What is the frequency of a photon with an energy

Answer: I believe the answer is A

Answer:

0.01 M

Explanation:

The chemist is performing a serial dilution in order tyo obtain the calibration curve for the instrument.

First we must obtain the concentration of the solution in the 250ml flask from

C1V1 = C2V2

Where;

C1 = concentration of the stock solution

V1 = volume of the stock solution

C2 = concentration of the diluted solution

V2= volume of the diluted solution

2.61 × 10 = C2 × 250

C2 = 2.61 × 10/250

C2 = 0.1 M

Hence for solution in 100ml flask;

0.1 × 10 = C2 × 100

C2 = 0.1 × 10/100

C2 = 0.01 M

Answer:

it is a compound

Explanation: i have it on a test

Answer:

the answer is 53.524 kg

Answer:

a model?

Explanation:

im not sure! i think so

Answer:

Yes, It is a model

Explanation:

A complex idea or a process can be demonstarated by using a Model because you can see things easier and its basically a copy of anything from forests to volcanoes but smaller to make it easier to see.

Hope This Helps

Answer:

Mass of water produced is 22.86 g.

Explanation:

Given data:

Mass of hydrogen = 2.56 g

Mass of oxygen = 20.32 g

Mass of water = ?

Solution:

Chemical equation:

2H₂ + O₂   →  2H₂O

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 20.32 g/ 32 g/mol

Number of moles = 0.635 mol

Number of moles of hydrogen:

Number of moles = mass/ molar mass

Number of moles = 2.56 g/ 2 g/mol

Number of moles = 1.28 mol

Now we will compare the moles of water with oxygen and hydrogen.

                    O₂            :            H₂O

                     1              :             2

                  0.635        ;            2×0.635 =  1.27

                   H₂             :              H₂O

                    2              :              2

                 1.28            :           1.28

The number of  moles of water produced by oxygen are less thus it will be limiting reactant.

Mass of water produced:

Mass = number of moles × molar mass

Mass = 1.27 × 18 g/mol

Mass = 22.86 g

Answer:

22.88

Explanation:

correct have a g'day mate

Answer:

C

Explanation:

its physical change.

Answer:

7.35 to 7.45

Explanation:

According to healthline.com, the average pH of blood is 7.35 to 7.45.

Answer:

The number of electrons in the outermost shell of an atom determines its reactivity.

Explanation:

Answer:

The number of electrons in the outermost shell of an atom determines its reactivity. Noble gases have low reactivity because they have full electron shells. Halogens are highly reactive because they readily gain an electron to fill their outermost shell.

Explanation:

Answer:

A.endoplamic reticulum

Explanation:

The endoplamic reticulum  is an important organelle in protein synthesis. The nucleus contains DNA, which is the template for transcription of mRNA. mRNA acts as a message, which leaves the nucleus to become translated into proteins.

The endoplasmic reticulum is important in the synthesis, folding, and modification of proteins.  

Answer:

Aluminium

Explanation:

From the question given above, the following data were obtained:

Diameter (d) = 1.25 cm

Height (h) = 6.48 cm

Volume (V) of cylindrical=.?

Mass (m) of cylindrical object = 21.535 g

Density of the cylindrical object =..?

Next, we shall determine the radius of the cylindrical object. This is illustrated below:

Diameter (d) = 1.25 cm

Radius (r) =?

r = d/2

r = 1.25/2

Radius (r) = 0.625 cm

Next, we shall determine the volume of the cylindrical object. This can be obtained as follow:

Height (h) = 6.48 cm

Radius (r) = 0.625 cm

Pi (π) = 3.14

Volume (V) of cylindrical=.?

V = πr²h

V = 3.14 × 0.625² × 6.48

V = 7.948 cm³

Recall:

1 cm³ = 1 mL

Therefore

7.948 cm³ = 7.948 mL

Thus, the volume of the cylindrical object is 7.948 mL

Finally, we shall determine the metal in which the cylindrical object is made up of by calculating the density of the cylindrical object. This can be obtained as follow:

Mass (m) of cylindrical object = 21.535 g

Volume of the cylindrical object = 7.948 mL

Density of cylindrical object =?

Density = mass /volume

Density = 21.535 / 7.948

Density of cylindrical object = 2.7 g/mL

Comparing the density of the cylindrical object (i.e 2.7 g/mL) with those given in the table in the question, the cylindrical object is made of aluminium since they have the same density.

Answer:

D-The hydrosphere looks blue and covers three-fourths of the Earth’s surface.

Explanation:

Answer:

The nitrogen atom has 5 electrons in the outermost shell, so it can accept 3 electrons to fulfil the octet structure. Therefore the valency of nitrogen is 3.

Answer:

I would place 0.5 M solution of the 6.0 stock solution to a 250 mL volumetric flask and then add 250 mL of water.

Explanation:

Answer:

is there an image

Explanation:

Answer:

C

Explanation:

Have a nice day

Answer:A. Direction

C. Resistance

Explanation:

Forces are due to an interaction of at least two objects. It may change the state of motion of an object. It may change the shape of an object. Forces applied on an object in the same direction add to one another and the resultant is in the same direction.

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Answer:

B. It undergoes phase change.

Explanation:

Answer:

The weight percent of NaCl in the container​ is 21.5%

Explanation:

Given that,

Mass of NaCl = 168.90 gram

Mass of water = 616.00 grams

We need to calculate the weight percent of NaCl in the container​

Using formula of percentage of weight

[tex]weight\ \%\  of\ component\ of\ the\ solution =\dfrac{weight\ of\ the\ component\ in\ the\ solution}{total\ weight\ of\ the\ solution}\times100[/tex]

Put the value into the formula

[tex]weight\ \%\  of\ component\ of\ the\ solution =\dfrac{168.90}{168.90+616.00}\times100[/tex]

[tex]weight\ \%\  of\ component\ of\ the\ solution=21.5\%[/tex]

Hence, The weight percent of NaCl in the container​ is 21.5%

Answer:convection

Explanation:

Answer: B. Convection

Explanation: I hope this helps! :)

Answer:

Na⁺,SO₄²⁻

Explanation:

Sodium sulfate is formed by the sodium and sulfate ion.

Sodium is present in group one thus it has only one valence electron. Sodium lose its one valence electron to get complete octet and thus form cation with +1 charge.

On other hand sulfate ion is an anion it carries -2 charge so when it react with sodium there are two sodium atom combine with one sulfate ion inorder to make the compound neutral.

2Na + SO₄²⁻  →  Na₂SO₄

Sodium sulfate is actually form when sodium react with sulfuric acid and hydrogen gas is liberated.

Chemical equation:

Na + H₂SO₄  →  Na₂SO₄ + H₂

Balance chemical equation:

2Na + H₂SO₄  →  Na₂SO₄ + H₂

Answer:

Approximately [tex]1.04\; \rm L[/tex] of the [tex]12.0\; \rm M[/tex] [tex]\rm NaOH[/tex] solution is needed. Approximately another [tex]3.96\; \rm L[/tex] of water will also be required.

Assumption: the volume of these [tex]\rm NaOH[/tex] solutions does not depend on the quantity of [tex]\rm NaOH\![/tex] (the solute) that each of them contain.

Explanation:

Calculate the number of moles of [tex]\rm NaOH[/tex] formula units in that [tex]5.00\; \rm L[/tex] of [tex]2.50\; \rm M[/tex] [tex]\rm NaOH\![/tex] solution:

[tex]n(\mathrm{NaOH}) = c\cdot V = 5.00\; \rm L \times 2.50\; \rm mol \cdot L^{-1} = 12.5\; \rm mol[/tex].

Calculate the volume of a [tex]12.0\; \rm M[/tex] [tex]\rm NaOH[/tex] with that many [tex]\rm NaOH\![/tex] formula units:

[tex]\displaystyle V = \frac{n}{c} = \frac{12.5\;\rm mol}{12.0\; \rm mol \cdot L^{-1}}\approx 1.04\;\rm L[/tex].

That should be the volume of the [tex]12.0\; \rm M[/tex] [tex]\rm NaOH[/tex] solution needed to prepare that [tex]5.00\; \rm L[/tex] of [tex]2.50\; \rm M[/tex] [tex]\rm NaOH\![/tex] solution. However, [tex]1.04\; \rm L[/tex] corresponds to only about one-fifth the volume of a [tex]5.00\; \rm L\![/tex] solution. The difference in volume should be filled with pure water:

[tex]\begin{aligned}V(\text{water}) &\approx 5.00\; \rm L - 1.04\; \rm L = 3.96\; \rm L\end{aligned}[/tex].

Answer: Sediment is important because it often enriches the soil with nutrients. Areas rich in sediments are often also rich in biodiversity. Sedimentary soil is usually better for farming. Deltas and river banks, where much sediment is deposited, are often the most fertile agricultural areas in a region.

Answer:

Compound is the answer

Answer:

Enery transformation is when a forn of energy changes into another.

Explanation:

An example of this would be a lamp. The lamp gets its energy through electricity. This electricity is later turned into light energy. Electrical energy to light evegy.

Answer:

a)

[SO2]: The concentration increases

[O2]: The concentration increases.

[SO3]: The concentration decreases.

b)

[SO2]: The concentration decreases.

[O2]: The concentration decreases.

[SO3]: The concentration increases.

c)

[SO2]:There is no change.

[O2]: There is no change.

[SO3]: There is no change

Explanation:

For an exothermic reaction, increase in temperature decreases the concentration of products and increases the concentration of reactants since increase in temperature shifts the equilibrium position to the left hand side.

Increase in pressure and decrease in volume will shift the equilibrium position towards the right hand side which means more SO3 in the system.

Catalyst increases the rate of forward and reverse reaction simultaneously hence at equilibrium, the concentration of reactants and products remain unchanged.

Answer:

true

Explanation:

Answer:

Explanation:

Given that:

P₅₀ = 20 torr in muscle

The partial pressure of O2 in lungs Po₂ = 100 torr

The hill coefficient [tex]n_h[/tex] = 3

According to the Hill coefficient;

[tex]\dfrac{\Upsilon}{1-\Upsilon}= (\dfrac{PO_2}{P_{50}})^n[/tex]

here;

[tex]\Upsilon[/tex] = fraction of haemoglobin monomers

[tex]\dfrac{\Upsilon}{1-\Upsilon}= (\dfrac{100}{20})^3[/tex]

[tex]\dfrac{\Upsilon}{1-\Upsilon}[/tex] = 125 θ lungs

However for θ muscle :

[tex](\dfrac{PO_2}{P_{50}})^n=( \dfrac{20}{20})^3[/tex]

= 125 (θ lungs) - 1 (θ muscle)

= 124

B.

if nh =1

[tex]\mathtt {\theta \ lungs} = \dfrac{\Upsilon}{1-\Upsilon}= (\dfrac{100}{20})^1[/tex]

[tex]\mathtt {\theta \ lungs} =5[/tex]

[tex]\mathtt {\theta \ muscle} = \dfrac{20}{20}^1[/tex]

(θ muscle) = 1

(θ lungs) - (θ muscle) = 5 - 1

(θ lungs) - (θ muscle) = 4

A) The efficiency of hemoglobin at O₂ delivery = 124

B) Efficiency of O₂ delivery will change by : 4  

Given data:

Partial pressure of O₂ in lungs ( PO₂ )  = 100 torr

Partial pressure of O₂ in muscle  = ( P₅₀ ) = 20 torr

Hill coefficient nh = 3

r = fraction of hemoglobin monomers

A) Determine the efficiency of hemoglobin at O₂ delivery

Given that Hill coefficient = [tex]\frac{r}{1-r} = (\frac{PO_{2} }{P_{50} } )^{n}[/tex]  

                                          = [tex]\frac{r}{1-r} = (\frac{100}{20})^{3}[/tex]  = 125 ∅ Lungs

For Muscle :

[tex](\frac{20}{20} )^{3}[/tex] =  1 ∅ muscle

Therefore the efficiency of hemoglobin at 0₂ delivery

= ( ∅ lungs - ∅ muscle )

=  ( 125 - 1 )  = 124

B )  Determine the change in efficiency of O2 delivery

when hill coefficient ( nh ) = 1

for lungs :

[tex]\frac{r}{1-r} = (\frac{100}{20})^{1}[/tex]  = 5

for muscle :

[tex](\frac{20}{20} )^{1}[/tex]   = 1

Therefore change on efficiency =  ( 5 - 1 ) = 4

Hence we can conclude that The efficiency of hemoglobin at O₂ delivery = 124 and Efficiency of O₂ delivery will change by  4  

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