The kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.
HOW TO CALCULATE KINETIC ENERGY:
The kinetic energy of a moving body can be calculated by using the following formula:
K.E = ½mv²
Where;
K.E = kinetic energy (J)m = mass (kg)v = velocity (m/s)According to this question, a toy truck has a mass of 0.75 kg and a velocity of 4 m/s. The kinetic energy is calculated as follows:
K.E = ½ × 0.75 × 4²
K.E = 8 × 0.75
K.E = 6J
Therefore, the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.
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Answer:
you should change that name
stella is driving down a steep hill. she should keep her car __________ to help _________.
Answer:
Stella is driving down a steep hill. She should keep her car in a lower gear to help slow her vehicle.
Explanation:
can someone explain why is the answer 3.1?
i dont know Im sorry but why Im messaging is because when more people respond it usually is the first to pop up so someone else will see this and be able to help you Explanation:
An object with a mass of 13.2 kg is accelerating at 9.4 m/s? What force is being applied on the object?
Round your answer to the appropriate number of significant figures and use the following formula:
force = mass x acceleration
Force = mass x acceleration:
Force = 13.2 kg x 9.4 m/s
Force = 124.08
Force = 124 Newtons
The force will be = 124 N
What is newton's second law of motion?
Newton's second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.
according to newton's second law of motion
Force = mass * acceleration
given
mass = 13.2 kg
acceleration = 9.4 m/s
force = 13.2 * 9.4
= 124.08 N
Rounding off answer to the appropriate number of significant figures
force = 124 N
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If the density of gold is 19.3 g/mL, what is the mass of 5mL of gold?
Answer:
96.5 mL
Explanation:
Which image shows an example of the electromagnetic force in action?
Answer:
Where are the images?
Explanation:
I can't help if there is no image(s) to this question.
what is the velocity of a 50 kg dog with 3000 j of kinetic energy
Answer:
KE = 225000000 J
Explanation:
Answer:
10.954. from equation. KE=1/2m(v^2)
2KE=m(v^2) 6000=50(v^2) (v^2)=6000/50
(v^2)=120. square root for all v=10.954 m/s
A book with a. mass of 1 kg is sliding on a table. If the frictional force on the book is 5 N, calculate the book’s acceleration. Is it speeding up or slowing down?
Force = mass x acceleration:
5N = 1kg x acceleration
Acceleration = 5N / 1 kg
Acceleration = 5 m/s^2
Acceleration is a positive value so it is speeding up
A single covalent bond is stronger than a single hydrogen bond so why does a group of polar molecules tend to have a higher boiling point than a group of non polar molecules
Answer:
this question makes no sense
Explanation:
like how do you get this question
Answer:They require more energy to break intermolecular forces hence polar molecules have higher melting points and boiling points than non-polar molecules of similar size, shape and number of electrons.
Explanation:
Block A has a mass of 2kg and a speed of 50 m/s along the positive x axis.
Block B has a mass of 4 kg and a speed of 25 m/s along the negative x axis.
The two blocks collide head-on in a perfectly elastic collision.
Determine the velocity of each mass after the collision.
Momentum is conserved, so
(2 kg) (50 m/s) + (4 kg) (-25 m/s) = (2 kg) v₁' + (4 kg) v₂'
where v₁' and v₂' are the velocities of the two blocks after the collision. Simplifying this gives
100 kg•m/s - 100 kg•m/s = (2 kg) v₁' + (4 kg) v₂'
0 = (2 kg) v₁' + (4 kg) v₂'
v₁' = -2v₂'
Energy is also conserved, so
1/2 (2 kg) (50 m/s)² + 1/2 (4 kg) (-25 m/s)² = 1/2 (2 kg) (v₁')² + 1/2 (4 kg) (v₂')²
Simplifying yields
2500 J + 1250 J = (1 kg) (v₁')² + (2 kg) (v₂')²
3750 J = (1 kg) (v₁')² + (2 kg) (v₂')²
Substitute v₁' = -2v₂' and solve for v₂' :
3750 J = (1 kg) (-2v₂')² + (2 kg) (v₂')²
3750 J = (6 kg) (v₂')²
(v₂')² = 625 J/kg = 625 m²/s²
v₂' = 25 m/s
Then the first block has final velocity
v₁' = -2 (25 m/s)
v₁' = -50 m/s