Answer:
[tex]F=1.334*10^-^6[/tex]
Explanation:
From the question we are told that
Mass of Dylan [tex]M_d=75kg[/tex]
Mass of Sarah [tex]M_s=54kg[/tex]
Centers separated by[tex]C=0.45m[/tex]
Generally the equation for solving gravitational force is given by
[tex]F=\frac{G*m_1m_2}{r^2}[/tex]
[tex]F=\frac{6.67*10^-^1^1*75*54}{(0.45)^2}[/tex]
[tex]F=1.334*10^-^6[/tex]
Therefore Gravitational force is given as
[tex]F=1.334*10^-^6[/tex]
On a circular racetrack with a radius of 3.23 m, a certain road car set a speed record of 3.72
m/s. If the car had a mass of 250 kg, what was the net force acting on it?
Answer:
F = 1071.08 N
Explanation:
Given that,
The radius of the circular track, r = 3.23 m
Speed of the car, v = 3.72 m/s
The mass of the car, m = 250 kg
We need to find the net force acting on it. The centripetal force will act on it and it is given by the relation as follows :
[tex]F=\dfrac{mv^2}{r}\\\\F=\dfrac{250\times (3.72)^2}{3.23}\\\\F=1071.08\ N[/tex]
So, the net force acting on the car is 1071.08 N.
If she returned home by the same path 7 h 30 min after she left, what were her average speed and velocity in km/h for the entire trip
Answer:
speed v = 0.148 m / s
velocity v = 0
Explanation:
In this exercise we must be careful that the speed is a scalar and the speed is a vector, let's start by looking for the speed
v = Δx /Δt
the distance traveled is x = 2d and the time taken is
t = 7h 30 min
let's reduce to seconds
t = 7 h 3600s / 1h + 30 min 60s / 1min = 27000 s
so the speed is
v = 2d / 27000
to finish the calculation suppose a distance traveled d = 2000 m
v = 2 2000/27000
v = 0.148 m / s
this is the raides which is the speed module
Velocity is a vector,
v = Dx / Dt
in this case the displacement is
Dx = d -d
Dx = 0
the total displacement is zero since it returns to the starting point, consequently the velocity is zero
v = 0
bold is a vector
Which is another way of saying the law of conservation of mass?
The mass of the reactants always equals the mass of the products.
Matter cannot be created or destroyed.
the law of conservation of matter
all of the above
Answer:is there a 1 2 3 4 answer?
Explanation:
A birthmark is generally a:
macule.
excoriation.
pustule.
bullae.
Answer:
macule
Explanation:
its aa flat round areausually distingurished from its surroundung skin by its changed in color. smaller than 1cm am small hemorrhage spot.
What is the Potential Energy of a spring stretched 5.0 cm that has a
spring constant of 79 N/m?
Answer:
The Potential Energy of the stretched spring is = 1.975 J
Explanation:
Recall that the potential energy of a spring of constant k stretched x\a distance x is given by the formula:
U = 1/2 k x^2
Therefore in our case, converting the stretch from cm of meters (0.05 m), this is
U = 1/2 * 79 * 0.05 J = 1.975 J
How much heat Q2Q2 is transferred to the skin by 25.0 gg of steam onto the skin? The heat of vaporization for steam is L=2.256×106J/kgL=2.256×106J/kg.
Answer:
56400Joules
Explanation:
The quantity of heat required is expressed as;
Q = mL
m is the mass = 25g = 0.025kg
L is the latent heat of vaporization for steam = 2.256×10^6J/kg
Substitute into the formula as shown;
Q = 0.025×2.256×10^6
Q = 56400Joules
Hence the quantity of hear required is 56400Joules
The amount of heat transfer from the steam is of 56400 J.
Given data:
The mass of steam is, m = 25.0 g = 0.025 kg.
The latent heat of vaporization of steam is, [tex]L = 2.256 \times 10^{6} \;\rm J/kg[/tex].
When heat is to be given to a unit mass of substance to converts it from a liquid phase to vapor phase. Then it is known as Latent heat of vaporization. The amount of heat is expressed as,
[tex]Q = m \times L[/tex]
Solving as,
[tex]Q = 0.025 \times (2.256 \times 10^{6})\\\\Q = 56400 \;\rm J[/tex]
Thus, we can conclude that the amount of heat transfer from the steam is of 56400 J.
Learn more about the Latent heat of vaporization here:
https://brainly.com/question/24203857
A particle moves in a circle 1.50 m in radius. Through what angle in radians does it rotate if it moves through an arc length of 2.50 m
Answer:
95.7 degrees
Explanation:
The angle through which the particle rotate in radians is 1.667 rad.
Given the following data:
Radius of circle = 1.50 meterArc length = 2.50 meters.To determine the angle through which the particle rotate in radians:
Mathematically, the angular displacement or arc length in circular motion is given by the formula:
[tex]S=r\theta[/tex]
Where:
S is the angular displacement or arc length.r is the radius.[tex]\theta[/tex] is the angle measured in radians.Making [tex]\theta[/tex] the subject of formula, we have:
[tex]\theta=\frac{S}{r}[/tex]
Substituting the given parameters into the formula, we have;
[tex]\theta = \frac{2.50}{1.50} \\\\\theta =1.667 \;rad[/tex]
Read more: https://brainly.com/question/8898885
54:29
Mason notices that his boat sinks lower into the water in a freshwater lake than in the ocean. What could explain
this?
The boat is more dense in salt water.
The boat is less dense in salt water.
Salt water is less dense than freshwater
O Salt water is more dense than freshwater
Save and Exit
Sube
Mark this and retum
Answer:
Salt water is more dense than freshwater
Explanation:
The only and best explanation for this phenomenon for this occurrence is that salt water is more dense than freshwater.
Density is the mass per unit volume of a substance. When a substance is A more dense than the other substance B, B will float on A. So, the density of the salt water is higher than that of the fresh water because it has more particles per unit volume compared to fresh water. Therefore, the boat will go farther into the fresh water compared to the salt water.Match each disease to the correct pathogen type
Protist:
Virus:
Fungus:
A) AIDS
B) Histoplasmosis
C) Amoebic dysentery
Answer:
Protist: C) Amoebic dysentery
Virus: A) AIDS
Fungus: B) Histoplasmosis
Hope that helps
The electrical resistance of a circuit is influenced by the _____, _____, and _____ of the wires.
Answer:
Length, gauge/size and composition
Explanation:
The longer the wire is the more resistance
The thinner the wire is more resistance
The difference in material effects the resistance ie. copper versus aluminium.
Which statements compare linear and angular momentum? Check all that apply.
Both measure the tendency of objects to resist a change in motion.
Both are affected by the mass of the object in motion.
Both are affected by the distribution of mass relative to an axis.
Both involve velocity.
Both involve rotation.
Answer:
A,B,D
Explanation:
cause ik
A horse is working steadily, providing 750 W of output power. How much food energy does the horse need to work for 1 hour, to the nearest MJ
Answer:
Under assumption that all food energy that needs the horse is transformed into work, then the horse needs approximately 3 megajoules of food energy to work for 1 hour.
Explanation:
Since horse is working steadily, the power experimented by the horse ([tex]\dot W[/tex]), measured in watts, is at constant rate. Then, the work needed by the horse ([tex]W[/tex]), measured in joules, is equal to that power multiplied by time ([tex]\Delta t[/tex]), measured in seconds. That is:
[tex]W = \dot W\cdot \Delta t[/tex] (1)
If we know that [tex]\dot W = 750\,W[/tex] and [tex]\Delta t = 3600\,s[/tex], then the work needed for the horse is:
[tex]W = (750\,W)\cdot (3600\,s)[/tex]
[tex]W = 2.7\times 10^{6}\,J[/tex]
[tex]W = 2.7\,MJ[/tex]
Under assumption that all food energy that needs the horse is transformed into work, then the horse needs approximately 3 megajoules of food energy to work for 1 hour.
what is rhe average velocity od a baseball dropped from rest that falls for 2 seconds?
Answer:
19.6m/s
Explanation:
Given parameters:
Initial velocity = 0m/s
Time = 2s
Unknown:
Average velocity = ?
Solution:
We can use the final velocity of the ball before landing to determines its average velocity ;
Using;
v = u + gt
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
t is the time
v = 0 + 9.8 x 2 = 19.6m/s
a proton travelling along is x-axis is slowed by a uniform electric field E. at x = 20.0 cm, the proton has a speed of 3.5x10^6 m/s and at 80.0 cm the speed is zero. Determine the magnitude and direction of e,
Answer:
[tex]E=101955.8volt/m[/tex]
The electric field direction is toward the right
Explanation:
From the question we are told that
Initial X-co-ordinate of proton [tex]X_1=20.0cm => \frac{20}{100}m[/tex]
Initial speed of Proton [tex]V_1= 3.5*10^6 m/s[/tex]
Final X-co-ordinate of proton [tex]X_2=80.0cm => \frac{80.0}{100}m[/tex]
Final speed of Proton [tex]V_2=0[/tex]
Generally the mass of Proton is given by
[tex]m_P=1.67*10^-27[/tex]
Generally the kinetic energy of the proton is mathematically given by
[tex]K.E_p=1/2mv^2[/tex]
[tex]K.E_p=1/2*1.6*10^-^2^7*(3.5*10^6)^2[/tex]
[tex]K.E_p=9.8*10^-^1^5[/tex]
Generally the change in electric potential [tex]\triangle V[/tex] is mathematically given by
[tex]\triangle V =\frac{K.E_p}{q}[/tex]
Charge on a proton [tex]q=1.602*10^-^1^9[/tex]
[tex]\triangle V =\frac{9.8*10^-^1^5}{1.602*10^-^1^9}[/tex]
[tex]\triangle V =61173.5volts[/tex]
Generally the equation for magnitude of an electric field is mathematically given by
[tex]E=\frac{\triangle V}{\triangle d}[/tex]
Where
[tex]d=0.8m-0.2m\\d=0.6m[/tex]
Therefore
[tex]E=\frac{61173.5}{0.8-0.2}[/tex]
[tex]E=\frac{61173.5}{0.6}[/tex]
[tex]E=101955.8volt/m[/tex]
The direction of the charge is towards the right
How much power is produced by flashlight that has a voltage of 12 volts and a current of 6.5 x 10^-2 amps? A. 0.78 watts B. 78 watts C. 190 watts D. 0.0054 watts E. 1.9 watts
Answer:
the powar produced is 0.7 watts
An Olympian lifts a 1,375-kilogram set of weights a vertical distance of 2 meters in the weightlifting event.
The force of gravity equals 9.8 m/s. What is the potential energy of the weights?
Answer:
PE = MGH. 1375 x 9.8 x 2. = 26950 joules
Explanation:
First do 1375 x 9.8 which is MG then times it by 2 which is H
Mass x Gravity x Height
the gravity will always be 9.8
I would love a brainliest
The the potential energy of the weights lifted 2 meters above the surface is E[P] = 26950 joules.
What is Potential energy?The energy of a body by virtue of its position is called potential energy. Mathematically -
E[P] = mgh
Given is an Olympian who lifted a 1,375-kilogram set of weights a vertical distance of 2 meters in the weightlifting event.
We can write the given data as follows -
Mass of weights = [M] = 1375 Kg
Displacement = [h] = 2 meters
Therefore, using the formula for potential energy, we can write -
E[P] = mgh
E[P] = 1375 x 9.8 x 2
E[P] = 26950 joules
Therefore, the the potential energy of the weights lifted 2 meters above the surface is E[P] = 26950 joules.
To solve more questions on Mechanical Energy, visit the link below-
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Experiencing a "jump scare" in a frightening movie most immediately activates your:
somatic nervous system.
sympathetic nervous system.
parasympathetic nervous system.
decentralized nervous system.
Answer:
Somatic I think
Explanation:
Answer:Sympathetic nervous system
Explanation:
How much work would be needed to lift the ball from the 2-m shelf to the 5-m shelf, and how much potential energy would it have on the 5-m shelf?
Answer:
a) 2.94 N
b) 4.90 N
Explanation:
Let us assume that the weight of the ball is 0.98 N
Solution:
a) An object’s gravitational potential energy depends on two factors which are height and its weight (or mass). The equation for gravitational potential energy (PE) is given as:
Potential energy = weight (w) * height (h)
PE = wh
Potential energy at 2 m shelf = weight * height = 0.98 N * 2 m = 1.96 N
Potential energy at 5 m shelf = weight * height = 0.98 N * 5 m = 4.90 N
The work needed to lift the ball from the 2-m shelf to the 5-m shelf = Potential energy at 5 m shelf - Potential energy at 2 m shelf
The work needed to lift the ball from the 2-m shelf to the 5-m shelf = 4.90 N - 1.96 N = 2.94 N
b) Potential energy at 5 m shelf = weight * height = 0.98 N * 5 m = 4.90 N
Sound waves are simultaneously interpreted through air (going through the external,
middle, then inner ear) and through the bone in the inner ear, stimulating the
acoustic nerve.
True
False
Answer:
its true
Explanation:
i took it
Migration is the seasonal movement of a population of organisms from one place to another True or false
Answer:
true lol its jist common sense
Answer: Seasonal migration is the movement of various species from one habitat to another during the year. Resource availability changes depending on seasonal fluctuations, which influence migration patterns. ... Many species, especially birds, migrate to warmer locations during the winter to escape poor environmental conditions.
Explanation:
A 2.5 kg tribble is placed in a bucket and whirled in a 1.4 m radius vertical circle at a constant tangential speed. If the force on the tribble from the bucket does not exceed 10 times its weight (tribbles are a hardy species), the maximum tangential speed is
Given that,
Mass of a tribble, m = 2.5 kg
Radius, r = 1.4 m
The force on the tribble from the bucket does not exceed 10 times its weight.
To find,
The maximum tangential speed.
Solution,
The force acting on the tribble is equal to the centripetal force.
F = 10mg
The formula for the centripetal force is given by :
[tex]F=\dfrac{mv^2}{r}[/tex]
v is maximum tangential speed
[tex]v=\sqrt{\dfrac{Fr}{m}} \\\\v=\sqrt{\dfrac{mgr}{m}} \\\\v=\sqrt{{10gr}} \\\\v=\sqrt{10\times 9.8\times 1.4} \\\\v=11.7\ m/s[/tex]
So, the maximum tangential speed is 11.7 m/s.
The five general principles from the APA are meant to __________. A. be enforceable rules B. be posted in every office C. guide and inspire good conduct D. stand up in court Please select the best answer from the choices provided
The five general principles from the APA are meant to: C. Guide and inspire good conduct.
Help please !
Which nucleotides form an RNA molecule?
Choose all that apply:
1) Adenine (A)
2) Uracil (U)
3) Thymine (T)
4) Cytosine (C).
Answer:
1) Adenine (A) 2. Uracil (U) 4) Cytosine (C)
Explanation:
"RNA consists of four nitrogenous bases: adenine, cytosine, uracil, and guanine."
An electric motor spins at 1000 rpm and is slowing down at a rate of 10 t rad/s2 ; where t is measured in seconds. (a) If the motor radius is 7.165 cm, what is the tangential component of acceleration at the edge of the motor at t = 1.5 seconds? (b) How long will it take, in seconds, to decrease its angular velocity by 75%?
Answer:
a) The tangential component of acceleration at the edge of the motor at [tex]t = 1.5\,s[/tex] is -1.075 meters per square second.
b) The electric motor will take approximately 3.963 seconds to decrease its angular velocity by 75 %.
Explanation:
The angular aceleration of the electric motor ([tex]\alpha[/tex]), measured in radians per square second, as a function of time ([tex]t[/tex]), measured in seconds, is determined by the following formula:
[tex]\alpha = -10\cdot t\,\left[\frac{rad}{s^{2}} \right][/tex] (1)
The function for the angular velocity of the electric motor ([tex]\omega[/tex]), measured in radians per second, is found by integration:
[tex]\omega = \omega_{o} - 5\cdot t^{2}\,\left[\frac{rad}{s} \right][/tex] (2)
Where [tex]\omega_{o}[/tex] is the initial angular velocity, measured in radians per second.
a) The tangential component of aceleration ([tex]a_{t}[/tex]), measured in meters per square second, is defined by the following formula:
[tex]a_{t} = R\cdot \alpha[/tex] (3)
Where [tex]R[/tex] is the radius of the electric motor, measured in meters.
If we know that [tex]R = 7.165\times 10^{-2}\,m[/tex], [tex]\alpha = 10\cdot t[/tex] and [tex]t = 1.5\,s[/tex], then the tangential component of the acceleration at the edge of the motor is:
[tex]a_{t} = (7.165\times 10^{-2}\,m)\cdot (-10)\cdot (1.5\,s)[/tex]
[tex]a_{t} = -1.075\, \frac{m}{s^{2}}[/tex]
The tangential component of acceleration at the edge of the motor at [tex]t = 1.5\,s[/tex] is -1.075 meters per square second.
b) If we know that [tex]\omega_{o} = 104.720\,\frac{rad}{s}[/tex] and [tex]\omega = 26.180\,\frac{rad}{s}[/tex], then the time needed is:
[tex]26.180\,\frac{rad}{s} = 104.720\,\frac{rad}{s}-5\cdot t^{2}[/tex]
[tex]5\cdot t^{2} = 104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s}[/tex]
[tex]t^{2} = \frac{104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s} }{5}[/tex]
[tex]t = \sqrt{\frac{104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s} }{5} }[/tex]
[tex]t \approx 3.963\,s[/tex]
The electric motor will take approximately 3.963 seconds to decrease its angular velocity by 75 %.
Beams of light undergo construction interference when two different beams intersect to form one brighter beam of light . Which model of the nature of light dose this behavior?
Answer:the wave model
Explanation:
My dog Ubu can run at 21 mi/h. How far can he travel in 40 minutes?
Answer:
14
Explanation:
21miles/3=7
7*2=14
What is the Pythagorean Theorem used to find and what must you have to use it?
a. magnitude, fight triangle
b. direction, right triangle
c. magnitude, parallelogram
d. direction, parallelogram
Answer:
A
Explanation:
During which season of the year will your nails grow most quickly?
summer
spring
fall
winter
Answer:
summer
Explanation:
If you live in the southern hemisphere, what season would you be experiencing in position C this diagram?
A)
Fall
B)
Summer
C)
Winter
D)
Spring
The alarm at a fire station rings and a 87.5-kg fireman, starting from rest, slides down a pole to the floor below (a distance of 4.10 m). Just before landing, his speed is 1.75 m/s. What is the magnitude of the kinetic frictional force exerted on the fireman as he slides down the pole?
Answer:
[tex]F_f=840N[/tex]
Explanation:
From the question we are told that
Weight of fireman [tex]W_f= 87.5kg[/tex]
Pole distance [tex]D=4.10m[/tex]
Final speed is [tex]V_f 1.75m/s[/tex]
Generally the equation for velocity is mathematically represented as
[tex]v^2 = v_0^2 + 2 a d[/tex]
Therefore Acceleration a
[tex]a'= v^2 / 2 d[/tex]
[tex]a'= 0.21m/s^2[/tex]
Generally the equation for Frictional force [tex]F_f[/tex] is mathematically given as
[tex]F_f=m*a[/tex]
[tex]F_f=m*(g-0.21)[/tex]
[tex]F_f=87.5*(9.81-0.21)[/tex]
Therefore
[tex]F_f=840N[/tex]