What is the mass of a 5 kg bag of flour on the moon?

Answers

Answer 1

Answer:

mass = 5 [kg]

Explanation:

The difference between weight and mass should be clarified, the weight is equal to the product of the mass by the gravity of the place. While the mass will always be conserved regardless of the place, it will never change.

weight = mass * gravity of the place

}Therefore the mass is the same in the earth as in the moon


Related Questions

corona virus vaccine​

Answers

Answer:

BIOFLU TABLET

Explanation:

PAG MAY LAGNAT UBO IBIOFLU NAYAN

Answer:

Antibodies are the answer.

Explanation:

Many companies are adding antibodies to ring a bell in the cells to tell the white blood cells to be able to notice the Corona Virus in the blood stream.

Before Collision Consider a system to be one train car moving toward another train car at rest When the train cars collide, the two cars stick together What is the total momentum of the system after the collision? O 800 kg . m/s m, = 600 kg V,= 4 m/s m = 400 kg v2 = 0 m/s 1,600 kg. m/s 0 2,400 kg • m/s 0 4,000 kg . m/s After Collision ​

Answers

Answer:

2,400kg * m/s

Explanation:

You are missing some information in the question but the rest could be found some where else.

The question gives the masses and starting velocity of each car.

Car 1: m = 600kg and sv = 4m/s

Car 2: m 400kg and sv = 0m/s

Find the momentum of both cars.

Car 1: 600 * 4 = 2400

Car 2: 400 * 0 = 0

Add both.

2400 + 0 = 2400

Best of Luck!

Answer: answer C

Explanation:

Your welcome

The superhero Green Lantern steps from the top of a tall building. He falls freely from rest to the ground, falling half the total distance to the ground during the last 1.00 s of his fall (Fig. 2.30). What is the height h of the building?

SOLUTION GUIDE

IDENTIFY and SET UP

1. You’re told that Green Lantern falls freely from rest. What does this imply about his acceleration? About his initial velocity?

2. Choose the direction of the positive y -axis. It’s easiest to make the same choice we used for freely falling objects in Section 2.5.

3. You can divide Green Lantern’s fall into two parts: from the top of the building to the halfway point and from the halfway point to the ground. You know that the second part of the fall lasts 1.00 s. Decide what you would need to know about Green Lantern’s motion at the halfway point in order to solve for the target variable h. Then choose two equations, one for the first part of the fall and one for the second part, that you’ll use together to find an expression for h. (There are several pairs of equations that you could choose.)

EXECUTE

4. Use your two equations to solve for the height h. Heights are always positive numbers, so your answer should be positive.

Answers

Answer:

1) its initial velocity is zero, 2) the downward direction as positive

3) h = 25.66 m

Explanation:

This is a free fall exercise.

1) with falls, its initial velocity is zero and the acceleration is constant throughout the path and is equal to the acceleration due to gravity.

2) a widely used selection to estimate the downward direction as positive

3) We know that for the second part of the fall

         y₀ -y = h/2   at  t = 1 s

        y = y₀ + v₁ t + ½ g t²

where v₁ is the initial velocity of this interval at the point y = h / 2

        v₁ t = (y -y₀) - ½ g t²

        v₁ = h / 2 - ½ g t²

        v₁ = h/2 - g/2

now let's write the equation for the first interval

         v₁² = v₀² + 2 g (y₁ - y₀)

       in this interval v₀ = 0

         v₁² = 2 g (y₁ -y₀)

         v₁² = 2g h/2

we write our system of equations

           v₁² = (h/2 - g/2)²

           v₁² = (2g h / 2)

       

           (h /2 - g/2)² = (2g h / 2)

            h² / 4 - 2  g/2  h/2 + (g/2)² = g h

            h² / 4 - g h/2 - g h + g²/4 = 0

            h² - 3 g h + g² =0              

            h² - 29.4 h +96.04 = 0

we solve the quadratic equation

            h = [29.4 ±√ (29.4² - 4 96.04)] / 2

            h = [29.4 ± 21.91] / 2

            h₁ = 25.66 m

            h₂ = 3.75 m

As the system takes more than 1 S to fall, the correct answer for the height is h = 25.66 m

Answer 1)

This is a free fall exercise with falls, its initial velocity is zero and the acceleration is constant throughout the path and is equal to the acceleration due to gravity.

Answer B :

A widely used selection to estimate the downward direction as positive.

Answer 3:

We know that for the second part of the fall:

        y₀ -y = h/2   at  t = 1 s

       y = y₀ + v₁ t + ½ g t²

where v₁ is the initial velocity of this interval at the point

       y = h / 2

       v₁ t = (y -y₀) - ½ g t²

       v₁ = h / 2 - ½ g t²

       v₁ = h/2 - g/2

Answer 4:

Now let's write the equation for the first interval

        v₁² = v₀² + 2 g (y₁ - y₀)

      in this interval v₀ = 0

        v₁² = 2 g (y₁ -y₀)

        v₁² = 2g h/2

we write our system of equations

          v₁² = (h/2 - g/2)²

          v₁² = (2g h / 2)

          (h /2 - g/2)² = (2g h / 2)

           h² / 4 - 2  g/2  h/2 + (g/2)² = g h

           h² / 4 - g h/2 - g h + g²/4 = 0

           h² - 3 g h + g² =0              

           h² - 29.4 h +96.04 = 0

we solve the quadratic equation

           h = [29.4 ±√ (29.4² - 4 96.04)] / 2

           h = [29.4 ± 21.91] / 2

           h₁ = 25.66 m

           h₂ = 3.75 m

As the height is h = 25.66 m.

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Which statement best compares the accelerations of two objects in free fall?
O The heavier object has a greater acceleration.
O The object that has the greater surface area has the lower acceleration.
O The object that has the smaller mass has the greater acceleration.
O The objects have the same acceleration,

Answers

Answer:

D) The objects have the same acceleration. With no air resistance and the same gravity, the acceleration due to gravity should be the same for both objects.

Answer:

b

Explanation:

A parallel plate capacitor contains a positively charged plate on the left, and a negatively charged plate on the right. An electron in between the plates is moving to the right. Which statement is true? Group of answer choices The potential energy of the electron is decreasing and it is moving to a region having a higher potential The potential energy of the electron is decreasing and it is moving to a region having a lower potential. The potential energy of the electron is increasing and it is moving to a region having a lower potential The potential energy of the electron is increasing and it is moving to a region having a higher potential.

Answers

Complete Question

A parallel plate capacitor contains a positively charged plate on the left, and a negatively charged plate on the right. An electron in between the plates is moving to the right. Which statement is true?

Group of answer choices

a The potential energy of the electron is decreasing and it is moving to a region having a higher potential

b The potential energy of the electron is decreasing and it is moving to a region having a lower potential.

c The potential energy of the electron is increasing and it is moving to a region having a lower potential

d  The potential energy of the electron is increasing and it is moving to a region having a higher potential.  

Answer:

The correct option is  C

Explanation:

From the question we are told that

  An electron in between the plates is moving to the right

Generally the potential energy of the electron is mathematically represented as  

          [tex]PE  =  e *  V[/tex]

Here  e is the charge on the electron and  V  is the electric potential of the electron

Generally the left side with the positive charge has a higher potential than the right side with the negative  charge

Now when the potential energy of the electron increases it will move toward the plate with the lower potential  which is the left plate

   

       

A chemical symbol is to an element as a chemical formula is to a(n)

Answers

A subscript is the answer

PLS HELP THIS IS FOR AN EXAM!!!
How many exercises encompass stretching in the human body
A) eight
B) too many to count
C) that depends on each individual
D) none​

Answers

Answer: (B) Too many to count

Explanation: Have a wonderful day everyone! :D

The exercises that encompasses stretching in the human body is : B) too many to count

Meaning of exercise

exercises can be defined as any activity that puts your muscle to work and helps burn calories in your body.

exercises are one of the keys to staying and living healthy.

exercises are of different types and forms and some encompasses stretching in the human body.

In conclusion, The exercises that encompasses stretching in the human body is too many to count

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A small truck has a mass of 2145 kg. How much work is required to decrease the speed of the vehicle from 25.0 m/s to 12.0 m/s on a level road?

Answers

Answer:

The work required is -515,872.5 J

Explanation:

Work is defined in physics as the force that is applied to a body to move it from one point to another.

The total work W done on an object to move from one position A to another B is equal to the change in the kinetic energy of the object. That is, work is also defined as the change in the kinetic energy of an object.

Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:

[tex]Ec=\frac{1}{2} *m*v^{2}[/tex]

where kinetic energy is measured in Joules (J), mass in kilograms (kg), and velocity in meters per second (m/s).

The work (W) of this force is equal to the difference between the final value and the initial value of the kinetic energy of the particle:

[tex]W=\frac{1}{2} *m*v2^{2}-\frac{1}{2} *m*v1^{2}[/tex]

[tex]W=\frac{1}{2} *m*(v2^{2}-v1^{2})[/tex]

In this case:

W=?m= 2,145 kgv2= 12 [tex]\frac{m}{s}[/tex]v1= 25 [tex]\frac{m}{s}[/tex]

Replacing:

[tex]W=\frac{1}{2} *2145 kg*((12\frac{m}{s} )^{2}-(25\frac{m}{s} )^{2})[/tex]

W= -515,872.5 J

The work required is -515,872.5 J

The amount of work needed by the vehicle to decrease its speed from 25 m/s to 12 m/s is 515872.5 J.

The amount of work required by the truck to decrease its speed can be calculated using the formula below.

Formula:

W = m(u²-v²)/2............. Equation 1

Where:

W = amount of work required to decrease the speed of the vehicle.m = mass of the truckv = Final speedu = initial speed.

From the question,

Given:

m = 2145 kgv = 12 m/su = 25 m/s.

Substitute these values into equation 1

W = 2145(25²-12²)²/2W = 2145(481)/2W = 515872.5 J.

Hence, The amount of work needed by the vehicle to decrease its speed from 25 m/s to 12 m/s is 515872.5 J.

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Oil is a powerful source of energy used for cars, machines, and many other purposes. While studying sources of energy that could replace the use of oil, a student thinks about solar power, wind power, nuclear power, and electric batteries. The students asks, "Which type of source will waste the least energy and provide the most energy in all situations?" Which best describes why a scientist would ask a different question than this one?

The question asks about subjective personal preferences regarding energy.

The question focuses on the objective measurements of amounts of energy.

The question has too wide of a focus, as though all situations can be studied at once.

The question is focused on the future and finding new answers about changing needs.

Answers

Answer:

The question has too wide of a focus, as though all situations can be studied at once

Explanation:

I took the test

Answer:

The question has too wide of a focus, as though all situations can be studied at once

Explanation:

i took ed test

Invisible fence for dogs. In this type of system, a wire is buried under the surface and a current at a given frequency passes through the wire. The dog wears a small unit made of a pickup coil and electronics that delivers a short high-voltage pulse to the dog through a couple of electrodes pressed against its skin. The pulse is not harmful, but it does provide a correction that encourages the dog to keep away. In an invisible fence, the wire carries a 10kHz sinusoidal current with an amplitude of 0.5 Amps. The dog carries a sensoron its collar made as a coil with 150 turns and 30 mm in diameter.If the detection level at the coil inside the collar is set at 200 μV RMS (i.e., the level at which the dog will receive a correction pulse), what is the furthest distance from the wire the dog will "feel" the presence of the fence?

Answers

Answer:

The distance is  [tex] s =  2.3 \  m [/tex]

Explanation:

From the question we are told that

   The  frequency of the current is  [tex]f =  10\ kHz  = 10 *10^{3} \  Hz[/tex]

   The magnitude of the  current  is  [tex]I_o  =  0.5\ Amps[/tex]

     The number of turns is  [tex]N =  150\  turns[/tex]

     The  diameter is  [tex]d =  30 mm  = 0.03 \ m[/tex]

      The detection level is  [tex]V_{rms}  =  200 \mu V  =  200 * 10^{-6} \  V[/tex]

Generally the radius is mathematically represented as

      [tex]r =  \frac{d}{2}[/tex]

=>    [tex]r =  \frac{0.03}{2}[/tex]

=>      [tex]r 0.015 \ m [/tex]

Generally the magnetic field  generated by the fence is mathematically represented as

      [tex]B  =  \frac{\mu_o *  N * I}{2 *  \pi * s}[/tex]

Here s is the point where the do will feel the magnetic field

      [tex]\mu_o[/tex] is the permeability of free space with value  [tex]\mu_o =   4\pi * 10^{-7} N/A^2 [/tex]    

   So

         [tex]B  =  \frac{ 4\pi * 10^{-7}  *  150 *  I}{2 * 3.142  * s}[/tex]

Generally the magnetic flux is mathematically represented as

     [tex]\Phi =  B *  \pi * r^2[/tex]

=>   [tex]\Phi =   \frac{ 4\pi * 10^{-7}  *  150 * I}{2 * 3.142  * s} *  \pi * r^2[/tex]

=>   [tex]\Phi  =  \frac{2.121 *10^{-8} *  I }{s}[/tex]

Generally the induced emf is mathematically represented as

      [tex]\epsilon  =- \frac{d \Phi}{dt}[/tex]

=>    [tex]\epsilon  =- \frac{ 2.121 *10^{-8} }{ s } *  \frac{d I}{dt}[/tex]

Generally the angular frequency is mathematically represented as

   [tex]w =  2 \pi f[/tex]

=>        [tex]w =  2 *  10*10^{3} \pi [/tex]

=>       [tex]w =  20000 \pi [/tex]

So the current is mathematically represented as

        [tex]I = I_o sin (wt)[/tex]

=>     [tex]I = I_o sin ( 20000 \pi * t)[/tex]

So

  [tex]\epsilon  =- \frac{ 2.121 *10^{-8} }{ s } *  \frac{d [ I_o sin ( 20000 \pi * t)]}{dt}[/tex]

  [tex]\epsilon  =- \frac{ 2.121 *10^{-8} }{ s } *  I_o * 20000 \pi   [  cos ( 20000 \pi * t) [/tex]  

   [tex]\epsilon  =- \frac{ 2.121 *10^{-8} }{ s } * 0.5 * 20000 \pi   [  cos ( 20000 \pi * t) [/tex]    

    [tex]\epsilon  =- \frac{ 6.6*10^{-4} }{ s } [  cos ( 20000 \pi * t) [/tex]  

Here the  

    [tex]\epsilon_{rms} = \frac{ \frac{ 6.6*10^{-4} }{ s }}{\sqrt{2} }[/tex]

=>     [tex]\epsilon_{rms} = \frac{ 6.6*10^{-4} }{ s\sqrt{2}  }[/tex]

But from the question we are told that  [tex]V_{rms}  =  200 \mu V  =  200 * 10^{-6} \  V[/tex]

So

    [tex]\frac{ 6.6*10^{-4} }{ s\sqrt{2}  } = 200 * 10^{-6}[/tex]

=>  [tex]6.6*10^{-4}= 2.8284 *10^{-4} * s[/tex]

=>  [tex] s =  2.3 \  m [/tex]

Convert 0.00389 seconds into Scientific Notation

Answers

Answer:

3.89*10^3

Explanation:

The Scientific notation of the question 0.00389 is 3.89*10^3 ( which is 3 point Eighty Nine Multiply ( Multiply sign " * " ) Ten with raising power (this sign is used normally to write power ^ ) Three).

What is the purpose of a free body diagram?
CO
to show the velocity of an object
to show the acceleration of an object
to show the forces acting on an object
to show the direction of motion vectors of an object

Answers

Answer:

i think the answer is c

Explanation:

zrrxtcyvjvugugyctcyvjv

A free body diagram consists of a diagrammatic representation of a single body or a subsystem of bodies isolated from its surroundings showing all the forces acting on it.

What is free body ?

"A body is said to be "free" when it is singled out from other bodies for the purposes of dynamic or static analysis." The object does not have to be "free" in the sense of being unforced, and it may or may not be in a state of equilibrium; rather, it is not fixed in place and is thus "free" to move in response to forces and torques it may experience.

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If you push on an object that has a mass of 400 kg and it accelerates at 4 m/s2, what would the acceleration (a) be if the mass was reduced to 1/4 as much?

(Hint: Instead of plugging 400 kg into the equation, plug 100 kg into the equation as the mass but keep the force at 1,600 N.)

a
1/4 m/s2

b
16 m/s2

c
8 m/s2

d
4 m/s2

Answers

Answer:

b  16 m/s².

Explanation:

Hello.

In this case, the force exerted to the mass of 400 kg at an acceleration of 4 m/s² is:

[tex]F=400kg*4m/s^2=1600N[/tex]

Now, since the mass is decreased to 100 kg (1/4 of 400 kg), and the force remain the same, the new acceleration should be:

[tex]a=\frac{F}{m}=\frac{1600kg*m/s^2}{100kg}\\ \\a=16m/s^2[/tex]

Thus, the answer is b  16 m/s².

Best regards.

How do waves transfer energy? Be detailed.

Answers

Answer:

Electromagnetic waves transfer energy through vibrations of electric and in magnetic fields. For sound waves the energy is transferred through the vibration of air particles or particles of a solid. Waves also carry energy, the amount of energy they carry depends on their frequency and their amplitude. The more energy and the higher frequency amplitude, the more energy waves are ^‿^

True or false- Lightning, sound, and thermal are three types of energy.

Answers

Answer:

It is true but there are more types of energy

A barometer accidentally contains 6.5 inches of water on top of the mercury column (so there is also water vapor instead of a vacuum at the top of the barometer). On a day when the temperature is 70oF, the mercury column height is 28.35 inches (corrected for thermal expansion). (a) Determine the barometric pressure in psia. If the ambient temperature increased to 85oF and the barometric pressure did not change, (b) would the mercury column be longer, be shorter, or remain the same length

Answers

Answer:

(a). 14.4 lbf/in^2.

(b). 27.8 in, AS THE TEMPERATURE INCREASES, THE LENGTH OF MERCURY DECREASES.

Explanation:

So, from the question above we are given the following parameters which are going to help us in solving this particular Question;

=> The "barometer accidentally contains 6.5 inches of water on top of the mercury column (so there is also water vapor instead of a vacuum at the top of the barometer)"

=> "On a day when the temperature is 70oF, the mercury column height is 28.35 inches (corrected for thermal expansion)."

With these knowledge, let us delve right into the solution;

(a). The barometric pressure = water vapor pressure + acceleration due to gravity (ft/s^2) × water density(slug/ft^3) × {ft/12 in}^3 × [ height of mercury column + specific gravity of mercury × height of water column].

The barometric pressure= 0.363 + {(62.146) ÷ (12^3) × 390.6425}. = 14.4 lbf/in^2.

(b). { (13.55 × length of mercury) + 6.5 } × (62.15÷ 12^3) = 14.4 - 0.603.

Length of mercury = 27.8 in.

AS THE TEMPERATURE INCREASES, THE LENGTH OF MERCURY DECREASES.

The current in the wires of a circuit is 180.0 milliamps. If the resistance of the circuit were doubled ( with no change in voltage), then its new current would be

Answers

Answer:

I = 0.09[amp] or 90 [milliamps]

Explanation:

To solve this problem we must use ohm's law, which tells us that the voltage is equal to the product of the voltage by the current.

V = I*R

where:

V = voltage [V]

I = current [amp]

R = resistance [ohm]

Now, we replace the values of the first current into the equation

V = 180*10^-3 * R

V = 0.18*R (1)

Then we have that the resistance is doubled so we have this new equation:

V = I*(2R) (2)

The voltage remains constant therefore 1 and 2 are equals and we can obtain the current value.

V = V

0.18*R = I*2*R

I = 0.09[amp] or 90 [milliamps]

A wind tunnel draws atmospheric air at 20°C and 101.3 kPa by a large fan located near the exit of the tunnel. If the air velocity in the tunnel is 80 m/s, determine the pressure in the tunnel.

Answers

Answer:

The pressure in the tunnel is 97.45 kPa

Explanation:

Given;

atmospheric pressure, P₁ = 101.3 kPa

air velocity in the tunnel, v₂ = 80 m/s

density of air at 20°C, ρ = 1.204 kg/m³

pressure in the tunnel, P₂ = ?

Apply Bernoulli's equation;

P₁ + ¹/₂ρv₁² + ρgz₁ = P₂ + ¹/₂ρv₂² + ρgz₂

v₁ = 0

z₁ = z₂ = 0

P₁ = P₂ + ¹/₂ρv₂²

P₂ = P₁ - ¹/₂ρv₂²

P₂ = 101.3 kPa - (0.5 x 1.204 x 80²)

P₂ = 101.3 kPa - 3.8528 kPa

P₂ = 97.45 kPa

Therefore, the pressure in the tunnel is 97.45 kPa

Consider a pair of charged particles, particles 1 and 2, separated by a distance r. 6) Which options below are true? [Enter your answer as a string of the letter options you believe are correct. For instance, if you think options A, D, and E are correct, then enter "ADE"] A) Particle 2's electric field contributes to the electric force on particle 1. B) Particle 1's electric field does not contribute to the electric force on particle 1. C) If particle 2 were removed, there would still be a non-zero electric field at its location. D) If particle 2's distance from particle 1 is tripled, particle 1's electric field at 2's new location is no different than before since the field does not depend on the the properties of particle 2. E) None of the above

Answers

Answer:

A, B and C

Explanation:

Option A is correct because, the force on particle 1 depends on the electric field due to particle 2. Since the electric field due to particle 2 is the force per unit charge acting at the point of particle 1, the force at the point of particle 1 is the product of that electric field due to particle 2 and the charge on particle 1. So, Particle 2's electric field contributes to the electric force on particle 1.

Option B is correct because the force on a charge can only be exerted due to an external electric field. So, Particle 1's electric field does not contribute to the electric force on particle 1

Option C is correct since an electric field is always present in the region surrounding a charge irrespective of whether there is a charge in the region of the electric field or not. So, If particle 2 were removed, there would still be a non-zero electric field at its location.


What is the equivalent temperature in kelvin if you have a metal at 50°F?
A.
50 K
B.
150 K
C.
283 K
D.
300 K

Answers

Answer:

The answer is C 283 kelvin

Answer: C.

283 K

Explanation: edmentum

(QUICK THIS IS DUE IN FIVE MINUTES) Please select A, B, or C

Answers

Answer:

a

Explanation:

Answer:

A

Explanation:

In the early 1900s, Robert Millikan used small charged droplets of oil, suspended in an electric field, to make the first quantitative measurements of the electron’s charge. A 0.71-um-diameter droplet of oil, having a charge of , is suspended in midair between two horizontal plates of a parallel-plate capacitor. The upward electric force on the droplet is exactly balanced by the downward force of gravity. The oil has a density of 860 kg/m^3 , and the capacitor plates are 4.5 mm apart.

Part A
What must the potential difference between the plates be to hold the droplet in equilibrium?
Express your answer to two significant figures and include the appropriate units

ΔV=

Answers

Answer:

The potential difference is   [tex]\Delta V  =  44.40 \  V [/tex]

Explanation:

From the question we are told that

   The diameter of the droplet of oil is [tex]d =  0.71 \mu m  =  0.71 *10^{-6} \ m[/tex]

    The density of the oil is  [tex]\rho =  860 kg/m^3[/tex]

    The distance of separation of the capacitor plate is  [tex]l  = 4.5 \ mm =  0.0045 \  m[/tex]

Generally the radius of the droplet is mathematically represented as

       [tex]r = \frac{d}{2}[/tex]

=>      [tex]r = \frac{0.71 *10^{-6} }{2}[/tex]

=>      [tex]r = 3.55 *0^{-7} \  m[/tex]

Generally the mass of  the oil droplet is mathematically represented as

       [tex]m  =  \rho  *  V[/tex]

Here  V  is the volume of the oil droplet which is mathematically represented as

      [tex]V  =  \frac{4}{3} * 3.142 * (3.55 *0^{-7} )^3[/tex]

       [tex]V  =  1.874 *10^{-19} \  m^3[/tex]

So

       [tex]m  =  860  *  1.874 *10^{-19} [/tex]

=>    [tex]m  =  1.611 *10^{-16} \  kg [/tex]

Generally the electric force acting on the droplet is mathematically represented as  

       [tex]F  =  E  *  q[/tex]

Here q is the charge on an electron with value  [tex]q =  1.60*10^{-19}\ C[/tex]

This force is equivalent to the weight of the droplet which is mathematically represented as

        [tex]W =  mg[/tex]

So

       [tex]E *  q =  m *  g[/tex]

Here E is the electric field which is mathematically represented as

    [tex]E =  \frac{\Delta V}{l}[/tex]

      [tex]\frac{\Delta V}{l}  *  q =  m *  g[/tex]

=>    [tex]\Delta V  =  \frac{m *  g  *  l }{q}[/tex]

=>    [tex]\Delta V  =  \frac{1.611 *10^{-16}  *  9.8   *  0.0045 }{1.60*10^{-19}}[/tex]

=>    [tex]\Delta V  =  44.40 \  V [/tex]

what’s the answer?? middle question

Answers

The new volume = 3 x 52.6 that’s because as the pressure decreases by 1/3 the volume increases x3

-Cesar the monkey observed the swinging behaviors of his parents. He is now able to swing from branch to branch after much practice. The observation of his parents swinging and practicing what he saw mainly involved _____ neurons; the neurons that are the basis of
Motor
Mirror
Sensory
Reticular

Answers


The 3rd one I think . I did something similar a while ago

The observation of his parents swinging and practicing what he saw mainly involved sensory neurons.

There are five senses in the human body, they are;

SightSmellTouch TasteHearing

Information is passed to the central nervous system (CNS) from each of these senses.

The neurons that convey sensory information of sight, smell, touch, taste and hearing to the brain are called sensory neurons.

Thus, the observation of his parents swinging and practicing what he saw mainly involved  sensory neurons.

Learn more: https://brainly.com/question/9911075

Sheba is texting and driving. She does not see the baby chinchila
sitting in the road! If she was traveling at 35 m/s, and at best her
car can accelerate at -3.5 m/p/s, how far would it take her to stop?

Answers

Answer:

dfmwekognjioq 4eijqgi24gno3p2qtijoq2 gjo23ijgto32tneqew gqewkgnoweqgmnlqwe gwjoegkqwji4toqn34goti34

Explanation:

please please please please ​

Answers

Answer:

....................

Answer:

20

Explanation:

40/2.0=20.......

hope it helps


What happens to the acceleration of a ball if the force increases while the mass remains the same?

Answers

Answer:

if the force increases while the mass of the ball remains the same, the acceleration increases.

Explanation:

According to Newton's second law of motion, the acceleration of an object produced by a net force is directly proportional to the magnitude of the net force Fn and inversely proportional to the mass of the object m.

[tex]\displaystyle a=\frac{Fn}{m}[/tex]

Suppose the net force doubles to 2Fn. The new acceleration will be:

[tex]\displaystyle a'=\frac{2Fn}{m}=2\frac{Fn}{m}=2a[/tex]

The acceleration doubles too. Thus, if the force increases while the mass of the ball remains the same, the acceleration increases.

Consider the data table charting the speed of a toy car moving across the floor. The line graph representing this data would BEST be described as a?
A) Curved line with varying slope
B) Diagonal line with a slope of 3
C) Horizontal line with a slope of 3
D) Diagonal line with varying slope, from 3 to 4​

Answers

Answer:

The answer is D) diagonal line with varying slope, from 3 to 5 on USATestprep

Explanation:

When using the superposition theorem on a two-source network, if the current produced by one source is in one direction, while that produced by the other source is in the opposite direction through the same resistor Select one: A. a mistake in the sign of the result occurred. B. the resulting current is the difference of the two and has the direction of the larger current. C. all voltage sources were not properly converted to current sources. D. the absolute values of the two currents add algebraically, and the direction is the same as the direction of the larger current.

Answers

Answer: B. The resulting current is the difference of the two and has the direction of the larger current.

Explanation: Superposition Theorem states that the result in a particular branch of a linear circuit when a variety of sources are acting at the same time equals the sum of the response of each particular source acting at a time, i.e., if sources are acting on a line circuit, the resulting current in any branch is the sum of all the currents produced if each source is producing it by itself.

To solve by this method:

1) Find current in a particular branch considering one only independent source and deactivating the others;

2) Repeat the first step for all the sources in the circuit;

3) Add all the results: If the current obtained is in the same direction, add them; If it's in the opposite direction, subtract them and obtain the net current;

Therefore, when using superposition, if one current is in one direction and the other produced by other source is in the opposite direction, the net current is the difference between the two abd has the direction of the larger current.

A 30.0 g object fell from a height y = 2.94 m. It’s velocity when y is zero is approximately equal to (in m/s) (a) 0 (b) 19.6 (c) 29.4 (d) 8.64

Answers

Analysing the question:

We are given:

mass of object (m) = 0.03 kg

height of object (h) = 2.94 m

acceleration due to gravity (a) = 10 m/s²

initial velocity (u) = 0 m/s [the object fell, we are NOT given any initial velocity]

final velocity (v) = v m/s

Solving for Final velocity:

from the third equation of motion:

v² - u² = 2ah

replacing the variables

(v)² - (0)² = 2(10)(2.94)

v² = 58.8

v = 7.67 m/s

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