What is the output for the following program?

numA = 10
while numA < 21:
numA = numA + 5
print(numA)

Answer:

Output:

15

20

25

Explanation:

In first iteration value of num is 10. Condition is checked 10 is less than 21 so value of num is incremented by 5 and value 15 is printed than again condition is checked 15<21 so value of num is incremented again and 20 is printed. Again condition is checked 20<21. So 25 is printed. Then 4th time when condition is checked vakue of num is 25 and while loop condition becomes false because 25 is not less than 21 and program is terminated here.

Answer: 15,20,25

Explanation: got it right on edgen

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Design
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public class B1

{


private int i;

private int j;

…

}


public class B2 extends B1

{

private int m;

private int n;

…

}


public class B3 extends B2

{

private int z;

…

}


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aList.sort()

aList(order)

sort(aList)

order(aList)

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RAW


JPEG


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7 != 7.0
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1)

I only

2)

II only

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1)

I only

2)

II only

3)

III only

4)

I and II only

5)

I and III only
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Question 3 options:

1)

True

2)

False

3)

0

4)

1

5)

An error occurs
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int x = 10;
if(x + 1 < 20)
x += 5;
System.out.println(x);

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1)

10

2)

11

3)

15

4)

16

5)

20
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System.out.print(num);

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1)

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2)

It prints num if its value is not a multiple of 10.

3)

It always prints the value of num.

4)

It never prints the value of num.

5)

An error occurs at compile time.

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