What is the length of side AB of the triangle? (1 point)
a 3
b 5
c Square root of 6
d Square root of 13

The product of the function is 2x^2+ 5x - 3

We are to find the product of the functions x + 3 and 2x -1

Taking the product:

f(x)g(x) = (x+3)(2x -1)

f(x)g(x) = x(2x) - x(1) + 3(2x) + 3(-1)

f(x)g(x) = 2x^2 - x + 6x - 3

f(x)g(x) = 2x^2+ 5x - 3

Hence the product of the function is 2x^2+ 5x - 3

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Answer:

c

Step-by-step explanation:

SANA MAKATULONG

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Answer:

B

Step-by-step explanation:

Luis started by subtracting 4.8b from both sides to get 2.4b + 6.5 < – 8.1.

Answer:

Luis’s, because he flipped the inequality sign when he subtracted

Step-by-step explanation:

Luis’s, because he flipped the inequality sign when he subtracted

Answer:

Step-by-step explanation:

the answer

the true answer  is A) 4x^2+52x+165=320; x = 2.5

proof:

since they want to limit its area to 320 in^2

x must be equal 2.5, because 4.(2.5)^2+52(2.5)+165= 25+130+165=320;

the main rule of the area of a triangle is

A= (base x height )/2

let be b the base and h the height

so h=20- 6b

so 50= b x( 20-6b) /2, implies 100/b = 20 - 6b

if b=x, we have 100= 20x -6x² this  is equivalent to 6x² - 20x = -100

so the answer is

D) None of the choices are correct.

the largest dimensions that can be used for the fountain are

B) x^2+8x+16=800

C) x^2+16=800

proof

x^2+8x+16=x^2+8x+4², 4² is the area of the square fountain, and x^2+8x should be the remaining of the area, the total space that the fountain and sidewalk can use is 800, it is  less than 800 ft^2.

Use the same method for. x^2+16=800

Answer:

I don't know but good luck!!!!!

Answer:

[tex]0.007[/tex]

Step-by-step explanation:

Round to the required significant figure:

[tex]0.007[/tex]

Answer:

x=2, perimeter=14

Step-by-step explanation:

Finding x

(x+1)(x+2)

x^2+2x+x+2=12

x^2+3x-10

x^2-2x+5x-10

x(x-2)5(x-2)

(x+5)(x-2)

x=-5

x=2

Length or Width should be a positve number.

x=2

Perimeter:

3+3+4+4=14

Answer:

i think 4.4n+3-3.4n = n+3

Answer:

n+3

Step-by-step explanation:

If Im not incorrect you have to combine like terms in the equation which would only leave you with 1n (Just N basically)  then you just plug in the three and equation done.

Answer:

w= 25

Step-by-step explanation:

Cost of water= (w -1)¢

Cost of milk= (2w -11)¢

Let the certain number be x.

x(w -1)¢= 480¢ -----(1)

x(2w -11)¢= 780¢ -----(2)

From (1):

wx -x= 480 -----(3)

From (2):

2wx -11x= 780 -----(4)

(3) ×2:

2wx -2x= 960 -----(5)

(5) -(4):

(2wx -2x) -(2wx -11x)= 960 -780

Expand:

2wx -2x -2wx +11x= 180

9x= 180

Divide both sides by 9:

x= 180 ÷9

x= 20

Substitute x= 20 into (3):

w(20) -20= 480

20w -20= 480

20w= 480 +20

20w= 500

w= 500 ÷20

w= 25

The cash payment for the article is RS. 2,260.

A discount reduces the price of an item. The article becomes cheaper after the discount.

Cost of the article after the RS. 20 discount = RS. 2020 - 20 = RS 2000

VAT means value added tax. VAT increases the price of an item. The cost of the article increases by 13% after the  VAT is levied,

Cost of the article = (100 + 13%) x 2000

1.13 x 2000 = RS 2,260.

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Answer:

y= 1/3x + 3

Step-by-step explanation:

Answer : i believe 100 X is 13 Z is 12

Step-by-step explanation:

sorry if im wrong

Answer:

[tex]\frac{5}{X^{2} } y^{2}[/tex]

Step-by-step explanation:

sorry the Y isn't under the 5 anyway hope this helped

Answer:

A is the answer.

Step-by-step explanation:

(X^7/2)(y^-3/5)

14. Slope (m) of PQ = -4

Slope (m) of RS = 1/4

The lines are perpendicular.

15. mPQ = -3

mRS = 3

They are neither perpendicular nor parallel lines.

16. mPQ = 0

mRS = 0

The lines are parallel.

17. x = -6

18. x = -2

If two lines have the same slope (m), then both lines are parallel to one another. On the other hand, if the slopes of two lines are negative reciprocals to each other, then both lines are regarded as perpendicular lines because the product of their slopes is equal to -1.

Slope (m) = change in y / change in x

14. Slope (m) of PQ = (-3 - 17) / (1 -(-4))

Slope (m) of PQ = -20/5 = -4

Slope (m) of RS = (4 - 3) / (-5 -(-9))

Slope (m) of RS = 1/4

(1/4)(-4) = -1, therefore, the lines are perpendicular.

15. Slope (m) of PQ = (-1 - 14) / (2 -(-3))

Slope (m) of PQ = -15/5 = -3

Slope (m) of RS = (-10 - 8) / (-2 - 4)

Slope (m) of RS = -18/-6 = 3

They are neither perpendicular nor parallel lines.

16. Slope (m) of PQ = (-1 - (-1)) / (-3 - 2)

Slope (m) of PQ = -0/-5 = 0

Slope (m) of RS = (9 - 9) / (-7 -(-11))

Slope (m) of RS = 0/4 = 0

The lines are parallel.

17. If CD║EF, their slope will be equal. Therefore:

Slope of CD = slope of EF

(-4 - 16)/(2 - x) = (4 - 14)/(-2 -(-6))

-20/(2 - x) = -10/4

-20/(2 - x) = -5/2

Cross multiply

-20(2) = -5(2 - x)

-40 = -10 + 5x

-40 + 10 = 5x

-30 = 5x

-30/5 = x

-6 = x

x = -6

18. Slope of JK = slope of l

(-5 -(-8))/(-1 - x) = 6/2

3/(-1 - x) = 3

3(-1 - x) = 3

-3 - 3x = 3

-3x = 3 + 3

-3x = 6

-3x/-3 = 6/-3

x = -2

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#a

[tex]\\ \sf{:}\Rrightarrow 15x+30y\geqslant 150[/tex]

[tex]\\ \sf{:}\Rrightarrow x+y\geqslant 10[/tex]

And

[tex]\\ \sf{:}\Rrightarrow 0.5x+2y\geqslant 8[/tex]

#2

Attached

#3

Answer:

2

Step-by-step explanation:

sin 90 is 1;

cos 360 is cos 0, or 1; and

tan 0 is 0.

Thus, sin 90° + cos 360° + tan 0° = 1 + 1 + 0 = 2

[tex]\dfrac{2x -3}{5} - \dfrac x3 \leq 2\\\\\implies \dfrac{6x-9-5x}{15} \leq 2\\\\\implies x-9 \leq 15 \times 2\\\\\implies x -9 \leq 30\\\\\implies x \leq 30 +9 \\\\\implies x \leq 39\\\\\text{Interval,}~ (-\infty, 39 ][/tex]

Answer:

x

Step-by-step explanation:

Refer to '<' as ' less than or equal to '

Whenever you are deal with these types of inequalities / equations, nake sure to equate the denominators of both entities involved in the operation be it ( -, × , ÷ ,+ )

with that in mind

* 2x - 3/5 - x/3 < 2 has 2 different denominators i.e - 5 & 3

so to equate both sides, let's multiply each by the denominator they are lacking.

* 2x - 3/5 lacks 3 compared to -x/3.

* similarly, -x/3 lacks 5 compared to 2x - 3/5

multiply both by what they lack (2)

thus, (2x - 3 )×3 /(5) × 3 - (x × 5) × 5/ (3) × 5 < 2

* 6x - 9/ 15 - 5x/15 < 2

we can now combine the numerators since we now have a common denominator which is 15.

* 6x - 9 - 5x/ 15 < 2 (6x-9-5x) is equal to -9 + x = x - 9.

criss cross

* x - 9 < 30

* x < 39

Answer:

We can find circumcenter by using the circumcenter of a triangle formula, where the location of the circumcenter is O(x,y) and the coordinates of a triangle are given as A(x1,y1),B(x2,y2) and C(x3,y3) A ( x 1 , y 1 ) , B ( x 2 , y 2 ) a n d C ( x 3 , y 3 ) .

Step-by-step explanation:

Answer:

Not too sure, but maybe this is what you need.

(Students = S, Adults = A) So, Ax + Sy = 266?

Or

x10 + y7 = $266

Step-by-step explanation:

I think the second one is the most accurate one, ignore the first equation. T^T

Answer:

B

4*2=8

Hope This Helps!!!

Answer:

Step-by-step explanation:

y = 4/3x

you can see the line passes through (0,0)

the next point it passes through is (3,4)

(y2-y1)/(x2-x1)

(4 - 0)/(3 - 0)

4 / 3

the slope = 4/3

meaning it goes up 4 and right 3 from point to point

Answer:

6432)10 = (1100100100000)2

Step-by-step explanation:

Step 1: Divide (6432)10 successively by 2 until the quotient is 0:

6432/2 = 3216, remainder is 0

3216/2 = 1608, remainder is 0

1608/2 = 804, remainder is 0

804/2 = 402, remainder is 0

402/2 = 201, remainder is 0

201/2 = 100, remainder is 1

100/2 = 50, remainder is 0

50/2 = 25, remainder is 0

25/2 = 12, remainder is 1

12/2 = 6, remainder is 0

6/2 = 3, remainder is 0

3/2 = 1, remainder is 1

1/2 = 0, remainder is 1

Step 2: Read from the bottom (MSB) to top (LSB) as 1100100100000. This is the binary equivalent of decimal number 6432 (Answer).

Hopes that it will help u...☺

[tex]\huge \bf༆ Answer ༄[/tex]

The method to convert the number from Decimal to binary number system is simple ~

Now let's solve the given question ~

Now, write the numbers from bottom to top ~

[tex] \sf{1100100100000}[/tex]

I hope it helps ~

Answer: graph b

Step-by-step explanation:

Vertex:  ( 3 ,0 )

Focus:  ( 3 , 1 4 )

Axis of Symmetry:  x = 3

Directrix:  y = − 1 4

Answer:

I don't know sorry

Answer:

3) a = 9

4) v = 16

Step-by-step explanation:

Assuming here that the two questions you're talking about are problem 3 and problem 4, here is my work to find each answer.

Problem 3

First, let's distribute the 5 onto both terms in the parentheses.

5(a - 3) = 30

5(a) - 5(3) = 30

5a - 15 = 30

Next, we can add 15 to both sides to isolate a.

5a - 15 = 30

5a = 45

Finally, divide both sides by 5 to find the value of a.

5a = 45

a = 9

Problem 4

First, let's remove 2 from both sides of the equation.

v/2 + 2 = 10

v/2 = 8

Then, we can multiply both sides by 2 to find the value of v.

v/2 = 8

v = 16

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\text{Number 1}[/tex]

[tex]\text{QUESTION: 5(a - 3) = 30}\\\\\large\textsf{DISTRIBUTE 5 WITHIN the PARENTHESES}\\\\\rm{5(a) + 5(-3) = 30}\\\\\rm{5a - 15 = 30}\\\\\large\textsf{ADD 15 to BOTH SIDES}\\\\\rm{5a - 15 + 15 = 30 + 15}\\\\\large\textsf{CANCEL out: -15 + 15 because it gives you 0}\\\large\textsf{KEEP: 30 + 15 because it helps solve for the a-value}\\\\\text{NEW EQUATION: 5a = 30 + 15}\\\\\large\textsf{SIMPLIFY IT!}\\\\\rm{5a = 45}\\\\\large\textsf{DIVIDE 5 to BOTH SIDES}\\\\\rm{\dfrac{5a}{5} = \dfrac{45}{5}}[/tex]

[tex]\large\textsf{CANCEL out: }\mathsf{\dfrac{5}{5}}\large\textsf{ because it gives you 1}\\\large\textsf{KEEP: }\mathsf{\dfrac{45}{5}}\large\textsf{ because it helps solve for the a-value}\\\\\text{YOUR NEW EQUATION: }\rm{a = \dfrac{45}{5}}\\\\\large\textsf{SIMPLIFY IT!}\\\\\large\text{a = 9}\\\\\huge\text{Therefore, your answer is: \boxed{\textsf{a = 9}}}\huge\checkmark[/tex]

[tex]\huge\text{NUMBER 2}[/tex]

[tex]\text{QUESTION: }\rm{\dfrac{v}{2} + 2 = 10}\\\\\rm{\rightarrow \dfrac{1}{2}v + 2 = 10}\\\\\large\textsf{SUBTRACT 2 to BOTH SIDES}\\\\\rm{\dfrac{1}{2}v + 2 - 2 = 10 - 2}\\\\\large\textsf{CANCEL out: 2 - 2 because it gives you 0}\\\large\textsf{KEEP: 10 - 2 because it helps solve for the v-value.}\\\\\text{YOUR NEW EQUATION: }\rm{\dfrac{1}{2}v = 10 - 2}\\\\\text{SIMPLIFY IT!}\\\\\rm{\dfrac{1}{2}v = 8}\\\\\large\textsf{MULTIPLY 2 to BOTH SIDES}\\\\\rm{2\times \dfrac{1}{2}v = 2\times8}[/tex]

[tex]\large\textsf{CANCEL out: }\mathsf{2\times\dfrac{1}{2}}\large\textsf{ because it gives you 1}\\\large\textsf{KEEP: }\mathsf{2\times8}\large\textsf{ because it helps solve for the v-value}\\\\\text{YOUR NEW EQUATION: }\rm{v = 2\times8}\\\\\large\textsf{SIMPLIFY IT!}\\\\\rm{v = 16}\\\\\huge\text{Therefore, your answer is: \boxed{\textsf{v = 16}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

A cube root function has the form of [tex]y = x^\frac{1}{3}[/tex]

The graph is given as:

[tex]y = \sqrt[3]{x}[/tex]

Rewrite the function as:

[tex]y = x^\frac{1}{3}[/tex]

The above function is the parent function of a cube root function, and it passes through point (0,0).

See attachment for the graph of function [tex]y = \sqrt[3]{x}[/tex]

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Answer: d on edge

Step-by-step explanation:

d