What is the measure of RPQ

What Is The Measure Of RPQ

Answers

Answer 1

Answer:

239

Step-by-step explanation:

SP is the diameter so Arc RP is supplementary to Arc SR

[tex]31 + x = 180[/tex]

[tex]x = 149[/tex]

Arc PQ is supplementary to Arc SQ so

[tex]90 + x = 180[/tex]

[tex]x = 90[/tex]

Arc Addition:

[tex]149 + 90 = 239[/tex]


Related Questions

Which property of exponents must be used first to solve this expression? (iy2)1/3

Answers

Step-by-step explanation:

"must be used first" is a very hard phrasing. multiplication is commutative.

and I am not sure that the problem is stated correctly.

I read here

(i×y²) to the power of 1/3.

i is the imaginary constant sqrt(-1) ?

exponents brought themselves to the power of something else multiply.

e.g.

[tex]({2}^{3})^{4} = {2}^{12} [/tex]

exponents in multimedia expressions of the same base simply add up.

e.g.

[tex] {2}^{3} \times {2}^{4} = {2}^{7} [/tex]

a negative exponent means that the expression with the same positive exponent is just at the bottom of a division.

e.g.

[tex] {2}^{ - 3} = 1 \div {2}^{3} [/tex]

and a fraction as exponent specifies a root to be taken.

e.g

[tex] {2}^{1 \div 3} = \sqrt[3]{2} [/tex]

so, I would do all the exponent multiplications to simplify the expression.

[tex] \sqrt[3]{i \times {y}^{2} } = ({i \times {y}^{2} })^{1 \div 3} = [/tex]

[tex] = ( { - 1}^{1 \div 2} \times {y}^{2} ) ^{1 \div 3} [/tex]

1/2 × 1/3 = 1/6

2 × 1/3 = 2/3

[tex] = { - 1}^{1 \div 6} \times {y}^{2 \div 3} = \sqrt[6]{ - 1} \times \sqrt[3]{ {y}^{2} } [/tex]

so, as we can see, we can move freely from multiplying the fraction exponents to converting them into root expressions and vice versa.

The profit for a car company can be represented by the function P=−0.5 x² +4 x+ 12,

where P is the profit in hundred thousands of dollars and x represents the number of cars sold in thousands. What is the maximum profit the company can make?

Answers

Answer:

3x+12

Step-by-step explanation:

-0.5x*2+4x+12

Multiply 0.5x*2=x

= -x+4x+12

Add similar elements -x+4x+12

= 3x+12

Use the law of cosines to find the length of a

Answers

Answer:

Step-by-step explanation:

You don't need the Law of Cosines, the Law of sines if what you need. You can't use the Law of Cosines because in order to find side a, you would need the length of side c and you don't have it. Using the Law of Sines is appropriate, knowing that angle B = 55:

[tex]\frac{sin55}{175}=\frac{sin42}{a}[/tex] and solving for a:

[tex]a=\frac{175sin42}{sin55}[/tex] so

a = 143.0

What is the measure of each exterior angle of a regular hexagon?

40°
45°
60°
72°

Answers

The measure of each exterior angle of a regular hexagon ( six sided regular polygon is 60°.

Option C)60° is the correct answer.

What is a polygon?

A polygon is simply a two-dimensional a plane shape enclosed by line segments called sides.

The formula for calculating the exterior angles of a polygon is;

E = 360° ÷ number of sides

Given the data in the question;

The polygon in question is a regular hexagonA regular hexagon has six sides, n = 6

So we substitute the value for number of sides into the expression above.

E = 360° ÷ number of sides

E = 360° ÷ 6

E = 60°

The measure of each exterior angle of a regular hexagon ( six sided regular polygon is 60°.

Option C)60° is the correct answer.

Learn more about polygons here: brainly.com/question/22408868

#SPJ2

Answer: (C) 60°

Just took it on edge

Solve for x. (have to add extra letters so the question works)
PLEASE ADD STEPS AND EXPLAIN IT IN ANY WAY POSSIBLE SO I CAN LEARN

Answers

Answer:

x=11°

Step-by-step explanation:

-Sum of angles of a triangle should alway be 180 degrees

35+110+2+3x=180

-Add all known values

147+3x=180

-Subtract 147 from both sides

3x=33

-Isolate x by divind both sides by 3

x=11°

Answer 2 questions about equations A and B.

A. 5x−2+x=x-4
B. 5x+x=x−4


1) How can we get Equation BBB from Equation AAA?
Choose 1 answer:
Choose 1 answer:

(Choice A)
A
Add/subtract a quantity to/from only one side

(Choice B)
B
Add/subtract the same quantity to/from both sides

(Choice C)
C
Rewrite one side (or both) using the distributive property

(Choice D)
D
Rewrite one side (or both) by combining like terms
2) Based on the previous answer, are the equations equivalent? In other words, do they have the same solution?
Choose 1 answer:
Choose 1 answer:

(Choice A)
A
Yes

(Choice B)
B
No

Answers

Step-by-step explanation:

Given that,

Two equations,

A. 5x−2+x=x-4

B. 5x+x=x−4

1.

The RHS of both the equations is same. To make them equal we need to remove the difference.

If we add 2 to the left side of equation A, then we get equation B.

The correct option is (A) i.e. Add/subtract a quantity to/from only one side.

2.

As the equations are not same, they will have different solutions. The answer choice is (b) "No".

Hey There Answer  Add/subtract a quantity to/from only one side

And No

Step-by-step explanation:

can someone answer my question.........​

Answers

Answer:

Rhombus

Energy used

Step-by-step explanation:

A rhombus is formed fromm the intersection, since the stick have equal length, Hence, all the sides will be equal and the opposite side will be parallel.

If a person exercises more and more, more energy is utilized, the dependemt variable here is the amount of energy utilized because it is the measured variable whose value is based on the amount or level of exercise the body is subjected to. The amount of exercise is the dependent variable as it gives influences the amount of energy expended

A sick person takes 10 ml of medicine three times a day how much medicine does the person take in 15 days

Answers

Answer:

450 mL

Step-by-step explanation:

Given that :

Amount in mL of medicine taken at a time = 10mL

Number of times taken per day = 3 times

Amount in mL taken per day = 3 * 10mL = 30mL

Total amount in mL of medicine taken in 15 days :

Amount in mL taken per day * 15 days

= 30mL * 15

= 450mL

The triangle below is isosceles. Find the length of side x in simplest radical form with

a rational denominator.




I really need help :(

Answers

Answer:

Value of x = 3√2 unit

Step-by-step explanation:

Given:

Hypotenuse of given triangle = 6 unit

Length of equal side = x units

Find:

Value of x

Computation:

Using pythagorean theorem

Hypotenuse² = Perpendicular² + Base²

Hypotenuse of given triangle² = Perpendicular² + Base²

6² = x² + x²

36 = 2x²

x² = 36/2

x² = 18

x = √18

x = 3√2

Value of x = 3√2 unit

Find the area of this triangle.
17 cm
10 cm
8 cm
21 cm
A = [ ? ] cm2

Answers

Answer:

84 cm^2

Step-by-step explanation:

8 * 21/2=84

what do i put for y and x , need help asap!!!

Answers

Pick a point on the line and then what ever number is directly across from that point put in the y section. Whatever is directly under or over that point put it in the x
For ex- y = -1 and x = -3

Find the values of a and b that make the second expression equivalent to the first expression. Assume that x > 0 and y ≥ 0.

Answers

Answer:

a= 16

b= 2

Step-by-step explanation:

edge 2021

Answer:

a=16 and b=2

Step-by-step explanation:

next one is B.

Triangle AEB is similar to triangle CBD by ​

Answers

Answer:

SAS

Step-by-step explanation:

25 points ! :)
Can anyone solve this ? with explanation?
[tex]A brick of weight 20N and dimensions 20 cm x1Ocm x Scm is placed once on its largest surface area and then on its smallest surface area on the ground. Find out the ratio of the pressure exerted by the brick.}}[/tex]

Answers

Answer:

1 : 4

Step-by-step explanation:

[tex]Pressure = \frac{F}{A}[/tex]

[tex]P_1 = Pressure \ on \ the \ largest \ surface \ area[/tex]

     [tex]=\frac{F}{20 \times 10 \times 20}[/tex]

[tex]P_2 = Pressure \ on \ small \ surface \ area[/tex]  

      [tex]=\frac{F}{20 \times 10 \times 5}[/tex]

[tex]\frac{P_1 }{P_2 }= \frac{20 \times 10 \times 5}{20 \times 10 \times 20} = \frac{5}{20} = \frac{1}{4}[/tex]          [tex][ \ \ \frac{F}{20 \times 10 \times 20}\ \div\ \frac{F}{20 \times 10 \times 5} => \frac{F}{20 \times 10 \times 20} \times \frac{20 \times 10 \times 5}{F} \ ][/tex]        

Therefore ,

     [tex]P_1 : P_2 = 1 : 4[/tex]

Given :

The dimensions of the brick are :

20 cm

10 cm

5 cm

Solution :

[tex]\large\boxed{\boxed{\mathrm{pressure = \frac{Force}{Area}}}}[/tex]

The largest surface area would be : -

[tex]➢ \: \: 20 \times 10[/tex]

[tex]➢ \: \: 200 \: \: cm {}^{2} [/tex]

[tex]➢ \: \: 0.02\: \: m {}^{2} [/tex]

(product of two greater sides)

pressure applied by greatest surface area of brick :

[tex]➢ \: \: \dfrac{20}{0.02} [/tex]

[tex]➢ \: \: \dfrac{20}{2} \times 100[/tex]

[tex]➢ \: \: 1000 \: \: pascals[/tex]

The smallest surface area would be : -

[tex]➢ \: \: 10 \times 5[/tex]

[tex]➢ \: \: 50 \: \: cm {}^{2} [/tex]

[tex]➢ \: \: 0.005 \: \: m {}^{2} [/tex]

(product of two Smaller sides)

pressure applied by smallest surface area of brick :

[tex]➢ \: \: \dfrac{20}{0.005} [/tex]

[tex]➢ \: \: \dfrac{20}{5} \times 1000[/tex]

[tex]➢ \: \: 4000 \: \: pascals[/tex]

Let's find the ratio :

[tex]➢ \: \: \dfrac{1000}{4000} [/tex]

[tex]➢ \: \: \dfrac{1}{4} [/tex]

[tex]➢ \: \: 1 : 4[/tex]

[tex]\mathrm{✌TeeNForeveR✌}[/tex]

how long is each side of a square with a perimeter of 12.32 centimeters

Answers

Step-by-step explanation:

Let each side of square be x

So, x+x+x+x = 12.32

4x = 12.32

x = 12.32/4

x = 3.02 cm

Find the mode of the data.
Weight (in ounces) of puppies in litter:
17, 15, 19, 18, 17, 16, 22
Mode: [?] oz
Enter

Answers

Mode=17

Step-by-step explanation:

Mode is to find the number which reoccurs/keeps on appearing.

Hope this helps u

Find the different between compound interest payable anually and half anually for a amount Rs14000 at the rate of 12•\•per annum for 2 yrs.​

Answers

Answer:

$113.08

Step-by-step explanation:

The formula for calculating future value:

FV = P (1 + r/m)^mn

FV = Future value  

P = Present value  

R = interest rate  

N = number of years

m = number of compounding

14,000(1.12)^2 =  17,561.60

14,000 ( 1 + 0.12/2)^(2x2) = 17674.68

Difference :  17674.68 -   17,561.60 = $113.08

lines a and b are parallel m<2 = ?°​

Answers

Answer:

50 degrees

Step-by-step explanation:

50 degrees because angle 2 is its vertical angle

6. Find the slope and y-intercept of the line.
y = 7/4x-10

Answers

Answer:

Slope= 7/4

y-intercept = (0, -10)

General Formulas and Concepts:

Algebra I

Coordinates (x, y)

Slope-Intercept Form: y = mx + b

m - slope b - y-intercept

Step-by-step explanation:

Step 1: Define

Identify

y = 7/4x - 10

↓ Compare to y = mx + b

Slope m = 7/4

y-intercept b = -10

Answer:

slope = 7/4

y-intercept = -10

Step-by-step explanation:

slope intercept form :

y = mx + b

m = slope

b = y-intercept

(6x+15)°
63° triangle

Answers

Answer:

x = 2

Step-by-step explanation:

The sum of the 3 angles in the triangle = 180°

Sum the 3 angles and equate to 180

6x + 15 + 90 + 63 = 180

6x + 168 = 180 ( subtract 168 from both sides )

6x = 12 ( divide both sides by 6 )

x = 2

which statement is true regarding the functions on the graph?

Answers

Answer:

where's the graph?

Step-by-step explanation:

Answer:

f(2) = 0 and g(2) = 0

f(2) = g(2) TRUE

b) f(0) = 2 and g(0) = -2

f(0) = g(0) FALSE

c) f(2) = 0 and g(0) = -2

f(2) = g(0) FALSE

d) f(0) = 2 and g(2) = 0

f(0) = g(2) FALSE

Hi guys pls answer this it’s easy tbh

Answers

365 that’s the answer

Answer:

this is the accurate answer of your questions

Simplify Negative two and one-third minus negative ten and one-sixth

Answers

Answer:

7 5/6

Step-by-step explanation:

-2 1/3 - (-10 1/6)

-7/3 + 61/6 (subtract neg = add positive)

-14/6 + 61/6 = 47/6 = 7 5/6

Answer:

[tex]-2\frac{1}{3} - (-10\frac{1}{6} )[/tex]

Minus minus is plus so:

[tex]-2\frac{1}{3} + 10\frac{1}{6} [/tex]

Make improper:

[tex]-\frac{7}{3} + \frac{61}{6} [/tex]

Common denominator:

[tex]-\frac{14}{6} + \frac{61}{6} [/tex]

Equals=

[tex]\frac{47}{6} [/tex]

6x - 5y= 70
7x + 2y=66

I need a answer in words step by step please help!!

Answers

(10,-2) or x=10 , y=-2

Answer:

x = 10

y = -2

Step-by-step explanation:

Elimination method:

6x -  5y = 70 -----------------(I)

7x + 2y = 66 -----------------(II)

Multiply equation (I) by 2 and equation (II) by 5 and add. So, y will be eliminated and you can now find the value of x

(I)*2           12x - 10y  = 140

(II)*5          35x + 10y = 330     {Now add}

                 47x           = 470

                              x = 470/47

x = 10

Plugin x = 10 in equation (II)

7*10 + 2y = 66

70 + 2y = 66

Subtract 70 from both sides

2y = 66 - 70

2y = -4

Divide both sides by 2

y = -4/2

y = - 2

Select the elements in H.
Let H = {cube numbers}

A-8
B-49
C-3
D-125
E-1
F-100
G-25
H-12

Answers

Answer:

H={8,125,1}

Step by step explanation:

8 is the cube of 2125 is the cube of 51 is the cube of 1

13. Which equation represents the line that passes through the point (4,-5) and is
perpendicular to y = 1/2x + 8?

Answers

Answer:

y = - 2x + 3

Step-by-step explanation:

since the line passing through ( 4, - 5 ) is perpendicular to y = 1/2 x + 8, product of the slope of the lines will be - 1.

That is ,

    [tex]m_1 \times m_ 2 = - 1[/tex]       [tex][ \ where \ m_ 1 = \frac{1}{2} \ ][/tex]

   [tex]\frac{1}{2 } \times m_2 = - 1 \\\\m_ 2 = -1 \times 2 = -2[/tex]

Find the equation the line perpendicular to the given line :

[tex]( y - y_2 ) = m_ 2 ( x - x_ 2 ) \ , [ \ where \ (x_2 , y_2 ) = ( 4 , -5 ) \ ][/tex]

[tex]( y - ( -5)) = -2 ( x - 4)\\\\( y + 5 ) = - 2 x + 8\\\\y = -2x + 8 - 5 \\\\y = -2x + 3[/tex]

y <= - 1/3 * x + 2; y > 2x - 3 linear inequalities

Answers

Step-by-step explanation:

Given

Inequalities are [tex]y\leq -\dfrac{1}{3}x+2[/tex] and [tex]y>2x-3[/tex]

Take the inequality as two equations to get the intersection point

[tex]y=-\dfrac{1}{3}x+2\ and\ y=2x-3[/tex]

Equate the value of y

[tex]\Rightarrow -\dfrac{1}{3}x+2=2x-3\\\Rightarrow 5=\dfrac{7x}{3}\\\\\Rightarrow x=\dfrac{15}{7}[/tex]

[tex]\therefore y=1.286[/tex]

The common region gives the required regions for inequalities.

AT&T has a family plan of four lines for $125 and additional lines are $15 each per month. If Jason wants to spend at most $200 per month on cell phone expenses, how many additional lines can he afford? Which inequality represent the given situation. please help for my final​

Answers

Given:

Cost of four lines = $125

Cost of each additional line = $15

Jason wants to spend at most $200 per month on cell phone expenses.

To find:

The inequality for the given situation.

Solution:

Let [tex]x[/tex] be the number of additional line.

Cost of one additional line = $15

Cost of [tex]x[/tex] additional line = [tex]\$15x[/tex]

Total cost = Fixed cost + Addition cost

                = [tex]125+15x[/tex]

It is given that Jason wants to spend at most $200 per month on cell phone expenses. It means the total cost must be less than or equal to 200.

[tex]125+15x\leq 200[/tex]

Therefore, the correct option is C.

Based on your observations, what conclusion can you draw about the lengths of AB DB AE EC

Answers

Answer:

The ratio of AD to DB is equal to the ratio of AE to EC. In other words, the pairs of lengths are proportional.

Step-by-step explanation:

Sample answer from plato

Which choice is equivalent to the product below? √2 x √5 x √8

A. 16√5
B. 4√20
C. 4√5. <-- correct answer
D. 8√10

Answers

[tex]\longrightarrow{\green{ C. \:4 \sqrt{5} }}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex] = \sqrt{2} \times \sqrt{5} \times \sqrt{8} [/tex]

[tex] = \sqrt{2 \times 5 \times 8} [/tex]

[tex] = \sqrt{2 \times 5 \times 2 \times 2 \times 2} [/tex]

[tex] = \sqrt{(2 \times 2) \times (2 \times 2) \times 5} [/tex]

[tex] = \sqrt{ {2}^{2} \times {2}^{2} \times 5} [/tex]

[tex] = \sqrt{ {2}^{2} } \times \sqrt{ {2 }^{2} } \times \sqrt{5} [/tex]

[tex] = 2 \times 2 \sqrt{5} [/tex]

[tex] = 4 \sqrt{5} [/tex]

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}[/tex]

[tex]\sf Q) \sqrt{2} \times \sqrt{5} \times \sqrt{8}[/tex]

[tex]\sf\implies \sqrt{2 \times 5 \times 8}[/tex]

[tex]\sf\implies \sqrt{2 \times 5 \times 2 \times 2 \times 2}[/tex]

[tex]\sf\implies \sqrt{(2 \times 2) \times (2 \times 2) \times 5}[/tex]

[tex]\sf\implies \sqrt{ {2}^{2} \times {2}^{2} \times 5}[/tex]

[tex]\sf\implies \sqrt{ {2}^{2} } \times \sqrt{ {2 }^{2} } \times \sqrt{5}[/tex]

[tex]\sf\implies 2 \times 2 \sqrt{5}[/tex]

[tex]\sf\implies 4 \sqrt{5}[/tex]

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