What is the net force acting on a 5.0 kg object that has a velocity of 15 m/s and is moving in a
circle of radius 1.6m?

Answer:

Period = 6 seconds.

Explanation:

Given the following data;

Number of oscillation, n = 10

Time = 1 minute to seconds = 60 seconds

To find the period;

A period is the number of revolutions in a minute.

[tex] Period = \frac {time}{number \; of \; oscillations}[/tex]

Substituting into the equation, we have;

[tex] Period = \frac {60}{10}[/tex]

Period = 6 seconds.

Answer:

d/s

Explanation:

speed = distance / time

speed × time = distance

time = distance / speed = d/s

Yes. Many people either know the answer, or can figure it out using the information in the picture.

Answer:

4

Explanation:

Waves that are squished have higher frequency. It has short wavelength.

Answer:

4

Explanation:

frequency and wavelength are inverses, so since this has the smallest wavelength it has the highest frequency. The smaller the wavelength, the more waves (more/high frequency) fit in a certain area in comparison to larger wavelengths fit fewer waves (less frequent).

Answer:

It's very simple- 8 valence electrons

Answer:

it's 8

Explanation:

that the answer for the question

Answer:

The final temperature of the bath water will be 55°C

Explanation:

A student is preparing to take a bath when she realizes that the hot water tap is not working.

The student goes to the kitchen and prepares 10 L of 100 degree Celsius water to mix with 10 L of 10 degree Celsius water. What will be the final temperature of the bath water?

Using the relation, Heat lost  = Heat gained (assuming no heat is lost to the surroundings).

Heat lost by hot water = heat gained by cold water

Using the formula of heat, Q = mcΔT

where m = mass of water, c = specific heat capacity of water, ΔT = temperature difference

mass of water = density * volume (density of water = 1 kg/L)

mass of hot water, m₁ = 1 kg/L * 10 L = 10 kg;

mass of cold water, m₂ = 1 kg/L * 10 L = 10 kg;

specific heat capacity of water, c = 4200 j/kg

Let the final temperature of the mixture be T

-m₁cΔT₁ = m₂cΔT₂ ( since heat is lost by the hot water)

-m₁ΔT₁ = m₂ΔT₂

-10 * (T- 100) = 10 * (T - 10)

-10T + 1000 = 10T - 100

20T = 1100

T = 1100/20

T = 55°C

Therefore, the final temperature of the bath water will be 55°C

Answer: 20m/s.

Explanation:

Remember the second Newton's law:

F = a*m

This is:

The net force acting on an object is equal to the mass of the object times the acceleration of the object.

In this case, we have a force of 5N pushing the object to the right.

We also have a force of 5N pushing the object to the left.

These forces act on opposite directions.

Then the net force will be equal to the difference of these forces, this is:

F = 5N - 5N = 0N

Then the net force is 0N, then we have:

0N = m*a

0N/m = 0m/s^2 = a

This means that the acceleration of the object is 0, then the velocity of the object does not change.

This means that if the object was moving at a constant velocity of 20m/s, the velocity of the object will still be equal to 20m/s. (because the net force acting on the object is zero)

Answer:

ya daddy is my zaddy

Explanation:

Answer:

Hammer

Anvil

Stirrup

Explanation:

The three tiny bones in the ear drum are:

Hammer, this is also known as malleus and it is attached to the eardrum

Anvil, this is also called incus and it found with the chain of bones in the middle ear.

Stirrup, also known as stapes and it attached to the membrane covered opening that connects the middle ear with the inner ear.

Answer:

I have know idea what that means lol.

Thanks for the free points. Hope you have a fantastic rest of your life!

Answer:

The correct option is (d). "3x stronger".

Explanation:

The force between two charged particle is given by :

[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]

If one charge is tripled, [tex]q_1'=3q[/tex]

New force will be :

[tex]F'=\dfrac{kq_1'q_2}{r^2}\\\\=3\times F[/tex]

It means if one of the charges were to triple in strength, then the force will become 3 times of the initial force.

Answer:

Trough

Explanation:

cuz physics you see

Answer:

there is no drag in a vacuum (why is father in a vaccum)

Explanation:

there is nothing to hit and slow the object other than gravity like dust or air

Answer:

Smoking damages the respiratory system by irritating the trachea and larynx due to the toxic chemicals and by causing swelling and narrowing of the airways and excess mucus in the lung passages. Two conditions that can develop when a person smokes is breathlessness and reduced lung function.

Explanation:

Smoking causes damages to the respiratory system by narrowing the airways and filling an excess of mucus in the lungs. It is a bad habit that may cause emphysema and chronic bronchitis.

Cigarettes contain more than 500 chemical substances in addition to nicotine, an addictive substance found in tobacco.

Cilia are hair-like projections localized in the airways that act to eliminate mucus and foreign (potentially harmful) matter.

The toxic compounds contained in cigarettes can paralyze the cilia in the airways and destroy them.

Smoking may produce:

In consequence, smoking is associated with chronic obstructive pulmonary diseases, including chronic bronchitis or emphysema.

In conclusion, smoking causes damages to the respiratory system by narrowing the airways and filling an excess of mucus in the lungs. It is a bad habit that may cause emphysema and chronic bronchitis.

Learn more in:

https://brainly.com/question/1193094?referrer=searchResults

Answer:

0.2 A

Explanation:

V= IR

3 = I × 15

I = 3/15

= 1/5 = 0.2 A

The flow of current in a battery will be "0.2 A". To understand the calculation, check below.

According to the question,

Voltage, V = 3 V

Resistance, R = 15 ohm

We know the relation,

→ Voltage (V) = Current (I) × Resistance (R)

or,

→ Current, I = [tex]\frac{V}{R}[/tex]

By substituting the values,

                    = [tex]\frac{3}{15}[/tex]

                    = 0.2 A

Thus the above answer is correct.  

Find out more information about current here:

https://brainly.com/question/1176850

Answer:

perhaps remote learning, which is a form of remote observation. Hope that it helps.

Answer:

No, The Moon, on the other hand, rotates once around its every 28 days, and once around the Earth in that same 28 days. The result of this combination is that the same side of the Moon is always facing the Earth.

Answer:

21.2m/s

Explanation

Given data

P=6.36 x 10⁴kg·m/s.

M=3000kg

From the momentum expression

P=mv

v=p/m

Substitute

v=63600/3000

v=21.2m/s

Hence the Velocity is 21.2m/s

The speed of the truck is 21.2 m /s

Momentum is the product of the mass of the object and the velocity of the object. Therefore,

p = mv

where

m  = mass

v = velocity

m = 3000 kg

p = 6.36 x 104 kg·m/s.

lets find the velocity

6.36 x 10⁴  = 3000 × v

v = 6.36 x 10⁴ / 3000

v = 21.2 m / s

The speed of the truck is 21.2 m /s

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Answer:

the value of the charge is   q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q, in the position  x= l/3

Explanation:

The forces in this system are given by Coulomb's law

           F = [tex]k \frac{q_1 q_2}{ r^2}[/tex]

As the forces are vector, we must add them as a vector, also let us take that charges of the same sign repel and charges of the opposite sign attract, therefore for the system to be in equilibrium the third charge must be of the opposite sign, that is, NEGATIVE .

Let's analyze the situation for card charge, let's use the indexes 1 for the charge q₁ = + q located at the origin (x₁ = 0), index 2 for the face q₂ = + 4q located at x₂ = l and the index 3 for the third charge

Let's find the location of charge 3 so that it is in balance

               ∑ F = F₁₃ - F₂₃ = 0

               F₁₃ = F₂₃

we seek every force

              F₁₃ = k [tex]\frac{q_1q_3 }{x_{13}^2}[/tex]

              F₂₃ = k [tex]\frac{q_2q_3}{ x_{23}^2}[/tex]

the distances are

              x₁₃ = x-0 = x

              x₂₃ = l -x

we substitute

              k \frac{q_1q_3 }{x^2} = k \frac{q_2q_3 }{(l-x)^2}

we solve

             (l-x)² = [tex]\frac{q_2}{q_1}[/tex]   x²

              l² - 2lx + x² = \frac{4q}{q} x²

              3x² + 2l x - l² = 0

we solve the quadratic equation

              x = [-2l ± [tex]\sqrt{4l^2 + 4\ 3\ l^2}[/tex] / (2 3)

              x = [-2l + 2l [tex]\sqrt{1+3}[/tex]] / 6 = 2l [-1 ± 2] / 6

              x₁ = -l

              x₂ = l / 3

as charge 3 must be between the two charges the correct answer is

              x = l / 3

with charge 3 in this location it remains in equilibrium regardless of the value of its NEGATIVE charge.

now let's analyze the force on the other charges

charge 1 so that it is in balance

           ∑F = F₁₃ - F₁₂ = 0

           F₁₃ = F₁₂

          [tex]k \frac{q_1q_3}{(l/3)^2} = k \frac{q_1 q_2}{ l^2}[/tex]

           l² q₃ = q₂ (l/3)²

           q₃ = q₂ / 9

            q₃ = 4q / 9

            q₃ = [tex]\frac{4}{9} q[/tex]

in summary the value of the charge is   q₃ = [tex]- \frac{4}{9} q[/tex]- 4/9 q

in the position  x= l/3

Answer:

p = 58,900 kg m/s

Explanation:

p = m × v

p = 1,550 × 38.0

p = 58,900 kg m/s

Answer:

35.14 m/s

Explanation:

The Law of Conservation of Momentum states that the momentum before and after a collision is the same.

Let's set the ball to have the subscript of 1 and the man to have the subscript of 2.

The initial and final mass of the ball is the same, so m₁ = 7.00 kg on both sides of the equation.

The initial velocity of the ball, v₁ on the left side of the equation, is the unknown variable we are trying to find.

The initial and final mass of the man is the same, so m₂ = 75.0 kg on both sides of the equation.

The man starts at rest, meaning that his initial velocity is v₂ = 0 m/s on the left side of the equation.

The final velocity of both the ball and the man is 3.00 m/s, so we can set v₁ and v₂ on the right side of the equation to equal 3.00 m/s.

Left side of the equation:

Right side of the equation:

Substitute these values into the Law of Conversation of Momentum formula.

Multiply and simplify.

Divide both sides of the equation by 7.

The ball needs to be moving at a speed of 35.14 m/s in order to send the man off at a speed of 3.00 m/s.

Answer:

a) At 0.20 m, the magnitude of the field is 675.0 kV

The direction of the field is acting outwards from the center of the charged spheres

b) At 0.10 m, the magnitude of the field is 135 kV

The direction is acting outwards from the center of the charged spheres

c) At 0.025 m

The magnitude of the field, V = -270.0 kV

The direction of the field is inwards, towards the center of the charged spheres

Explanation:

The charged spherical shell parameters are;

The charge on the inner sphere, q₁ = -1.50 × 10⁻⁶ C

The radius of the inner shell, R₁ = 0.050 m

The charge on the outer sphere, q₂ = +4.50 × 10⁻⁶ C

The radius of the outer shell, R₂ = 0.15 m

Let 'r', represent the distance at which the electric field is measured, the following relationships can be obtained;

When r < R₁ < R₂,

[tex]V = k \cdot \left( \dfrac{q_1}{R_1} + \dfrac{q_2}{R_2} \right )[/tex]

When R₁ < r < R₂,

[tex]V = k \cdot \left( \dfrac{q_1}{r} + \dfrac{q_2}{R_2} \right )[/tex]

When R₁ < R₂ < r,

[tex]V = k \cdot \left( \dfrac{q_1 + q_2}{r^2} \right )[/tex]

a) When r = 0.20 m, we have;

R₁ < R₂ < r, therefore

[tex]V = k \cdot \left( \dfrac{q_1 + q_2}{r^2} \right )[/tex]

By plugging in the values, we get;

[tex]V = 9 \times 10^9 \times \left( \dfrac{-1.50 \times 10^{-6} + 4.50\times 10^{-6} }{0.20^2} \right ) = 675.0 \ kV[/tex]

Therefore, the magnitude of the field, V = 675.0 kV

The direction of the field is outwards

b) When r = 0.10 m, we have;

When R₁ < r < R₂, therefore;

[tex]V = k \cdot \left( \dfrac{q_1}{r} + \dfrac{q_2}{R_2} \right )[/tex]

By plugging in the values, we get;

[tex]V = 9 \times 10^9 \times \left( \dfrac{-1.50 \times 10^{-6} }{0.10} + \dfrac{4.50\times 10^{-6}}{0.15} \right ) = 135 \ kV[/tex]

Therefore, the magnitude of the field, V = 135 kV

The direction of the field is outwards from the center

c) When r = 0.025 m, we have;

When r < R₁ < R₂, therefore;

[tex]V = k \cdot \left( \dfrac{q_1}{R_1} + \dfrac{q_2}{R_2} \right )[/tex]

By plugging in the values, we get;

[tex]V = 9 \times 10^9 \times \left( \dfrac{-1.50 \times 10^{-6} }{0.05} + \dfrac{4.50\times 10^{-6}}{0.15} \right ) = -270 \ kV[/tex]

Therefore, the magnitude of the field, V = -270.0 kV

The direction of the field is inwards, towards the center of the charged spheres.

Answer:

the final temperature of the gas is 785.18 K

Explanation:

The computation of the final temperature of the gas is shown below:

Here we apply the gas law

= PV ÷ T

Given that

P1 = 1.9 atm

V1 = 24.6 L

T1 = 335 K  

P2 = 3.5 atm

V2 = 31.3 L  

T2 = ?

Now

P1V1 ÷ T1 = P2V2 ÷ T2

(1.9 × 24.6) ÷ 335 = (3.5 × 31.3)/T2

T2 = 785.18 K

hence, the final temperature of the gas is 785.18 K

Answer: D

Explanation: edge

Answer:

I Believe the Correct Answer is respiratory system; obtains oxygen so the energy in nutrients can be extracted.

Explanation:

Respiratory System is made for oxygen and involves the Lungs Diaphragm etc.

Please give me Brainliest!

Answer: I believe the answer is C

Explanation:

Cars are composed of hundreds of simple machines

Answer:

En 1589 Galileo realizó un experimento lanzando dos bolas de diferentes masas desde la famosa Torre Inclinada de Pisa para demostrar que el tiempo de caída es independiente de la masa de la bola. A través de este experimento, Galileo descubrió que los cuerpos caían casi simultáneamente, refutando la teoría de Aristóteles de que la tasa de caída era proporcional a la masa del cuerpo.  

Debido a la imperfección de los equipo de medición de esa época, la caída libre de los cuerpos era casi imposible de estudiar. En busca de una forma de reducir la velocidad de movimiento, Galileo reemplazó la caída libre por rodar sobre una superficie inclinada, donde había velocidades y resistencia del aire significativamente más bajas. Se notó que con el tiempo, la velocidad del movimiento aumenta: los cuerpos se mueven con aceleración. Se concluyó que la velocidad y la aceleración no dependen ni de la masa ni del material de la pelota.

Answer:

the density of the wooden cube is 204.1 kg/m³

Explanation:

Given;

applied force, F = 54 N

length of each side of the solid wooden cube, L = 30 cm = 0.3 m

mass of the wooden cube is calculated as;

F = mg

m = F/g

m = 54/9.8

m = 5.51 kg

The volume of the wooden cube is calculated as;

V = L³

V = (0.3)³

V = 0.027 m³

The density of the wooden cube is calculated as;

ρ = m/V

ρ = (5.51 kg) / (0.027 m³)

ρ = 204.1 kg/m³

Therefore, the density of the wooden cube is 204.1 kg/m³

Answer: I put the importance of the lab in the topic is to find how dense an object is and if it can sink or float and it's important to answer the question so you can also find mass and volume.

Explanation: I dunno haha...