: 4.4 x 10^-7
Explanation:
0.000066 x 0.0000066 / 0.01
= 4.4 x 10^-7
Ethanol (C2H5OH) is produced from the fermentation of sucrose in the presence of enzymes.
C12H22O11(aq) + H2O(g) 4 C2H5OH(l) + 4 CO2(g)
Determine the theoretical yield and the percent yields of ethanol if 665 g sucrose undergoes fermentation and 305.0 g ethanol is obtained.
theoretical
actual yield of ethanol = 305.0g
molar mass of sucrose = 342g
molar mass of ethanol =46g
mass of sucrose = 665g
mole of sucrose = mass / molar mass = 665/342
mole of sucrose =1.9 mole
sucrose : C2H5OH
1 : 4
1.9 : 1.9x4 =7.6 mole of C2H5OH are formed
mass (therotical yield ) of C2H5OH= mole x mass
mass (therotical yield ) of C2H5OH= 7.6 x 46 = 349.6g
percent yields of ethanol = actual /therotical x100
=305/349.6x100 = 87.24 %
GROUP NUMBER
ELEMENT
Potassium
Fluorine
Silicon
Radon
Gold
Beryllium
Oxygen
Neon
Rubidium
Tungsten
Arsenic
Calcium
Sodium
Aluminum
Chromium
Iodine
Helium
Nitrogen
Iron
Zinc
Answer:
Jet ğıpep2pep2p2pp3oroe88r82
Calculate the molarity of a solution that contains 3.00x10-2 mol NH4Cl in exactly 450 cm3 of solution.
Answer:
0.06moles/litres
Explanation:
molarity = no of moles / volume in litres = 3.00*10^-2/(450/1000)=0.06 moles/litres
Answer:
0.07mol/dm^3
Explanation:
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Why does an asteroid get hotter when it goes close to the sun?
Help bestie pls help ASAP thank you
Explanation:
heyyyyyyyyy how are you sure
What is 2AI(s) + FeO3(s) = Ai2O3(s) + 2Fe(s)
Answer:
it's a double displacement Reaction.
Is the Swedish timber industry more likely a result of good resource availability or a lack of trees elsewhere on Earth?
Answer:
The forest products industry plays a major role in the Swedish economy, and accounts for between nine and 12 percent of Swedish industry's total employment, exports, sales and added value. It includes companies within the pulp and paper industry, as well as the wood-mechanical industry.
If 220 mL of a 12.0 M HCl solution is diluted to 1000 mL, what will be the concentration of the new solution?
Answer:
2.64 M
Explanation:
Use the dilution equation M1V1 = M2V2, where:
M1 = 12.0 M HCl
V1 = 220 mL HCl
M2 = ?
V2 = 1000 mL HCl
(12.0 M HCl)(220 mL HCl) = M2(1000 mL HCl)
M2 = 2.64 M HCl
write a balanced equation between oxalic acid and potassium hydroxide
2.0M Propionic Acid HC3H5O2 Dissolves In Distilled Water. If It Has A Ka Of 1.3*10-5, What Is The Final PH?
The base ethylamine C2H5NH2 has a Kb of 5.6*10-4. What will the pH be in .53 molar solution?
Answer: first you have to calculate the amount ionized. We will say it is x mol / L
then % ionization = (amount ionized / initial concentration) * 100%
x can be calculated using an ice chart
HC3H5O2 -----> H+ + C3H5O2-
Initial HC3H5O2 = 0.250
change = -x
equilibrium = 0.250 - x
initial H+ = 0
change = +x
equilibrium = x
C3H5O2- initial = 0
change = +x
equilibrium = x
Ka = [H=][C3H5O2-] / HC3H5O2]
1.3 * 10 ^ -5 = [x][x] / (0.250 - x)
So 1.3 * 10 ^ -5 * (0.250 - x) = x ^ 2
3.25 * 10^ -6 - (1.3 * 10^-5)x = x^2 now this is a quadratic equation and you have to rearrange it and solve for x
x^2 + 1.3 * 10^-5)x - 3.25 * 10^ -6 = 0
use the equation x = {-b (+ or -)[b^2 - 4.a.c] ^ 1/2} / 2a
you should get x = 1.80 * 10 ^ -3 or x = -1.80* 10^-3
but x can not be negative..
so x = 1.80 * 10 ^ -3
so percent ionization = (1.80 * 10 ^ -3 / 0.250) * 100%
=0.72 %
the other way which is more easier is
assuming that x is very small and therefore 0.250 - x is approximately equals to 0.250
then 1.3 * 10^-5 = x^2 / 0.250
so x^2 = 1.3 * 10^-5 * 0.250
x = 1.80 * 10 ^-3
then percent ionization is = (1.80 * 10 ^ -3 / 0.250) * 100%
=0.72 %
if the percent ionization is > 5 % you can not do that approximation. in such a case you have to solve the quadratic equation. that is why I showed both methods.
now you can do the parts b and c
b answer : percent ionization = 1.27 %
c answer : 2.54%
good luck
Write a structural formula for each of the following: (a) 3-Methylcyclobutene (b) 1-Methylcyclopentene (c) 2,3-Dimethyl-2-pentene (d) (Z)-3-Hexene (e) (E)-2-Pentene (f) 3,3,3-Tribromopropene (g) (Z,4R)-4-Methyl-2-hexene (h) (E,4S )-4-Chloro-2-pentene (i) (Z)-1-Cyclopropyl-1-pentene (j) 5-Cyclobutyl-1-pentene (k) (R)-4-Chloro-2-pentyne (l) (E)-4-Methylhex-4-en-1-yne
Answer:
Attached below
Explanation:
(a) 3-Methylcyclobutene
(b) 1-Methylcyclopentene
(c) 2,3-Dimethyl-2-pentene
(d) (Z)-3-Hexene
(e) (E)-2-Pentene
(f) 3,3,3-Tribromopropene
(g) (Z,4R)-4-Methyl-2-hexene
(h) (E,4S )-4-Chloro-2-pentene
(i) (Z)-1-Cyclopropyl-1-pentene
(j) 5-Cyclobutyl-1-pentene
(k) (R)-4-Chloro-2-pentyne
(l) (E)-4-Methylhex-4-en-1-yne
The structural formula of a compound ( chemical ) is the representation of the molecular structure of the compounds ( i.e. it shows how the atoms in the compound is arranged, also the chemical bonding within the molecules are represented as well.
I don’t understand please help
Pictures of every moon
Answer:
Where?
Explanation:
What are ALL full chemical reactions that ensue for each of the following disinfectants (may be more than one for each): (5 points) Cl2 (g) at pH 9
Answer:
The reactions that might ensue are
Cl[tex]_{2}[/tex](g) + H[tex]_{2}[/tex]O ---------- > HOCl + HCl
HOCl -------- > [tex]H^+[/tex](aq) + O[tex]CI^-[/tex](aq)
Cl2(g) + [tex]OH^-[/tex](aq) ----- > O[tex]CI^-[/tex](aq) + HCl
Explanation:
The Disinfectant Given is
CI2 (g) at PH 9
Determine the chemical reactions that might ensue
due to the High concentration of [tex]H^{+} (aq)[/tex] the formation of [tex]OCI^-[/tex](aq) will be better and this will decrease the power of the disinfectant.
Hence the chemical reactions that might ensue can be represented below as :
Cl[tex]_{2}[/tex](g) + H[tex]_{2}[/tex]O ---------- > HOCl + HCl
HOCl -------- > [tex]H^+[/tex](aq) + O[tex]CI^-[/tex](aq)
Cl2(g) + [tex]OH^-[/tex](aq) ----- > O[tex]CI^-[/tex](aq) + HCl
Look at the H-R diagram. Which area of the diagram represents the white dwarfs? Give answer like top, right corner.
Answer:
I did this TGA got it right it is bottom left corner
Explanation:
During a running (dynamic) compression test at idle, a good engine should produce PSI. A. 150 to 200 B. 100 to 150 C. 30 to 60 D. 60 to 90
Answer:
b
Explanation:
During a running (dynamic) compression test at idle, a good engine should produce PSI between 60 to 90. The correct answer is option D.
A running compression test is a diagnostic test that measures the compression pressure of an engine while it is running.
The test is performed by connecting a compression gauge to the spark plug hole of each cylinder and then cranking the engine over to measure the compression pressure. The compression pressure of an engine is an important indicator of its overall health and performance. A low compression pressure can indicate a number of issues, such as worn piston rings, damaged valves, or a blown head gasket. On the other hand, a high compression pressure can indicate that the engine is in good condition and has strong compression.Therefore, in general, a good engine should produce compression pressure between 60 to 90 PSI during a running compression test at idle. Option D is the correct answer.
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Consider a free lysine amino acid in a solution buffered to pH = 9.00. What will be the overall charge on the residue?
Is it -2, -1, 0, 1, 2?
Answer:
Explanation:
+1
The overall charge on the residue ( lysine residue ) is ; ( C ) 0 charge
The a-aminium group of lysine amino acid will begin deprotonating by the presence of NaOH as the pH level of the solution increases.
Given that the pKa level of a-aminium group = 9. when the pH of the solution is buffered to 9.0 . half of the a-aminium ions that is present in the lysine amino acid will deprotonate leaving the overall charge on the lysine residue at neutral ( 0 charge ).
Hence we can conclude that the overall charge on the residue is a 0 charge.
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is sublimation exothermic or endothermic
Answer:
endormic
Explanation:
It occurs at a temperature and pressures below a substance's triple point on its phase diagram, which corresponds to the lowest pressure at which the substance can exist as a liquid
Calculate the pH of a 4.988 M solution of ascorbic acid, which has a ka of 8.0 x 10-5.
Report your answer with two decimal places. Example: 6.99
Answer:
pH= 1.70
Explanation:
I 4.988 0 0
C -x +x +x
E 4.988 -x x x
8.0 x 10^-5 = X^2/ 4.988 - x
(since the X value is so small, round 4.988-x to 4.988 because X is close to zero)
8.0 x 10^-5 = x^2/4.988
x4.988 x4.988
4.0 x 10^-4 = x^2
x = .0199
pH=-log[.0199] = 1.70
Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the equation PV = C, where C is a constant. Suppose that at a certain instant the volume is 300 cm3, the pressure is 180 kPa, and the pressure is increasing at a rate of 30 kPa/min. At what rate is the volume decreasing at this instant?
Answer:
The gas is decreasing at a rate of 50 cubic centimeters per minute.
Explanation:
The Boyle's Law is represented by the following expression:
[tex]P\cdot V = k[/tex] (1)
Where:
[tex]P[/tex] - Pressure, in kilopascals.
[tex]V[/tex] - Volume, in cubic centimeters.
[tex]k[/tex] - Proportionality constant, in kilopascal-cubic centimeters.
By definitions of rate of change and implicit differentiation, we derive the following differential equation:
[tex]\dot P \cdot V + P\cdot \dot V = 0[/tex] (2)
Where:
[tex]\dot P[/tex] - Rate of change of the pressure, in kilopascals per minute.
[tex]\dot V[/tex] - Rate of change of the volume, in cubic centimeters per minute.
Then, we clear the rate of change of the volume within (2):
[tex]P\cdot \dot V = -\dot P\cdot V[/tex]
[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]
If we know that [tex]P = 180\,kPa[/tex], [tex]\dot P = 30\,\frac{kPa}{min}[/tex] and [tex]V = 300\,cm^{3}[/tex], then the rate of change of the volume is:
[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]
[tex]\dot V = -50\,\frac{cm^{3}}{min}[/tex]
The gas is decreasing at a rate of 50 cubic centimeters per minute.
Calculate the pH of a solution with [H+] =1x10^-5
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Answer: 5
Explanation:
I hope this helped!
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How many grams are in 1.2 x 1024 atoms of sodium?
Answer:
46 g
Explanation:
First we convert 1.2 x 10²⁴ atoms of sodium into moles, using Avogadro's number:
1.2x10²⁴ atoms ÷ 6.023x10²³ atoms/mol = 2.0 molThen we convert 2.0 moles of sodium into grams, using sodium's molar mass:
2.0 mol Na * 23 g/mol = 46 gThus, there are 46 grams in 1.2x10²⁴ atoms of sodium.
10) 81 grams of Au is how many mL ?
Answer: Thus 81 grams of Au is 9210 ml
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]
[tex]\text{moles of Au}=\frac{81g}{196.96g/mol}=0.411moles[/tex]
1 mole of Au occupies = 22.4 L
Thus 0.411 moles of Au occupy = [tex]\frac{22.4}{1}\times 0.411=9.21L=9210ml[/tex]
81 grams of Au is 9210 ml