What is the mass of :

a) 6 X 10²³ atoms of He

b) 6 X 10²³ atoms of Na

c) 6 X 10²³ molecules of nitrogen

d) 6 X 10²⁴ atoms of Cl

e) 1.2 X 10²⁴ atoms of B

f) 1.8 X 10²⁴ atoms of Mg


How many atoms are there in:

a) 7 g of Li

b) 28 g of Si

c) 62 g of S

d) 12 g of Mg

e) 10 g of Ca

f) 200 g of Ne

The pH of the solution when 50.0 mL of a 0.10 M solution of fully protonated glycine (glycine hydrochloride) is titrated with 50.0 mL of 0.10 M NaOH is approximately 8.72.

This is because NaOH is a strong base and will completely neutralize the glycine hydrochloride. To calculate the pH, we can use the equation pH = -log[H3O+], where [H3O+] is the concentration of the hydronium ions in the solution. In this case, the concentration of hydronium ions is equal to the concentration of the NaOH, which is 0.10 M. Taking the negative log of this gives us a pH of 8.72.

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Answer:

If a crystal of a coloured soluble chemical, eg potassium manganate(VII), is placed in water, the particles spread out and mix with the water particles. When the potassium manganate(VII) has dissolved it becomes the solute . The water is the solvent . The mixture that results is the solution .

yes have very good day

the energy is located in this 3-carbon molecule as chemical bonds and thermal energy.

The energy in a 3-carbon molecule can be stored in various ways, depending on the specific molecule and its state. Here are some common places where energy can be stored in a 3-carbon molecule:Chemical Bonds: Energy can be stored in the chemical bonds of the molecule, as a result of the arrangement of the electrons in the molecule. Breaking these bonds releases energy, as the electrons rearrange to form new bonds.Electrons: Energy can also be stored in the arrangement of electrons in the molecule. This can be seen in the electron configuration of the molecule, and the amount of energy stored depends on the distance between the electrons and the nuclei of the atoms.Thermal Energy: The 3-carbon molecule can also store energy in the form of thermal energy, as a result of the movement and vibrations of the atoms in the molecule.Conformational Energy: Energy can also be stored in the 3-carbon molecule due to its conformation, or shape. Changing the shape of the molecule requires energy input, and the energy stored in the new conformation can be released when the molecule returns to its original shape.In conclusion, the energy in a 3-carbon molecule can be stored in various forms, including chemical bonds, electrons, thermal energy, and conformational energy.

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The ratio of the potential energies for the interaction of a water molecule with an Al3+ ion and with a Be2+ ion is 3/2,

The potential energy for the interaction of a dipole with a point charge (ion) is given by:

U = (1/4πε0) [(p · r) / r^3] q

where p is the dipole moment,

r is the distance from the center of the dipole to the ion,

q is the charge of the ion, and

ε0 is the permittivity of free space.

To compare the potential energies for the interaction of a water molecule with an Al3+ ion and with a Be2+ ion, we need to calculate the values of U for each case and then take the ratio:

U(Al3+) / U(Be2+) = [(p · rAl) / rAl^3] qAl / [(p · rBe) / rBe^3] qBe

where rAl and rBe are the distances from the center of the dipole to the Al3+ and Be2+ ions, respectively.

We are given that the center of the dipole is located at rion + 100. pm for both ions. The dipole moment of a water molecule is approximately 6.17 D, or 1.85 × 10^-29 C·m.

The charge of an Al3+ ion is 3+ e, or 3 × 1.602 × 10^-19 C, and the charge of a Be2+ ion is 2+ e, or 2 × 1.602 × 10^-19 C.

Substituting these values and simplifying, we get:

U(Al3+) / U(Be2+) = (3 / 2) (rBe / rAl)^3

We can see that the ratio of the potential energies depends only on the ratio of the distances from the center of the dipole to the ions.

Therefore, if we assume that the distances are equal, i.e. rAl = rBe, we get:

U(Al3+) / U(Be2+) = (3 / 2) (1 / 1)^3 = 3/2

So the ratio of the potential energies for the interaction of a water molecule with an Al3+ ion and with a Be2+ ion is 3/2, if the center of the dipole is located at the same distance from both ions.

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If 3.37 g of hcl is reacted with exc3ss fe and 4.20g of fecl2 then the %yield for the reaction will be 71.56%.

The percent yield for a reaction can be calculated as follows:

% yield = (actual yield / theoretical yield) x 100

First, we need to find the theoretical yield of FeCl2. To do this, we need to determine the number of moles of Fe that reacted with the HCl. The balanced chemical equation for this reaction is:

Fe + 2HCl → FeCl2 + H2

From the given information, we know that 3.37 g of HCl was used in the reaction. We can use the molar mass of HCl (36.46 g/mol) to convert this mass to moles:

3.37 g HCl / 36.46 g/mol = 0.0927 moles HCl

Since two moles of HCl react with one mole of Fe, the number of moles of Fe used in the reaction is half of the number of moles of HCl:

0.0927 moles HCl / 2 = 0.04635 moles Fe

Next, we can use the molar mass of FeCl2 (126.90 g/mol) to determine the theoretical yield of FeCl2:

0.04635 moles FeCl2 x 126.90 g/mol = 5.89 g FeCl2

Finally, we can calculate the percent yield:

% yield = (4.20 g FeCl2 / 5.89 g FeCl2) x 100 = 71.56%

So, the percent yield of FeCl2 in this reaction is 71.56%.

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A commonly used piece of equipment to hold a dissolved substance in water and then place it on a hot plate to drive off the water is a rotary evaporator or a rotovap.

This equipment consists of a flask that holds the solution, a heating bath to control the temperature, a vacuum pump to reduce the pressure, and a rotating mechanism that spins the flask.

The flask is filled with the dissolved substance and water, and the rotation causes the solution to form a thin film on the flask wall. The hot plate heats the solution, causing the water to evaporate, and the vacuum pump removes the resulting water vapor. The reduced pressure helps to lower the boiling point of the water, making it easier to evaporate.

The rotary evaporator is a useful tool in chemical synthesis and purification because it allows for efficient removal of solvents and can be used for large-scale operations. It also helps to maintain a low temperature, which can be important for delicate reactions or to avoid thermal degradation of the substance being purified.

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Yes, the flame test can be used to determine the identity of certain unknowns in a mixture, but it is not a foolproof method and has some limitations.

The flame test is based on the principle that when a metal ion is heated, it will emit light at a characteristic frequency, which results in a unique color. By observing the color of the flame produced by a sample, it is possible to determine the presence of certain metal ions, such as sodium (yellow), potassium (purple), lithium (red), and copper (green).

However, this method has some limitations. The color of the flame produced by a sample may be affected by the presence of other elements in the mixture, which can produce similar colors or interfere with the interpretation of the results. In addition, not all metal ions produce a distinctive color in the flame test, and some elements cannot be detected by this method at all.

Therefore, while the flame test can be a useful tool for identifying certain elements in a mixture, it is not a definitive method and should be used in conjunction with other techniques to confirm the results.

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The corresponding change in pressure in atmospheres is 0.002026 atm

The change in pressure due to the rise of the mercury in a barometer can be calculated by using the formula:

ΔP = ρgh

where,

ΔP = change in pressure

ρ = density of mercury ([tex]13.6 g/cm^3[/tex])

g = acceleration due to gravity ([tex]9.8 m/s^2[/tex])

h = height of the mercury rise in the barometer.

Given that,

The height of the mercury rise = 15.5 cm.

Now convert the pressure from pascals to atmospheres.

1 atm = 101,325 Pa

To find the pressure in atmospheres multiply the pressure in pascals by 1 atm / 101,325 Pa

ΔP = ρgh

ΔP = (13.6 g/cm^3)(9.8 m/s^2)(0.155 m)

ΔP = [tex]205.5 N/m^2[/tex] = 205.5 Pa

Now, to convert the pressure from pascals to atmospheres:

ΔP (in atm) = ΔP (in Pa) / 101,325 Pa/atm

ΔP (in atm) = 205.5 Pa / 101,325 Pa/atm

ΔP (in atm) = 0.002026 atm

So, the corresponding change in pressure in atmospheres is 0.002026 atm

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Answer: Option B

Explanation: Answer B. Traits always show up in at least one offspring is not true.

Answer:

Option B is not true about traits. Traits do not always show up in at least one offspring. The expression of traits in offspring depends on the genetic makeup of the parents and the way their genes interact with each other during inheritance. Some traits may skip generations or not appear in any offspring at all.

Explanation:

Haloarenes have polarized C-X bonds because halogens are more electronegative than carbon. Halogen acquires a tiny negative charge due to its high electronegativity, whereas carbon acquires a slight positive charge by drawing the electron cloud more strongly towards it.

Only one sigma bond is created between one carbon atom and one halogen atom because halogens only require one electron to attain their closest noble gas state.

Dipole moment is a function of the electronegativity differential between halogens and carbon, and as we are aware, when halogen electronegativity drops within a group, so does the dipole moment. Dipole moments between C-Cl and C-F are an exception.

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If a sample of solid nh4hs is put in a closed vessel and allowed to break down until equilibrium is reached, the concentrations of nh3 and h2s are at their equilibrium values, which are 0.011 m.

1.2 x 104 = [NH3][H2S] where [NH3] = [H2S] = square root 1.2 x 10^-4 = 0.011 M

The concentrations of NH3, H2, and N2 are respectively 1.2102, 3.0102, and 1.5102M at equilibrium. In the flask, NH3 and H2S gases are produced as ammonium hydrogen sulphide breaks down. Total pressure in the flask increases to 0.84 atm when the decomposition reaction achieves equilibrium. At this temperature, the equilibrium constant for the breakdown of NH4HS is. Fear not! K=[Lmol]−2=L2mol−2. The equilibrium expression for the reaction N2 + 3H2 2NH3 can be expressed as K [NH3]2/[N2] [H2]3.

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In the mechanism for the acid-catalyzed hydrolysis of an ester, "HB" could refer to a hydrogen bond. Hydrogen bonds are a type of non-covalent interaction that occur between a hydrogen atom that is covalently bonded to one electronegative atom (such as nitrogen or oxygen) and another electronegative atom.

Hydrolysis is a chemical reaction of the interaction of chemicals with water, leading to the decomposition of both the substance and water. Reactions of hydrolysis are possible with salts, carbohydrates, proteins, fats, etc.

In the mechanism for the acid-catalyzed hydrolysis of an ester, hydrogen bonds may play a role in stabilizing the intermediate species that are formed during the reaction. For example, the hydrogen bond may occur between the hydrogen ion (H+) of the acid catalyst and the oxygen atom of the ester molecule. This interaction helps to facilitate the transfer of the hydrogen ion to the ester molecule, leading to the formation of the intermediate species that are involved in the hydrolysis reaction.

Without more information about the specific mechanism you are referring to, it is difficult to say exactly what species is represented by "HB".

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The pH will rise as a result of the addition of NaOH because it will increase the amount of OH- ions in the solution.

The pH of a solution determines whether it is acidic or basic. It is described as the hydrogen ion (H+) concentration in a solution expressed as a negative logarithm.

The formula for the concentration of hydroxide ions can be used to determine how the pH of a solution will change when 0.005 mol of NaOH is added to 0.50 L of the solution (OH-). The pH will rise as a result of the addition of NaOH because it will increase the amount of OH- ions in the solution.

A neutral solution has a pH of 7, while a basic solution has a pH higher than 7. The initial pH and hydrogen ion (H+) concentration of the solution will determine the precise pH change. If the starting solution is acidic, adding NaOH will cause a considerable rise in pH. The pH will only slightly rise if the starting solution is neutral or mildly basic.

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Based on molecular structure, the packing density of fatty acids in a solid state is determined by their shape and size. Cis-oleic acid has a bent shape due to the double bond, whereas lauric acid has a straight shape.

Therefore, lauric acid is likely to pack more closely together in a solid state due to its straight shape. This close packing results in a higher density and a lower melting point compared to cis-oleic acid. In general, straight-chain fatty acids tend to pack more closely together than their bent-chain counterparts, which affects their physical properties.

The molecular structure of a fatty acid affects its ability to pack closely together and form a solid. The two fatty acids, cis-oleic acid and lauric acid, have different structures that will influence their packing behavior. Cis-oleic acid is a cis-unsaturated fatty acid with a double bond in its carbon chain, which creates a kink in the molecule and makes it more difficult for the molecules to pack closely together. Lauric acid, on the other hand, is a saturated fatty acid with a straight, uniform structure that allows for more efficient packing. Based on this information, it can be inferred that lauric acid is more likely to pack more closely together than cis-oleic acid when they form a solid.

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The corresponding value of the entropy is 28.35*10^-23 J/K.

Entropy is the extent of randomness (or disorder) of a system. It may also be notion of as a degree of the strength dispersal of the molecules withinside the system. Microstates are the wide variety of various feasible preparations of molecular role and kinetic strength at a specific thermodynamic state.

The entropy can be calculated as,

S=k ln W

Here, W= number of microstates, K= Boltzmann's constant, the value for k= 1.38 *10^-23 J/K

The microstates are given that are 8.39*10^8

Substituting the values in the above formula,

S =1.38*10^-23 ln (8.39*10^8)

  = 1.38*10^-23 * 20.548

  =28.35*10^-23 J/K

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2.000 g of water was cooled 3.00 °c, 25.104 J heat was transferred to the water.

To calculate the amount of heat transferred to the water, we can use the following formula:

Q = mcΔT

where Q is the amount of heat transferred, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature of the water.

Given that the mass of the water is 2.000 g and the change in temperature is 3.00 °C, we can find the amount of heat transferred as follows:

Q = (2.000 g) x (4.184 J/g·°C) x (3.00 °C)

Q = 25.104 J

Therefore, the amount of heat transferred to the water is 25.104 J.

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Due to nonpolar molecules' ability to reject water molecules, oil and water do not combine. Nonpolar molecules are attracted to polar molecules.

Oil molecules have a non-polar structure. Instead of having a positive and negative end, its charge is uniformly distributed. Accordingly, water and oil never combine because water and oil molecules are more attracted to each other than oil molecules are to each other. In actuality, oils are hydrophobic, or "fearful of water." Oil molecules are repelled by water molecules as opposed to being drawn to them. Because of this, when you add oil to a cup of water, the two don't mix.

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0.2706 moles of carbon dioxide will result from the complete combustion of 4 kg of propane is burned.

Propane (C₃H₈) undergoes complete combustion to produce carbon dioxide (CO₂) and water (H₂O):

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

To calculate the number of moles of CO₂ produced, we first need to find the number of moles of propane that was burned. We can use the equation:

moles = mass / molecular weight

where the molecular weight of propane is 44.1 g/mol.

moles of propane = 4 kg / 44.1 g/mol = 0.0902 moles

Since one mole of propane reacts with 5 moles of oxygen to produce 3 moles of CO₂, the number of moles of CO₂ produced is 3 ₓ 0.0902 moles of propane = 0.2706 moles.

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To weigh approximately 10g of NaCl we can use triple beam balance and to

weigh 10. 1 g of NaCl we can use top loading balance.

Triple-Beam Balance Compared to a top-loading balance, this kind of laboratory balance is less sensitive. Due to the three decades of weights that glide along separately calibrated scales, these balances are known as triple-beam balances. Typically, the three decades are divided into 100g, 10g, and 1g graduations. These scales are appropriate for many weighing applications despite having substantially less readability. We can weigh 10 g with this balance

Top-Loading Balance Another balance that is mostly utilized in laboratories is this one. Typically, they can measure things weighing between 150 and 5000 g. Although they provide less readability than an analytical balance, they enable measurements to be made rapidly, making them a more practical option when precise readings are not required.

Additionally, top-loaders are less expensive than analytical balances. Modern electric top-loading balances provide a digital readout in

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Answer:

Explanation:

The mass of silver that would occupy a volume of 24 cm³ can be calculated using the density formula:

mass = density x volume

At 20 °C, the density of silver is 10.5 g/cm³, so the mass of silver that would occupy a volume of 24 cm³ would be:

mass = 10.5 g/cm³ x 24 cm³ = 252 g

So, the mass of silver that would occupy a volume of 24 cm³ is 252 grams.

209.8J  of heat needed to melt of solid ethanol () and bring it to a temperature of -10°c.

To calculate the amount of heat needed to melt solid ethanol and bring it to a certain temperature, we need to use the specific heat capacity and the heat of fusion of ethanol, as well as the mass of the sample and the temperature change.

The heat required to melt the solid ethanol:

Q1 = [tex]m × ΔH_fusion[/tex] = 1 g × 109 J/g = 109 J

The heat required to raise the temperature of the liquid ethanol from the melting point to -10 °C:

The total heat required is the sum of Q1 and Q2:

Q = Q1 + Q2 = 109 J + 100.8 J = 209.8 J

Therefore, the amount of heat needed to melt 1 gram of solid ethanol and bring it to a temperature of -10 °C is 209.8 J.

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The force on the atom by the point charge will decrease by a factor of 16.

An atom is the smallest unit of matter that can exist. Atoms are composed of protons, neutrons, and electrons, held together by electromagnetic forces. Protons and neutrons are located in the nucleus of the atom, while electrons orbit around the nucleus. Atoms can form molecules when they share electrons, allowing them to bond together. Atoms can also form ions when they gain or lose electrons, altering their electrical charge. All matter is made up of atoms, and atoms can combine to form many different substances. Even though atoms are very small, the structure of atoms is essential to understanding the properties of matter.

This is because the force between two point charges is inversely proportional to the square of the distance between them. Therefore, if the distance is quadrupled, the force will be reduced by a factor of 16 (= 4^2).

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41.4 mol air would be inside the container at the tension determined to a limited extent c.

41.4 mol air would be inside the container at the tension determined to a limited extent c in light of the fact that the strain of the air inside the container is 1 atm. Since the molar mass of air is 28.97 g/mol, the crate would contain 41.4 mol of air at this tension. The molar mass of air is the typical molar mass of the parts of air, which are nitrogen, oxygen, argon, carbon dioxide, and other following gases. In this manner, the number of moles of air inside the container at the tension determined to a limited extent c is equivalent to 41.4 mol.

Computation of tension of the air inside the container.

To ascertain the tension of the air inside the container, the ideal gas regulation condition is utilized which is:

where P is the strain, V is the volume of the container, n is the number of moles of air, R is the all-inclusive gas consistency, and T is the temperature of the crate.

In this manner, the tension of the air inside the container can be determined as follows:

where V and T are the volume and temperature of the container, individually.

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Table 3-2 on page 50 lists various substances that can be tested for reducing sugars in the lab. The positive control for the test for reducing sugars would typically be a known reducing sugar, such as glucose or fructose, while the negative control would typically be a non-reducing sugar, such as sucrose. These controls are used to confirm the reliability and accuracy of the test results.

The positive control will give a positive result for the presence of reducing sugars, while the negative control should give a negative result, indicating the absence of reducing sugars. By comparing the results of these two controls with the results obtained for the unknown substances, the reliability and accuracy of the test can be confirmed.

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A mixture consists of 122 moles of n2, 137 moles of c3h8, and 212 moles of co2 at 200 k in a 75.0 l container. The total pressure of the gas is 2850.89 kilopascals and the partial pressure of CO2 is 1307.48 kilopascals.

The total pressure of a mixture of gases is equal to the sum of the partial pressures of each gas. The partial pressure of a gas is proportional to the number of moles of that gas present in the mixture. In this case, we can use the ideal gas law, PV = nRT, to find the partial pressures.

First, we need to find the molar gas constant R:

R = 8.31 J/mol * K

Next, we need to find the temperature in Kelvin:

T = 200 K

Now, we can calculate the partial pressure of each gas in the mixture:

P N2 = (122 moles . R . T) / (75.0 L) = 122 . 8.31 . 200 / 75.0 = 735.72 kilopascals.

P C3H8 = (137 moles . R . T) / (75.0 L) = 137 . 831 . 200 / 75.0 = 807.69 kilopascals.

P CO2 = (212 moles . R . T) / (75.0 L) = 212 . 831 . 200 / 75.0 = 1307.48 kilopascals.

Finally, we can find the total pressure of the mixture:

Ptotal = P N2 + P C3H8 + P CO2

Ptotal = 735.72  + 807.69 + 1307.48

Ptotal = 2850.89 kilopascals

So, the total pressure of the gas is 2850.89 kilopascals, and the partial pressure of CO2 is P CO2 = 1307.48 kilopascals.

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The theoretical density of iron that has a bs=cc crystal structure, an  atomic radius of 0.124 nm, and an atomic weight of 55.85 g/mol is 7.87 [tex]g/cm^3.[/tex].

To compute the theoretical density of iron with a bcc crystal structure, we can use the formula:

density = (Z × M) / ([tex]a^3[/tex] × N_A)

where Z is the number of atoms per unit cell, M is the molar mass of the element (55.85 g/mol for iron), a is the lattice parameter, which is related to the atomic radius (a = 4√(2) × r/3 for bcc structure), and N_A is Avogadro's constant (6.022 × [tex]10^23 mol^-1).[/tex]

Substituting the given values, we get:

a = 4√(2) × r/3 = 4√(2) × 0.124 nm × (1 m / [tex]10^9[/tex] nm) / 3 = 0.287 nm

density = (2 × 55.85 g/mol) / (0.287 nm)^3 / (6.022 × [tex]10^23[/tex] mol^-1) = 7.87 g/cm^3

Therefore, the theoretical density of iron with a bcc crystal structure, an atomic radius of 0.124 nm, and an atomic weight of 55.85 g/mol is 7.87 [tex]g/cm^3.[/tex].

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The rapid destruction of tropical rain forests is harmful because it reduces habitats for animals and plants, leading to a decrease in biodiversity.

It can also cause climate change due to reduced carbon absorption and an increase in heat-trapping greenhouse gases, resulting in more extreme weather patterns.  The destruction of tropical rain forests is a serious concern, with millions of acres destroyed worldwide each year. This destruction can be attributed to many causes, such as illegal logging, wildfires, over-farming and over-grazing. As a result, essential services and resources provided by the forests, such as clean water and soil health, are diminished. Additionally, the trees themselves can store large amounts of carbon, which is released into the atmosphere when they are burned or cut down. This further contributes to climate change, as carbon dioxide is a major heat-trapping greenhouse gas. Furthermore, deforestation reduces the habitats of many animals, leading to a decrease in biodiversity.

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35.3 L volume of  gas at stp would be needed for the complete combustion of 10 g of octane

The volume of oxygen gas needed for the complete combustion of 10 g of octane is 35.3 L at STP.

The chemical equation for the complete combustion of octane (C8H18) is:

2C8H18 + 25O2 -> 16CO2 + 18H2O

From the equation, we can see that for every one mole of octane burned, 25 moles of oxygen are needed. The number of moles of octane can be calculated using its molecular weight (114 g/mol) and the given mass: 10 g / 114 g/mol = 0.087 moles.

Using the stoichiometry of the reaction, we can calculate the number of moles of oxygen needed: 0.087 moles x 25 moles O2/mole C8H18 = 2.18 moles of O2.

Finally, we can convert the number of moles of oxygen to volume at STP (Standard Temperature and Pressure: 0°C and 1 atm): 2.18 moles x 22.4 L/mole = 35.3 l

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The density of 1 mole of carbon dioxide in 11.2 litres at Standard Temperature and Pressure (STP) is 1.984 grams per litre.

How do you find the density?

The density of a gas is equal to its mass divided by its volume. If we know the density of the gas, we can calculate the molar mass of the substance. Density varies with temperature and pressure. The formula D = M/V is used in STP, where M equals the molar mass and V is the molar volume of the gas (22.4 liters/mol).

This density is calculated by dividing the molar mass of carbon dioxide by the molar volume of any gas at STP .

Here,

D = M/V

D = 44.01  /22.4

D =  1.984 grams per litre

Therefore, The density of 1 mole of carbon dioxide in 11.2 litres at Standard Temperature and Pressure (STP) is 1.984 grams per litre.

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In order to separate magnesium metal from benzoic acid, a process of ionic precipitation was used.

In this process, a solution containing magnesium ions was added to a benzoic acid solution and a precipitate of magnesium benzoate was formed, which was then filtered out. In order to separate magnesium metal from benzoic acid, a process of ionic precipitation was used.The magnesium benzoate was then heated, which caused it to decompose into magnesium oxide and benzoic acid, and the pure magnesium oxide was then extracted. The extracted magnesium oxide was then reduced in temperature and passed through a current of hydrogen to form pure magnesium metal.

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