Chemistry High School

what is the electron domain geometry of hbro2

Answers

Answer 1

The electron domain geometry of HBrO2 is pyramidal.

When something is described as "pyramidal," it typically refers to its shape, which is a three-dimensional geometric structure with a polygonal base and triangular sides that converge at a point. The phrase is frequently used to describe a variety of structures, such as the brain's neural network or a mountain's structure.A "pyramidal peak" in geology is a mountain peak that is triangular in shape with steep sides and a flat summit. These peaks can be found in numerous mountain ranges all over the world. They are created by glacial activity and erosion.

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Related Questions

Calculate the molecular mass (u) of Phosphoric Acid (H3PO4).[H=1,P=31,O=16] ?
a)96
b)97
c)98
d)99

Answers

The molecular mass (u) of Phosphoric Acid (H3PO4).[H=1,P=31,O=16]  is 98U.so, option (c) is correct.

What is mass?

The term matter defines mass, and it measures matter. Mass is discovered from the different atoms and particles. Group, in simple terms, determines the weightage of the substance. Mass is expressed in the terms kilograms. Mass of the quantity is a much-needed thing in the laboratory. The quantity of the substance does the majority of the experiment. Gravity also takes place as an independent factor in calculating mass. Mass is the scalar quantity. Gravity and force are playing the independent factor in the mass. For calculating the two planet mass, know the force of the planet.

What is molar mass?

The molar mass is the substance; it helps to determine the mass of the sample substance to the atom of the sample or substance. The molar mass depends on the molecular formula and the isotopes of the atom. Molar mass is used for the inducement of electric charge. Molar mass is the measurement of the volume of the mass. The molar mass is expressed in the unit of dalton.

Molar mass is the sum of the masses of all the individual atoms present in a molecule or compound.

Orthophosphoric acid is the important acid of oxygen and phosphorous.

It is used for making phosphate salts for fertilizers.

Chemical formula of Orthophosphoric acid is H3PO4.

Atomic mass of Oxygen O is 16 u.

Atomic mass of hydrogen H is 1 u.

Atomic mass of Phosphorous P is 31 u.

Molecular mass of Orthophosphoric acid H3PO4 = (Atomic mass of Hydrogen) x 3 + (Atomic mass of Phosphorous) x 1 + (Atomic mass of Oxygen) x 4

= ( 1 x 3 ) + ( 31 x 1 ) + ( 16 x 4 )

= 3 + 31 + 64

= 98 u.

Molecular mass of Orthophosphoric acid H3PO4 is 98

Therefore,  molecular mass (u) of Phosphoric Acid (H3PO4).[H=1,P=31,O=16]  is 98U.(c).

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Freon-113, C2Cl3F3, has an enthalpy of vaporization of 27.0 kJ/mol and a normal boiling point of 48.0 degrees Celsius. What is the vapor pressure (in atm) of Freon-113 at 40.3 degrees Celsius? (R = 8.314 J/K.mol)

Answers

Enthalpy of vaporisation for Freon 113, also known as C2Cl3F3, is 27.0 kJ/mol, and its usual boiling point is 48.0 °C. Therefore, Freon-113 has a vapour pressure of 0.77 atm.

The amount of energy (enthalpy) required to convert a portion of a liquid into a gas is known as the enthalpy of vaporisation,

abbreviated as H vap and also referred to as the (latent) heat of vaporisation or heat of evaporation.The substance's enthalpy of vaporisation is H=27.0 kJ/mol=27.0 103 J/mol.

P1=1atM is the pressure at the typical boiling point.

The chemical C2Cl3F3 has an initial temperature of T1=48.0C=48.0+273.15

The material C2Cl3F3 has an initial temperature of T2=40.3C=40.3+273.15K.

R=8.314J/Kmol is the gas constant's value.

The formula for vapour pressure is given as ln(P2P1)=HR(1T21T1)

all the plugs Vapor pressure is expressed as ln(P2P1)=HR(1T21T1)

The following results from simplifying the previous formula for the necessary vapour pressure and plugging in all the values:

(atm)=3247.53 K(321.15K113.15 K313.15K(321.15K)) where ln(P21atm)=27.0103J/mol 8.314J/Kmol (140.3+273.15K148.0+273.15K)

P21atm = ln(3247.53 K) (8100568.1225K)

ln(P21atm)=−0.25833

If we multiply each side of the equation by the exponent of base e, we get: Eln (P21atm) = e 0.25833P2 1 atm = e 0.25833 P2 = e 0.258331 atm

P2=0.77atm

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