Calculating for mass given moles:
Generally: [tex]n=\frac{n}{M} }[/tex]
n= molesm= massM or MM = molar massRearranging the equation we get:
[tex]m=nM[/tex]
1. Finding the molar mass of a compound
is the sum of the molar masses of each element respective to the coefficients and subscriptsMM of CH4:[tex]1(12.0g/mol) +4(1.01g/mol) = 16.05g/mol[/tex]
2. Insert the known values and solve
[tex]m=(0.10mol)(16.05g/mol)[/tex]
[tex]m=1.60 g[/tex]
in a butane lighter, 9.7g of butane combine with 34.7g of oxygen to form 29.3g carbon dioxide and how many grams of water?
The equation for the combustion of butane is C4H10 + O2 --> CO2 + H2O.
What is combustion ?Combustion is a chemical reaction between a fuel and an oxidizing agent, usually oxygen, to produce energy, usually in the form of heat and light. Combustion can be used to generate electricity, power engines, and heat homes and buildings. Combustion is also used in a wide variety of industrial processes, such as smelting, manufacturing, and food production. In combustion, the fuel is oxidized, releasing energy in the form of heat and light. This energy is usually released in the form of heat, but some fuels, such as hydrogen, can also be used to produce light. Combustion is an exothermic reaction, meaning that it releases energy in the form of heat.
When 9.7 grams of butane reacts with 34.7 grams of oxygen, 29.3 grams of carbon dioxide will be produced. In order to find the amount of water produced, we need to use the law of conservation of mass. This states that the total mass of the reactants will equal the total mass of the products.
Therefore, 9.7 grams + 34.7 grams = 29.3 grams + x, where x is the mass of water produced. Solving for x, we get x = 25.7 grams of water. Therefore, 25.7 grams of water is produced when 9.7g of butane reacts with 34.7g of oxygen.
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a chemical equation is a statement using chemical that expresses both the identities and the relative of the reactants and products involved in a chemical or physical change. multiple choice question. numbers; masses formulas; quantities formulas; masses names; quantities
A chemical equation is a statement using chemical formulas expresses both the identities and the relative quantities of the reactants and products involved in a chemical or physical change. The correct answer is B.
An expression of the identities and relative quantities of the reactants and products involved in a chemical or physical transformation is called a chemical equation. Chemical equations are statements made using chemical formulas.
What exactly is a chemical equation?In chemical equations, variables like the direction of a reaction and the physical states of the reacting parties are represented by symbols. In 1615, the French chemist Jean Beguin created the first chemical equation.
Chemical equations, such as the one below, can be used to depict chemical reactions on paper (for the reaction between hydrogen gas and oxygen gas to form water).
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a sample of gas occupies 250 ml at 1 atm. if the pressure increases to 2 atm while the temperature stays the same, what is the new volume?
At 1 atm, a sample of gas takes up 250 ml. if the pressure increases to 2 atm while the temperature stays the same, 125ml is the new volume.
The ideal gas law states that PV = nRT, where n is the number of moles of gas, P is the pressure, V is the volume, R is the gas constant, and T is the temperature in Kelvin.
P1V1 = P2V2
where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.
Substituting the given values, we have:
1 atm x 250 ml = 2 atm x V2
Solving for V2, we get:
V2 = (1 atm x 250 ml) / (2 atm)
V2 = 125 ml
Therefore, the new volume of the gas is 125 ml when the pressure increases from 1 atm to 2 atm while the temperature remains constant.
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the amino acid histidine has a side chain for which the pka is 6.0. calculate what fraction of the histidine side chains will carry a positive charge at physiological ph at 7.4.
Fraction of positively charged histidine side chains at pH 7.4: 0.01. The pKa of histidine's side chain is 6.0,
The pKa of histidine's side chain is 6.0, which means that at a pH of 6.0, half of the side chains will be positively charged and half will be negatively charged. At a pH of 7.4, which is closer to neutral, fewer side chains will be positively charged. To calculate the fraction of positively charged side chains, we can use the Henderson-Hasselbalch equation, which relates the pH to the pKa and the ratio of protonated to deprotonated species. The result is a very small fraction, indicating that only a small percentage of histidine side chains will be positively charged in physiological conditions.
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Determine the atomic number, atomic mass, and number of protons, neutrons and electrons for phosphorus using the periodic table.
Help please
Atomic number is the number of protons in an atom with the symbol Z.
The periodic table is a tabular chart of the chemical elements according to their atomic numbers so that elements with similar properties are in the same group (column).
In a neutral atom, the number of protons is equal to the number of electrons in the atom. However, the number of neutrons can be derived by subtracting the neutron number from the atomic mass.
Hence, the number of protons, electrons and neutrons of phosphorus are as illustrated above.
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Sort of the chemical equation based on chemical reaction that they represent
Water breaking to hydrogen and oxygen is decomposition reaction. Iron and oxygen combining to give iron oxide is a combination reaction or synthesis reaction. Reaction of sodium and chlorine to produce sodium chloride is synthesis reaction.
What are different types of reaction ?There are different types of reactions namely, decomposition, displacement, synthesis, combustion etc. The breaking one compound into its constituents compounds or elements is called decomposition reaction.
Water splitting into hydrogen and oxygen is decomposition reaction. When two elements or molecules combine to form a single product, it is called combination or synthesis reaction.
Fe and oxygen reacts to form iron oxide is a synthesis reaction. Similarly formation of NaCl and sulphur dioxide from sulphur and oxygen is also a synthesis reaction.
Combination of potassium and chlorine to form potassium chloride is also a synthesis reaction. The breaking of calcium carbonate into calcium oxide and carbon dioxide is a decomposition reaction.
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Your question probably include the following options:
water → hydrogen + oxygen
*iron + oxygen → iron oxide
*sodium + chlorine → sodium chloride
*sulfur + oxygen → sulfur dioxide
*potassium + chlorine → potassium chloride
*calcium carbonate →calcium oxide + carbon dioxide
Lactose is disaccharide ; which monosaccharides are present in it
Lactose is a disaccharide. It is composed of the two monosaccharides, glucose and galactose.
The chemical bond between these two sugars is called a glycosidic bond, and it can be broken down by the enzyme lactase in the small intestine, releasing the two individual sugars that can be absorbed into the bloodstream.
Lactose is found primarily in mammalian milk, which makes it a significant source of energy for newborn mammals. Some individuals, however, may have lactose intolerance, a condition where their bodies are unable to produce enough lactase to break down lactose, leading to digestive symptoms after consuming lactose-containing products.
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container a holds 777 ml of an ideal gas at 2.50 atm. container b holds 174 ml of a different ideal gas at 4.80 atm. container a and container b are glass spheres connnected by a tube with a stopcock. container a is larger than container b. if the gases are allowed to mix together, what is the resulting pressure?
The resulting pressure will be the average of the pressures in container A and container B.
The pressure of the resulting mixture of gases will be equal to the average of the initial pressures in container A and container B. The volume of the mixture is equal to the sum of the volumes of the two containers, so the pressure will be proportional to the number of gas particles present. To find the average pressure, we can add the initial pressures in container A and container B and divide by 2. In this case, the average pressure is (2.50 atm + 4.80 atm) / 2 = 3.65 atm.
container b holds 174 ml of a different ideal gas at 4.80 atm. container a and container b are glass spheres connnected by a tube with a stopcock. container a is larger than container b. if the gases are allowed to mix together,
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a balloon permeable to water but not to glucose contains a 10% glucose solution. a beaker contains a 5% glucose solution. what will happen when the balloon is submerged in the beaker?
A 10% glucose solution is contained in a balloon that is impermeable to glucose but not water. a beaker contains a 5% glucose solution. while glucose molecules cannot pass through the balloon into the beaker.
Since the balloon is permeable to water but not to glucose, water molecules can pass through the membrane of the balloon from the beaker into the balloon, while glucose molecules cannot pass through the balloon into the beaker.
Initially, the concentration of glucose in the balloon is 10%, which is higher than the concentration of glucose in the beaker, which is 5%. As a result, This process is called osmosis. AS water molecules move from the beaker into the balloon, the volume of the balloon will increase. This increase in volume will continue until the concentration of glucose on both sides of the membrane is equal, or until the pressure inside the balloon is high enough to prevent further water molecules from entering the balloon.
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chemists commonly use a rule of thumb that an increase of 10 k in temperature doubles the rate of a reaction. what must the activation energy be for this statement to be true for a temperature increase from 25 to 358c?
According to Arrhenius equation, the activation energy for a temperature increase from 25°C to 358°C will be 52.4 kJ/mol.
The general rule states that the rate of reaction doubles for a 10° C increase in temperature and this applies only at a certain temperature for a given activation energy .
To establish a connection between the temperature and activation energy for the rule to be valid, we have to ignore any concentration-related temperature variations.
According to the general rule of thumb in organic chemistry, a reaction's pace doubles for every 10° increase in temperature from room temperature. For a given reaction, the ratio of its rate constant at a higher temperature to its rate constant at a lower temperature is known as its temperature coefficient, it is denoted by (Q).
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what would happen tot eh ratio of copper percipate to iron consumed if you had let the reaction for less time?
The accepted iron:copper ratio ranges from 1:1 to 15:1. For comparison, our Optimizers have an average iron:copper ratio of 12.6.
What is the meaning of participating?
In our daily lives, many chemical reactions take place. Burning, corrosion, food preparation, and digestion are typical examples of these reactions. Precipitation reactions are a significant class of chemical reactions. Two different soluble salts that are in aqueous solutions combine in these reactions to create two products. One of these products, which is referred to as the "precipitate," is insoluble in the solution and precipitates out.
Supplemental zinc can reduce the absorption of copper and raise demand for it. Birth control, eating a lot of foods high in copper like liver, and leaching copper from copper pipes and pans can all have an adverse effect on how well zinc and iron are absorbed.
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4. the equivalence points of this titration is not the same as a the equivalence point when a strong base is titrated to a strong acid. explain.
When a strong acid and a strong base are titration together, the acid and base will mix to form a neutral solution. The hydronium (H+) and hydroxide (OH-) ions will unite to create water.
Titration, also known as titrimetry, is a technique for analyzing a mixture's composition chemically to ascertain the concentration of a certain analyte. Volumetric analysis is another name for titration, a key analytical chemistry technique.
A standard solution with a set volume and concentration is created as part of the titration process and is known as a titrant or titrator. When an endpoint or equivalence point is attained, the titrant is made to continue reacting with the analyte, and at that point, the concentration of the analyte can be determined from the amount of titrant consumed. Titration is another method for using the stoichiometry principle to figure out the concentration of an unknown solution.
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why do we keep metal dry by heating in a test tube rater than placing the metal directly into boiling water
Keeping a metal dry during heating in a test tube provides a safer and more controlled environment for conducting reactions and analyzing the results.
When heating a metal in a test tube, it is common practice to keep the metal dry rather than placing it directly into boiling water for several reasons:
Prevention of oxidation: Keeping the metal dry during heating reduces the exposure to water and atmospheric oxygen, which can cause oxidation and corrosion of the metal.
Control of reaction conditions: Heating a dry metal in a test tube allows for better control over the temperature and reaction conditions. The temperature can be monitored and adjusted more precisely than when the metal is immersed in boiling water.
Safety: Placing a metal directly into boiling water can be dangerous, as the metal can rapidly heat up and cause the water to boil over, splashing hot liquid and steam. Heating a metal in a test tube eliminates this risk.
Avoidance of dilution: When a metal is placed directly into boiling water, it can become diluted by the water, affecting the outcome of the reaction. Heating the metal in a dry test tube eliminates this risk of dilution.
Ease of observation: When a metal is heated in a dry test tube, any changes or reactions that occur can be more easily observed and monitored, as the contents of the test tube are visible.
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a hypothetical element has a bcc crystal structure, an atomic radius of 0.132 nm, and an atomic weight of 137.3 g/mol. what is the density of this element? express your answer in units of g/cm3.
The atomic weight of a hypothetical element is 137.3 g/mol, and it has a bcc crystal structure with an atomic radius of 0.132 nm. The density of this element is 9.05 g/[tex]cm^3.[/tex]
The body-centered cubic (bcc) crystal structure has 2 atoms per unit cell, and the atomic radius (r) of the element is 0.132 nm. The volume of the unit cell (V) can be calculated as:
V = a^3 * [tex]2^(1/2)\\[/tex]
a = 4(0.132 nm) / [tex](3)^(1/2)[/tex] = 0.3579 nm
V = (0.3579 nm)^[tex]3 * 2^(1/2)[/tex]= 0.04516 nm^3
Avogadro's number (NA) is 6.022 x [tex]10^23 mol^-1.[/tex] The mass of one atom (m) can be calculated as:
m = M / NA
m = 137.3 g/mol / (6.022 x [tex]10^23 mol^-1[/tex]) = 2.281 x [tex]10^-22[/tex]g
The density (ρ) of the element can be calculated as:
ρ = (2 * m) / V
ρ = 2(2.281 x [tex]10^-22[/tex] g) / 0.04516[tex]nm^3[/tex]
Converting nm to cm:
1 nm = 1 x[tex]10^-7[/tex] cm
0.04516[tex]nm^3[/tex] = (0.04516 x [tex]10^-7[/tex] cm)^3 = 0.8217 x[tex]10^-21 cm^3[/tex]
ρ = 9.05 g/[tex]cm^3[/tex]
Therefore, the density of this hypothetical element with a bcc crystal structure, an atomic radius of 0.132 nm, and an atomic weight of 137.3 g/mol is 9.05 g/[tex]cm^3.[/tex]
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Calculate the number of moles of helium that contains 3.29 × 1021 atoms.
The number of moles of helium that contains 3.29 × 1021 atoms is 5.49 × 10-3 moles.
What is helium?
Helium is a colorless, odorless, and tasteless chemical element, and is the second-lightest element in the periodic table. It is a noble gas, meaning it has a very low level of reactivity, and it is found in abundance in the universe. In the atmosphere, helium is the second most abundant element, making up about 24% of the total elemental mass.
The number of moles of helium that contains 3.29 × 1021 atoms can be calculated using Avogadro's number. Avogadro's number is the number of atoms in one mole of a substance, which is equal to 6.02 × 1023 atoms.
Therefore, the calculation is as follows:
Number of moles of helium = 3.29 × 1021 atoms ÷ 6.02 × 1023 atoms/mole = 5.49 × 10-3 moles.
Hence, the number of moles of helium that contains 3.29 × 1021 atoms is 5.49 × 10-3 moles.
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Decane is a minor component in some gasolines. The standard molar enthalpy of formation of n-decane C₁0H22(0) is-249.4 kJ/mol. For the balanced reaction equation of
decane use:
C10H22(I)+ 12.5O2 --> 10CO₂ + 11H₂O.
Decane is a liquid, but all the other chemicals in this reaction are gases. What is the enthalpy change of this reaction in kJ/mol of decane?
The standard molar enthalpies of formation of:
O₂(s) - 0 kJ/mol;
CO₂(g)--393.5 kJ/mol; and
H₂O(g)--241.8 kJ/mol.
The enthalpy change of the reaction of decane would be -6582.3 kJ/mol of decane.
Enthalpy change calculationThe enthalpy change of a reaction can be calculated using the following equation:
ΔH = ∑nΔH_f(products) - ∑mΔH_f(reactants)
We are given the standard molar enthalpy of formation of n-decane, C10H22, which is -249.4 kJ/mol.
Using the balanced chemical equation, we can identify the stoichiometric coefficients of the reactants and products:
C10H22(I) + 12.5O2(g) --> 10CO2(g) + 11H2O(g)
Reactants:
n(C10H22) = 1
n(O2) = 12.5
Products:
n(CO2) = 10
n(H2O) = 11
Now we can calculate the enthalpy change of the reaction:
ΔH = ∑nΔH_f(products) - ∑mΔH_f(reactants)
ΔH = [10(-393.5 kJ/mol) + 11(-241.8 kJ/mol)] - [1(-249.4 kJ/mol) + 12.5(0 kJ/mol)]
ΔH = -6582.3 kJ/mol
The enthalpy change of the reaction is -6582.3 kJ/mol of decane.
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describe the simalarities and diffrences between the isotopes 18 o 8 and 16 o 8
Same number of protons and different number of neutrons.
Oxygen is a chemical element with 8 protons. It is capable of achieving a noble gas electronic configuration by accepting two electrons. Oxygen is important for many living organisms.
Oxygen-16 and oxygen-18 differ in the number of neutrons in their nuclei. Oxygen-16 has 8 neutrons, while oxygen-18 has 10 neutrons. Oxygen-16 and oxygen-18 have the same number of protons and electrons. Both neutrons and protons have mass, so changing the number of neutrons changes the mass of oxygen. These elements with different numbers of neutrons are referred to as isotopes. Both oxygen-16 and oxygen-18 are stable isotopes of oxygen and are not radioactive.
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a balloon containing 0.40 mol of a gas with a volume of 5.0 l was deflated to 1.0 l. what is the final number of moles?
The final number of moles of a balloon containing 0.40 moles with a volume of 5.0 is 0.08 moles.
The equation that can be used to find the final moles of gas in the balloon would be calculated as Avogadro's law.
Avogadro's law states that at constant pressure, the number of moles present in a gas is directly proportional to the volume of the gas. In other words, there is a direct relationship between the volume and the number of moles present in a gas.
The law is mathematically expressed as: v1/n1 = v2/n2
Where v1 is the initial volume of gas, v2 is the final volume, n1 is the initial number of moles, and n2 is the final number of moles of gas.
In this case, n1 = 0.40 mol, v1 = 5.0 L, and v2= 1.0 L. What we are looking for is v1.
n2= n1v2/v1
= 0.4x1/5
= 0.08 mol
Thus, the equation to be used to find the final number of moles of the gas would be the equation derived properly from Avogadro's law.
The final number of moles of a balloon containing 0.40 moles with a volume of 5.0 is 0.08 moles.
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the half-life for the second-order decomposition of hi is 15.4 s when the initial concentration of hi is 0.34 m. what is the rate constant for this reaction?
The rate constant is 0.09691 m-1 s-1.
Half-life is defined as the time it takes for a quantity to decrease to half its original value. A second order reaction can be defined as a chemical reaction for which the sum of the exponents of the corresponding rate laws of the chemical reaction is equal to two. A rate constant or specific rate constant is the constant of proportionality in the equation that describes the relationship between the rate of a chemical reaction and the concentration of reacting substances.
secondary half-life
t=1/Kao
Substituting the given values of initial concentration and half-life into equation (1), we get
k = 0.09691 m-1 s-1
The rate constant is 0.09691 m-1 s-1
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Convert 0.62 mol of H2SO4 to grams
in this experiment you reflux your solvent using a water condenser. why is that necessary rather then just heating an open flask?
Refluxing a solvent using a water condenser provides a safer and more controlled environment for a chemical reaction to occur, increasing the chances of a successful outcome.
Refluxing a solvent using a water condenser is necessary because it provides a controlled environment for the reaction to occur. When a reaction mixture is heated in an open flask, the solvent can easily evaporate, causing the reaction to proceed at a different rate than desired or even stop altogether. Additionally, volatile or hazardous compounds can escape into the atmosphere, posing a safety risk.
In a reflux setup, the water condenser acts as a barrier, preventing the solvent from evaporating and also trapping any volatile compounds that may be produced during the reaction. The water flowing through the condenser helps to cool the reaction mixture, preventing it from overheating and potentially causing a dangerous runaway reaction. By controlling the temperature and limiting evaporation, refluxing helps to ensure that the reaction proceeds at a predictable and controlled rate, leading to a higher yield of product.
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When 0.10 mol NO2 is added to a 1.0-L flask at 25 °C, the concentration changes so that at equilibrium, [NO2] = 0.016 M and [N2O4] = 0.042 M. (a) What is the value of the reaction quotient before any reaction occurs? (b) What is the value of the equilibrium constant for the reaction?
(a) The value of the reaction quotient before any reaction occurs is 0.10 M.
(b) The value of the equilibrium constant for the reaction is 0.38.
The reaction quotient (Q) before any reaction occurs is the ratio of the concentrations of the products raised to their stoichiometric coefficients, to the concentrations of the reactants raised to their stoichiometric coefficients, prior to any reaction taking place.
The reaction between NO2 and N2O4 can be written as:
2NO2(g) ⇌ N2O4(g)
At the start of the reaction, before any reaction occurs, the concentration of NO2 is 0.10 M, and there is no N2O4.
Therefore, the value of Q at this point would be:
Q = (N2O4^2)/(NO2^2)
= 0.10^2 / 0
= 0
The equilibrium constant (Kc) is the value of the reaction quotient at equilibrium, which can be determined from the equilibrium concentrations of reactants and products.
Given that [NO2] = 0.016 M and [N2O4] = 0.042 M, we can calculate the value of Q at equilibrium as:
Q = (0.042^2)/(0.016^2)
= 0.38
So the value of the equilibrium constant, Kc, is equal to the value of the reaction quotient at equilibrium, which is Kc = 0.38.
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cyclooctane is 85.6 % c and 14.4 % h by mass with a molar mass of 112.2 g/mol . what is its molecular formula?
The molecular formula is then C8H14, meaning there are 8 carbon atoms and 14 hydrogen atoms in one molecule of cyclooctane.
What is cyclooctane?
Cyclooctane is a cycloalkane hydrocarbon consisting of eight carbon atoms arranged in a ring. It is an organic compound and is classified as an aromatic hydrocarbon due to its aromatic character. It is a colourless, flammable liquid with a low boiling point and a strong smell. Cyclooctane is used in the production of certain plastics, in the synthesis of drugs and chemicals, and as a solvent.
The molecular formula of cyclooctane can be calculated by using the following formula:
Number of moles (n) = Mass (m) / Molar mass (M)
n = 112.2 g / 112.2 g/mol
= 1 mol
To determine the number of carbon atoms in the molecule, multiply the number of moles (1) by the percent of carbon by mass (85.6%).
n_C = 1 mol x 85.6% = 0.856 mol
To determine the number of hydrogen atoms in the molecule, multiply the number of moles (1) by the percent of hydrogen by mass (14.4%).
n_H = 1 mol x 14.4% = 0.144 mol
The molecular formula is then C8H14, meaning there are 8 carbon atoms and 14 hydrogen atoms in one molecule of cyclooctane.
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We place 3. 2 mol PCl5 in a 2. 0 L flask and allow it to reach equilibrium at a given temperature. What is the final concentration of Cl2 in the flask?
PCl5(g) PCl3(aq) + Cl2(g)
Kc = 0. 47
A) 0. 55 M
B) 0. 27 M
C) 0. 66 M
D) 0. 11 M
E) 0. 32 M
The final concentration of Chlorine gas in the flask is 0.55M.
The initial concentration of PCl5 can be calculated using the number of moles and volume:
[PCl5] = n/V = 3.2 mol / 2.0 L = 1.6 M
At equilibrium, the concentration of products and reactants remains constant. Therefore, the concentration of Cl2 can be determined using the equilibrium constant (Kc) and the initial concentration of PCl5:
Kc = [PCl3][Cl2] / [PCl5]
[Cl2] = Kc × [PCl5] / [PCl3] = 0.47 × 1.6 M / [PCl3]
Since [PCl3] is not given, we cannot determine the exact concentration of Cl2. However, the answer choices can be used to estimate the closest answer. Based on the answer choices, the closest estimate is 0.55 M, which is answer choice A.
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hy does pumping air into a tire at a constant temperature increase the pressure? responses the atmospheric pressure decreases. the atmospheric pressure decreases. the number of molecules increases. the number of molecules increases. the temperature increases. the temperature increases. the volume increases.
pumping air into a tire at a constant temperature increases the pressure volume of the tire increases slightly as air is pumped in, but this is not the main factor causing the increase in pressure.
Pumping air into a tire at a constant temperature increases the pressure because the number of air molecules in the tire increases, leading to an increase in pressure. The pressure inside a tire is directly proportional to the number of air molecules in the tire, and an increase in the number of air molecules leads to an increase in pressure. The atmospheric pressure does not change significantly in this scenario, and the temperature remains constant. The volume of the tire increases slightly as air is pumped in, but this is not the main factor causing the increase in pressure.
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Answer:
The volume increases.
Explanation:
propose or recommend the concentration of [cv ] that should be used in this part of the experiment when varying the hydroxide ion concentration. explain.
When varying the hydroxide ion concentration, it is recommended to use a concentration of 0.1 M for the CV.
This is because a low concentration of CV helps to reduce the effect of the hydroxide ions and maintain a more consistent pH throughout the experiment. Additionally, a low concentration of CV also reduces the amount of time required for the experiment. With the help of spectroscopy and graphical analysis, the rate law for the color-fading reaction between crystal violet and sodium hydroxide will be ascertained in this advanced inquiry lab exercise. The lab starts off with a tutorial on how to build a calibration curve for the absorbance vs concentration of the dye crystal violet. A stock solution of crystal violet is used to create a series of known or standard solutions, and the absorbance of each is measured at the ideal wavelength. In a rate law experiment, the concentration of any "unknown" dye solution can be calculated using a Beer's law plot of absorbance as a function of concentration.
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part of the treatment of diabetic ketoacidosis is intravenous d5w, a solution of dextrose in water. calculate the mass of dextrose in ml of this solution. be sure your answer has a unit symbol and is rounded to the correct number of significant digits.
In 180mL of D5W, there is a total mass of 9g dextrose part of the treatment of diabetic ketoacidosis is intravenous d5w, a solution of dextrose in water.
To calculate the mass of dextrose in mL of D5W, first determine the concentration of dextrose in the solution.
D5W is a 5% dextrose solution, meaning that each 100mL of D5W contains 5g of dextrose.
Thus, for a given volume of D5W, the mass of b can be determined by multiplying the volubme in mL by 0.05.
For example, in 180mL of D5W, there is a total mass of 9g dextrose (180mL x 0.05 = 9g).
that the pressure of a gas is equal to the number of moles of the gas multiplied by its temperature and the universal gas constant, divided by the volume of the container.
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mass, in grams, of 18.00 L of methane gas (CH4) at STP
Answer:
12.83 g.
Explanation:
At standard temperature and pressure (STP), which is defined as 0°C and 1 atm pressure, 1 mole of any gas has a volume of 22.4 liters.
Since the volume of methane gas is given as 18.00 L, we can calculate the number of moles by dividing the volume by the volume of one mole at STP:
18.00 L / 22.4 L/mol = 0.8 mol
The molar mass of CH4 is 16.04 g/mol, so we can calculate the mass of 0.8 mol of CH4 as follows:
0.8 mol * 16.04 g/mol = 12.83 g
So, the mass of 18.00 L of methane gas at STP is approximately 12.83 g.
what is the molarity (mol/l) of a sodium hydroxide (naoh) solution containing 30 mg/l? atomic weights: na
The molarity of a solution that contains 30g of Noah in 500ml of solution is 1.5
What is Molarity ?Molarity is a measure of the concentration of a solute in a solution, expressed as the number of moles per liter of solution (mol/L). It is an important part of chemistry, as it is used to describe the concentration of a solution and its components. When a solute is dissolved in a solvent, the resulting solution has a certain concentration of that solute. Molarity is a measure of this concentration, and it is calculated by dividing the number of moles of solute in the solution by the total volume of the solution. For example, if one mole of a solute is dissolved in one liter of solvent, the resulting solution has a molarity of 1M (1 mole/liter). Molarity is an important concept in chemistry because it can be used to calculate the amount of a solute that is present in a solution, and also to compare the relative concentrations of different solutions. It is also used to describe the reaction rates of solutions, and to determine the amount of reactants and products present in a reaction.
The molarity of a solution is given as-
m = n/v × 1000
Where n is the number of moles of v is the volume of the solution.
The molecular mass of NaOH is 23+16+1=40grams.
Thus the number of moles will be-
30/40 = 3/4
now
m = (3/4)/500 × 1000
m = 1.5
Thus, the molarity of a solution that contains 30g of Noah in 500ml of solution is 1.5.
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Complete question:
What is the molarity of a solution that contains 30g of Noah in 500ml of solution?
does the luminous flame appear steady or unsteady
Answer:
the answer is unsteady
Answer:
luminous flame appears unsteady