What is the first step in
solving this equation?
4|2-v|-3= 25

Answer:

Step-by-step explanation:

The answer is true

The ball reaches a maximum height of approximately 146 feet, to the nearest foot.

Maximum Height refers to the highest point of the structure or sign as measured from the average natural ground level at the base of the supporting structure.

The ball is thrown upward with an initial velocity of 75 feet per second, implying that v0 = 75. We are also told that the ball is thrown from a height of 4 feet, implying that h0 = 4.

The function: can be used to model the ball's vertical motion.

16t2 + v0t + h0 = h(t).

Substituting v0 and h0 values yields:

h(t) = -16t^2 + 75t + 4

To determine the maximum height of the ball, we must first locate the vertex of the parabolic function h. (t). The vertex of the parabola is given by the equation y = ax2 + bx + c:

x = -b / 2a

y = c - b^2 / 4a

a = -16, b = 75, and c = 4 in this case. Substituting these values into the above formulas yields:

t = -75 / 2(-16) = 2.34 sec

h(t) = 4 - (752) / (4(-16)) 146 ft.

As a result, the ball reaches a maximum height of about 146 feet to the nearest foot.

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Step-by-step explanation:

This is an equation for a LINE.....ANY point on the line will satisfy this equation....so there are INFINITE solutions.

Answer: 300 minuets

Step-by-step explanation:

Answer:

350

Step-by-step explanation:

60 miles is 1 hr. all it is, is a ratio.  multiply 60 by 5 to get your answer; 350

Answer:

Step-by-step explanation:

The mixed number for 3.6 is 3 6/10.

What is a Mixed Fraction?

Improper fractions and mixed numbers have the same value but are written differently. Whole numbers are displayed separately from fractions in mixed numbers. The numerator is larger than the denominator and complete numbers are not displayed separately in improper fractions.

Given:

We have to write 3.6 into a mixed number

So, the decimal 3.6 into a fraction

= 3.6

= 36/10

Then, the division is

                           10 | 36| 3

                                  30

                                 _____

                                    6  

So, the mixed number is 3 6/10.

The chance that a hypothesis test will incorrectly reject the null hypothesis when the p-value cutoff is 1%. The correct option is A.

A hypothesis test is used to test the validity of a hypothesis by calculating the probability that a sample statistic occurred by chance.

The null hypothesis is the hypothesis that is being tested, and it is usually assumed to be true unless there is evidence to the contrary.

The p-value is the probability of obtaining a sample statistic at least as extreme as the one observed, assuming the null hypothesis is true. If the p-value is less than the significance level, which is the p-value cutoff chosen by the researcher, then the null hypothesis is rejected.

If the p-value is greater than or equal to the significance level, then the null hypothesis is not rejected. The p-value cutoff is the significance level chosen by the researcher, and it represents the maximum probability of rejecting the null hypothesis when it is actually true.

In this case, the p-value cutoff is 1%, which means that the maximum probability of rejecting the null hypothesis when it is actually true is 1%. Therefore, the chance that a hypothesis test will incorrectly reject the null hypothesis when the p-value cutoff is 1%.

Therefore, the correct option is A.

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The equations of straight lines are \hat{y} = 2h, \hat{y} = 23r + 4 and \hat{y}= 2s + 3t. Option(A),(B) and (F) are correct.

A line in the coordinate plane can be described with the help of a linear equation, that is, an equation that has a first-degree expression, like y = 2x – 3.

There are many ways to put the equation of a line in the form y = mx + b,

where m is the slope and

b is the y-intercept,

but they all require the use of algebraic properties of equations, such as addition, subtraction, multiplication, division, and substitution.

The equations of straight lines among the following are:  \hat{y} = 2h,  \hat{y} = 23r + 4 and \hat{y}= 2s + 3t

Hence, the correct options are:Option A: \hat{y} = 2h , Option B: \hat{y} = 23r + 4  and Option F: \hat{y}= 2s + 3t.

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based on these assumptions, the country will first experience shortages of food in approximately year 25 (measured from the present).

We can use the concept of exponential growth to model the population and food supply of the country.

Let P(t) be the population of the country at time t (measured in years since the present), and F(t) be the amount of food supply (measured in units of people) at time t. Then, we have:

P(0) = 4 million (initial population)

P(t) = P(0) × (1 + r) raise to the power of t, where r is the annual growth rate of the population (5%) and t is the time in years since the present

F(0) = 8 million (initial food supply)

F(t) = F(0) + p × g, where p is the population growth rate (5%) and g is the additional food supply per person (0.25)

We want to find the year when the food supply first becomes inadequate for the population. This happens when:

P(t) > F(t)

Substituting the expressions for P(t) and F(t), we get:

P(0) × (1 + r)t > F(0) + p × g × t

Simplifying this inequality, we get:

4 × (1.05)t > 8 + 0.25t

Dividing both sides by 4, we get:

(1.05)t > 2 + 0.0625t

We can use trial and error or a graphing calculator to solve this inequality. One way is to try different values of t until we find a value that satisfies the inequality. For example, we can try t = 20:

(1.05)²⁰ = 2.6533...

2 + 0.0625 × 20 = 3.25

Since (1.05)²⁰ < 2 + 0.0625 × 20, this means that the food supply is still adequate at t = 20.

We can try larger values of t until we find a value that satisfies the inequality. For example, we can try t = 25:

(1.05)²⁵ = 3.386...

2 + 0.0625 × 25 = 3.15625

Since (1.05)²⁵ > 2 + 0.0625 × 25, this means that the food supply is no longer adequate at t = 25.

Therefore, According to these projections, the nation's first food shortages will occur around the year 25. (measured from the present).

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No, the given question is not a statistical question. The statistical form of the given question is: "What is the distribution of the number of people who tried out for the Volleyball team over a certain period of time?"

A statistical question is one that can be answered by collecting data and analyzing it. In this case, the original question was “How many people tried out for the Volleyball team?” which can be answered with a specific number. However, to make it a statistical question, we derived a new question: “What is the distribution of the number of people who tried out for the Volleyball team over a certain period of time?” This question asks about the pattern or spread of the data over time and can be answered by collecting data on the number of people who tried out for the Volleyball team at different points in time and analyzing it to see how it changes.

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The complete question is:

"How many people tried out for the Volleyball team?" - Is this a statistical question?

If not, then rewrite it accordingly.

0.5 does not equal 1, the point (-0.5, sin(4π/3)) is not on the unit circle.

The origin of a coordinate plane serves as the center of the unit circle, which has a radius of 1. The values of the trigonometric functions (sine, cosine, tangent, etc.) at different angles are frequently seen and calculated in trigonometry. The lengths of any point's x- and y-coordinates upon that circle remain equal to the cosine and the sine of an angle since the unit circle's radius is 1, respectively.

The equation of a unit circle is given by:

x^2 + y^2 = 1

For the given coordinates (-0.5, sin(4π/3)), substitute the values:

(-0.5)^2 + sin^2(4π/3) = 0.25 + sin^2(240°)

The value of sin(240°) = -0.5:

0.25 + (-0.5)^2 = 0.25 + 0.25 = 0.5

Since 0.5 does not equal 1, the point (-0.5, sin(4π/3)) is not on the unit circle.

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Answer 1: The solution to the equation is x = 4.

Answer 2:

The graph shows that the revenues for online ads have steadily increased since the paper started its online version, while the revenues for printed ads have been steadily decreasing.

Answer 3a:

Beach A is decreasing at a faster rate than Beach B, with its width decreasing from around 400 feet in 1995 to around 250 feet in 2015.

Answer 3b:

Between the years 2011 and 2012, the beaches have approximately the same width.

Answer 3c:

To get a better approximation of when the two beaches will have the same width, the rate of erosion of each beach should be calculated over time.

Equation is an statement that two expressions have the same value, and can be written using symbols, numbers and/or variables.

Answer 1: The equation 2.5x − 10.5 = 64(0.5x) can be solved by completing the table below:

x | 2.5x | 0.5x | 64(0.5x) | 2.5x - 10.5 | 2.5x - 64(0.5x)

--|------|------|-----------|--------------|-----------------

1 | 2.5  | 0.5  | 32        | -8.5         | -29.5

2 | 5    | 1    | 64        | -5.5         | -21.5

3 | 7.5  | 1.5  | 96        | -3.5         | -13.5

4 | 10   | 2    | 128       | -0.5         | -5.5

Answer 2:

The graph shows that the revenues for online ads were approximately equal to the revenues for printed ads around 2006, which is the 12th year after the online version of the paper was started.

Answer 3a:

Beach A is decreasing at a faster rate than Beach B, with its width decreasing from around 400 feet in 1995 to around 250 feet in 2015. Beach B's width is decreasing at a slower rate, from around 500 feet in 1995 to around 350 feet in 2015.

Answer 3b:

Between the years 2011 and 2012, the beaches have approximately the same width.

Answer 3c:

To get a better approximation of when the two beaches will have the same width, the rate of erosion of each beach should be calculated over time. This can be done by plotting the width of each beach over time and calculating the slope of the line, which will give an indication of the rate of erosion.

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1: The solution to the equation is x = 4.

2: The graph shows that the revenues for online ads have steadily increased since the paper started its online version, while the revenues for printed ads have been steadily decreasing.

3a: Beach A is decreasing at a faster rate than Beach B, with its width decreasing from around 400 feet in 1995 to around 250 feet in 2015.

3b: Between the years 2011 and 2012, the beaches have approximately the same width.

3c: To get a better approximation of when the two beaches will have the same width, the rate of erosion of each beach should be calculated over time.

Equation is an statement that two expressions have the same value, and can be written using symbols, numbers and/or variables.

1: The equation 2.5x − 10.5 = 64(0.5x) can be solved by completing the table below:

x | 2.5x | 0.5x | 64(0.5x) | 2.5x - 10.5 | 2.5x - 64(0.5x)

--|------|------|-----------|--------------|-----------------

1 | 2.5  | 0.5  | 32        | -8.5         | -29.5

2 | 5    | 1    | 64        | -5.5         | -21.5

3 | 7.5  | 1.5  | 96        | -3.5         | -13.5

4 | 10   | 2    | 128       | -0.5         | -5.5

2: The graph shows that the revenues for online ads were approximately equal to the revenues for printed ads around 2006, which is the 12th year after the online version of the paper was started.

3a: Beach A is decreasing at a faster rate than Beach B, with its width decreasing from around 400 feet in 1995 to around 250 feet in 2015. Beach B's width is decreasing at a slower rate, from around 500 feet in 1995 to around 350 feet in 2015.

3b: Between the years 2011 and 2012, the beaches have approximately the same width.

3c: To get a better approximation of when the two beaches will have the same width, the rate of erosion of each beach should be calculated over time. This can be done by plotting the width of each beach over time and calculating the slope of the line, which will give an indication of the rate of erosion.

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The correct answer is option b.24.

The given options are Meat: beef, chicken, pork vegetables: baked beans, corn, potatoes, tomatoesDessert: brownies, chocolate cake, chocolate pudding, ice creamThe order of food items is not important, so we need to find the number of combinations we can form by selecting one type of meat, two types of vegetables, and one dessert from the given options.

In selecting the meat, we have three choices, i.e. beef, chicken, and pork. We need to choose one of these three types. So, the number of ways to choose meat is 3. In selecting the vegetables, we have four choices, i.e. baked beans, corn, potatoes, and tomatoes. We need to choose two of these four types.

So, the number of ways to choose two vegetables is,4C2 = 6 (We can select any two vegetables out of four, and the order of vegetables does not matter)In selecting the dessert, we have four choices, i.e. brownies, chocolate cake, chocolate pudding, ice cream. We need to choose one of these four types. So, the number of ways to choose the dessert is 4. So, by the rule of multiplication, we can select a meal in 3 × 6 × 4= 72ways.

However, as the order of food items is not important, we need to divide the total number of combinations by the number of ways to arrange the selected items, i.e. 2! (since we have selected two types of vegetables), and 1! (for meat and dessert). So, the total number of possible meals that Tyler can choose is,72/2! = 36/2 = 18 meals (arranging 2 items from 4),18 × 4! = 18 × 24 = 432 total possible arrangements.

Hence the answer is option b.24.

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The perimeter of the figure is 16p + 10.

The whole length of a two-dimensional or three-dimensional shape's sides or edges is known as its perimeter. It is frequently referred to as the shape's perimeter or circumference. It is possible to determine the perimeter of many geometric forms with accuracy. The perimeter is a key idea in geometry and has several practical uses, such as determining the radius of a circular racetrack or determining the length of fencing required for a certain property.

The perimeter of a figure is the sum of the lengths of all its sides.

Thus,

Perimeter = (p - 9) + (7p + 5) + (p - 9) + (7p + 5)

Perimeter = 2p + 2(7p) + 2(5)

Perimeter = 16p + 10

Hence, the perimeter of the figure is 16p + 10.

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The completed table:

                                  Die

                     1          2          3         4          5        6

 Head      H - 1     H - 2    H - 3   H - 4   H - 5    H - 6

  Tail        T - 1      T - 2    T - 3    T - 4    T - 5   T - 6

We have,

The set of all possible outcomes when rolling the die and flipping the coin is the sample space.

The total number of outcomes.

= 6 x 2

= 12 outcomes.

Each cell in the table will represent one possible outcome.

Here's the completed table:

                                  Die

                     1          2          3         4          5        6

 Head      H - 1     H - 2    H - 3   H - 4   H - 5    H - 6

  Tail        T - 1      T - 2    T - 3    T - 4    T - 5   T - 6

Thus,

The completed table is given above.

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The correct option is B. The trips will each bus has to make to get everyone to the stadium is 40 trips.

The number of fans who will need to use satellite parking is:

150,000 x 0.52 = 78,000

Each bus can carry 65 fans, so the total number of trips required is:

78,000 / 65 = 1200

Therefore, each bus will need to make 1200/30 = 40 trips

Satellite parking typically offers lower rates than the central parking area and provides a shuttle service to transport passengers to and from the main terminal. This type of parking is a popular option for travelers who need to park their car for an extended period of time, such as those going on vacation or business trips.

Satellite parking can be located either on-site or off-site, depending on the transportation hub. Some airports have several satellite parking lots located at various distances from the main terminal, while others have a single satellite parking area. Overall, satellite parking is an important component of transportation infrastructure, as it provides a convenient and affordable parking solution for travelers while also helping to alleviate congestion in the main parking area.

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The sum of the two coefficients will be the effect of D1 on Y when D2=0.

The sum of the regression coefficients on D1 and I1 will be the effect of D1 on Y when D2=0. In other words, it is the effect of a change of D1 on Y when D2=0, holding all other variables constant.

This can be better understood by understanding what interaction variable I1 represents. I1 is the interaction between D1 and D2 and is equal to D1*D2. So, the coefficient of I1 is the effect of D1 when D2=1 and the coefficient of D1 is the effect of D1 when D2=0. Therefore, the sum of the two coefficients will be the effect of D1 on Y when D2=0.

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Smallest number in the data set that is not an outlier is 15, Median of the first half is 17, Median of the entire data set is 20.5. Median of the second half is 22. Largest number in the data set that is not an outlier is 35.

Give a short note on Median?

In statistics, the median is a measure of central tendency that represents the middle value in a dataset. To find the median, the data must first be sorted in ascending or descending order. If the dataset contains an odd number of values, the median is the middle value. If the dataset contains an even number of values, the median is the average of the two middle values.

The median is a useful measure of central tendency in datasets that are skewed or have outliers, as it is less sensitive to extreme values than the mean. It is also useful in datasets with non-numeric values, such as rankings or survey responses.

To create a modified box plot, we need the following values:

The smallest number in the data set that is not an outlier: 15

The median of the first half of the data set: 17

The median of the entire data set: 20.5

The median of the second half of the data set: 22

The largest number in the data set that is not an outlier: 35

So the values needed to create a modified box plot for this data set are: 15, 17, 20.5, 22, 35.

If we are told that the counterfeit coin is too light, we can identify it with a minimum of ⌈log3(n)⌉ weighings.

First, we divide the n coins into three groups of equal size. We then weigh any two of these groups against each other. If the scale tips, the counterfeit coin is in the lighter group, and we repeat this process with that group of coins. If the scale is balanced, the counterfeit coin is in the remaining group, and we repeat the process with that group of coins.

We continue to divide the remaining coins into three groups of equal size and weigh two of them against each other until we are left with a single coin, which must be the counterfeit coin.

Since each weighing reduces the number of possible coins by a factor of 3, we need at most ⌈log3(n)⌉ weighings to identify the counterfeit coin.

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Assuming a 0.05 significance level, both hypothesis tests would reject the null hypothesis. This means that there is enough evidence to suggest that the shopping cart icon's design affects the users' behavior. Therefore, the design should be changed to improve the user's experience.

Step by step explanation:

The problem is not stated, so we need to make some assumptions. We will assume that the hypothesis tests were done to determine whether a change in the shopping cart icon design would affect the users' behavior.

The null hypothesis (H0) is that the design of the shopping cart icon does not affect the users' behavior, while the alternative hypothesis (Ha) is that the design of the shopping cart icon affects the users' behavior.

The significance level is 0.05, which means that we are willing to accept a 5% chance of making a type I error (rejecting the null hypothesis when it is actually true).

If both hypothesis tests reject the null hypothesis, it means that the p-values were less than 0.05, and there is enough evidence to suggest that the design of the shopping cart icon affects the users' behavior.

Therefore, it is recommended to proceed with changing the design of the shopping cart icon to improve the user's experience.

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the price of a burrito is $3.50.

How to solve?

Let the price of a burrito be denoted by "b" and the price of a taco be denoted by "t". Then we can set up the following system of equations:

2b + 5t = 19.50

5b + 2t = 22.50

We can solve for one variable in terms of the other in one of the equations, and substitute that expression into the other equation. For example, we can solve the first equation for b:

2b + 5t = 19.50

2b = 19.50 - 5t

b = (19.50 - 5t)/2

Now we can substitute this expression for b into the second equation:

5b + 2t = 22.50

5[(19.50 - 5t)/2] + 2t = 22.50

Simplifying and solving for t:

(97.50 - 25t)/2 + 2t = 22.50

97.50 - 25t + 4t = 45

-21t = -52.50

t = 2.50

So the price of a taco is $2.50. We can substitute this value back into one of the original equations to solve for the price of a burrito. Using the first equation:

2b + 5t = 19.50

2b + 5(2.50) = 19.50

2b + 12.50 = 19.50

2b = 7

b = 3.50

So, the price of a burrito is $3.50.

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Let's start by writing a differential equation for the rate of formation of chemical C. Since the rate is proportional to the product of the amounts of A and B not converted to C, we can write:

d[C]/dt = k[A](B - 2[C]/B)

where [A] and [B] are the amounts of A and B not converted to C at any time t, [C] is the amount of C formed at time t, and k is a proportionality constant. Note that the term 2[C]/B represents the amount of A that has been used up to form C, since 2 grams of A are used for every gram of B.

At t=0, [A]=40 g and [B]=50 g. We also know that 25 g of C is formed in 8 minutes, so at that time [C]=25 g.

d[C]/dt = k[A](B - 2[C]/B)

25/8 = k40(50 - 2*25/50)

k = 1/800

Now we can use this value of k to solve for [C] at t=16 minutes:

d[C]/dt = k[A](B - 2[C]/B)

C - C = ∫[0]^16 k[A](B - 2[C]/B) dt

C - 25 = ∫[0]^16 (1/800)40(50 - 2[C]/50) dt

C = 37.2 g

Therefore, 37.2 grams of C is formed in 16 minutes.

To find the limiting amount of C after a long time, we can set the derivative of [C] with respect to time to zero and solve for [C]:

d[C]/dt = k[A](B - 2[C]/B) = 0

[C] = B/2 = 25 g

So the limiting amount of C after a long time is 25 grams.

To find the amounts of A and B that remain after a long time, we can use the fact that the total amount of A used is twice the amount of B used. Therefore, the amount of A remaining after a long time is:

[A] = 40 g - 2*[C] = 40 g - 2*25 g = -10 g

This means that all of the A is used up in the reaction, and there is none remaining. The amount of B remaining can be found as:

[B] = 50 g - [C] = 50 g - 25 g = 25 g

So 25 grams of B remains after a long time. Note that this is the same as the limiting amount of C, since one gram of B is converted to one gram of C.

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Each person in the United States uses an average of 18 metric tons of mineral resources each year.

Step by step explanation:According to the USGS, each person in the United States uses an average of 18 metric tons of mineral resources each year. It has been stated that many of the minerals we use in our daily lives are found in things we use every day, such as electronic devices, personal care products, and vehicles.

Mineral resources are utilized in many aspects of our lives, including construction, transportation, energy production, and electronics. As a result, minerals are an essential component of the modern economy.

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Answer: Gavin drank 2.25 quarts today.

Step-by-step explanation: First you need to find out how many quarts are in 8 ounces -the answer to that is 0.25. Then you will need to times that by 9.

Answer:

4=1.28

6=1.92

10=3.2

25=8

1=0.32

3.125≈3 = 1

2=0.64

7=2.24

Step-by-step explanation:

hope this helpz

(a) False; A subspace is formed by the set of vectors that do not belong to the column space.

(b) True; If the matrix contains solely the zero vector, then it is the zero matrix.

(c) True; The column space of a particular matrix is equivalent to the column space of another specified matrix.

(d) False; The column space of one matrix is identical to the column space of another matrix.

(a) False; if A = [1 0; 0 0], then the column space of A is { e1 }, where e1 is the standard unit vector in the plane. If v is not in the column space of A, but w is not in the column space of A, then v + w is not in the column space of A.

Therefore, the set of vectors that are not in the column space of A does not form a subspace.

(b) True; if every vector in Rn is in the null space of A, then in particular, every standard unit vector is in the null space of A. Thus, the ith column of A is zero for i = 1, . . . , n, so A is the zero matrix.

(c) True; the column space of A is generated by the columns of A, while the column space of AB is generated by linear combinations of the columns of AB. By definition of matrix multiplication, the columns of AB are linear combinations of the columns of A, so the column space of AB is a subspace of the column space of A. Conversely, let b be in the column space of A. Then there is an x in Rm such that Ax = b. Thus, ABx = A(Bx), so b is in the column space of AB. Therefore, the column space of A is a subspace of the column space of AB. Hence the two column spaces are equal.

(d) False; if A = [1 0; 0 0] and B = [0 0; 0 1], then the column space of A is { e1 }, while the column space of B is { e2 }. The column space of AB is { 0 }, so it is not equal to either column space.

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The scientific and standard notation and clue obtained from the clue sheet are;

1. Name starts with; J

2. Difference = 145 million miles = Weight = 145 lbs

3. Height: 5 ft, 6 in

4. I. 2.54 × 10⁸ miles corresponding to letter I

II. 0.0005825 corresponds to letter G

III. 5.0432 × 10⁶ corresponds to letter N

IV. 1.547 × 10³ corresponds to letter R

V. 4.977 × 10⁻² corresponds to letter W

VI. 1.3 × 10¹⁰ light years away; corresponds to letter D

VII. 5.04 × 10⁻⁵ corresponds to letter A

The suspects hubby is DRAWING

Scientific notation is a format used to express very large or very small numbers such that they are much easier to work with. The scientific notation format is; a × 10ⁿ, where; a is the coefficient, which is a number between 1 and 10 (10 excluded), and n is an integer.

1. G = (6.07 × 10⁷)/(7.035 × 10³) ≈ 8628.29

J = (6.03 × 10⁻³)/(5.05 × 10⁻⁷) ≈ 11940.59

Therefore; J > G

The suspects name starts with J

2. The distance the telescope in the laboratory allows the viewer to see = 1.5 × 10⁹ miles away

The distance the other telescope a few hours away allows the viewer to see = 1.355 × 10⁹ miles away

The difference between the distances = (1.5 - 1.355) × 10⁹ miles = 1.45 × 10⁸ miles

The difference in the distance is 1.45 × 10⁸ miles = 145 million miles

The suspect weight is 145 lbs

3. The numbers are;

Feet; 532.063 × 10³ = 5.32063 × 10⁵

Inches; 5,030,045 = 5.030045 × 10⁶

The height of the suspect is 5 feet 6 inches (5'6'') = 5.5 feet

Height; = 5 ft, 6 in

4. I. The difference in distances between Earth and Saturn can be found as follows;

The difference in the distances = (1000 - 746) million miles = 254 million miles apart

Scientific notation is the expression of numbers in the form consisting of a number between 1 and 10, multiplied by 10 raised to a power

254 million miles = 2.54 × 10⁸ miles

The corresponding letter from the code cracker is; I

II Standard notation is the expression of numbers in the standard form without the use of exponents or special symbols

The number 5.825 × 10⁻⁴ in standard notation is; 0.0005825

The corresponding letter from the code cracker is; G

III. The number 504.32 × 10⁴ in scientific notation can be obtained by moving the decimal point two places to the left followed by increasing the index of 10 by 2 as follows;

504.32 × 10⁴ = 5.0432 × 10⁶

The corresponding letter from the code cracker is; N

IV. The sum of the numbers 1.202 × 10³ and 3.45 × 10² can be obtained by expressing both numbers to the same power of 10 as follows;

1.202 × 10³ + 3.45 × 10² = 12.02 × 10² + 3.45 × 10² = 15.47 × 10²

15.47 × 10² = 1.547 × 10³

Therefore; 1.202 × 10³ + 3.45 × 10² = 1.547 × 10³

The corresponding letter from the code cracker is; R

V. The difference of the numbers can be obtained as follows;

5.023 × 10⁻² - 4.6 × 10⁻⁴ = 502.3 × 10⁻⁴ - 4.6 × 10⁻⁴ = 497.7 × 10⁻⁴

497.7 × 10⁻⁴ = 4.977 × 10⁻²

Therefore; 5.023 × 10⁻² - 4.6 × 10⁻⁴ = 4.977 × 10⁻²

The corresponding letter from the code cracker is; W

VI. 13 billion light years = 13 × 10⁹ light years = 1.3 × 10¹⁰ light years

The distance a standard telescope can allow to be seen is 1.3 × 10¹⁰ light years away

The corresponding letter from the code cracker is; D

VII. 0.0000504 in scientific notation is; 5.04 × 10⁻⁵

The corresponding letter from the code cracker is; A

IGNRWDA

The suspects favorite hubby is DRAWING

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Using distance between two points formula, a = 0

The distance between two points (x, y) and (x', y') is given by

d = √[(x' - x)² + (y' - y)²]

Now, If the distance between the points (0, 6) and (a, 0) is 6 units, to find the value of a,

Let

So, substituting the values of the variables into the equation, we have

d = √[(x' - x)² + (y' - y)²]

6 = √[(a - 0)² + (0 - 6)²]

⇒ √[a² + (- 6)²] = 6

√[a² + 36] = 6

Squaring both sides, we have that

a² + 36  = 6²

a² + 36  = 36

a² = 36 - 36

a² = 0

a = √0

a = 0

So, a = 0

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The question is incomplete. Here is the complete question

If the distance between (0, 6) and (a, 0) os 6 units. Find the value of a

​

The expected value is the arithmetic mean of a large number of independently selected outcomes of a random variable.

a) No, X and Y are not independent since the lifetime of a part (Y) is modeled by X.

b) The joint PDF fX,Y(x,y) = x-1exp(-xy) for 1 ≤ x ≤ 2, y ≥ 0, 0 otherwise.

c) P[Y < 1] = 1 - exp(-x) for 1 ≤ x ≤ 2.

d) The marginal PDF fY(y) = exp(-xy) for 1 ≤ x ≤ 2, y ≥ 0, 0 otherwise.

e) The expected value of Y using fY(y) is 1/x for 1 ≤ x ≤ 2.

f) The conditional expected value of Y given X = x is 1/x for 1 ≤ x ≤ 2.

g) Using E[Y] = E[E[Y∣X]], the expected value of Y is 1.

h) The expected value of X + Y is 2.

i) The expected value of XY is 1.

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Answer:

10

Step-by-step explanation:

Based on the given conditions, formulate: 40x16 divided by 64

Cross out the common factor: 40/4

Cross out common factor: 10

Get the result

Answer: 10