What is the distance from the origin to point A graphed on the complex plane below?

Answer:

-10

Step-by-step explanation:

5 - 3*5

= 5 - 15

= -10

Answer: 48

Step-by-step explanation:

The number 0.14 is bigger than 0.135.

To compare the two numbers, you can look at their digits after the decimal point. In both numbers, the digit in the tenths place is 1. The next digit in 0.14 is 4, which is greater than the corresponding digit in 0.135, which is 3.

Since the digit in the hundredths place (4) is greater than the digit in the hundredths place (3), the number 0.14 is bigger than 0.135.

In summary, the order of the numbers from smallest to largest is:

0.135 < 0.14.

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Velocity of jet in still air is

970

miles per hour and velocity of wind is

210

miles per hour.

Explanation:

Jet's velocity against wind is

3040

4

=

760

mile per hour and flying with wind it is

8260

7

=

1180

miles per hour.

Let the velocity of jet in still air be

x

miles per hour and velocity of wind be

y

miles per hour.

As such its velocity against wind is

x

−

y

and with wind is

x

+

y

and therefore

x

−

y

=

760

and

x

+

y

=

1180

Adding the two

2

x

=

1940

and

x

=

970

and

y

=

1180

−

970

=

210

Hence velocity of jet in still air is

970

miles per hour and velocity of wind is

210

miles per hour.

The speed of an aircraft in still air is 200kmh−1. The wind blows from the west at a speed of 85.0kmh−1.

1 Expert Answer

The speed of the plane in still air is 110 mph.

Multiply the headwind or tailwind component by your estimated flight time expressed as a decimal, such as "3.2 hours." Add the result (don't forget that tailwinds are negative numbers) to the geographic distance of your route. The resulting number will be total nautical air miles of your trip.

Answer:

The correct answer is B: 3 cubic feet.

Step-by-step explanation:

If you want to find the volume of a rectangular prism, you need to know the length, width, and height. The first rectangular prism is a cube with a length of 3 feet, so the volume of the figure would be [tex]3^{3}=27 ft^{3}[/tex]. The second rectangular prism has a length of 3 feet, a width of 2 feet, and a height of 4 feet, so the volume of the prism would be 3 × 2 × 4 = [tex]24 ft^{3}[/tex]. Now that you know the 2 volumes, you need to subtract the volumes in order to find the difference, which is 27 - 24 = 3 [tex]ft^{3}[/tex].

Answer:

68 units

Step-by-step explanation:

Given:

As the x-values of points A and B are the same (x = -3), the line through points A and B is vertical.

Therefore, to find the distance between the two points, simply subtract the y-value of point B from the y-value of point A:

[tex]\sf distance=y_A-y_B=80-12=68 \ units[/tex]

Answer:

42,40,58

Step-by-step explanation:

The median value in the data set is the average of the two middle values which is: 23.

In an ordered data set, the median is the middle value or average of the two middle values in the data set.

List out each data point in the data set given:

20, 20, 20, 22, 22, 24, 26, 26, 26, 26

The middle values in the data set are, 22 and 24.

Median = (22 + 24)/2

Median = 23

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Answer:

1 (the answer will always be 1)

Step-by-step explanation:

Let's forget about the absolute value signs for a second and just look at what's inside

[tex]\frac{x+y}{-x-y}[/tex]

This can be rewritten as

[tex]-\frac{x+y}{x+y}[/tex]

When you have the same numerator and denominator, it will always come out to 1, so we can just say that this is saying

[tex]-\frac{x+y}{x+y} = -1[/tex]

Now, back to the absolute value signs

This comes out to negative 1, but the absolute value signs means to always change the negative to a positive (but if it's a positive, it stays positive!)

So that means:

[tex]|-1| = 1[/tex]

and 1 is your answer

Answer: C

Step-by-step explanation:

[tex]2x+5y=5[/tex]

[tex]\mathrm{Subtract\:}2x\mathrm{\:from\:both\:sides}[/tex]

[tex]2x+5y-2x=5-2x[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]5y=5-2x[/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}5[/tex]

[tex]\frac{5y}{5}=\frac{5}{5}-\frac{2x}{5}[/tex]

[tex]\mathrm{Simplify}[/tex]

[tex]\bf{y=-\frac{2}{5}x + 1}[/tex]

Answer:

b i think because 50 minus 9.99 then 1.29 will be less than cuz it cant go over

Answer:

$1470 coupon of their product I have

Answer:

28, 28, 34, 34

Step-by-step explanation:

8x - (6 + y)

8(5) - (6 + 6)

40-12

28

w ¾ + x²

4(¾) + 5²

3 + 25

28

y² - 0.5w

6² - 0.5(4)

36 - 2

34

w / 4 + 3(x + y)

4 / 4 + 3(5 + 6)

1 + 3(11)

34

Step-by-step explanation:

-80 is less than 0.

+76 is more than 0.

-8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4

-12, -11, -10, -9, -8, -7, -6, -5, -4, -3, -2

Answer:

3.38

Step-by-step explanation:

primero tienes que restar 2.23 por 0.58 que es igual a 1.65 luego sumas 1.65 por 4.46 porque 2.23 multiplicado por 2 es igual a 4.46 y eso es igual a 6.11 luego tienes que restar 10 por 6.11 que es igual a 3.89

Answer:

The graph would not be as able to see the form and/or function so hope this helps

Answer:  There should at least be 23 tables

Step-by-step explanation:

If there is 23 tables there will still be six students with nowhere to sit :)

a) El tiempo requerido por el camión para recorrer 0.5 kilómetros es aproximadamente 35.355 segundos.

b) La rapidez que llevará el camión en ese tiempo es 28.284 metros por segundo (101.822 kilómetros por hora).

El camión experimenta un movimiento uniformemente acelerado, que ocurre al considerar que su aceleración ([tex]a[/tex]), en metros por segundo al cuadrado, es constante en el tiempo ([tex]t[/tex]), en segundos.

a) El tiempo requerido es determinado por el siguiente polinomio de segundo orden:

[tex]x = v_{o}\cdot t + \frac{1}{2}\cdot a\cdot t^{2}[/tex]   (1)

Donde:

Si sabemos que [tex]x = 500\,m[/tex], [tex]a = 0.8\,\frac{m}{s}[/tex] y [tex]v_{o} = 0\,\frac{m}{s}[/tex], entonces tenemos que el tiempo requerido es:

[tex]0.4\cdot t^{2}-500 = 0[/tex]

[tex]t \approx 35.355\,s[/tex]

El tiempo requerido por el camión para recorrer 0.5 kilómetros es aproximadamente 35.355 segundos. [tex]\blacksquare[/tex]

b) La rapidez final ([tex]v[/tex]), en metros por segundo, se determina con el siguiente polinomio de primer orden:

[tex]v = v_{o} + a\cdot t[/tex]   (2)

Si sabemos que [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]a = 0.8\,\frac{m}{s^{2}}[/tex] y [tex]t = 1250\,s[/tex], entonces tenemos que la rapidez final es:

[tex]v = 0 + 0.8\cdot (35.355)[/tex]

[tex]v = 28.284\,\frac{m}{s}[/tex]   [tex]\left(101.822\,\frac{km}{h} \right)[/tex]

La rapidez que llevará el camión en ese tiempo es 28.284 metros por segundo (101.822 kilómetros por hora). [tex]\blacksquare[/tex]

Para aprender más sobre movimiento uniforme, invitamos a ver esta pregunta verificada: https://brainly.com/question/118814

Answer:

  x = 9

  x+7 = 16

Step-by-step explanation:

The triangles in this geometry are similar, so the ratios of corresponding sides are proportional.

  long side/short side = (x+7)/12 = 12/x

  x(x +7) = 12²

  x +7x -144 = 0 . . . . . subtract 144 to put in standard form

  (x +16)(x -9) = 0 . . . . factor

  x = 9 . . . . . . only the positive solution is useful here

The missing lengths are ...

Answer:

tan m‹G = 28.2/45.8

m‹G= 31.62°

Check the picture below, so the lines look more or less like so, so the shape that we'll be getting will be the shape of a bowl with a hole in it, thus we'll use the washer method.

the way I use to get the larger Radius is simply using the "area under the curve" method, namely f(x) - g(x), where g(x) in this case is the axis of rotation.

so to get "R" and "r" we can get it by

[tex]\stackrel{y = 1}{(1)}~~ - ~~\stackrel{\stackrel{\textit{axis of rotation}}{y = -3}}{(-3)}\implies 1+3\implies \stackrel{R}{4} \\\\\\ \stackrel{y = \ln(x)}{\ln(x)}~~ - ~~\stackrel{\stackrel{\textit{axis of rotation}}{y = -3}}{(-3)}\implies \stackrel{r}{ln(x)+3} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{R^2}{(4)^2}~~ - ~~\stackrel{r^2}{[\ln(x)+3]^2}\implies 16~~ - ~~[\ln^2(x)+6\ln(x)+9] \\\\\\ \ln^2(x)+6\ln(x)+7~\hfill \boxed{\displaystyle\int~[\ln^2(x)+6\ln(x)+7]dx}[/tex]

Answer:

48 miles

Step-by-step explanation:

To find the mileage when both cost the same, first form two equations for the total cost for each rental place.

Let the mileage be m.

Sunshine Rental

Daily rate= $57.99

Total cost= $(57.99 +0.48m)

City Rentals

Daily rate= $58.95

Total cost= $(58.95 +0.46m)

Let's equate both equations together.

When both costs the same,

57.99 +0.48m= 58.95 +0.46m

0.48m -0.46m= 58.95 -57.99

0.02m= 0.96

Solve for m:

m= 0.96 ÷0.02

m= 48

The cost is the same at 48 miles.

Answer:37,500

Step-by-step explanation: Find 60% of 25000 which is 15000 then multiply by 2.5

Answer:

A

Step-by-step explanation:

26 + 28 = 54

54 + 21 = 75

75 + 13 = 88

88 / 4 = 22

Answer is A

Answer: 22

Step-by-step explanation: Add all of the numbers in the data set: 28+26+21+13= 88

Then divide 88 by 4: 22

Answer:

First convert two feet into yards, knowing that:

1 foot = 0.333... yards

So,

2 feet in yards would mean double of 0.333... because one single foot is 0.333... yards.

2(0.333...)

= 0.666..., which we can round to 0.67.

So our new ratio will be 32 bulbs per 0.67 yards.

Now we convert this ratio into a unit rate,

Order your units;

Bulbs         32           47.76

______   ______ = ______, which rounds to about 48.

Yards        0.67             1

So the unit rate is 48 bulbs per yard.

Answer:

The answer is B.

Step-by-step explanation:

15÷3=5    15÷5=3

30÷3=10   30÷5=6

45÷3=15    45÷5=9

60÷3=20    60÷5=12

let's recall that d = rt, distance = rate * time.

a = speed of the airplane in still air.

w = speed of the wind

the distance travelled with the wind is 960 miles, so the return trip is pretty much just that, 960 miles.

when the airplane is going with with wind, the airplane is really not going as fast as "a" mph, is really going faster due to the wind, so the speed of the plane is "a + w", because the wind is adding its speed to it.

when the airplane is going against the wind is not really going "a" mph fast either, is really going slower at "a - w" mph, because the wind is subtracting speed from it, so

[tex]\begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ \textit{with the wind}&960&a+w&5\\ \textit{against the wind}&960&a-w&6 \end{array}~\hfill \begin{cases} 960=(a+w)(5)\\\\ 960=(a-w)(6) \end{cases} \\\\\\ \stackrel{\textit{using the 1st equation}}{960=(a+w)(5)}\implies \cfrac{960}{5}= a + w\implies 192=a+w\implies \boxed{192-w=a}[/tex]

[tex]\stackrel{\textit{substituting on the 2nd equation}}{960=(\underline{192-w}~~ - ~~w)(6)}\implies \cfrac{960}{6}=192-w-w\implies 160=192-2w \\\\\\ 2w+160=192\implies 2w=32\implies w=\cfrac{32}{2}\implies \blacktriangleright w=16 \blacktriangleleft ~\hfill \blacktriangleright \stackrel{192 - 16}{176=a} \blacktriangleleft[/tex]