What is the molar mass of CuCIO3

Answers

Answer 1
Answer:

147.05 g/mol

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic TableExplanation:

Step 1: Define

CuClO₃

Step 2: Find MM

Molar Mass of Cu - 63.55 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CuClO₃ - 63.55 + 35.45 + 3(16.00) = 147.05 g/mol


Related Questions

Sb2S3 + 3Fe --> 2Sb + 3FeS
When 0.022mol Sb2S3 react with an excess of Fe, 0.08mol Sb is produced. What is the percent yield of
this reaction? (hint: what's the theoretical yield?)

Answers

The actual value is greater than the theoretical value

Further explanation

Given

Reaction

Sb2S3 + 3Fe --> 2Sb + 3FeS

0.022 mol Sb2S3

0.08mol Sb

Required

The percent yield

Solution

Percent yield is the comparison of the amount of product obtained from a reaction(actual) with the amount you calculated (theoretical)

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

Theoretical yield of Sb : 2/1 x 0.022 mol = 0.044 moles

In the question, there seems to be an error, because the actual yield value(0.08=?) should be smaller than the theoretical yield(0.044)

determine the empirical and molecular formula of a compound composed of 18.24 g carbon, 0.51 g hydrogen, and 16.91 g fluorine and has a molar mass 562.0 g/mol.

Answers

Answer: The empirical formula for the given compound is [tex]C_3HF_2[/tex]  and molecular formula for the given compound is [tex]C_{24}H_8F_{16}[/tex]

Explanation : Given,

Mass of C = 18.24 g

Mass of H = 0.51 g

Mass of F = 16.91 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =[tex]\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{18.24g}{12g/mole}=1.52moles[/tex]

Moles of Hydrogen = [tex]\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.51g}{1g/mole}=0.51moles[/tex]

Moles of Fluorine = [tex]\frac{\text{Given mass of Fluorine}}{\text{Molar mass of Fluorine}}=\frac{16.91g}{19g/mole}=0.89moles[/tex]

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.51 moles.

For Carbon = [tex]\frac{1.52}{0.51}=2.98\approx 3[/tex]

For Hydrogen  = [tex]\frac{0.51}{0.51}=1[/tex]

For Fluorine = [tex]\frac{0.89}{0.51}=1.74\approx 2[/tex]

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : F = 3 : 1 : 2

The empirical formula for the given compound is [tex]C_3H_1F_2=C_3HF_2[/tex]

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

[tex]n=\frac{\text{molecular mass}}{\text{empirical mass}}[/tex]

We are given:

Molar mass  = 562.0 g/mol

Mass of empirical formula = 3(12) + 1(1) + 2(19) = 75 g/eq

Putting values in above equation, we get:

[tex]n=\frac{562.0}{75}=7.49\approx 8[/tex]

Multiplying this valency by the subscript of every element of empirical formula, we get:

[tex]C_3HF_2=(C_3HF_2)_n=(C_3HF_2)_8=C_{24}H_8F_{16}[/tex]

Thus, the molecular formula for the given compound is [tex]C_{24}H_8F_{16}[/tex]

The proportionate of the atom found in a given compound is called the empirical formula while the molecular formula represents the actual digits of the atoms found in the given molecule of the compound.

The empirical formula for the given compound is [tex]\rm C_{3}HF_{2}[/tex]  and molecular formula for the given compound is [tex]\rm C_{24}H_{8}F_{16}[/tex].

The empirical formula can be determined as:

Given,

Mass of C = 18.24 gMass of H = 0.51 gMass of F = 16.91 g

Step 1: For determining the empirical formula, convert mass into moles:

For Carbon:

[tex]\begin{aligned}&\rm Moles \;of \;Carbon = \dfrac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}\\\\&= \dfrac{18.24 \rm g}{ 12 \rm g/mol}\\\\&=1.52\text{ moles}\end{aligned}[/tex]

For Hydrogen:

[tex]\begin{aligned}&\rm Moles \;of \;Hydrogen= \dfrac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}\\\\&= \dfrac{0.51\rm g}{ 1\rm g/mol}\\\\&=0.51\text{ moles}\end{aligned}[/tex]

For Fluorine:

[tex]\begin{aligned}&\rm Moles \;of \;Fluorine= \dfrac{\text{Given mass of Fluorine}}{\text{Molar mass of Fluorine}}\\\\&= \dfrac{16.91\rm g}{ 19\rm g/mol}\\\\&=0.89\text{ moles}\end{aligned}[/tex]

Step 2: Calculation of mole ratio for the assigned elements:

For this divide the moles of elements with the smallest number of moles calculated above.

[tex]\begin{aligned}\text{For Carbon} & = \dfrac{1.52 }{0.51}\\&= 2.98\end{aligned}[/tex]

Moles of C = 3

[tex]\begin{aligned}\text{For Hydrogen}& = \dfrac{0.51}{ 0.51}\\&= 1\end{aligned}[/tex]

Moles of Hydrogen = 1

[tex]\begin{aligned}\text{For Fluorine}& = \dfrac{0.89}{ 0.51}\\&= 1.74\end{aligned}[/tex]

Moles of Fluorine = 2

Step 3: The calculated mole ratio will be the subscript of the elements.

C : H : F = 3 : 1 : 2

Therefore, the empirical formula will be,

[tex]\rm C_{3}H_{1}F_{2} \;or\; C_{3}HF_{2}[/tex]

The molecular formula can be determined as:

Determining the valency (n):

[tex]n = \dfrac {\text{molecular mass} }{\text{empirical mass}}[/tex]

Given,

Molar mass = 562.0 g/molMass of empirical formula = [tex]3(12) + 1(1) + 2(19)[/tex]

= 75 g/eq

Substituting values in the above equation, we get:

[tex]\begin{aligned}n &= \dfrac{562 }{ 75}\\\\&= 7.49 \\\\&= 8\end{aligned}[/tex]

Multiply the valency calculated with the empirical formula:

[tex]\begin{aligned}\rm C_{3}HF_{2} &=\rm (C_{3}HF_{2})n\\&= \rm (C_{3}\rm HF_{2})8\\\\\\\\&= \rm (C_{24}H_{8}F_{16})\end{aligned}[/tex]

Therefore, the molecular formula is [tex]\rm C_{24}H_{8}F_{16}[/tex].

Thus, the empirical formula is  [tex]\rm C_{3}HF_{2}[/tex]  and the molecular formula is [tex]\rm C_{24}H_{8}F_{16}[/tex].

Learn more about empirical and molecular formulas here:

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Seth and Leah each kick a soccer ball. Leah's ball goes farther than Seth's. What must be true of the force of Leah's kick?
A) Leah's force can not be compared to Seth's force.
B) Leah kicked the soccer ball with more force than Seth.
C) Leah kicked the soccer ball with less force than Seth.
D) Leah kicked the soccer ball with the same force than Seth.

Answers

Answer:

B) Leah kicked the soccer ball with more force than Seth.

Explanation:

The true statement is that Leah kicked the soccer ball with more force compared to Seth.

We know that both balls have the same mass and that Seth's ball went further compared to Leah's ball.

 So;

       Force  = mass x acceleration

We are sure that Leah's ball has a greater acceleration due to the force applied and it will travel farther due to the energy it contains.

Weathering is a process in the rock cycle. How does weathering contribute to the
formation of rocks?

Answers

Answer:

Forces like wind and water break down rocks through the processes of weathering and erosion. ... Forces like wind and water move the rock pieces. They mix with matter like sand to become sediment. Weathering and erosion help shape Earth's surface.

Explanation:

C 6 H 12 O 6 +6O2 = 6CO2+......



PLEASE BALANCE THIS EQUATION


ANSWER AND I WILL GIVE YOU BRAINILIEST

Answers

Answer:

2C2 H6 +7O2=4co2+6h2o+heat

What would be the mass of 9.03 x 10^21 molecules of hydrobromic acid?

Answers

Answer:

1.21 g HBr

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Compounds

Writing CompoundsAcids/Bases

Atomic Structure

Reading a Periodic TableUsing Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Explanation:

Step 1: Define

9.03 × 10²¹ molecules HBr

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of H - 1.01 g/mol

Molar Mass of Br - 79.90 g/mol

Molar Mass of HBr - 1.01 + 79.90 = 80.91 g/mol

Step 3: Convert

Set up:                              [tex]\displaystyle 9.03 \cdot 10^{21} \ molecules \ HBr(\frac{1 \ mol \ HBr}{6.022 \cdot 10^{23} \ molecules \ HBr})(\frac{80.91 \ g \ HBr}{1 \ mol \ HBr})[/tex]Multiply/Divide:                                                                                               [tex]\displaystyle 1.21325 \ g \ HBr[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.21325 g HBr ≈ 1.21 g HBr

Determine the correct empirical formula of a compound containing 26.68% carbon, 2.24% hydrogen, and 71.08% oxygen.

Answers

Answer:

CHO₂

Explanation:

The following data were obtained from the question:

Carbon (C) = 26.68%

Hydrogen (H) = 2.24%

Oxygen (O) = 71.08%

Empirical formula =?

The empirical formula of the compound can be obtained as follow:

C = 26.68%

H = 2.24%

O = 71.08%

Divide by their molar mass.

C = 26.68 /12 = 2.223

H = 2.24 / 1 = 2.24

O = 71.08 / 16 = 4.4425

Divide by the smallest.

C = 2.223 / 2.223 = 1

H = 2.24 / 2.223 = 1

O = 4.4425 /2.223 = 2

Thus the empirical formula of the compound is CHO₂

The correct empirical formula of a compound containing 26.68% carbon, 2.24% hydrogen, and 71.08% oxygen is CHO₂

The empirical formulae shows us how elements in a compound are in their simplest ratio.

From the question, we can see  

Carbon (C) with  26.68%

Hydrogen (H)with  2.24%

Oxygen (O) with 71.08%

Now, the empirical formula of the compound can begotten following these steps:

We find the  molar amounts of carbon, hydrogen and oxygen  in a 100-g sample by dividing each element’s mass by its molar mass

Carbon  = 26.68 /12 = 2.223

Hydrogen= 2.24 / 1 = 2.24

Oxygen  = 71.08 / 16 = 4.4425

We divide each molar amount by the least  of the three

C arbon = 2.223 / 2.223 = 1

H ydrogen= 2.24 / 2.223 = 1

Oxygen  = 4.4425 /2.223 = 2

Giving us the empirical formula of the compound as CHO₂

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At equilibrium the reactant and product concentrations are constant because a change in one direction is balanced by a change in the other as the forward and reverse rates become equal: (MTS 5/5/2018) When a chemical system is at equilibrium, Group of answer choices the concentrations of the reactants and products have reached constant values. the concentrations of the reactants are equal to the concentrations of the products. the forward and reverse reactions have stopped. the reaction quotient, Q, has reached a maximum. None of the choices.

Answers

Answer:

concentrations of the reactants and products have reached constant values

Explanation:

When a reaction is carried out in a closed system, it attains dynamic equilibrium after sometime. We define dynamic equilibrium as a situation in which the forward and reverse reactions proceed at the same rate.

When this occurs, the concentration of the reactants and products remain fairly constant. Hence the answer.

A container holds one mole of a gas if the amount of gas is tripled how many molecules of gas will be in the container?

Answers

Answer:At the molecular level, the pressure of a gas depends on the number of collisions its molecules have with the walls of the container. If the pressure on the piston is doubled, the volume of the gas decreases by one-half. The gas molecules, now confined in a smaller volume, collide with the walls of the container twice as often and their pressure once again equals that of the piston.

Explanation:

Answer:

thanks

Explanation:

How many atoms of sulfur, S, are in 4.00 g sulfur?

Answers

Answer:

7.51 × 10²² atoms S

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic TableUsing Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Explanation:

Step 1: Define

4.00 g S

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of S - 32.07 g/mol

Step 3: Convert

Set up:                              [tex]\displaystyle 4.00 \ g \ S(\frac{1 \ mol \ S}{32.07 \ g \ S})(\frac{6.022 \cdot 10^{23} \ atoms \ S}{1 \ mol \ S})[/tex]Multiply:                            [tex]\displaystyle 7.51107 \cdot 10^{22} \ atoms \ S[/tex]

Step 4: Check

Follow sig figs and round. We are given 3 sig figs.

7.51107 × 10²² atoms S ≈ 7.51 × 10²² atoms S

what volume will 2 moles of nitrogen occupy at 780 torr and 10C.

Answers

The volume : V = 45.22 L

Further explanation

Given

Moles = n = 2

Pressure = P = 780 torr = 1,02632 atm

Temperature = T = 10 + 273 = 283 K

Required

Volume

Solution

Ideal gas law : PV = nRT

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

Input the value :

V = (nRT)/P

V = (2 x 0.082 x 283)/1,02632

V = 45.22 L

I just need help on 4 and 5 please ​

Answers

Answer:

4. 12 km.

5. 2 km.

Explanation:

Hello!

In this case, we need to distinguish between two terms:

- Distance traveled: it stands for the total displacement, no matter the initial and final position the body has; it means that the total displacement was:

DT = 3km + 4 km + 3 km + 2 km = 12 km.

- Displacement: it stands for the relationship between the initial position and the final one, it means that the initial position was 0 km and the final one is 2 km away, thus, the displacement is:

D = 2km - 0 km = 2 km.

Best regards!

how many grams of carbon are there in 706 grams of acetic acid

Answers

Answer:

How many grams Acetic Acid in 1 mol? The answer is 60.05196.

We assume you are converting between grams Acetic Acid and mole?

(人◕ω◕)

Explanation:

You can view more details on each measurement unit:

molecular weight of Acetic Acid or mol

The molecular formula for Acetic Acid is CH3COOH.

The SI base unit for amount of substance is the mole.

1 grams Acetic Acid is equal to 0.016652245821785 mole.

Note that rounding errors may occur, so always check the results.

Use this page to learn how to convert between grams Acetic Acid and mole.

Examples

1 grams Acetic Acid to mol = 0.01665 mol

10 grams Acetic Acid to mol = 0.16652 mol

20 grams Acetic Acid to mol = 0.33304 mol

30 grams Acetic Acid to mol = 0.49957 mol

40 grams Acetic Acid to mol = 0.66609 mol

50 grams Acetic Acid to mol = 0.83261 mol

100 grams Acetic Acid to mol = 1.66522 mol

200 grams Acetic Acid to mol = 3.33045 mol

areas and organisms where carbon is stored

Answers

Answer:

Carbon is stored on our planet in the following major sinks (1) as organic molecules in living and dead organisms found in the biosphere; (2) as the gas carbon dioxide in the atmosphere; (3) as organic matter in soils; (4) in the lithosphere as fossil fuels and sedimentary rock deposits such as limestone, dolomite

What do all the different types of motor nerves
have in common? Select all that apply.

A. They use sensory receptors to receive
information from the environment.
B. They transmit information to and from muscles
C. They connect to muscle fibers through the motor endplate
D. They control voluntary motor function

Answers

Answer:

B and C

Explanation:

The different types of motor nerves transmit information to and from muscles, and they connect to muscle fibers through the motor endplate.

according to the kinetic theory the pressure exerted by a sample of gas at constant volume doubles when the absolute temperature is doubled because

Answers

Answer:

Due to expansion.

Explanation:

The pressure exerted by a sample of gas at constant volume doubles when the absolute temperature is doubled because with the increase of temperature, the molecules of gas start expansion which increases their volume and as a result pressure of a gas increases. Increasing temperature of a gas sample increases the kinetic energy of the particles, and as a result the gas expand.

Explain why the strength of a polycrystalline metal at room temperature decreases as its grain size increases.

Answers

Answer:

Metals with larger grains have less grain-boundary area per unit volume, and hence will not be as able to generate as many entanglements at grain boundaries, thus the strength will be lower.

The maximum amount of SF6 that can be produced from the reaction of 3.5 g of sulfur with 4.5 g of fluorine is __________ g.

Answers

Answer:

16.06 g

Explanation:

Reaction equation;

S(s) + 3F2(g) ----> SF6(s)

Number of moles of sulphur reacted = 3.5g/32g/mol = 0.11 moles

If 1 mole of sulphur yields 1 mole of SF6

Then 0.11 moles of sulphur yields 0.11 moles of SF6

Also

Number of moles of fluorine = 4.5g/38 g/mol= 0.12 moles

Hence sulphur his the limiting reactant;

Maximum amount of SF6 = 0.11 × 146 = 16.06 g

What rules should you follow when adding and subtracting? Check all that apply.

Answers

Answer:

The answer to this question would be:  

2. The exponents need to be the same so the leading numbers can be added or subtracted.

3. The result has the same number of decimal places as the least precise number.

The exponent is the 10^x that used in scientific notation. .When adding 12.3* 10^5 with 34.56 * 10^4, you need to make the exponent same first. In this case, it would become 12.3* 10^5 + 3.456 * 10^5= 15.756* 10^5

The decimal place could be rounded up to the least precise number. I'm not sure with the significant figures but it seems to use the biggest one.

Explanation:

https://brainly.com/question/7413247

The food web above shows how energy moves through a lake environment. If a chemical company were to put a harmful chemical
that kills off all of the phytoplankton, which animal would be immediately affected?

A)bacteria

B)invertebrates

C)human

D)prey fish

Answers

Answer:

B: Invertebrates

Explanation:

Since no other food source for invertebrates is shown, the invertebrates will starve and die off first

What is the noble gas configuration of sulfur

Answers

[Ne] 3s² 3p⁴

Not sure if that’s right

Write a balanced equation for the double-replacement precipitation reaction described, using the smallest possible integer coefficients. A precipitate forms when aqueous solutions of silver(I) nitrate and magnesium sulfate are combined.

Answers

Answer: [tex]2AgNO_3(aq)+MgSO_4(aq)\rightarrow Ag_2SO_4(s)+Mg(NO_3)_2(aq)[/tex]

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.  

A double displacement reaction in which on e of the product is formed as a solid is called as precipitation reaction.  

The balanced chemical equation is:

[tex]2AgNO_3(aq)+MgSO_4(aq)\rightarrow Ag_2SO_4(s)+Mg(NO_3)_2(aq)[/tex]

. What is the percent by mass of iron in the compound Fe2O32 The molar mass Fe2O3 is 159,69 g/mol. of​

Answers

Answer:

Percent by mass is 69.42% Fe

Explanation:

If the molar mass is 159.69 grams per mol, and our goal is to find the percent by mass of iron, then we need to find the mass of iron first. We will calculate the amu of Iron and divide that by the total molar mass of Fe2O3.. and then multiply by 100 and write with a % in order to find the percent by mass (percent composition)

Fe2 = 2(55.845) = 111.69

111.69/159.69 = 0.69941762164

0.69941762164 * 100 = 69.42% Fe

The study of chemicals is called chemistry.

The correct answer to the question is Percent by mass is 69.42% Fe

What is a molecule?A molecule is an electrically neutral group of two or more atoms held together by chemical bonds. Molecules are distinguished from ions by their lack of electrical charge.

If the molar mass is 159.69 grams per mole, and our goal is to find the percent by mass of iron, then we need to find the mass of iron first.

We will calculate the AMU of Iron and divide that by the total molar mass of Fe2O3. and then multiply by 100 and write with a % in order to find the percent by mass (percent composition)

[tex]Fe2 = 2(55.845) = 111.69\\\\\\frac{111.69}{159.69} = 0.69941762164\\\\0.69941762164 * 100 = 69.42% Fe[/tex]

Hence, the correct option answer is 69.42.

For more information about the question, refer to the link:-

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10. How do scientific investigations advance scientific knowledge?
Help please

Answers

Answer:

Technology used to gather data enhances accuracy and allows scientists to analyze and quantify results of investigations. Scientific explanations emphasize evidence, have logically consistent arguments, and use scientific principles, models, and theories

Explanation:

a laboratory procedure calls for making 510.0 mL of a 1.6 M KNO3 solution. How much KNO3 in grams is needed

Answers

Answer:

82.416 g of KNO ₃  is needed to produce 510.0 mL of a 1.6 M KNO ₃ solution.

Explanation:

Since molarity is the number of moles of solute that are dissolved in a given volume, calculated by dividing the moles of solute by the volume of the solution, the following rule of three can be applied: if in 1 L (1,000 mL) of KNO₃ there are 1.6 moles of the compound present, in 510 mL how many moles will there be?

[tex]moles=\frac{510 mL*1.6 moles}{1000 mL}[/tex]

moles= 0.816

Being the molar mass of the elements:

K: 39 g/moleN: 14 g/moleO: 16 g/mole

So the molar mass of the compound KNO₃ is:

KNO₃= 39 g/mole + 14 g/mole + 3*16 g/mole= 101 g/mole

Now I can apply the following rule of three: if in 1 mole of KNO₃ there are 101 g, in 0.816 moles how much mass is there?

[tex]mass=\frac{0.816 moles*101 grams}{1 mole}[/tex]

mass= 82.416 grams

82.416 g of KNO ₃  is needed to produce 510.0 mL of a 1.6 M KNO ₃ solution.

Aqueous sulfuric acid H2SO4 reacts with solid sodium hydroxide NaOH to produce aqueous sodium sulfate Na2SO4 and liquid water H2O. What is the theoretical yield of sodium sulfate formed from the reaction of 75.5g of sulfuric acid and 105.g of sodium hydroxide

Answers

Answer:

109.34 g

Explanation:

2NaOH(aq) + H2SO4(aq) ------> Na2SO4(aq) + 2H2O(l)

Number of moles of NaOH = 105g/40g/mol = 2.6 moles

From the reaction equation;

2 moles of NaOH yields 1 mole of sodium sulphate

2.6 moles of NaOH yields = 2.6 × 1/2 = 1.3 moles of sodium sulphate

Number of moles of H2SO4= 75.5g/98 g/mol = 0.77 moles

From the reaction equation;

1 mole of H2SO4 yields 1 mole of sodium sulphate

Hence, 0.77 moles of H2SO4 yields 0.77 moles of sodium sulphate

So H2SO4 is the limiting reactant.

Theoretical yield = number of moles × molar mass

= 0.77 mol ×142 g/mol

= 109.34 g

What is not a basic need of all organisms?
soil
water
food
air

Answers

Answer:

soil

Explanation:

some organisms aren't plants

The answer is:

A.(soil)

Some organisms need soil but not all, hope this helps!

Which causes genetic variations and can result in different alleles?

predation rate
random mutations
competition
environmental changes

Answers

Answer:

Environmental Changes

Explanation:

Over time, a species will adjust to the changes in environment in order to survive.

Answer:

The correct answer is B, random mutations

Explanation:

Alleles are shuffled in the offspring when random mating, fertilization, and recombination between homologous chromosomes during meiosis occur.

I also took the quiz, Good luck!  \ (•◡•) /

What is the correct name for N2O

Answers

Explanation:

Nitrous oxide

^_^^.^^.^

Which of these organisms is considered the most complex?

squid
whale
spider
ladybug

Answers

B because it had bones and the others don’t
B because whales have bones
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