Answer:
The basic difference between Total cost and total revenue is that the total cost includes the total expenditure incurred on the production of a commodity whereas total revenue refers to the money received from selling that commodity.
Explanation:
For a sixth-order Butterworth high pass filter with cutoff frequency 3 rad/s, compute the following:
a. The locations of the poles.
b. The transfer function H(s).
c. The corresponding LCCDE description.
Solution :
Given :
A six order Butterworth high pass filter.
∴ n = 6, [tex]w_c=1 \ rad/s[/tex]
a). The location at poles :
[tex]$s^6-(w_c)^6=0$[/tex]
[tex]$s^6=(w_c)^6=1^6$[/tex]
∴ [tex]$s^6 = 1$[/tex]
Therefore, it has 6 repeated poles at s = 1.
b). The transfer function H(S) :
Transfer function H(S) [tex]$=\frac{1}{1+j\left(\frac{w_c}{s}\right)^6}$[/tex]
[tex]$=\frac{1}{1-\left(\frac{w_c}{s}\right)^6}$[/tex]
∴ H(S) [tex]$=\frac{s^6}{s^6-(w_c)^6}=\frac{s^6}{s^6-1}$[/tex]
H(S) [tex]$=\frac{Y(s)}{X(s)}=\frac{s^6}{s^6-1}$[/tex]
c). The corresponding LCCDE description :
[tex]$=\frac{Y(s)}{X(s)}=\frac{s^6}{s^6-1}$[/tex]
[tex]$Y(s)(s^6-1) = s^6 \times (s)$[/tex]
[tex]$Y(s)s^6-y(s).1 = s^6 \times (s)$[/tex]
By taking inverse Laplace transformation on BS
[tex]$L^{-1}[Y(s)s^6-Y(s)1]=L^{-1}[s^6 \times (s)]$[/tex]
[tex]$\frac{d^6y(t)}{dt^6}-y(t)=\frac{d^6 \times (t)}{dt^6}$[/tex]
Hence solved.
Một máy nghiền bi thùng ngắn đường kính D = 1.6m, dài L = 2m dùng để nghiền VL. Kích thước đầu vào D1 = 20mm, sản phẩm sau nghiền có kết quả phân tích rây sau:
Số mesh
60/80
80/100
100/150
150/200
Khối lượng VL trên rây
0.1
0.3
2.5
0.1
Hỏi
1. Tính kích thước bi nghiền bi.
2. Tính số vòng quay tối ưu.
3. Tính năng suất (biết K1 = 1.01).
4. Tính số lượng bi cần nạp vào thùng. Biết hệ số chứa đầy φ = 0.25, hệ số rỗng = 0.65, ⍴bi = 8000 kg/m3
Answer:
bood ekogcd gcaerh is an American fbnuxc
Nguyên lý hoạt động của cảm biến áp điện là gì?
Answer:
Nguyên lý hoạt động của cảm biến từ
Cảm biến từ có nguyên lý hoạt động khá đơn giản. Theo đó, một cuộn cảm sẽ phát triển một từ trường khi có dòng điện chạy qua nó; hay nói cách khác một dòng điện sẽ chạy qua một mạch chứa cuộn cảm khi từ trường xuyên qua nó thay đổi.
Ngoài ra, hiệu ứng này còn có thể được sử dụng để phát hiện các vật kim loại có tương tác với từ trường. Các chất phi kim loại như chất lỏng hay một số loại bụi bẩn không tương tác với từ trường. Do đó, cảm biến từ hoàn toàn có thể hoạt động được trong điều kiện ẩm ướt hoặc bụi bẩn.
Explanation:
A viscous liquid is sheared between two parallel disks; the upper disk rotates and the lower one is fixed. The velocity field between the disks is given by V=e^θrωz/h (The origin of coordinates is located at the center of the lower disk; the upper disk is located at z = h.) What are the dimensions of this velocity field? Does this velocity field satisfy appropriate physical boundary conditions? What are they?
Answer:
For lower disk : V = e^θrω(0)/h = 0
At the upper disk: V = e^θrω(h)/h = e^θrω
Hence The physical boundary conditions are satisfied
Explanation:
Velocity field ( V ) = e^θrωz/h
Upper disk located at z = h
Determine the dimensions of the velocity field
velocity field is two-dimensional ; V = V( r , z )
applying the no-slip condition
condition : The no-slip condition must be satisfied
For lower disk Vo = 0 when disk is at rest z = 0
∴ V = e^θrω(0)/h = 0
At the upper disk V = e^θrω given that a upper disk it rotates at z = h
∴ V = e^θrω(h)/h = e^θrω
Hence we can conclude that the velocity field satisfies the appropriate physical boundary conditions.
Động lực quá trình truyền khối là gì? Khi quá trình truyền khối xảy
ra, động lực truyền khối xảy ra như thế nào ?
Answer:
5354
Explanation:
A 14 bit A to D converter is to be employed with an Iron-constantan thermocouple. What temperature resolution can be expected with a full scale voltage of 100 mV? Thermocouple shows 0.5 mV at 50oC and 3.052 mV at 100oC.
Answer:
[tex]\gamma=0.122^oC[/tex]
Explanation:
From the question we are told that:
Word length[tex]n=14bit[/tex]
Full scale voltage of 100 mV
Thermo-couple shows:
[tex]0.5 mV\ at\ 50^oC[/tex]
[tex]3.052\ mV\ at\ 100^oC.[/tex]
Generally the equation for Average output voltage V_[avg} is mathematically given by
[tex]V_[avg}=\frac{3.052-0.5}{100-50}[/tex]
[tex]V_[avg}=0.05mv[/tex]
Since
[tex]Word lenght =14[/tex]
Therefore
[tex]Voltage\ steps=\frac{100}{2^{14}}[/tex]
[tex]Voltage\ steps=6.10*10^3mv steps[/tex]
Generally the equation for The required temperature resolution\gamma is mathematically given by
[tex]\gamma=\frac{100}{2^{14}*V_[avg}}[/tex]
[tex]\gamma=\frac{100}{2^{14}*0.05}[/tex]
[tex]\gamma=0.122^oC[/tex]
An astronaut orbits the earth in a space capsule whose height above the earth is equal to the earth's radius. How does the mass of the astronaut in the capsule compare to her mass on the earth?
Answer:
The weight will be [tex]\frac{1}{4}[/tex] of its weight on earth surface. A further explanation is provided below.
Explanation:
According to the question,
h = R
The value of gravitational acceleration at height equivalent to radius of earth R.
⇒ [tex]g=\frac{g_0}{(1+\frac{h}{R} )^2}[/tex]
or,
⇒ [tex]g=\frac{g_0}{(1+\frac{R}{R} )^2} =\frac{g_0}{4}[/tex]
here,
[tex]g_0[/tex] = gravitational acceleration earth's surface
then,
⇒ [tex]mg=\frac{mg_0}{4}[/tex]
Thus, the above is the appropriate solution.
Do you know anything about Android graphics?
Android provides a huge set of 2D-drawing APIs that allow you to create graphics.
Android has got visually appealing graphics and mind blowing animations.
The Android framework provides a rich set of powerful APIS for applying animation to UI elements and graphics as well as drawing custom 2D and 3D graphics.
Three Animation Systems Used In Android Applications:-1. Property Animation
2. View Animation
3. Drawable Animation
convert 25 inches / min to mm/hour
Answer:
25 mins into hours = 0.416667 hours
25 inches as mm = 635
Explanation:
Please label the following statements as either True (T) or False (F).
(a) The true stress is higher than the engineering stress for a sample under tension.
(b) Creep test is carried out with a dynamic stress under elevated temperature.
Answer:
a. True
b. False
Explanation:
a. Since true stress, σ' = σ(1 + ε) where σ = engineering stress and ε = engineering strain.
Also under tension ε > 0, so, (1 + ε) > 1
Since (1 + ε) = σ'/σ > 1, ⇒ σ' > σ
So, the true stress is greater than the engineering stress.
So, the statement is true
b. Creep is a time-dependent deformation under certain applied load.
Creep occurs at high temperatures under different types of stress.
But, Creep test is carried out at constant high temperature and constant stress.
This statement is false.
Write a program to calculate overtime pay of 10 employees. Overtime is paid at the rate of Rs. 12.00
per hour for every hour worked above 40 hours. Assume that employees do not work for fractional
part of an hour.
Answer:
Here is the code.
Explanation:
#include<stdio.h>
int main()
{
int i, time_worked, over_time, overtime_pay = 0;
for (i = 1; i <= 10; i++)
{
printf("\nEnter the time employee worked in hr ");
scanf("%d", &time_worked);
if (time_worked>40)
{
over_time = time_worked - 40;
overtime_pay = overtime_pay + (12 * over_time);
}
}
printf("\nTotal Overtime Pay Of 10 Employees Is %d", overtime_pay);
return 0;
}
Output :
Enter the time employee worked in hr 42
Enter the time employee worked in hr 45
Enter the time employee worked in hr 42
Enter the time employee worked in hr 41
Enter the time employee worked in hr 50
Enter the time employee worked in hr 51
Enter the time employee worked in hr 52
Enter the time employee worked in hr 53
Enter the time employee worked in hr 54
Enter the time employee worked in hr 55
Total Overtime Pay Of 10 Employees Is 1020.
R-134a vapor enters into a turbine at 250 psia and 175°F. The temperature of R-134a is reduced to 20°F in this turbine while its specific entropy remains constant. Determine the change in the enthalpy of R-134a as it passes through the turbine.
Answer:
Δ enthalpy = -23 Btu/Ibm
Explanation:
Given data:
Pressure ( P1 ) = 250 psi
Initial Temperature ( T1 ) = 175°F
Final temperature ( T2 ) = 20°F
Calculate the change in the enthalpy of R-134a
From R-134 table
h1 = 129.85 Btu/Ibm
s1 = 0.23281 Btu/Ibm.R
note : entropy is constant
hence ; s1 = s2
by interpolation ; h2 = 106.95
Δ enthalpy = h2 - h1
= ( 106.95 - 129.85 ) = -23 Btu/Ibm
An asphalt concrete mixture includes 94% aggregates by weight. The specific gravity of aggregate and asphalt are 2.7 and 1.0, respectively. If the bulk density of the mix is 2.317 g/cm3, what is the percent voids in the total mix?
Answer:
The correct solution is "5.74%".
Explanation:
The given values are:
Gravity of aggregate,
[tex]G_{agg}=2.7[/tex]
Gravity of asphalt,
[tex]G_{asp}=1.0[/tex]
Asphalt concrete mixture,
[tex]W_{agg}=0.94 \ W_m[/tex]
We know that,
[tex]W_{asp}=W_m-W_{agg}[/tex]
[tex]=0.06 \ W_m[/tex]
Now,
The theoretical specific gravity of mix,
⇒ [tex]G_t=\frac{W_{agg}+W_{asp}}{\frac{W_{agg}}{G_{agg}} +\frac{W_{asp}}{G_{asp}} }[/tex]
By putting the values, we get
[tex]=\frac{0.94 \ Wm+0.06 \ Wm}{\frac{0.94 \ Wm}{2.7} +\frac{0.06 \ Wm}{1} }[/tex]
[tex]=2.45[/tex]
hence,
The percentage of voids will be:
⇒ %V = [tex]\frac{G_t-G_m}{G_t}\times 100[/tex]
= [tex]\frac{2.45-2.317}{2.45}\times 100[/tex]
= [tex]\frac{0.133}{2.317}\times 100[/tex]
= [tex]5.74[/tex] (%)
A school teacher must schedule seven sessions, which are abbreviated M, N, O, P, S, T, and U, during a day. Seven different consecutive time periods are available for the sessions, and are numbered one through seven in the order that they occur. Only one session can be schedules for each period. The assignment of the sessions to the periods is subject to the following restrictions:
M and O must occupy consecutive periods. M must be scheduled for an earlier period than U.
O must be scheduled for a later period than S.
If S does not occupy the fourth period, then P must occupy the fourth period.
U and T cannot occupy consecutively numbered periods.
Which of the following could be true?
a. M is assigned to the first period.
b. O is assigned to the fifth period.
c. S is assigned to the seventh period.
d. T is assigned to the sixth period.
Given:
There are seven sessions to be scheduled in seven different consecutive time periods. Only one session can be scheduled for each period. The sessions are abbreviated as M, N, O, P, S, T, U. The restrictions are:
(i) M & O must occupy consecutive periods.
(ii) M must be scheduled for an earlier period than U.
(iii) O must be scheduled for a later period than S.
(iv) If S does not occupy the fourth period, then P must occupy the fourth period.
(v) U & T cannot occupy consecutively numbered periods.
Solution:
We will construct the sequence of sessions based on the given restrictions.
Since M & O must occupy consecutive periods, we can have the sequence as {..., M, O, ...} or {..., O, M, ...}
Since M must be scheduled for an earlier period than U, we can have the sequence as {..., M, O, ..., U, ...} or {..., O, M, ..., U, ...}
Since O must be scheduled for a later period than S, we can have the sequence as {..., S, ..., M, O, ..., U, ...} or {..., S, ..., O, M, ..., U, ...}
We can see that, according to the given restrictions, M cannot be assigned the first period as S has to be assigned before M. Thus option (a) is incorrect.
We can see that, according to the given restrictions, S cannot be assigned to the seventh period as seventh period is the last period and M, O & U has to be assigned after S. Thus option (c) is incorrect.
Now, T can be assigned in the following ways:
(I) After U: In this case, there are at least 4 sessions before T, the last of which is U. Moreover, according to the given restrictions, U & T cannot occupy consecutive periods. Also, since we are assuming that S is the first element, the fourth element has to be P, so that U is assigned to 5th period or after. Thus T has to be assigned to 7th, if we skip the period after U. That is, T cannot be assigned to the 6th period in this case.
(II) Between O, M & U: Even if U is assigned to the last (7th) period, since U & T cannot occupy consecutive periods, T cannot be assigned the 6th period in this case.
(III) Between S & O, M: This would imply that there are at least 3 sessions after T. This would automatically imply that T cannot be assigned to the 6th period in this case.
(IV) Before S: This implies that there are at least 4 sessions after T. Thus, T cannot be assigned to the 6th period in this case either.
Thus, T cannot be assigned to the sixth period in any case. That is, option (d) is incorrect.
Now, following all the given restrictions, one of the arrangements can be,
{1-N, 2-P, 3-T, 4-S, 5-O, 6-M, 7-U}
We can see that S is occupying the 4th period & U and T are not occupying consecutive periods. Thus, all the restrictions are followed. We can see that it is possible for O to be assigned to fifth period by following all the restrictions. Thus option (b) is the correct choice.
Final answer:
Option (b) is the correct choice. That is, based on the given restrictions, O can be assigned to the fifth period.
The option that is true as regards the 7 sessions for the consecutive time periods under the given conditions is;
B; O is assigned to the fifth period.
We are given the seven sessions during the day as;
M, N, O, P, S, T and U.
There are seven consecutive time periods for the sessions with the following conditions;
Only one session can be schedules for each period.M and O must occupy consecutive periods.M must be scheduled for an earlier period than U.O must be scheduled for a later period than S. If S does not occupy the fourth period, then P must occupy the fourth period. U and T cannot occupy consecutively numbered periods.Combining the 2nd and third conditions above, we have the order;M, O, U or O, M, U.
Considering the fourth condition given with the order above, we have; S, M, O, U or S, O, M, U.Considering the fifth condition given with the orders above, we have the orders;- S, M, O, P, U
- T/U
, S
, N
, P
, T/U
, M/O
, M/O
- S
, T/U
, N
, P
, T/U
, M/O
, M/O
- S, O, M, P, U
Now, from the sixth condition we can say that the order for N, T and U is;U, N, T or T, N, U
Finally, looking at the options and considering the orders from the conditions applied, the only correct answer is that O can be assigned to the fifth period since M/O are in the fifth and sixth period from our arranged orders.Read more about Logical reasoning at; https://brainly.com/question/14458200
thiết kế ic 555 và code để ic hoạt động
Answer:
here you go.
screenshot 2 should give you some basic idea
4kj of energy are supplied to a machine used for lifting a mass.The force required is 800N.If the machine has an efficiency of 50%. To what height will it lift the mass?
Identify the best drying agent or process for each described purpose. Removal of small amounts of water from a polar solvent____. Removal of visible pockets of water from an organic solvent____. Storage of solvents or other materials in a desiccator_____.
Answer:
Calcium Chloride
Brine Wash
Drierite
Explanation:
Removal of small amounts of water from a polar solvent is Calcium Chloride
Removal of visible pockets of water from an organic solvent is Brine Wash
Storage of solvents or other materials in a desiccator is Drierite
The view factor for radiation emitted by surface 1 to surface 2 was calculated to be 0.4. The working area of surface 1 is 0.01 m2, the working area of surface 2 is 0.04 m2. What is the view factor for radiation emitted by surface 2 to surface 1?
Answer:
The view factor for radiation emitted by surface 2 to surface 1 is 0.1
Explanation:
Given
[tex]F_{12} = 0.4[/tex]
[tex]A_1 = 0.01m^2[/tex]
[tex]A_2 = 0.04m^2[/tex]
Required
Determine [tex]F_{21}[/tex]
To do this, we make use of the following equivalent ratio
[tex]A_1 * F_{12} = A_2 * F_{21}[/tex]
Make [tex]F_{21[/tex] the subject
[tex]F_{21} = \frac{A_1 * F_{12}}{ A_2}[/tex]
Substitute values into the equation
[tex]F_{21} = \frac{0.01m^2 * 0.4}{0.04m^2}[/tex]
[tex]F_{21} = \frac{0.01 * 0.4}{0.04}[/tex]
[tex]F_{21} = \frac{0.004}{0.04}[/tex]
[tex]F_{21} = 0.1[/tex]
nơi nào có điện tích thì xung quanh điện tích đó có :
Explanation:
sory sorry sorry sorrysorrysorry
16) Find the output of the following flowchart
Address
100
101
102
103
104
105
Value
1
2.
3
8
15
16
hi
Answer:80
Answer:
364 566 inches of class-6th from a
In a series circuit, there ______ for current to flow.
a.
are at least two paths
b.
are multiple paths
c.
is only 1 path
d.
are very small paths
Answer:
Option C = Only 1 path for current to flow.
list 3 appliances each of the following
soil
waste
Answer:
soil>>Slop sink
>Urinal
>water closet
8. The operation of a TXV is controlled by the
O A. thermostatic spring.
O B. temperature bulb.
O C. external pressure of the evaporator.
O D. modulating valve.
You find an unnamed fluid in the lab we will call Fluid A. Fluid A has a specific gravity of 1.65 and a dynamic viscosity of 210 centipoise [cP]. What is the kinematic viscosity of Fluid A, in units of stokes [St]
Answer:
1.2727 stokes
Explanation:
specific gravity of fluid A = 1.65
Dynamic viscosity = 210 centipoise
Calculate the kinematic viscosity of Fluid A
First step : determine the density of fluid A
Pa = Pw * Specific gravity = 1000 * 1.65 = 1650 kg/m^3
next : convert dynamic viscosity to kg/m-s
210 centipoise = 0.21 kg/m-s
Kinetic viscosity of Fluid A = dynamic viscosity / density of fluid A
= 0.21 / 1650 = 1.2727 * 10^-4 m^2/sec
Convert to stokes = 1.2727 stokes
A steel beam is used in the roadbed of a bridge. The beam is mounted between two concretesupports when the temperature is 23 [oC], with no room provided for thermal expansion. Whatcompressional stress must the concrete supports apply to each end of the beam, if they are to keep the beam from expanding when the temperature rises to 42 [oC]
Answer:
13.86 MPa
Explanation:
We need to find the change in length ΔL of the steel beam and thus, the strain in the beam, ε.
ΔL = L₀αΔθ
Strain, ε = ΔL/L₀ = αΔθ where α = coefficient of linear expansion of steel = 11 × 10⁻⁶ °C and Δθ = temperature change of steel beam = θ₂ - θ₁ where θ₁ = initial temperature of steel beam = 23 °C and θ₂ = final temperature of steel beam = 42 °C
Substituting the values of the variables into the equation, we have
ε = αΔθ
ε = α(θ₂ - θ₁)
ε = 11 × 10⁻⁶ /°C(42 °C - 23 °C )
ε = 11 × 10⁻⁶ /°C(42 °C)
ε = 462 × 10⁻⁶
ε = 4.62 × 10⁻⁴
Now, the Young's modulus of concrete is Y = 30 GPa = 30 × 10⁹ N/m²
Y = σ/ε where σ = compressional stress from concrete and ε = strain on steel
So, σ = Yε
σ = 30 × 10⁹ N/m² × 4.62 × 10⁻⁴
σ = 138.6 × 10⁵ N/m²
σ = 1.386 × 10² × 10⁵ N/m²
σ = 1.386 × 10⁷ N/m²
σ = 13.86 × 10⁶ N/m²
σ = 13.86 MPa
The mean of 10 numbers is 9, then the sum (total) of these numbers will be
Answer:
90
Explanation:
mean is basically taking the sum of all numbers and then dividing the sum with the number of all given numbers..
here, the mean is 9, total numbers are 10.. so the sum will be 9 multiplied by 10, that is 90.
If the mean of 10 numbers is 9, then the sum (total) of these numbers will be 90. The correct option is D.
What is mean?The mean is the average of a set of variables in mathematics and statistics. The mean can be calculated in a variety of ways, including the simple arithmetic mean (add the numbers and divide the total by the number of observations), geometric mean, and harmonic mean. Mean is denoted by a small m.
To calculate mean: Arrange the data items in ascending order from least to greatest. If the number of points is odd, the median is the data point in the middle of the list. If the number of data points in the list is even, the median is the average of two middle data points.
Mean = total sum of the numbers/total numbers
9 = total sum of the numbers / 10
The sum of the terms = 9 x 10 = 90
90 = total sum of the numbers
Therefore, the correct option is D. 90
To learn more about the mean, refer to the link:
https://brainly.com/question/28670966
#SPJ2
The question is incomplete. Your most probably complete question is given below:
A. 9. B. 0.9. C. 70. D. 90
good housekeeping can increase production in a work place is it true or false
False, Good housekeeping eliminates accident and fire hazards. It also maintains safe, healthy work conditions; saves time, money, materials, space, and effort; improves productivity and quality; boosts morale; and reflects an image of a well-run, successful organization.
Hope it helps you❤️
Which is one characteristic shared by electromagnetic and mechanical waves?
A. Both have a crest and a trough.
B. Both move due to particles bumping into each other.
C. Both are formed by charged particles.
D. Both occur as a result of a disturbance.
Answer:
its A
Explanation:
An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after traveling a distance d.
a. What is the magnitude of the electric field?
b. What is the direction of the electric field?
1. in the direction of the electron's motion
2. opposite to the direction of the electron's motion
3. perpendicular to the direction of the electron's motion
Answer:
The answer is below
Explanation:
a) The work done is equal to the loss in kinetic energy (KE)
Change in kinetic energy (ΔKE) = Final kinetic energy - initial kinetic energy
Final KE = [tex]\frac{1}{2}mv_f^2[/tex]
But the final velocity is 0 (at rest). Hence:
Final KE = [tex]\frac{1}{2}mv_f^2=\frac{1}{2}m(0)^2=0[/tex]
ΔKE = 0 - K = -K
W = ΔKE = -K
Also, the work done (W) = charge (q) * distance (d) * electric field intensity (E)
W = qEd
but q = -e, hence:
W = -e * E * d
Using:
W = ΔKE
-e * E * d = -K
E= K / (e * d)
b) The electric field is in the direction of the electrons motion
Why is the newtons law of cooling and explain how to derive it/
Answer:
For small temperature difference between a body and its surrounding, the rate of cooling of the body is directly proportional to the temperature difference and the surface area exposed. qf = final temperature of object
Explanation:
hope this helps you sorry if it doesn’t help you