What is the height of a cylinder with a volume of 315 pi cubic meters and a radius of 6 meters?

a
12.25 meters
b
52.5 meters
c
8.75 meters
d
26.25 meters

Answer:

y=x-2

Step-by-step explanation:

y=2^x and y=x-2 have the same domain. Any x-values work for both functions. The domain is all real numbers.

If this answer is correct, please make me Brainliest!

Answer:

-x+3

Step-by-step explanation:

hope this helps

Answer:

Step-by-step explanation:

Given

height of the pine cone above the ground can be modelled by

[tex]h=-16t^2+40[/tex]

When pine cone reaches the ground [tex]h=0[/tex]

[tex]\Rightarrow 0=-16t^2+40[/tex]

[tex]\Rightarrow 40=16t^2[/tex]

[tex]\Rightarrow t=\sqrt{\frac{40}{16}}[/tex]

[tex]\Rightarrow t=\frac{\sqrt{40}}{4}[/tex]

[tex]\Rightarrow t=\frac{2\sqrt{10}}{4}[/tex]

[tex]\Rightarrow t=\frac{\sqrt{10}}{2}[/tex]

[tex]\Rightarrow t=1.58\ s[/tex]

Thus cone take 1.58 s to reach ground

Answer & Step-by-step explanation:

First, we will multiply 5 by 28 to find out the total number of ages in the room.

5 * 28 = 140

Now, we will multiply 6 by 29 to find out the total number of ages in the room after the new person comes in.

6 * 29 = 174

Now, in order for us to find the age of the new person, then we will subtract 140 from 174.

174 - 140 = 34

So, the person that entered the room is 34 years old.

Answer:

34

Step-by-step explanation:

Answer:

The combination that gives the most profit is 12 VIP rings and 12 SST rings (900 $/day).

Step-by-step explanation:

This is a linear programming problem.

The objective function is profit R, which has to be maximized.

[tex]R=40V+35S[/tex]

being V: number of VIP rings produced, and S: number of SST rings produced.

The restrictions are

- Amount of rings (less or equal than 24 a day):

[tex]V+S\leq24[/tex]

- Amount of man-hours (up to 60 man-hours per day):

[tex]3V+2S\leq60[/tex]

- The number of rings of each type is a positive integer:

[tex]V, \;S\geq 0[/tex]

This restrictions can be graphed and then limit the feasible region. The graph is attached.

We get 3 points, in which 2 of the restrictions are saturated. In one of these three points lies the combination of V and S that maximizes profit.

The points and the values for the profit function in that point are:

Point 1: V=0 and S=24.

[tex]R=40V+35S=40\cdot 0+35\cdot 24=0+840\\\\R=840[/tex]

Point 2: V=12 and S=12

[tex]R=40V+35S=40\cdot 12+35\cdot 12=480+420\\\\R=900[/tex]

Point 3: V=20 and S=0

[tex]R=40V+35S=40\cdot 20+35\cdot 0=800+0\\\\R=800[/tex]

The combination that gives the most profit is 12 VIP rings and 12 SST rings (900 $/day).

Answer:

The number of students who attend music club only is 13.

Step-by-step explanation:

The three different types of clubs are:

D = drama club

M = music club

S = sports club

The information provided is:

n (M) = 39

n (D) = 35

n (Exactly 2 clubs) = 26

Consider the Venn diagram attached.

From the Venn diagram it is clear that 13 students attended the Music club only.

Thus, the number of students who attend music club only is 13.

Answer:

need more info

Step-by-step explanation:

need more info

Answer:

Null hypothesis:[tex]\mu \geq 6[/tex]

Alternative hypothesis:  [tex] \mu <6[/tex]

For this case after conduct the one lower tail test we got the following p value:

[tex] p_v = P(t <-1.68) = 0.0465[/tex]

And for this case if we want to conduct a bilateral test or two sided the sytem of hypothesis are:

Null hypothesis:[tex]\mu = 6[/tex]

Alternative hypothesis:  [tex] \mu \neq 6[/tex]

And for this case the p value can be calculated like this:

[tex] p_v = 2* P(t <-1.68) =2* 0.0465= 0.0930[/tex]

Step-by-step explanation:

For this case we are trying to proof the following system of hypothesis:

Null hypothesis:[tex]\mu \geq 6[/tex]

Alternative hypothesis:  [tex] \mu <6[/tex]

For this case after conduct the one lower tail test we got the following p value:

[tex] p_v = P(t <-1.68) = 0.0465[/tex]

And for this case if we want to conduct a bilateral test or two sided the sytem of hypothesis are:

Null hypothesis:[tex]\mu = 6[/tex]

Alternative hypothesis:  [tex] \mu \neq 6[/tex]

And for this case the p value can be calculated like this:

[tex] p_v = 2* P(t <-1.68) =2* 0.0465= 0.0930[/tex]

Answer:

64

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh

A = 1/2 (16) *8

A =64

Answer:

[tex]64[/tex]

Step-by-step explanation:

[tex]area \\ = \frac{1}{2} \times b \times h \\ = \frac{1}{2} \times 16 \times 8 \\ = 64[/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

t = 4.26

Step-by-step explanation:

Sample, n = 453

Proportion, x = 60%

Required

Test Statistic

Test statistic is calculated as follows

t = (x - p)/(σ/√n)

Where σ = √p(1 - p)

When an experiment is conducted repeatedly, the results moves close to the expected value (Law of large numbers).

Hence p = 0.5

Calculating σ

σ = √p(1 - p)

σ = √0.5(1 - 0.5)

σ = √(0.5 * 0.5)

σ = √0.5²

σ = 0.5

So,

t = (x - p)/(σ/√n) becomes

t = (60% - 0.5)/(0.5/√453)

t = (0.6 - 0.5)/(0.5/√453)

t = (0.1)/(0.5/21.28)

t = 0.1 * 21.28/0.5

t = 2.128/0.5

t = 4.256

t = 4.26 ---- Approximated

Answer:

Answer is A

Step-by-step explanation:

100× x is 100x

100 × 10 is 1000

Answer:

A is the answer

Step-by-step explanation:

PLZZZ give me brainliest

Answer:

Project B is preferable solely from the standpoint of expected monetary return.

Step-by-step explanation:

Calculations of Expected Returns:

Project A:

Net Profits             Probability          Expected Returns:

GHȼ 20,000.00    0.2                      GHȼ 4,000

GHȼ 30,000.00    0.4                      GHȼ 12,000

GHȼ 50,000.00    0.4                      GHȼ 20,000

Total Expected Returns                   GHȼ 36,000

Project B:

Net Profits             Probability          Expected Returns:

GHȼ 100,000         0.5                      GHȼ 50,000

GHȼ 0.00               0.5                      GHȼ 0.00

Total Expected Returns                   GHȼ 50,000

Expected Returns are the returns or income which have been weighed with their probabilities of occurrence.  It is used to determine the best outcome given events that have different probabilities of occurring.   It is an important measure of returns which helps in deciding the best investment option to pursue.

Answer:

This is what I found on the internet

Step-by-step explanation:

2019 LEGISLATIVE RECORD OF THE HOUSE OF REPRESENTATIVES TO DATE

11/27/19

The House has passed MORE THAN 275 BIPARTISAN BILLS this Congress that are stuck in the Senate, where Mitch McConnell refuses to bring them for a vote.

This includes bipartisan legislation to:

Give American workers a long overdue raise by raising the minimum wage and making sure women are paid fairly for their work.

Protect the retirement of Americans who worked hard all their lives.

Enact gun safety background checks.

Cut taxes for Gold Star families.

Protect consumers from being ripped off by fine print contracts.

Protect people with pre-existing conditions, reverse health care sabotage & lower drug costs.

Support veterans.

BY THE NUMBERS

The House has passed nearly 400 bills this Congress. More than 300 bills, or 80% of the bills the House has passed, are stuck in the Senate, where McConnell refuses to bring them for a vote. Most ofthe bills that are stalled in the Senate,more than 275, are bipartisan.

Examples of Bipartisan Bills McConnell is Refusing to Act on Include:

H.R.5, Equality Act

H.R.6, The American Dream and Promise Act

H.R.7, Paycheck Fairness Act

H.R.8, Bipartisan Background Checks Act

H.R.9, Climate Action Now Act

H.R.987, Protecting People With Pre-Existing Conditions/Lowering Drug Costs

H.R.582, Raise The Wage Act

H.R.397, Rehabilitation For Multiemployer Pensions Act (The Butch Lewis Act)

H.R.1585, Violence Against Women Reauthorization Act

H.R.1644, Save The Internet Act

H.R 2722, Securing America’s Federal Elections (SAFE) Act

H.R.2513, The Corporate Transparency Act

H.R.1112, Enhanced Background Checks

H.R.1994, Secure Act/Gold Star Family Tax Relief Act

H.R.205, 1146, 1941 – Banning Offshore Drilling on Atlantic, Pacific, Eastern Gulf & ANWR Coasts

H.R.1423, Forced Arbitration Injustice Repeal (FAIR) Act

More than 30 bills to support veterans

Other Examples of Bills McConnell is Refusing to Act on that Democrats Support:

H.R.1, For The People Act

H.R.4617, Stopping Harmful Interference in Elections for a Lasting Democracy (SHIELD) Act

H.R.1500, Consumers First Act

Answer:

The correct conclusion is:

"The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches."

Step-by-step explanation:

A doctor is measuring the average height of male students at a large college.

The doctor measures the heights, in inches, of a sample of 40 male students from the baseball team.

Using this data, the doctor calculates the 95% confidence interval (63.5, 74.4).

The following conclusions is valid:

"The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches."

Since we know that the confidence interval represents an interval that we can guarantee that the target variable will be within this interval for a given confidence level.  

For the given case, the confidence level is 95% and the corresponding confidence interval is (63.5, 74.4) which represents the true mean of heights for male students at the college where the doctor measured heights.

Therefore, it is valid to conclude that the doctor is 95% confident that the mean height of male students at the college is within the interval of (63.5, 74.4).

Answer:

x = -1

Step-by-step explanation:

32(-1)+20=28(-1)-16(-1)

-32+20=-28+16

-12=-12

Answer:

63,616

Step-by-step explanation:

use long repeated addition or multiply

Answer:

We conclude that the true average percentage of Silicon Dioxide is smaller than 5.5.

Step-by-step explanation:

We are given that the desired percentage of Silicon Dioxide (SiO2) in a certain type of aluminous cement is 5.5.

16 independently obtained samples are analyzed and a sample mean of 5.25 was obtained. Suppose that the percentage of SiO2 in a sample is normally distributed with a sigma of 0.3.

Let [tex]\mu[/tex] = true average percentage of Silicon Dioxide.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] [tex]\geq[/tex] 5.5     {means that the true average is greater than or equal to 5.5}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < 5.5     {means that the true average is smaller than 5.5}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

                            T.S. =  [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]  ~ N(0,1)

where, [tex]\bar X[/tex] = sample mean percentage of Silicon Dioxide = 5.25

            σ = population standard deviation = 0.3

            n = sample size = 16

So, the test statistics  =  [tex]\frac{5.25-5.5}{\frac{0.3}{\sqrt{16} } }[/tex]

                                      =  -3.33

The value of z test statistics is -3.33.

Now, the P-value of the test statistics is given by;

                P-value = P(Z < -3.33) = 1 - P(Z [tex]\leq[/tex] 3.33)

                              = 1 - 0.9996 = 0.0004

Since, the P-value of the test statistics is less than the level of significance as 0.0004 < 0.01, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the true average percentage of Silicon Dioxide is smaller than 5.5.

Answer:

The true average percentage of Silicon Dioxide (SiO2) is less than 5.5.

Step-by-step explanation:

In this case we need to test whether the true average percentage of Silicon Dioxide (SiO2) in a certain type of aluminous cement is smaller than 5.5.

The hypothesis can be defined as follows:

H₀: The true average percentage of Silicon Dioxide (SiO2) is 5.5, i.e. μ = 5.5.

Hₐ: The true average percentage of Silicon Dioxide (SiO2) is less than 5.5, i.e. μ < 5.5.

The information provided is:

[tex]\bar x=5.25\\\sigma=0.30\\n=16\\\alpha =0.01[/tex]  

As the population standard deviation is provided, we will use a z-test for single mean.

Compute the test statistic value as follows:

 [tex]z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}=\frac{5.25-5.5}{0.30/\sqrt{16}}=-3.33[/tex]

The test statistic value is -3.33.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

Compute the p-value for the two-tailed test as follows:

[tex]p-value=P(Z<-3.33)=0.00043[/tex]  

*Use a z-table for the probability.

The p-value of the test is 0.00043.

p-value = 0.00043 < α = 0.05

The null hypothesis will be rejected at 5% level of significance.

Thus, it can be concluded that the true average percentage of Silicon Dioxide (SiO2) is less than 5.5.

Answer:

Step-by-step explanation:

Bring to one side

x^2-12x+y^2-8y+27=0

Complete the square

(x^2-12x+A)+(y^2-8y+B)=-27

Answer:

First option is the correct answer

The equation of the circle is: [tex](x-6)^2+(y-4)^2= 25[/tex]

The center is at (6, 4), and the radius is 5 units.

Step-by-step explanation:

[tex]x^{2} -12x+27=-y^2 +8y\\\\x^{2} -12x+27+y^2 -8y=0\\(x^{2} -12x+36)-36+27+(y^2 -8y +16)-16=0\\(x^{2} -12x+6^2)+(y^2 -8y +4^2)-25=0\\(x-6)^2+(y-4)^2= 25\\(x-6)^2+(y-4)^2= 5^2\\Equating\: it \: with\\(x-h)^2+(y-k)^2= r^2\\we\:find:\\Center = (h,\:k) = (6,\:4)\\Radius \:(r) = 5[/tex]

Answer:

a = 15

Step-by-step explanation:

Perhaps your question is:

[tex] 4^{12}= 4^{a-3}[/tex]

If it is so then let us solve:

[tex] 4^{12}= 4^{a-3}[/tex]

Since, bases are equal hence exponents will also be equal. Therefore,

12 = a - 3

12 + 3 = a

a = 15

Answer:

As x gets smaller, pointing to negative infinity, the value of p increases, pointing to positive infinity.

As x increases, pointing to positive infinity, the value of p increases, pointing to positive infinity.

Step-by-step explanation:

To find the end behaviour of a function f(x), we calculate these following limits:

[tex]\lim_{x \to +\infty} f(x)[/tex]

And

[tex]\lim_{x \to -\infty} f(x)[/tex]

At negative infinity:

[tex]\lim_{x \to -\infty} (4x^{8} - 6x^{7} + 3x^{3} - 10)[/tex]

When the variable points to infinity, we only consider the term with the highest exponent. So

[tex]\lim_{x \to -\infty} (4x^{8} - 6x^{7} + 3x^{3} - 10) = \lim_{x \to -\infty} 4x^{8} = 4*(-\infty)^{8} = \infty[/tex]

Plus infinity, because the exponent is even.

So as x gets smaller, pointing to negative infinity, the value of p increases, pointing to positive infinity.

At positive infinity:

[tex]\lim_{x \to \infty} (4x^{8} - 6x^{7} + 3x^{3} - 10) = \lim_{x \to \infty} 4x^{8} = 4*(\infty)^{8} = \infty[/tex]

As x increases, pointing to positive infinity, the value of p increases, pointing to positive infinity.

Answer:

A - As x -> infinity, p(x) -> infinity, and as x -> -infinity, p(x) -> infinity.

Step-by-step explanation:

Answer:

Step-by-step explanation:

Hello!

Full text

In a national survey college students were​ asked, "How often do you  wear a seat belt when riding in a car driven by someone​ else?" The response frequencies appear in the table to the right.​ (a) Construct a probability model for​ seat-belt use by a passenger.​ (b) Would you consider it unusual to find a college student who never wears a seat belt when riding in a car driven by someone​ else?

Response , Frequency  

Never  102

Rarely  319

Sometimes  524

Most of the time  1067

Always  2727

n= 102+319+524+1067+2727= 4739

​(a) Complete the table below.

Response

Probability  To calculate the probability for each response you have to divide the frequency of each category by the total of people surveyed:

Never P(N)= 102/4739= 0.0215

​(Round to the nearest thousandth as​ needed.)

Rarely P(R)= 319/4739= 0.0673

​(Round to the nearest thousandth as​ needed.)

Sometimes P(S)= 524/4739= 0.1106

​(Round to the nearest thousandth as​ needed.)

Most of the time  P(M)= 1067/4739= 0.2252

​(Round to the nearest thousandth as​ needed.)

Always  P(A)= 2727/4739= 0.5754

​(Round to the nearest thousandth as​ needed.)

​(b) Would you consider it unusual to find a college student who never wears a seat belt when riding in a car driven by someone​ else?

A.

​No, because there were 102  people in the survey who said they never wear their seat belt. Incorrect, an event is considered unusual if its probability (relative frequency) is low, you cannot know if it is usual or unusual just by looking at the absolute frequency of it.

B.

​Yes, because ​P(never) < 0.05. Correct

C.

​No, because the probability of an unusual event is 0.    Incorrect, the probability of unusual events is low, impossible events are the ones with probability zero

D.

​Yes, because 0.01 < ​P(never) <  0.10. Incorrect, by the definition an event is considered unusual when its probability is equal or less than 5%.

I hope this helps!

Answer:

Question 1:

A) Parallelogram

B) Right Angled Triangle

Question 2:

Using parallelogram to use properties of parallel lines. To find whether a quadrilateral is parallelogram, first we will write it's coordinates. After writing coordinates, we find slope of each line by slope formula. After this , we compare the slope of equal lines through which we come to know whether they are parallel to eachother or not. After that, if two pairs of lines are parallel, then the given quadrilateral is a parallelogram.

Answer:

Center = (5, 0)

Radius = 9

Step-by-step explanation:

Look at the picture

The radius of the circle is 9units and the center of the circle is at (5, 0)

The standard equation of a circle is expressed as:

(x-a)^2+(y-b)^2 = r^2

where

r is the radius of the circle

(a, b) is the centre of the circle

GIven the equation is (x – 5)² + y² = 81.

Compare both equations

a = 5, b = 0

r^2 = 81

r = 9units

Hence the radius of the circle is 9units and the center of the circle is at (5, 0)

Learn more on equation of circle here: https://brainly.com/question/14150470

Answer:

D

Step-by-step explanation:

i did the assignment.

The correct solution of the system of the equation is -3y = 3.

The correct option is D.

One or many equations having the same number of unknowns that can be solved simultaneously called as simultaneous equation. And simultaneous equation is the system of equation.

Given:

A system of equations,

x – 5y = 6    {equation 1}

–x + 2y = –3    {equation 2}

In order to solve the equations, using linear combination method.

Combining the two equations 1 and 2 to eliminate one of the variables x.

Adding both the equations,

-3y = 3

y = -1.

Therefore, –3y = 3 is the solution.

To learn more about the system of equation;

brainly.com/question/13729904

#SPJ6

Answer:

d) The additional training did not significantly lower the defect rate

Step-by-step explanation:

Let proportion of defective chips be = x

Null Hypothesis [H0] : Additional training has no impact on defect rate             x = 8% = 0.08

Alternate Hypothesis [H1] : Additional training has impact on defect rate          x < 8% , x < 0.08  

Observed x proportion (mean) : x' = 27 / 450 = 0.06

z statistic = [ x' - x ]  / √ [ { x ( 1-x ) } / n ]

( 0.06 - 0.08 ) /  √ [ 0.08 (0.92) / 450 ]

= -0.02 / √ 0.0001635  

= -0.02  / 0.01278

z = - 1.56

Since calculated value of z, 1.56 < tabulated value of z at assumed 0.01 significance level, 2.33

Null Hypothesis is accepted, 'training didn't have defect rate reduction impact' is concluded