7. A gas takes up a volume of 15 liters, has a pressure of 3.3 atm, and a temperature of 299 K. If I raise the
temperature to 350 K and lower the pressure to 1050 mmHg, what is the new volume of the gas?
8. I have an unknown volume of gas held at a temperature of 115 K in a container with a pressure of 60.0
atm. If by increasing the temperature to 225 K and decreasing the pressure to 30.0 atm causes the volume
of the gas to be 25 liters, how many liters of gas did I start with?
9. A gas has a temperature of 14oC, and a volume of 5.5 liters. If the temperature is raised to 29oC and the
pressure is not changed, what is the new volume of the gas?
10. A gas that has a volume of 28 liters, a temperature of 65oC, and an unknown pressure has its volume
increased to 36 liters and its temperature decreased to 35oC. If I measure the pressure after the change to
be 2.0 atm, what was the original pressure of the gas?
Answer:
See explanation
Explanation:
7) P1 =3.3 atm
V1= 15 litres
T1 = 299 K
T2 = 350 K
P2 = 1050 mmHg/760 = 1.38 atm
V2?
From;
P1V1/T1 = P2V2/T2
P1V1T2 = P2V2T1
V2 = P1V1T2/P2T1
V2 = 3.3 * 15 * 350/1.38 * 299
V2 = 17325/412.62
V2 = 42 litres
8) V1= unknown
T1= 115 K
P1 = 60 atm
T2= 225 K
P2 = 30 atm
V2 = 25 litres
From;
P1V1/T1 = P2V2/T2
P1V1T2 = P2V2T1
V1 = P2V2T1/P1T2
V1 = 30 * 25 * 115/ 60 * 225
V1 = 86250/13500
V1 = 6.4 litres
9) T1 = 14 + 273 = 287 K
V1 = 5.5 liters
T2 = 29 + 273 = 302 K
V2 = the unknown
From Charles law;
V1/T1 = V2/T2
V1T2 = V2T1
V2 =V1T2/T1
V2 = 5.5 * 302/ 287
V2 = 5.8 litres
10) V1= 28 litres
T1= 65 + 273 = 338 K
P1 = the unknown
V2 = 36 liters
T2 = 35 + 273 = 308 K
P2 = 2 atm
P1V1/T1 = P2V2/T2
P1V1T2 = P2V2T1
P1 = P2V2T1/V1T2
P1 = 2 * 36 * 338/ 28 * 308
P1 = 24336/8624
P1 = 2.82 atm
9) Consider the reaction of C6H6 Br2 C6H5Br HBr a. What is the theoretical yield of C6H5Br if 42.1 g of C6H6 react with 73.0 g of Br2
Answer:
71.7 g of C₆H₅Br are produced at the theoretical yield.
Explanation:
The reaction is:
C₆H₆ + B₂ → C₆H₅Br + HBr
This is an easy excersie, stoichiometry is 1:1
We determine moles of reactants:
42.1 g / 78g/mol = 0.540 moles of benzene
73 g / 159.80 g/mol = 0.457 moles of hydrogen bromide
Certainly, the HBr is the limiting reactant, because I need 0.540 moles of HBr for 0.540 moles of benzene and I only have, 0.457 moles.
0.457 moles of HBr will produce 0.457 of bromobenzene, at the 100 % yield reaction (theoretical yield)
We convert the moles to mass: 0.457 g . 157 g/mol = 71.7 g
The theoretical yield of the reaction has been 0.457 mol.
The balanced chemical equation for the reaction can be given by:
[tex]\rm C_6H_6\;+\;Br_2\;\rightarrow\;C_6H_5Br\;+\;HBr[/tex]
Accordingly, 1 mole of benzene will give 1 mole of Bromobenzene and 1 mole of Hydrobromide.
The moles can be calculated as;
Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]
Moles in 42.1 grams Benzene:
Moles of Benzene = [tex]\rm \dfrac{42.1}{78}[/tex]
Moles of Benzene = 0.540 mol
Moles of Bromine = [tex]\rm \dfrac{73}{159.80}[/tex]
Moles of Bromine = 0.457 mol.
The limiting reactant in the reaction has been the one that has been present in the lesser quantity as the other reactant to continue to the product formation.
The 1 mole of Benzene requires 1 mole of bromine. So, 0.54 mol of benzene requires. 0.54 mol of bromine. Since the available bromine has been 0.457 mol, Bromine has been the limiting reactant.
The theoretical yield of the reaction will be based on the concentration of Bromine.
Thus, 1 mol of Bromine forms 1 mol of Bromobenzene.
0.457 mol of Bromine will form 0.457 mol of bromobenzene.
The theoretical yield of the reaction has been 0.457 mol.
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Write balanced equations for each of the processes, choosing from the following substances as reactants: BaCl2 O2 H2SO4 HNO3 C2H5OH H2O Ca(OH)2 K Na2CrO4 KOH Pb(NO3)2
Answer:
BaCl₂ and H₂SO₄
Explanation:
The reaction is the precipitation of BaSO₄ from solution.
This means that our reactants must contain the Ba ion and SO₄²⁻ ion. The reactants that meet this criteria are the; BaCl₂ aand H₂SO₄
The reaction is given as;
BaCl₂ + H₂SO₄ --> BaSO₄ + 2HCl
A reservoir could supply an urban setting with (1 point
A safe drinking water from
a rural part of the state.
B a good swimming spot for families.
C a good source of wind-created energy.
D freedom from annual river flooding.
If 22.5 L of nitrogen at 90 Kpa are compressed to 40 Kpa at a constant temperature. What is the new volume?
Answer:
51 L
Explanation:
Step 1: Given data
Initial volume of nitrogen (V₁): 22.5 LInitial pressure of nitrogen (P₁): 90 kPaFinal volume of nitrogen (V₂): ?Final pressure of nitrogen (P₂): 40 kPaStep 2: Calculate the final volume of nitrogen
The volume of a gas is inversely proportional to the pressure. If we consider nitrogen as an ideal gas at a constant temperature, we can find the final volume using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁ / P₂
V₂ = 90 kPa × 22.5 L / 40 kPa
V₂ = 51 L
1. A gas at 116 kPa and 303 K fills a container at 2.0 x 105 L. If the temperature changes to 293 K, What is the new pressure?
Answer:
P₂ = 112.17 KPa
Explanation:
Given data:
Initial pressure = 116 KPa
Initial temperature = 303 K
Final temperature = 293 L
Final pressure = ?
Volume= constant
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
116 KPa / 303 K = P₂/293 K
P₂ = 116 KPa × 293 K / 303 K
P₂ = 33988 KPa. K / 303 K
P₂ = 112.17 KPa
A solution is prepared by dissolving 74.2 g NaI in 527 g of water. Determine the mole fraction of NaI if the final volume of the solution is 565 mL.
a. 8.84 times 10^-2
b. 1.40 times 10^-3
c. 6.04 times 10^-3
d. 1.32 times 10^-2
e. 1.65 times 10^-2
Answer:
The correct answer is option e, that is, 1.65 * 10^-2.
Explanation:
Based on the given information, the weight of NaI given is 74.2 grams and the weight of water given is 527 grams.
The final volume of the solution given is 566 ml.
The formula to calculate the moles is weight/molecular mass,
The moles of NaI will be,
= 74.2/150 = 0.494
Now moles of water will be,
= 527/18 = 29.3
The mole fraction of NaI will be,
= 0.494 / (0.494 + 29.3)
= 0.0165 or 1.65 * 10^-2
Hence, the mole fraction of NaI is 1.65 * 10^-2
atoms that vary in the number of neutrons found in their nuclei are called?
Answer:
Isotopes are atoms of an element with the normal number of protons and electrons, but different numbers of neutrons. Isotopes have the same atomic number, but different mass numbers. GOOD LESSONS♡
WHAT PROBLEMS DID PRESIDENT JEFFERSON HAVE WITH TRIPOLI AND HOW DID HE SOLVE THEM
Answer:
Although Thomas Jefferson came to power determined to limit the reach of the federal government, foreign affairs dominated his presidency and pushed him toward Federalist policies that greatly contrasted with his political philosophy. The first foreign episode involved Jefferson's war with the Barbary pirates. For the previous century or so, Western nations had paid bribes to the Barbary states, which would later become Morocco, Algeria, Tunis, and Tripolitania, to keep them from harassing American and merchant ships
Explanation:
which part of earth absorbs the most sunlight?
A oceans
b soil
c atmosphere
d rivers and lakes
Answer:
atmosphere
Explanation:
The atmosphere absorbs the most in light because the atmosphere surrounds our planet
Answer:
c
Explanation:
Which of these compounds is most likely to contain an ionic bond?
O CaCl2
O CHA
SO2
O H2
Answer:
O CaCl₂
Explanation:
The compound most likely to contain an ionic bond is CaCl₂ because it is the only specie with a metal and non-metal.
The metal here is Ca and non-metal is Cl.
In this bond type, there is a transfer of electrons from the metal to the non-metal. There must be a significant electronegativity difference between the two bodies for this bond to form. The metal Calcium loses two electrons and becomes isoelectronic with argon. Two chlorine non-metal gain one of the electrons each and becomes stable. The electrostatic attraction between the oppositely charged ions results in the ionic bonding.3.
A gas at 1.1 atm and 30°C occupies a volume of 41mL. What volume will the gas occupy at STP
conditions?
If the temperature outside is 60°F, what is the approximate temperature on the Celsius scale and the Relvin scale?
If the air temperature drops to 30°F during the night, how has the kinetic energy of the air particles changed?
KE at 30°F=0.942 KE at 60°F
Further explanationThe average kinetic energy value is only affected by temperature changes. The higher the temperature, the average kinetic energy of the molecule increases
This molecule is very small when compared to the distance between molecules, so the volume of gas contains mostly empty space
Gas particles move randomly (both speed and direction , as vector)
Average velocities of gases can be expressed as root-mean-square averages. (V rms)
[tex]\large{\boxed{\bold{v_{rms}=\sqrt{\frac{3RT}{Mm} } }}[/tex]
R = gas constant, T = temperature, Mm = molar mass of the gas particles
Kinetic energy :
[tex]\tt KE=\dfrac{1}{2}mv^2[/tex]
The temperature outside is 60°F
Convert to Celcius and Kelvin
°C = 5/9 (°F-32)
[tex]\tt ^OC=\dfrac{5}{9}(60-32)=15.56[/tex]
°K = °C + 273
[tex]\tt ^oK=15.56+273=288.56[/tex]
For 30°F :
[tex]\tt ^oC=\dfrac{5}{9}(30-32)=-1.1\\\\^oK=-1.1+273=271.9[/tex]
KE at 288.56 °K(60 °F)[tex]\tt KE_1=\dfrac{1}{2}m.\dfrac{3R.288.56}{Mm}[/tex]
KE at 271.9°K(30°F)[tex]\tt KE_2=\dfrac{1}{2}m.\dfrac{3R.271.9}{Mm}[/tex]
[tex]\tt \dfrac{KE_2}{KE_1}=\dfrac{271.9}{288.56}=0.942\\\\KE_2=0.942KE_1[/tex]
In some molecules and polyatomic ions, the sum of the valence electrons is odd and as a result the octet rule fails.
a. True
b. False
Answer:
a
Explanation:
Answer:
True
Explanation:
as electronegativity difference increases, bond length decreases. when a metal gains an electron, the process is endothermic. ... atoms surrounded by 7 valence electrons tend to lose electrons
PLEASE HELP ASAP WILL MARK YOU BRAINLIEST!!!!!! :)
Question 13
Convert 178,300 mL into L. Use 1,000 mL/L as your conversion factor.
1.73 L
178.3 L
0.1783L
17.83
Answer:
B. 178.3
178,300 divided by 1,000 is 178.3
Answer:
178.3L
Explanation:
1mL=0.001L
178300mL=?
we just criss-cross it
178300×0.001=178.3L
The Lewis dot diagram for LiBr
Give the name for the molecular compound with the the formula P2I4.
Answer:
Diphosphorus tetraiodide
Explanation:
Diphosphorus tetraiodide is an orange crystalline solid with the formula P2I4. It has been used as a reducing agent in organic chemistry. It is a rare example of a compound with phosphorus in the +2 oxidation state, and can be classified as a subhalide of phosphorus.
Can I please have brainliest?
The name of the molecular compound with the formula [tex]\rm P_2I_4[/tex] is diphosphorus tetraiodide.
The term "compound" refers to two or more elements joined together such that the elements have lost their individual identity in favor of a new set of properties.
The given molecular compound [tex]\rm P_2I_4[/tex] is diphosphorus tetraiodide.
This name is derived from the prefixes "di-" and "tetra-" which indicate that there are two phosphorus atoms and four iodine atoms in the molecule, respectively. The ending "-ide" is used to indicate that the compound is a binary compound consisting of two different elements.Therefore, diphosphorus tetraiodide is the name of the molecular compound with the formula [tex]\rm P_2I_4[/tex] .
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Which atom has the most pronounced metallic properties
1) 1s²2s²2p⁵ 2) 1s²2s²2p³
3)1s²2s²2p⁶3s² 4) 1s²2s²2p⁶3s²3p⁴
heat transfer through any intermediate fluid is known as?
Answer:
convection
Explanation:
Answer: At the beach, differences in temperatures create wind which transfers heat between the land and the water. ... Heat transfer through any intermediate fluid is known as
(A.) Condensation.
A normal saline solution for injecting hospital patients is 0.90 % NaCl. What is the mass of NaCl
dissolved in 50.0 g of 0.90 % saline solution Report only the numerical portion of the problem,
with two signifcant figures.
Answer:
0.45 g
Explanation:
Which transition is associated with an emission of energy?
n = 5 to n = 4
n = 4 to n = 7
Answer:
n = 4 to n = 7
Explanation:
Which reactions have a positive ΔSrxn? 2A(g)+B(g)⟶4C(g) 2A(g)+3B(g)⟶4C(g) A(s)+2B(g)⟶C(g) 2A(g)+B(s)⟶3C(g)
Answer:
Most likely:
[tex]{\rm 2\, A}\, (g) + {\rm B}\, (g) \to 4\, {\rm C}\, (g)[/tex] (the first choice.)
[tex]2\, {\rm A}\, (g) + {\rm B}\, (s) \to 3\, {\rm C}\, (g)[/tex] (the fourth choice.)
Explanation:
[tex]\Delta S_\text{rxn}[/tex] denotes the entropy change in a reaction.
The value of [tex]\Delta S_\text{rxn}[/tex] is greater than zero if the reaction corresponds to an increase in entropy. In other words, entropy should be higher for the products of this reaction than for its reactants.
The exact entropy of each species depends on both the environment (temperature, pressure, etc.) and on the structure of the species. However, there are some general trends.
Consider one mole of some gaseous molecules and one mole of some solid particles. If that gas and that solid are under the same temperature and pressure, which one would have a higher entropy? Generally, the gas would have a higher entropy.
Also, the entropy of a gas is approximately proportional to the number of particles in that gas.
Therefore, it is likely that [tex]\Delta S_\text{rxn}[/tex] would be positive for a reaction if there are more gas particles among the products than among the reactants.
Note that [tex](s)[/tex] is the state symbol for solids, whereas [tex](g)[/tex] is the state symbol for gases.
In this question:
First reaction: [tex]{\rm 2\, A}\, (g) + {\rm B}\, (g) \to 4\, {\rm C}\, (g)[/tex].
In each unit of this reaction, there are:
two gas particles among the reactants.four gas particles among the products. The number of gas particles that this reaction produces is larger than the number of gas particles that it consumes. Therefore, it is likely that [tex]\Delta S_\text{rxn} > 0[/tex] for this reaction.Second reaction: [tex]{\rm 2\, A}\, (g) + 3\, {\rm B}\, (g) \to 4\, {\rm C}\, (g)[/tex].
In each reaction, there are:
five gas particles among the reactants.four gas particles among the products. The number of gas particles that this reaction produces is smaller than the number of gas particles that it consumes. Therefore, it is likely that [tex]\Delta S_\text{rxn} < 0[/tex] for this reaction.Third reaction: [tex]{\rm A}\, (s) + 2\, {\rm B}\, (g) \to {\rm C}\, (g)[/tex].
In each reaction, there are:
two gas particles among the reactants.one gas particle among the products. The number of gas particles that this reaction produces is smaller than the number of gas particles that it consumes. Therefore, it is likely that [tex]\Delta S_\text{rxn} < 0[/tex] for this reaction.Fourth reaction: [tex]{\rm 2\, A}\, (g) + {\rm B}\, (s) \to 3\, {\rm C}\, (g)[/tex].
In each unit of this reaction, there are:
two gas particles among the reactants (note that the state symbol [tex](s)[/tex] suggests that [tex]{\rm B}\, (s)[/tex] is not a gas.)three gas particles among the products. The number of gas particles that this reaction produces is larger than the number of gas particles that it consumes. Therefore, it is likely that [tex]\Delta S_\text{rxn} > 0[/tex] for this reaction.Plzz helppppppppppppp
Answer:
i got you stop doing work and forget about this one class you will still pass trust me i did it it 8th grade and still made it to 9th but today im not even in school so just do better in your other classes
Explanation:
A flammable liquid with many branches of carbon and hydrogen atoms forming a complex molecules
What is the atomic number of this atom?
Answer:
1
Explanation:
A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place over the next few minutes? Molecules in both the metal and the surrounding air will start moving at lower speeds. Molecules in both the metal and the surrounding air will start moving at higher speeds. The air molecules that are surrounding the metal will slow down, and the molecules in the metal will speed up. The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.
Answer:
150 gs for me aww thanks
Explanation:
Answer:
D) The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.
Explanation:
Edg
Electromagnetic waves are ? and have ?
more energy moving from left to right on the electromagnetic
Electromagnetic waves are
radiation diagram
shorter/less
o longer/more
shorter/more
longer/less
Answer:
longer/less
Explanation:
In moving from left to right on the periodic table, electromagnetic waves have longer wavelength and less energy.
The electromagnetic radiation diagram is made up of electromagnetic waves.
From left to right, the energy of the wave decreases. Waves at the left most edge have the highest energy. As we move rightward, the wavelength also becomes longer. The frequency also reduces. Wavelength and energy are inversely proportional.How are work and force related
Answer:
Work is done when a force that is applied to an object moves that object. The work is calculated by multiplying the force by the amount of movement of an object (W = F * d). A force of 10 newtons, that moves an object 3 meters, does 30 n-m of work. ... You have to exert a force AND move something to qualify as doing work.
Explanation:
Which statement describes effusion?
It occurs when a gas passes through a tiny hole.
It occurs when a liquid passes through a tiny hole.
It occurs when gas molecules disperse throughout a container.
It occurs when a liquid disperses throughout a container.
Answer:
A. It occurs when a gas passes through a tiny hole.
Explanation:
Edge2020
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Describe how to calculate the average atomic mass for the following element.
Isotopes: % Abundance:
neon-20 90.00%
neon-22 10.00%
Answer:
Average atomic mass = 20.2 amu
Explanation:
Given data:
Average atomic mass of neon = ?
Abundance of Ne-20 = 90.00%
Abundance of Ne-22 = 10.00%
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (90.00×20)+(10.00×22) /100
Average atomic mass = 1800 + 220 / 100
Average atomic mass = 2020 / 100
Average atomic mass = 20.2 amu.